Explain why this is not true. WILL GIVE BRAINLIEST

The domain is written in the form { x : x ≠ 7/3 }

Given data

Y= 1-7x / 8-|3x-15|

The domain refers to the values of x, from the equation we solve for the possible values that will not make the equation undefined.

For the equation to be undefined the denominator should be zero hence we solve for the value of x that will make the equation, to have a denominator equal to zero and the domain will be any other values of x except the value that gives the denominator equal to zero,

The denominator is 8-|3x-15|

solving for the value of x that gives the equation that makes the equation equal to zero

8-|3x-15| = 0

3x - 15 = -8

3x = -8 + 15

3x = 7

x = 7/3

The domain is written in the form { x : x ≠ 7/3 }

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In the garage 33.33 percentage of work were MOTS.

Percentage is defined as per-cent, that is out of hundred. The percentage is calculated by dividing the acquired value by the total value and multiplying the result by 100.

Now in the given problem,

Total number of vehicles on which Keith worked is 105.

The number of MOTS among the 105 is 35.

Now we have to calculate the percentage of the MOTS out of a total 105 vehicles.

Let us use the formula=(number of MOTS ÷ total vehicles)×100

Therefore required percentage=[tex]\frac{35}{105}\times 100\%[/tex]

or, percentage=33.333...%

Therefore we can conclude that the total percentage of MOTS were approximately 33.33%(rounded to 2 decimal places).

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The distance between the starting point(initial) and the ending point(last) is known as displacement is  9.46miles.

What is displacement?

In the first(1st) part of the race displacement of Erica is

d1 = 5.2 miles at 25(twenty-five) deg North of East

x(ax) and y-component of 1st(first) part of the race will be:

d1 = 5.2*cos 25(twenty five) deg i + 5.2*sin 25(twenty five) deg j

d1 = (4.71 i + 2.20 j) miles (this id d1)

In the second(2nd) part of the race

d2 = 6(six) miles towards north,

So

d2 = (6 j) miles (this is d2)

Now net(accurate) displacement of Erica will be, Using Vector addition(summation):

d = d1(4.71 i + 2.20 j) + d2(6j)

d = (4.71 i + 2.20 j) +(sum) (6 j)

d = 4.71 i +(sum) 8.20 j

So Magnitude of net(accurate) displacement will be:

|d| = [tex]\sqrt{4.71^2+8.20^2}[/tex]

|d| = 9.46 miles(nine.four-six) = distance between starting(initial) point and ending point

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Answer:

  19 seconds

Step-by-step explanation:

You want to know the time it takes for Juan, running 18 m/s, to overtake Mahdi, running 6 m/s, if Mahdi has a 228 meter head start.

The time to close the gap between the runners will be ...

  time = distance/speed

  time = (228 m)/(difference in speeds) = (228 m)/(18 m/s -6 m/s)

  time = (228 m)/(12 m/s) = (228/12) s = 19 s

It will take Juan 19 seconds to catch Mahdi.

__

Additional comment

The fastest human runner will not exceed 12.3 meters per second, especially over a 300+ meter distance.

Answer:

the slope intercept form is 5y= -x+12

The statement correctly describes the perpendicular bisector construction below The construction of JK to bisect GH: Option D is the correct answer

The term perpendicular bisector refers to the line that divides another line into two equal parts, making an angle of 90 degrees. The term is made up of two words, perpendicular and bisector.

Perpendicular refers to angle 90 degrees, while the bisector refers to dividing into two equal parts.

In the picture, the main line is GH while JK is the line constructed to bisect the main line

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A reasonable domain for this function is [0, 18)

The domain of a function is a value of the independent variable of the function for which it exists.

Given the equation below:

M(x)= -40x+720

Since the function represents the The amount of money remaining in the budget for marketing  then the function f(x) must be greater than zero;

−40x + 720 > 0

-40x> -720
x < 720/40
x < 18

This shows that a reasonable domain for this function is [0, 18)

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Answer:

x∈(-3;0)∪(3;+∞).

Step-by-step explanation:

1) if to solve the inequality x³-9x>0, then

x(x-3)(x+3)>0, and solution is

x∈(-3;0)∪(3;+∝).

2) the graph is provided in the attachment (it is marked with red colour).

Answer:

A Cartesian Plane is a plane in Geometry which is an flat surface of infinite size. It has two number lines that intersect at right angles at their zeros. One number line is horizontal, and the other number line is vertical. The point of intersection is the zero of each line. In the horizontal line, the numbers increase to the right. In the vertical line, the numbers increase up. The horizontal line is called the x axis. The vertical line is called the y axis. The center of the Cartesian Plane is the intersection of the two axes, the two number lines, and is called the origin. Points on the Cartesian Plane are described with two numbers in parentheses separated by a comma. The position of the point in the Cartesian Plane is given by the first number, called the x-coordinate, telling us the number of units to the right (positive) or left (negative) of the origin and by the second number, called the y-coordinate, telling us the number of units up (positive) or down (negative) from the origin.

(a) The leading coefficient is positive and the degree is odd, so:

(b) The leading coefficient is negative and the degree is even, so:

Step-by-step explanation:

[tex] 3\sqrt{8} + \sqrt{114} [/tex]

Answer: Yes, it is.

Step-by-step explanation:

given: x is 0 and y is 3. Plug in the equation and solve

y=x+3

3=0+3

3=3

Yes, it is a solution

By decomposing the figure into simpler ones, we conclude that the area of the irregular figure is 108 square inches.

Here we have an irregular figure that can be decomposed into 3 simpler figures, these are:

Remember that the area of a rectangle is the product between the two dimensions, so the areas of these 3 rectangles are:

a = 6in*8in = 48in^2

a' = 10in*4in = 40in^2

a'' = 5in*4in = 20in^2

Adding these areas we get:

48in^2 + 40in^2 + 20in^2 = 108 in^2

The area of the irregular figure is 108 square inches.

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Solve the homogeneous equation

[tex]y'' + 3y' + 2y = 0[/tex]

Its characteristic equation is

[tex]r^2 + 3r + 2 = (r + 1) (r + 2) = 0[/tex]

with roots at [tex]r=-1[/tex] and [tex]r=-2[/tex], hence the characteristic solution is

[tex]y_c = C_1 e^{-x} + C_2 e^{-2x}[/tex]

For the nonhomogeneous equation, I'll use variation of parameters. We're looking for a solution of the form

[tex]y = u_1 y_1 + u_2 y_2[/tex]

to the equation

[tex]y'' + a(x) y'' + b(x) y = f(x)[/tex]

such that

[tex]\displaystyle u_1 = - \int \frac{y_2f(x)}{W(y_1,y_2)} \, dx[/tex]

[tex]\displaystyle u_2 = \int \frac{y_1 f(x)}{W(y_1,y_2)} \, dx[/tex]

The Wronskian [tex]W(y_1,y_2)[/tex] of the two fundamental solutions [tex]y_1=e^{-x}[/tex] and [tex]y_2=e^{-2x}[/tex] is

[tex]W(y_1,y_2) = \begin{vmatrix} y_1 & y_2 \\ {y_1}' & {y_2}' \end{vmatrix} = -e^{-3x}[/tex]

Then we have

[tex]\displaystyle u_1 = - \int \frac{e^{-2x} \cdot 4e^x \cos(3x)}{-e^{-3x}} \, dx = 4 \int e^{2x} \cos(3x) \, dx[/tex]

[tex]\displaystyle u_2 = \int \frac{e^{-x} \cdot 4e^x \cos(3x)}{-e^{-3x}} \, dx = -4 \int e^{3x} \cos(3x) \, dx[/tex]

Recall Euler's identity,

[tex]e^{(a+bi)t} = e^{at} (\cos(bt) + i \sin(bt))[/tex]

Then we have the general antiderivative

[tex]\displaystyle \int e^{(a+bi)t} \, dt = \frac1{a+bi} e^{(a+bi)t} + C = \frac{a-bi}{a^2+b^2} e^{(a+bi)t} + C[/tex]

Taking the real parts of both sides, we have

[tex]\displaystyle \mathrm{Re}\left\{\int e^{(a+bi)t} \, dt \right\} = \mathrm{Re}\left\{\frac{a-bi}{a^2+b^2} e^{(a+bi)t} + C\right\} \\\\ \int\,\mathrm{Re}\left\{e^{(a+bi)t}\right\} \, dt = \frac{e^{at}}{a^2+b^2} \mathrm{Re}\left\{(a-bi)(\cos(bt) + i \sin(bt))\right\} + C \\\\ \int e^{at} \cos(bt) \, dt = \frac{e^{at}}{a^2+b^2} (a\cos(bt)+b\sin(bt)) + C[/tex]

so that

[tex]\displaystyle u_1 = 4 \int e^{2x} \cos(3x) \, dx = \frac{4e^{2x}}{13} (2\cos(3x) + 3 \sin(3x))[/tex]

and

[tex]\displaystyle u_2 = -4 \int e^{3x} \cos(3x) \, dx = -\frac{2e^{3x}}3 (\cos(3x) + \sin(3x))[/tex]

We've found

[tex]y = u_1 y_1 + u_2 y_2[/tex]

[tex]\displaystyle y = \frac{4e^x}{13} (2\cos(3x) + 3 \sin(3x)) - \frac{2e^x}3 (\cos(3x) + \sin(3x))[/tex]

[tex]\displaystyle y = \frac2{39} e^x (5\sin(3x) - \cos(3x))[/tex]

Then the general solution to the differential equation is

[tex]\boxed{y(x) = C_1 e^{-x} + C_2 e^{-2x} + \frac2{39} e^x (5\sin(3x) - \cos(3x))}[/tex]

The percent of juniors whose score is at least 71 % is 69.15 %.

We are given that:

Test of the students are normally distributed.

Mean = μ = 71

Standard deviation = σ = 5

We need to find the percent of juniors whose score is at least 71 %.

Now, we know that:

z = ( x - μ) / σ

z = 100 - 71 / 5

z = 29 / 5

z = 5.8

So, percentage = 69.15 %

Therefore, we get that, the percent of juniors whose score is at least 71 % is 69.15 %.

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Answer:

Please add the graph for these problems so I can solve your questions? Thank you!

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

The range of a data set in statistics is the difference between the largest and the smallest values. While range does have different meanings within different areas of statistics and mathematics, this is its most basic definition, and is what is used by the provided calculator. Using the same example:

2,10,21,23,23,38,38

38 - 2 = 36

The range in this example is 36. Similar to the mean, range can be significantly affected by extremely large or small values. Using the same example as previously:

2,10,21,23,23,38,38,1027892

The range, in this case, would be 1,027,890 compared to 36 in the previous case. As such, it is important to extensively analyze data sets to ensure that outliers are accounted for.

Answer: Range is all the values of the y-axis therefore, the range of the graph is {0,4,6,8}

If you meant to say [tex]|5x+1| < -2[/tex], then there are no solutions.

This is because the |5x+1| is never negative. This applies to the result of any absolute value function. Absolute value represents distance on a number line. Negative distance is not possible.

---------------------------------------------------------------

If you meant to say [tex]|5x+1| \le 2[/tex], then the steps are shown below

[tex]|5x+1| \le 2\\\\-2 \le 5x+1 \le 2\\\\-2-1 \le 5x+1-1 \le 2-1\\\\-3 \le 5x \le 1\\\\-3/5 \le 5x/5 \le 1/5\\\\-3/5 \le x \le 1/5\\\\-0.6 \le x \le 0.2\\\\[/tex]

The interval notation would be [-3/5, 1/5] in fraction form

That is equivalent to [-0.6, 0.2] in decimal form.

Use square brackets to include each endpoint.

Explanation:

Place the decimal point between the first two digits to get 5.0

Then we must move the decimal point 4 spots to the right to get back to 50,000

So that's where the "4" comes in with the 10^4

This means 50,000 = 5 * 10^4 which is in scientific notation.

The answer in scientific notation is 5 times 10^4

The exponent of four tells you to multiply 10 by itself 4 times.

10 x 10 = 100 x 10 = 1000 x 10 = 10000

And 10000 times 5 is equal to 50,000.

Answer:

give me those points boy=o >:)

Step-by-step explanation:

While horizontal and vertical shifts involve adding constants to the input or to the function itself, a stretch or compression occurs when we multiply the parent function

f

(

x

)

=

b

x

by a constant

|

a

|

>

0

. For example, if we begin by graphing the parent function

f

(

x

)

=

2

x

, we can then graph the stretch, using

a

=

3

, to get

g

(

x

)

=

3

(

2

)

x

and the compression, using

a

=

1

3

, to get

h

(

x

)

=

1

3

(

2

)

x

.

Measure of linear pair A and B are 86 and 38 respectively.

Let the measure of  B = x

And measure of  A = 3x – 28

As  A and B are linear pair. Therefore their sum will be equal to 180

That is numerically,

      A + B = 180

Putting the required values of A and B we will get

     3x – 28 + x = 180

      4x  = 180-28

       4x = 152

        x = 38

Hence the measure of A = 3*38 – 28 = 86

And the measure of B = x = 38

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Number of hours Aviva's work for gross earnings of $662.30 for a week with regular rate of $10.80 per hour for 35 hour week and 1.5 of regular pay for overtime is 52.6hours.

Given,

Gross earning for week=$662.30

Regular rate per hour for 35hour week=$10.80

Overtime rate=1.5×(10.80)

For 'h' number of hours

(10.80×35)+(10.80×1.5) h=$662.30

⇒378 +16.20h=662.30

⇒h=284.30/16.20

⇒h≈17.6hours

Number of hours Aviva's work=35 +17.6

                                                  =52.6hours

Therefore, number of hours Aviva's work for gross earnings of $662.30 for a week with regular rate of pay $10.80 per hour for a 35 hour week and 1.5 of regular pay for overtime is 52.6hours.

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Optionally you can replace 0.25 with the fraction 1/4

===================================================

Explanation:

The variable y varies directly with x, which means we have the template of y = kx for some constant k.

Plug in x = 8 and y = 2. Then solve for k

y = kx

2 = k*8

8k = 2

k = 2/8

k = 1/4

k = 0.25

Therefore, we go from y = kx to y = 0.25x

-------------

Check:

Plugging in x = 8 should get us to y = 2

y = 0.25x

y = 0.25*8

y = 2

The answer is confirmed.

The conditional statement is that; If generally a person is 1% shorter in the evening than in the morning, then my height is about 1.62326 m in the evening.

First, we will calculate how much is one percent of your height and then subtract that percentage from the total height to get your" height in the evening".

For example:

If my height is 1.64 m, then;

0.01 * 1.64 m = 0.0164 m

Step 2 is;

1.64m - 0.0164m = 1.62326 m

​

Now, using these height, let's write a conditional that uses the described fact:

Conditional:

If generally a person is 1% shorter in the evening than in the morning, then my height is about 1.62326 m in the evening.

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Answer:

x=+2√7

Step-by-step explanation:

Answer:

y = 19.2

Step-by-step explanation:

We know there is relationship between y and x, so according to the formula [tex]y = kx[/tex]

k = 12/5

we get one function y = 2.4x

when x = 8, input it into the function,

y = 2.4×8 = 19.2

Answer:

The given Divisor = 405 and Dividend = 48849

The Quotient is 120 and the Remainder is 249

Hope it helps you

Answer:

4x12 equals 48 therefore 48+5= 53......

Answer:

500

Step-by-step explanation:

500*2=1000

1000/2=500