At rest, hydrogen has a spectral line at 116 nm. if this line is observed at 107 nm for the star sirius, how fast is sirius moving in km/s?

Answers

Answer 1

According to the given statement the speed of sirius is =2.3275862×10¹²km/s.

What is the wavelength?

A waveform signal's wavelength, which is the distance between two identical locations (adjacent crests) in the succeeding cycles, determines whether it is sent through space or via a wire. Typically, in wireless systems, this length is specified in meters (m), centimeters (cm), or millimetres (mm).

Briefing:

Hydrogen has a spectral line at = 116nm=116×10⁻⁹m

Line is observed at = 107 nm=107×10⁻⁹m

Now, from the Hubble's law

V=[tex](\Delta \lambda / \lambda)[/tex]×C

Where,

v is the velocity

Δλ = Change in wavelength = 116 - 107= 9nm=9×10⁻⁹m

λ = Actual wavelength=116nm=116×10⁻⁹m

C is the speed of the light=3×10⁸m/s

on substituting the respective values, we get

V=(9/116)×3×10⁸=23275862.069×10⁵m/s

V=2.3275862×10¹²km/s.

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Related Questions

Best answer will be mark Brainliest!

Do you feel that Mendeleev should receive the main credit for the structure of today’s periodic table? Defend your position in a paragraph

Answers

Answer:

Mendeleev is generally given more credit than Meyer because his table was published first, and because of several key insights that he made regarding the table.

Explanation:

The lung volume that represents the maximum amount of exchangeable air is the _____

Answers

The lung volume that represents the maximum amount of exchangeable air is the: vital capacity

The vital capacity is the volume of air that can be taken into the lungs by inhaling and expelling air by inspiration and expiration. it is also known as (VC).

The value of the VC is around 4800 mL and it varies according to the age and body size. The formula to calculate the vital capacity is:

VC = TV+IRV+ERV

Where:

TV = tidal volumeIRV = inspiratory reserve volumeERV = expiratory reserve volume

What are the lungs?

The lungs are one of the largest organs of the body and are in charge of the respiratory function. They have a spongy appearance and are located in the thorax, protected by the ribs, one on each side of the heart.

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A ball is thrown directly downward with an initial speed of 7.95 m/s from a height of 30.6 m. after what time interval does it strike the ground?

Answers

Answer:

1.82 seconds

Explanation:

∆ y = 1/2at^2 + Vi*t
a is acceleration, y is height, and Vi is initial velocity
30.6 = 1/2*9.8*t^2 + 7.95 * t
simplify and rearrange
4.9t^2 + 7.95t - 30.6 = 0
solve the quadratic
t = 1.816128... and a negative number, but since this is physics, in this case time can't be negative
Round to 3 significant figures
t = 1.82

If the work input of a machine is 30 joules,what would be it's efficiency when the output is 25 joules?

Answers

The efficiency of the machine is 83.3% when the output is 25 joules.

What is efficiency?

This can be defined as the ratio of the work output to the work input of a machine, expressed in percentage.

To calculate the efficiency of the machine we use the formula below.

Formula:

• E (%) = (Wo/Wi)100........... {Eq1}

Where:

• E (%) = Efficiency of the machine

Wo = Work output

Wi = Work input.

From the question,

Given:

Wo = 25 Joules

Wi = 30 Joules

Substitute these values into equation 1

We have,

• E (%) = (25/30)100

• E (%) = 83.3%

Hence, the efficiency of the machine is 83.3%.

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A doctor measures the temperature of a patient
to be 101°F. What is this temperature in kelvins?
(A) 38.3 K
73.8 K
311 K
(C)
214 K
(E) 346 K
(B)
(D)
-please help I’m too lazy to do the math

Answers

Answer: 311.483

Explanation:

(101°F − 32) × 5/9 + 273.15 = 311.483K

A glass tube (open at both ends) of length l is positioned near an audio speaker of frequency f 5 680 hz. for what values of l will the tube resonate with the speaker?

Answers

The lowest possible value of the length

L1 = 0.25m

- Second lowest possible value

L2 = 0.45m

- Third lowest possible value

L3 = 0.75

Calculation

Before calculating the length of the resonance tube, we have to first know the wavelength produced by the wave.

Using the expression

v = Foλ

V is the velocity of wave

Fo is the resonance frequency

λ is the wavelength

From the formula,

λ = v/Fo

λ = 343/680

λ = 0.50m

For an open pipe, the first resonant length L1 = λ/2

Second resonant length L2= λ

Third resonant length L3 = 3λ/2

The lowest possible value of the length L1 = 0.50/2

L1 = 0.25m

Second lowest possible value

L2 = 0.50m

Third lowest possible value

L3 = 3(0.50)/2

L3 = 0.75m

Hence, for values of 0.25,0.50 and 0.75, the tube resonates with the speaker.

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An urn contains 17 red marbles, 20 blue marbles, and 41 yellow marbles. one marble is to be chosen from the urn without looking. what is the probability of choosing a red marble?

Answers

The probability of choosing a red marble is 0.2179 or 21.79%.

We need to know about probability to solve this problem. The probability can be described as how possible an event will happen. It can be determined by

P = a / n

where P is the probability, a is the number of events and n is the total events.

From the question above, we know that:

red marbles = 17

blue marbles = 20

yellow marbles = 41

Hence, the total marble is

n = red + blue + yellow

n = 17 + 20 + 41

n = 78

The probability of choosing red marble is

P = a / n

P = 17 / 78

P = 0.2179

Convert to percent

P = 0.2179 x 100%

P = 21.79%

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With light microscopy, if the objective lens (lens closest to the specimen) magnifies 40-fold, and the eyepiece lens magnifies 10-fold, the final magnification will be:_________

Answers

The final magnification will be 400-fold or 400 times the original size of the object.

For magnifying smaller objects, a compound microscope is used.

A compound microscope consists of an objective and an eyepiece, whose diagram is shown in the adjoining image.

The lens  near  the object is called an objective and the other one is the eyepiece.

Let the magnification of the objective be m1

Let the magnification of the eyepiece be m2

The final magnification by the microscope, M, will be

M = m1 x m2

Putting the values in the above equation

M = 40 x 10

M= 400

Thus, the final magnification will be 400-fold or 400 times the original size of the object.

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A bumblebee flies with a ground speed of 15.3 m/s . calculate its speed in kilometers per hour (km/h).

Answers

The speed of the bumblebee in kilometers per hour (km/h) is 55.08 Km/h

Conversion scale

1 m/s = 3.6 Km/h

Data obtained from the question

The following data were obtained from the question:

Speed (in m/s) = 15.3 m/sSpeed (in Km/h) =?

How to convert 15.3 m/s to Km/h

We can convert 15.3 m/s to Km/h as illustrated below:

1 m/s = 3.6 Km/h

Therefore,

15.3 m/s = (15.3 m/s × 3.6 Km/h) / 1 m/s

15.3 m/s = 55.08 Km/h

Thus, 15.3 m/s is equivalent to 55.08 Km/h. Therefore, we can say that the speed of the bumblebee in Km/h is 55.08 Km/h

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A ball is thrown directly downward with an initial speed of 7.40 m/s from a height of 30.8 m. after what time interval does it strike the ground?

Answers

The time interval in fall motion is 1.86 seconds.

We need to know about fall motion to solve this problem. Gravity has a big role in fall motion. It can be described as

vt = vo + g . t

vt² = vo² + 2 . g . h

h = vo . t + 1/2 . g . t²

where vo is initial speed, vt is final speed, g is the gravitational acceleration (9.8 m/s²), h is height and t is time.

From the question above, we know that:

h = 30.8

vo = 7.4 m/s

Find the final velocity

vt² = vo² + 2 . g . h

vt² = 7.4² + 2 . 9.8 . 30.8

vt² = 54.76 + 603.68

vt² = 658.44

vt = 25.66 m/s

Find the time interval

vt = vo + g . t

25.66 = 7.4 + 9.8t

9.8t = 18.26

t = 1.86 seconds

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Almotorcycle has a maximum acceleration of 3 m/s2 in either direction and a maximum
speed of 25 m/s. How long does it take for the motoreycle to reach someone who is 1 km away?

Answers

Answer:

44.2 seconds

Explanation:

to accelerate to 25 m/s  will take   25/3 = 8.33 sec

   and cover  d = 1/2 a t^2 = 104.1 m

       this leaves  1000 - 104.1 = 895.92 meters to cover at 25 m/s

                = 35.84 seconds   added to the original 8.33 second required to get up to ax speed = 44.2 seconds

A 25 kg biker is riding their bike
down the street with a force of 35N.
A sudden gust of wind pushes back
the biker with 20N. What is the
acceleration of the biker?

Answers

The acceleration of the biker is 0.6 m s⁻².

Acceleration is the price of change in the velocity of an object with respect to time. Accelerations are vector quantities. The orientation of an object's acceleration is given through the orientation of the internet force performing on that item.

Acceleration is the name we deliver to any process where the speed changes. for the reason, that speed is a speed and a course, there are best methods so one can accelerate. Acceleration and Deceleration are one of the most essential subjects in the subject of science. Acceleration is the price of the converting of speed in any item, and deceleration refers to the price of acceleration,

forward force = 35 N

backward force = 20 N

Net force = 35 - 20

               = 15 N

we know that,

  force = mass × acceleration

      15 N = 25 kg × acceleration

Acceleration = 15/25

                       = 0.6 m s⁻²

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A current carrying wire is placed vertically. the magnetic field around the wire is rotating clockwise around the wire. what direction is the current moving?

Answers

A current carrying wire is placed vertically. The magnetic field around the wire is rotating clockwise around the wire. The current is moving from top to bottom

Holding a current carrying wire in your right hand with the thumb pointing in the direction of current flow, the fingers wrapping the wire will portray the magnetic lines of force direction, following the right-hand thumb rule.

As a result, a current carrying conductor is vertically held. If you follow the rule, the current should be passed through it to generate a clockwise magnetic field around the conductor from top to bottom.

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Find the vector v with the given magnitude and the same direction as u. magnitude direction v = 93 u = 0, 4, 4

Answers

Vector v is [tex]0,27\sqrt{2},27\sqrt{2}[/tex] for the given magnitude and the same direction as u, magnitude direction v = 93 u = 0, 4, 4.

What is a vector?

Vector, in physics, a quantity that has both the magnitude and direction. It is typically represented by an arrow whose direction is same as that of the quantity and whose length is proportional to the quantity’s magnitude. Although vector has magnitude and direction, it does not have position. That is, as long as its length is not changed, vector is not altered if it is displaced parallel to itself.

In contrast to vectors, the ordinary quantities that have a magnitude but not a direction are called scalars. For example, displacement, velocity, and acceleration are vector quantities, while speed (magnitude of velocity), time, and mass are scalars.

To qualify as a vector, a quantity having the magnitude and direction must also obey certain rules of combination. One of these is the vector addition, written symbolically as A + B = C (vectors are conventionally written as boldface letters). Geometrically, vector sum can be visualized by placing the tail of vector B at the head of vector A and drawing vector C—starting from tail of A and ending at the head of B—so that it completes triangle. If A, B, and C are the vectors, it must be possible to perform the same operation and achieve the same result (C) in reverse order, B + A = C. Quantities such as the displacement and velocity have this property (commutative law), but there are quantities (e.g., finite rotations in the space) that do not and therefore are not vectors.

Given that,

|v|= 27 and u= 0,4,4

Now unit vector

u= [tex]\frac{u}{|v|}[/tex]=[tex]\frac{0,4,4}{|0,4,4|}[/tex]

  =0,4,4/[tex]\sqrt{0^{2}+4^{2}+4^{2} }[/tex] = 0,4,4/ [tex]\sqrt{32}[/tex]

   =0/[tex]4\sqrt{2}[/tex],4/[tex]4\sqrt{2}[/tex],4/[tex]4\sqrt{2}[/tex]

   =1/[tex]\sqrt{2}[/tex],1/[tex]\sqrt{2}[/tex]

now the vector v in same direction as u means,

v= |v|.u= 27*([tex]0,1/\sqrt{2}, 1/\sqrt{2}[/tex])

Thus,

v= [tex](0,27/\sqrt{2},27/\sqrt{2})[/tex]

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A wave has an angular frequency of 127 rad/s and a wavelength of 2.62 m. calculate (a) the angular wave number and (b) the speed of the wave.

Answers

The angular wave number and (b) the speed of the wave is 522.66 m/s.

What is angular wave?

Precise wavenumber is an amount in hypothetical material science that is characterized as the quantity of radians per unit distance. Precise recurrence is the rakish dislodging of any component of the wave per unit time. Likewise, in wave wording for a sinusoidal wave, the rakish recurrence alludes to the precise dislodging of any component of the wave per unit time. It is addressed by A recurrence is a rate, thus, the elements of this amount are radians per unit time. Precise hubs are level planes (or cones) where the likelihood of finding an electron is zero. This implies we can't at any point track down an electron in a rakish (or some other) hub. While outspread hubs are situated at fixed radii, precise hubs are situated at fixed points.

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