Help me solve this ASAP please

Answer: X = 9

Step-by-step explanation:

First insert the function into a graphing calculator.

We are trying to find the x intercepts, we substitute y=0.

With a graphing calculator look at where the line intercepts the x axis, (9,0) , and we find that x=9.

Answer:

a. 35 people participated in the walk.

b. About 16 people traveled more than 14 kilometers.

Step-by-step explanation:

(Warning: This may be wrong)

Answer:

168

Step-by-step explanation:

first find out how many rows of squash there are

21 = x + 2x

21 = 3x

7 = x

then find out how many rows of tomatoes there are

7 × 2 = 14

if there are 12 plants per row, we can multiply

14 × 12 = 168

Gardener Gary planted 168 tomato plants

Let the rows of tomato be x and the rows of squash be y.

So, we have:

x + y = 21

The statement twice as many rows of tomatoes as rows of squash means that:

x = 2y

Substitute x = 2y in x + y = 21

2y + y = 21

This gives

3y = 21

Divide by 3

y = 7

Substitute y = 7 in x = 2y

x = 2 * 7

x = 14

This means that Gary planted 14 rows of tomato.

The number of tomato plants is then calculated using

Tomato plants= 14 * plants per row

This gives

Tomato plants = 14 * 12

Evaluate the product

Tomato plants = 168

Hence, Gardener Gary planted 168 tomato plants

Read more about system of equations at:

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Answer:

Suzy needs to work 62.5 hours, or 62 hours and 30 minutes.

Hope it helps!

Answer:

5v^10

or

9765625v

Step-by-step explanation:

5^10 = 9765625

Ans multiplied by v (when we don't know the value of v) is 9765625v

Answer:

- 16k + 28

Step-by-step explanation:

3 - 2(k - 2) - 7(2k - 3) ← distribute parenthesis

= 3 - 2k + 4 - 14k + 21 ← collect like terms

= - 16k + 28

Answer:28−16k

Step-by-step explanation:

3−2(k−2)−7(2k−3)

Use the distributive property to multiply −2 by k−2.

3−2k+4−7(2k−3)

Add 3 and 4 to get 7.

7−2k−7(2k−3)

Use the distributive property to multiply −7 by 2k−3.

7−2k−14k+21

Combine −2k and −14k to get −16k.

7−16k+21

Add 7 and 21 to get 28.

28−16k

[tex]\\ \sf\longmapsto 1\dfrac{2}{3}+2\dfrac{3}{4}+3\dfrac{5}{6}[/tex]

[tex]\\ \sf\longmapsto \dfrac{5}{3}+\dfrac{11}{4}+\dfrac{23}{6}[/tex]

[tex]\\ \sf\longmapsto \dfrac{20+33+46}{12}[/tex]

[tex]\\ \sf\longmapsto \dfrac{99}{12}[/tex]

[tex]\\ \sf\longmapsto 8.2ft[/tex]

Rope left

[tex]\\ \sf\longmapsto 10-8.2=1.8ft[/tex]

1¾ ft ≈ 1,75 ft

[tex] \sf 1\frac{2}{3} + 2 \frac{3}{4} + 3\frac{5}{6} [/tex]

[tex] \sf = \frac{3 + 2}{3} + \frac{4 \times 2 + 3}{4} + \frac{6 \times 3 + 5}{6} [/tex]

[tex] = \sf \frac{5}{3} + \frac{11}{4} + \frac{23}{6} [/tex]

[tex] \sf = \frac{5 \times 4 + 11 \times 3}{3 \times 4} + \frac{23}{6} [/tex]

[tex] = \sf \frac{20 +33 }{12} + \frac{23}{6} [/tex]

[tex] \sf = \frac{53}{12} + \frac{23}{6} [/tex]

[tex] = \sf \frac{53}{12} + \frac{23 \times 2}{6 \times 2} [/tex]

[tex] \sf = \frac{53}{12} + \frac{46}{12} [/tex]

[tex] \sf = \frac{99}{12} [/tex]

[tex] \sf = \frac{10}{1} - \frac{99}{12} [/tex]

[tex] \sf = \frac{10 \times 12 - 99}{12} [/tex]

[tex] = \sf \frac{120 - 99}{12} [/tex]

[tex] \sf = \frac{21}{12} [/tex]

= 1¾ ft ≈ 1,75 ft

Solution 1 :-

Given expression ,

[tex]\implies 13^{\frac{3}{4}} [/tex]

We know that, [tex] a^{\frac{m}{n}} = \sqrt[n]{a^m} [/tex]

Therefore , this can be written as ,

[tex]\implies \sqrt[4]{13^3} [/tex]

Solution 2:-

Given expression ,

[tex]\implies \sqrt[3]{24^{10}} [/tex]

We know that,[tex] a^{\frac{m}{n}} = \sqrt[n]{a^m} [/tex]

Therefore, this can be written as ,

[tex]\implies 24^{\frac{10}{3}}[/tex]

Answer: 1.) D.  

--------------------------------------------------------------------------------------------------------------

2.)    C. (24 10/3)

Answer:

21 T-shirts, (this is just a thought of what i think i need to do) Hope it helps

Step-by-step explanation:

I think iv seen this question somewhere so did u forget to put 22?

Here is the explaination if u did...

5T -22 = 83

revenue minus expense = profit

5T = 83+22 = 105

T = 105/5 = 21 T shirts sold

Answer:

Step-by-step explanation:

12

Answer:

3/8g + 2 = 5  

Subtract the number 2 from both sides of the equation.

3/8g = 3

Now divide 3/8 from both sides of the equation.

3/8 divided by 3/8 equals 0.  3 divided by 3/8 equals 8.

The final answer is:

g = 8

------------------------------------------------------------------------------------------

Check your answer:

3/8g + 2 = 5

Substitute 8 into the spot where the variable g was.

3/8 X 8 + 2 = 5

So our answer x = 8 is true.

Step-by-step explanation:

I hope that this has helped you to understand this equation. If you have any questions please put them below in the comments. If there are no questions, please have a great rest of your day/night!

Answer:

1/3.75

Step-by-step explanation:

Answer:

26.66666666666667

Step-by-step explanation:

1200/45=

Answer:

34

Step-by-step explanation:

The left shapes' side is 10 and the other side is 7. The difference between these sides are 3.  Onto the next polygon we would do the same thing. So 37-3 = 4

Answer:

7 to the power of 13

Step-by-step explanation:

Answer:

7  to the power of 13

Step-by-step explanation:

Step 1 - 7 to the power of 8 (7 x 8 = 56)

Step 2 - 7 to the power of 5 (7 x 5 = 35)

Step 3 - (7 x 8) + (7 x 5) = 91

Step 4 - Divide 91 by 7

Then your answer would be 7 to the power of 13

Answer:

6

Step-by-step explanation:

{0; 2}

{0; 4}

{0; 6}

{2; 4}

{2; 6}

{4; 6}

a) The linear function that models the amount of water after t minutes is given by:

[tex]V(t) = 200 + 12t[/tex]

b) It takes 92 minutes to completely fill the pond.

Item a:

Then, the function is:

[tex]V(t) = 200 + 12t[/tex]

Item b:

It takes t minutes to fill the pond, t is found for which:

[tex]V(t) = 1304[/tex]

Then

[tex]200 + 12t = 1304[/tex]

[tex]12t = 1104[/tex]

[tex]t = \frac{1104}{12}[/tex]

[tex]t = 92[/tex]

It takes 92 minutes to completely fill the pond.

A similar problem is given at https://brainly.com/question/16302622

Step-by-step explanation:

[tex]\large\underline{\sf{Solution-}}[/tex]

[tex]\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)[/tex]

Let assume that

[tex]\rm :\longmapsto\:y = {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)[/tex]

We know,

[tex]\boxed{\tt{ {cosec}^{ - 1}x = {sin}^{ - 1}\bigg( \dfrac{1}{x} \bigg)}}[/tex]

So, using this, we get

[tex]\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2x}{1 + {x}^{2} } \bigg)[/tex]

Now, we use Method of Substitution, So we substitute

[tex] \red{\rm :\longmapsto\:x = tanz \: \rm\implies \:z = {tan}^{ - 1}x}[/tex]

So, above expression can be rewritten as

[tex]\rm :\longmapsto\:y = sin^{ - 1} \bigg( \dfrac{2tanz}{1 + {tan}^{2} z} \bigg)[/tex]

[tex]\rm :\longmapsto\:y = sin^{ - 1} \bigg( sin2z \bigg)[/tex]

[tex]\rm\implies \:y = 2z[/tex]

[tex]\bf\implies \:y = 2 {tan}^{ - 1}x[/tex]

So,

[tex]\bf\implies \: {cosec}^{ - 1}\bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = 2 {tan}^{ - 1}x[/tex]

Thus,

[tex]\rm :\longmapsto\:\dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg)[/tex]

[tex]\rm \:  =  \: \dfrac{d}{dx}(2 {tan}^{ - 1}x)[/tex]

[tex]\rm \:  =  \: 2 \: \dfrac{d}{dx}( {tan}^{ - 1}x)[/tex]

[tex]\rm \:  =  \: 2 \times \dfrac{1}{1 + {x}^{2} } [/tex]

[tex]\rm \:  =  \: \dfrac{2}{1 + {x}^{2} } [/tex]

Hence,

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ \dfrac{d}{dx} {cosec}^{ - 1} \bigg( \dfrac{1 + {x}^{2} }{2x} \bigg) = \frac{2}{1 + {x}^{2} }}}}[/tex]

Hence, Option (d) is correct.

Same question here answered by me with proper explanation.Visit the link below for your ans

https://brainly.com/question/24967986?

Answer:

AB

Step-by-step explanation:

They are the shortest combined side

Answer:

1478 is the answer

have a fang-tastic day <3

Step-by-step explanation:

Answer:

1478

Step-by-step explanation:

lol have a good day/night!!

Scientific Notation is the way of writing a number or expressing them in a shorter or more compact way.

No, Taylor's resoning is incorrect because  2,800,000 = [tex]2.8 * 10^{6}[/tex]

From the question, we are given:

2,800,000 .

2,800,000 in scientific notation is  [tex]2.8 * 10^{6}[/tex].  

The reason the power is not to the negative 6 is that we are moving from the right-hand side to the left-hand side 6 times.

Therefore, Taylor's reasoning is incorrect.

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