Find the midpoint of the given line segment with the given endpoints
(-3, 8) and (2, -4)

Answer:

1.1

Step-by-step explanation:

Find the mean of the data:(3+4+5+5+5+6+6+6+7+8)/10 = 5.5Step 2: Find the difference between each data and mean:Difference between 3 and 5.5 is 2.5Difference between 4 and 5.5 is 1.5Difference between 5 and 5.5 is 0.5Difference between 5 and 5.5 is 0.5Difference between 5 and 5.5 is 0.5Difference between 6 and 5.5 is 0.5Difference between 6 and 5.5 is 0.5Difference between 6 and 5.5 is 0.5Difference between 7 and 5.5 is 1.5Difference between 8 and 5.5 is 2.5Step 3: Add all the differences:2.5+1.5+0.5+0.5+0.5+0.5+0.5+0.5+1.5+2.5 = 11Step 4: Divide it by the number of data:11/10 = 1.1So, the MAD = 1.1

Answer:

B

Step-by-step explanation:

H,E on the line perpendicular to the plane

D,E,F on the horizontal line on the plane

The data sets with a range that is greater than 10 are:

1 5 7 8 14

5 7 9 21 23

The range of any given data set is the difference between the largest and the lowest data point in the data set.

Range for 4 5 6 7 13:

Range = 13 - 4 = 9

Range for 1 5 7 8 14:

Range = 14 - 1 = 13

Range for 10 11 14 17 18:

Range = 18 - 10 = 8

Range for 5 7 9 21 23:

Range = 23 - 5 = 18

11 11 11 11 11 has no range.

Therefore, the data sets with a range that is greater than 10 are:

1 5 7 8 14

5 7 9 21 23

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Work Shown:

5 times 2 = 10

5 times 13 = 65

5 times 2.13 = 10.65

This rounds to 10.7 when rounding to the nearest tenth, i.e. one decimal place.

The area and perimeter of the rectangle are 80 cm and 375 cm² respectively.

The rectangle is 15 cm wide.

The width is 3 / 5 of its length

Therefore, the area and the perimeter of the rectangle can be found as follows:

area of a rectangle = lw

where

Therefore,

w = 15 cm

15 = 3 / 5 × l

cross multiply

75 = 3l

l  =75 / 3

l = 25 cm

Therefore,

area of the rectangle = 25 × 15 = 375 cm²

Perimeter of the rectangle = 2l + 2w

Perimeter of the rectangle = 2(l + w)

Perimeter of the rectangle = 2(25 + 15)

Perimeter of the rectangle = 2(40)

Perimeter of the rectangle = 80 cm

Therefore, the area and perimeter of the rectangle are 80 cm and 375 cm² respectively.

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Answer:

5i is an imaginary number and it's square is - 25.

by definition zero is considered to be both real and imaginary.

Step-by-step explanation:

#studywell #workhard #worksmart

Answer:

Step-by-step explanation:

0.29 as a fraction is 29/100. Anytime you have a decimal, just turn it into a whole number and simplify it. However, 29/100 is already in its simplest form.

For the given sample data, 42, 25, 86, 30, 25, 15, 42, 42, the mode is 42.

In statistics, the mode, denoted by Mo, refers to the most frequent value or values in the data set. If all the numbers in the data set appears only once, then the data set has no mode.

For the given sample data,

42, 25, 86, 30, 25, 15, 42, 42

the number 42 appears thrice, 25 appears twice and the rest appears only once.

The number 42 appeared the most frequent among all the other data.

Hence, the mode of the data set that contains 42, 25, 86, 30, 25, 15, 42, 42 is 42.

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f(-3) = -1

We can find an unknown y-value by plugging an x-value into a given function.

Function Notation

Before we answer this question, we need to understand the notation of the equation. In function notation, the equation is given in terms of f(x).

For example, f(-3) represents the value of y when x = -3.

Finding f(3)

As stated above, to find f(-3) we need to plug -3 in for x. *Remember to use PEMDAS when solving.* This creates the new equation:

Then, distribute the exponent.

Next, multiply.

Distribute the negative.

Finally, add the remaining terms.

This means that when x = -3, y or f(-3) = -1.

0.00345    is the value of p(x).

What means binomial distribution?

P(x₁= 2 , x₂ = 2 , x₃ = 5 )

p( x₁= 2) . p(  x₂ = 2) . p( x₃ = 5)        .........( as these are independent variable)

[c⁴₂ ( 0.5 )² ( 0.5 )² ] [ c⁶₂  ( 1/3)²(2/3)⁴ ] [ c¹²₅ (1/6)⁵ (5/6)⁷  

= 0.375 × 0. 329 × 0.028

= 0.00345  

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Answer:

here is my answer........

Step-by-step explanation:

(3-x)^2 = 9 - 3x - 3x + X2

= X2 - 6x +9

Answer:

i think the question might be incorrect or the question is incomplete

Answer:

I would say A

Step-by-step explanation:

Because just because a quadrilateral has 4 congruent sides, does not make it a rhombus. Because a square has 4 congruent sides too.

The larger of the two integers is 18 and the smaller integer is 17.

Integers are collection of whole numbers and negative numbers. Integers are not fractional numbers or decimal. Some examples of integers are -5,-25,0,13,9 .

Let us consider the smaller integer be x.

As the integers are consecutive, the larger integer is (x+1).

Now according to the given condition:

Twice the large integer=2(x+1)

15 less than the 3 times the smaller integer=3x-15

Now the value of these two expressions is equal.

Therefore: [tex]2(x+1)=3x+-15[/tex]

Solving the above equation to find the value of x:

[tex]or,2(x+1)=3x-15\\or,2x+2=3x-15\\or,2x-3x=-15-2\\or,-x=-17\\or,x=17[/tex]

Therefore the smaller integer is 17.

Larger integer(x+1) : 17+1=18

Therefore the integers are 17 and 18.

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Probability= 5/9

Even cards = 2,4,6,8

Odd cards = 1,3,5,7,9

The number of ways of choosing one odd and one even number is 5C1 * 4C1

            (  5!/ 1!* 4!) * (4!/1! * 3!)

            5* 4= 20

Total number of ways of choosing 2 cards out of 9 = 9C2

        9!/ 2! * (9-2)!

     = 9!/ 2! * 7!

     = 9*8/2

    = 9 *4= 36

Thus, Probability is = 20/ 36

                             = 5/9

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Answer:

False

Step-by-step explanation:

Sometimes, multiplication can occur after addition. For example, in 3+4*7, you don't add 3 and 4 first. You multiply 4 and 7 first since that's following the PEMDAS rule. After multiplying 4 and 7, then you add 3 to get a total of 31. ==> 3+4*7=3+28=31.

The homogeneous linear ODE

[tex]y^{(4)} + y''' + y'' = 0[/tex]

has characteristic equation

[tex]r^4 + r^3 + r^2 = r^2 (r^2 + r + 1) = 0[/tex]

with a double root at [tex]r=0[/tex] and two complex roots

[tex]r^2 + r + 1 = 0 \implies r = -\dfrac{1 \pm i\,\sqrt3}2[/tex]

Hence the characteristic solution is

[tex]y = C_1 e^{0x} + C_2x e^{0x} + C_3 e^{((-1/2)-i(\sqrt3/2))x} + C_4 e^{((-1/2)+i(\sqrt3/2))x}[/tex]

[tex]y = C_1 + C_2x \\\\ ~~~~~~~~~~ + C_3 e^{-x/2} \left(\cos\left(\dfrac{\sqrt3}2x\right) - i\, \sin\left(\dfrac{\sqrt3}2x\right)\right) \\\\ ~~~~~~~~~~ + C_4 e^{-x/2} \left(\cos\left(\dfrac{\sqrt3}2x\right) + i\,\sin\left(\dfrac{\sqrt3}2x\right)\right)[/tex]

[tex]y = C_1 + C_2x + C_3 e^{-x/2} \cos\left(\dfrac{\sqrt3}2x\right) + C_4 e^{-x/2} \sin\left(\dfrac{\sqrt3}2x\right)[/tex]

Check the picture below.

Step-by-step explanation:

-3x+7-5x<15

-5x-3x+7<15

-8x+7<15

-8x<15-7

-8x<8

The smallest integer is -3x.

Answer: 27.3861278753

Step-by-step explanation:

√750 = 27.3861278753

The area of the region inside both curves r = 9 sin(θ) and r = 9 cos(θ) is 11.56 square units.

It is defined as the mathematical calculation by which we can sum up all the smaller parts into a unit.

The curves are:

r = 9 sin(θ) and

r = 9 cos(θ)

On graphing the above curves:

From the graph:

A = (1/2)∫(9sin(θ))2dθ + (1/2)∫(9cos(θ)2dθ

The region is symmetrical about π/4,:

A = 81∫sin2(θ)dθ from 0 to π/4

After solving:

= 11.56 square unit

Thus, the area of the region inside both curves r = 9 sin(θ) and r = 9 cos(θ) is 11.56 square units.

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Answer:

30 Mins

Step-by-step explanation:

9 mins for 3 waffles is 3 mins per waffle. 9÷3=3

3 mins for each of 10 waffles is 30 mins. 3×10=30.

Answer: get a verified 340

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

Answer: 6

Step-by-step explanation:

First, take the prime factorization of all 3 numbers.

30: 15*2 ==> 5*3*2

60: 30*2 ==> 15*2*2 ==> 5*3*2*2

78: 39*2 ==> 13*3*2

Notice any common factors? That's the GCF.

GCF: 3*2=6

GCF: 6

Answer:

I'm pretty sure the answer is D

Step-by-step explanation:

I took the test

The sentence that contains a dangling modifier is D. Searching frantically, the homework was finally found and turned in.

A word or phrase that modifies a term that is not explicitly expressed in the sentence is known as a dangling modifier. A modifier provides a concept's definition, clarification, or more information.

A grammatical modifier that could be mistakenly understood as being connected to a word other than the one intended is known as a hanging modifier. A hanging modifier, which usually refers to a participle, has no subject.

Therefore, the sentence that contains a dangling modifier is Searching frantically, the homework was finally found and turned in.

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Answer:

4. $216 gain

5. 30g

I hope this helps