Given: sin theta=2/3 and is in the second quadrant; evaluate the following expression. sin 2 theta

Answer: 6 tablets.

Given:

• A certain medication is available only in 400 μg tablets.

So, in milligrams :- 0.4 mg

• It is also given that the patient needs to take 2.4 mg per day.

Solution:

So, in order to know how many tablets she should take, please do as following:-

[tex] \frac{2.4}{0.4} [/tex]

[tex] = > \: 6[/tex]

Hence, she must take 6 tablets per day.

✍️ By Benjemin ☺️

For this derivative, you could set

[tex]\boxed{u = x^2 - 4x}[/tex]

Then

[tex]y = \sin(x^2-4x) = \sin(u)[/tex]

so that

[tex]\boxed{\dfrac{\mathrm dy}{\mathrm du} = \cos(u)}[/tex]

and

[tex]\boxed{\dfrac{\mathrm du}{\mathrm dx} = 2x - 4}[/tex]

Then the chain rule gives

[tex]\dfrac{\mathrm dy}{\mathrm dx} = \dfrac{\mathrm dy}{\mathrm du}\dfrac{\mathrm du}{\mathrm dx} \\\\ \dfrac{\mathrm dy}{\mathrm dx} = \cos(u)(2x-4) \\\\ \boxed{\dfrac{\mathrm dy}{\mathrm dx} = (2x-4)\cos(x^2-4x)}[/tex]

Answer:

y= 80/9

Step-by-step explanation:

Given

" y varies directly as x" and "as the square of z" so y = x* z²* some number

if y =25/9 when x= 5, z= 1 and y = x*z²* some number

then 25/9  = 5 * 1² * some number

      5*(5/9) = 5 * some number

therefore y = x* z²* (5/9)

y= ? when x=1 , z= 4

y = x * z² * (5/9)

y = 1 * 4² * (5/9)

y = 16*5 / 9

y = 80/9

Answer:

160

Step-by-step explanation:

the answer is -800 ______________________

Answer:

Datas are not given...............

Answer:

there is no data? pls give data

Answer:bbbbb

Step-by-step explanation:

sssđs

Given : 13 apples for every 2 pies

We know that : 12 = 2 × 6

Therefore, the number of apples will be 13 × 6 = 78

So, the answer is 78

Answer:

E=1/2mv2, v/10./17

Step-by-step explanation:

Answer:

the 34 yrs Is wrong it will be 4yrs only.

Step-by-step explanation:

Let my present age=x years

After 12 years my age=x+12 years

4 years ago my age =x−4 years

According to the question,

x+12=3(x−4)

⇒x+12=3x−12

⇒3x−x=12+12

⇒2x=24

or x= 24/2 =12 years.

∴ my present age is 12 years.

hope this helps you.

The confidence interval for the mean gives an estimated range in which the true population mean of the data resides. Since, the fan uses all the population data, then he could find the population mean directly.

Therefore, since the fan is already using all the population data, then he could just calculate the population mean directly.

Learn more :https://brainly.com/question/2396419

9514 1404 393

Answer:

  3

Step-by-step explanation:

The square root function (√) only gives positive values, so graphs 1 and 4 make no sense.

When x = -3, the y-value is 0, consistent with graph 3.

Answer:

2

Step-by-step explanation:

Degree of the monomial is the highest power in the monomial.

Highest power in the monomial - 1.57k^2 is 2.

So, the degree of the monomial - 1.57k^2 is 2.

Answer:

None of the option is correct.

The right answer is 18/7 or 2.57

Step-by-step explanation:

Answer:

I believe it is D

Step-by-step explanation:

If I am correct please mark Brainlyiest

The table that shows these data correctly entered in a two-way frequency table is:

                    In Band Not in Band Total

Play                   15                10       25

Do Not Play    5               20       25

Total           20               30       50

A two-way frequency table is a way of organizing and displaying data that shows the frequency of occurrences of two categorical variables.

In such a table, the rows represent one variable, the columns represent the other variable, and the cells show the number (or frequency) of times that each combination of categories occurs.

We have,

A two-way frequency table shows how many times each combination of two categorical variables occurs.

In the table, the rows represent the "play an instrument" variable, the columns represent the "are in band" variable, and the totals are shown at the end of each row and column.

The entries in the table represent the frequency, or the number of students who belong to each combination of categories.

In this case, the two variables are "play an instrument" and "are in band". Based on the given information, we can create the following table:

Thus,

The table that shows these data correctly entered in a two-way frequency table is:

                    In Band Not in Band Total

Play                   15                10       25

Do Not Play    5               20       25

Total           20               30       50

Learn more about two-way frequency here:

https://brainly.com/question/31189964

#SPJ7

Answer:

multiply 9*512= 4,608

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

Answer:J is between H and K. If HJ=6x-5, JK=4x-6 and KH= 129, find the value of HJ

Explanation:J is between H and K. If HJ=6x-5, JK=4x-6 and KH= 129, find the value of HJ

Step-by-step explanation:

mark me as the brainliest

Answer:

Answer is: two electrons.

n - principal quantum number, indicating relative overall energy of each orbital, n=1,2,3,...

l - angular momentum quantum number, shape of the orbital, l = 0,1,...,n−1.      

l =1 for the p orbitals.

ml - magnetic quantum number, ml = 0,±1,...,±l.

This is 2px orbital, in every orbital there is two electrons with different spin.

Step-by-step explanation:

Mark Brainliest Please

x = 72

Step-by-step explanation:

x + (2x - 36) = 180

3x - 36 = 180

3x = 180 + 36

3x = 216

x = 216/3

x = 72

Answer

x=21

Step-by-step explanation:

1/3+2=1/2x-1.5

2/6x+2=3/6x-1.5

-2/6+1.5 =-2/6x+1.5

3.5=1/6x

----- = -----

1/6      1/6

21

Answer:

The person in the comments was correct it is x=21

Step-by-step explanation:

hope this helps you if not please let me know

12 because you can enter through 2 front doors. Let's call them A and B. You enter through A and you have 6 doors to leave through. You enter through B you have 6 doors to leave.

Answer:

y =  2x - 1

Step-by-step explanation:

To find out the equation of the line, you will always need the following information in order to determine the linear equation in slope-intercept form, y = mx + b:

1. 2 sets of ordered pairs (x, y)

2. Slope (m)

3. Y-intercept (b)

First, we need to choose 2 points from the graph to solve for the slope:

Let (x1, y1) = (0, -1)

(x2, y2) = (3, 5)

Substitute these values into the following slope formula:

[tex]m = \frac{y2 - y1}{x2 - x1} = \frac{5 - (-1)}{3 - 0} = \frac{5 + 1}{3} = \frac{6}{3} = 2[/tex]

Therefore, the slope (m) = 2.

Next, we need the y-intercept, (b). The y-intercept is the y-coordinate of the point where the graph of the linear equation crosses the y-axis. The y-intercept is also the value of y when x = 0. The y-coordinate of the point (0, -1) is the y-intercept.  Hence, the y-intercept (b) = -1.

Given our slope, m = 2, and the y-intercept (b) = -1, the linear equation is:

y = 2x - 1

Please mark my answers as the Brainliest if you find my explanations/solution helpful :)

9514 1404 393

Answer:

  0.9114

Step-by-step explanation:

That multiplier would be ...

  (1 -2%)×(1 -7%)

  = (1 -0.02)(1 -0.07)

  = 0.98×0.93 = 0.9114

9514 1404 393

Answer:

  4

Step-by-step explanation:

The exponents of m in the two terms are 4 and 6. The exponent of the common factor can be no greater than the smallest of these. (It is the smallest of these.)

  GCF(30m^4, 36m^6) = 6m^4 . . . . exponent is 4

Answer:

hi

Step-by-step explanation:

for example

[tex] \frac{8}{4} = 2 \\ \\ 1 \times \frac{4}{5} = \frac{9}{5} [/tex]

in the second one you should multiple 5 and 1 then add 4

Answer:

y''=sec^3(x)*csc(x)+sec^2(x)*tan(x)-2cot(x)*csc(x)*sec(x)*tan(x)+cot^2(x)*csc(x)*sec(x)+csc^3(x)*sec(x)

Step-by-step explanation:

we are given y= csc x sec x

We use the rule for multiplying derivatives and the knowledge that the derivative of csc is -csc*cot and the derivative of sec is sec*tan to get

csc(x)*sec(x)*tan(x)+sec(x)*-csc(x)*cot(x)

which simplifies to

csc(x)*sec(x)*tan(x)-sec(x)*csc(x)*cot(x)

Using the same rules again (in tedium so they are not listed but can be inferred) we find the second derivative is

sec^3(x)*csc(x)+sec^2(x)*tan(x)-2cot(x)*csc(x)*sec(x)*tan(x)+cot^2(x)*csc(x)*sec(x)+csc^3(x)*sec(x)

Answer:

Hello! I can help you with it :)

Well, I do not know where you live, so I do not know what nooks and crannies your hm could be hiding.

Answer:

it will look like this 4(a+3)-2/3

Step-by-step explanation:

look since the equation "a+3" replaced for the place of "x" in f(x), you replace it on the equation "4x- 2/3" and just solve

Answer:

Step-by-step explanation:

Id..k how to help u sorry

Answer:

no yes of couse its yes but no so yes  1727x+293

Step-by-step explanation:

Answer: Choice C

4/(3*sqrt(3))

which is the same as writing [tex]\frac{4}{3\sqrt{3}}[/tex]

==============================================================

Explanation:

We have the line [tex]\left(\sqrt{2}\right)x+y +2 = 0[/tex] in which points B and C are on this line. In other words, all of segment BC is on that line.

Point A is somewhere off that line as the diagram below indicates. We need to find the line through A that is perpendicular to the given line.

Recall that for any line of the standard form [tex]Px+Qy+R = 0\\\\[/tex], any perpendicular line will look like this: [tex]Qx-Py+S = 0\\\\[/tex]. Note the swap and sign change for the P,Q coefficients.

So anything perpendicular to [tex]\left(\sqrt{2}\right)x+y +2 = 0[/tex] will be of the form [tex]x-\left(\sqrt{2}\right)y+S = 0[/tex]. The sub-goal here is to find what S is equal to.

If you plugged in the origin point (x,y) = (0,0), then you should find that S = 0.

Therefore, the equation [tex]x-\left(\sqrt{2}\right)y = 0[/tex] is perpendicular to the given line and it passes through point A(0,0).

---------------------------

The reason why we computed that perpendicular line is to help determine the point D as shown in the diagram below. This point is at the intersection of the green perpendicular lines. This is at the base of the triangle such that BC is the base.

To find the location of point D, you need to solve this system of equations

[tex]\begin{cases}\left(\sqrt{2}\right)x+y +2 = 0\\\\x-\left(\sqrt{2}\right)y = 0\end{cases}[/tex]

Let's isolate x in the second equation

[tex]x-\left(\sqrt{2}\right)y = 0\\\\x=\left(\sqrt{2}\right)y\\\\[/tex]

Then substitute that into the other equation. Solve for y.

[tex]\left(\sqrt{2}\right)x+y +2 = 0\\\\\left(\sqrt{2}\right)*\left(\sqrt{2}\right)y+y +2 = 0\\\\2y+y +2 = 0\\\\3y +2 = 0\\\\3y = -2\\\\y = -2/3\\\\[/tex]

Now we can find x like so

[tex]x=\left(\sqrt{2}\right)y\\\\x=\left(\sqrt{2}\right)*(-2/3)\\\\x=\frac{-2\sqrt{2}}{3}\\\\[/tex]

The point D is located at the exact coordinates of

[tex]D=(x,y) = \left(\frac{-2\sqrt{2}}{3},\frac{-2}{3}\right)\\\\[/tex]

---------------------------

Next, we use the distance formula to compute the distance between point A and point D.

I'll use lowercase d to represent distance.

[tex]A = (x_1,y_1) = (0,0)\\\\D = (x_2,y_2) = \left(\frac{-2\sqrt{2}}{3},\frac{-2}{3}\right)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{\left(0-\left(\frac{-2\sqrt{2}}{3}\right)\right)^2 + \left(0-\left(\frac{-2}{3}\right)\right)^2}\\\\d = \sqrt{\left(\frac{2\sqrt{2}}{3}\right)^2 + \left(\frac{2}{3}\right)^2}\\\\d = \sqrt{\frac{8}{9} + \frac{4}{9}}\\\\d = \sqrt{\frac{12}{9}}\\\\d = \sqrt{\frac{4}{3}}\\\\d = \frac{\sqrt{4}}{\sqrt{3}}\\\\d = \frac{2}{\sqrt{3}}\\\\[/tex]

This represents the exact length of segment AD.

---------------------------

Since triangle ABC is equilateral, this means triangles ADB and ADC are identical mirrored copies of each other. Those two smaller triangles are equal in area and combine to form triangle ABC back again. Furthermore, they are right triangles. This last fact mentioned will allow us to use the pythagorean theorem like so

[tex]a^2+b^2 = c^2\\\\\left(\text{AD}\right)^2+\left(\text{DC}\right)^2=\left(\text{AC}\right)^2\\\\\left(\frac{2}{\sqrt{3}}\right)^2+\left(\frac{x}{2}\right)^2=\left(x\right)^2\\\\[/tex]

where x represents the lengths of AB, BC and AC.

After skipping a bit of steps, solving that said equation should lead to these two solutions

[tex]x = -\frac{4}{3}, \ x = \frac{4}{3}[/tex]

Because x is a side length, we ignore the negative solution.

---------------------------

We can now compute the area of triangle ABC

[tex]\text{area of triangle} = \frac{1}{2}*\text{base}*\text{height}\\\\\text{area of triangle ABC} = \frac{1}{2}*\text{BC}*\text{AD}\\\\\text{area of triangle ABC} = \frac{1}{2}*\frac{4}{3}*\frac{2}{\sqrt{3}}\\\\\text{area of triangle ABC} = \frac{1*4*2}{2*3*\sqrt{3}}\\\\\text{area of triangle ABC} = \frac{8}{6\sqrt{3}}\\\\\text{area of triangle ABC} = \frac{4}{3\sqrt{3}}\\\\[/tex]

which points us to choice C as the final answer.

When writing this on a keyboard, we would write "4/(3*sqrt(3))" without quotes. The use of parenthesis is needed to ensure we divide by all of 3*sqrt(3). Otherwise, the computer might mistake it for [tex]\frac{4}{3}\sqrt{3}[/tex] which is entirely different.