After the core of a sun-like star starts to fuse helium on the horizontal branch, the core becomes?

The algebraic expression for the electric field for a point

We know that,

Φ = Q / ε[tex]_{0}[/tex]

Φ = EA

Q = σ A

where,

Φ = Electric flux

Q = Total charge

ε[tex]_{0}[/tex] = Electric constant

σ = Surface charge density

A = Area

Area of cylinder = 2 π R l

where,

R = Radius of cylinder

l = Length of cylinder

To calculate electric field at a point outside the cylinder, a gaussian surface is considered outside the cylinder with a radius r ( > R ) and length l. The flux on Gaussian cylinder is equal to the charge on surface of the cylinder.

Q = σ 2 π R l

The electric flux on the surface of cylinder is

Φ = σ 2 π R l / ε[tex]_{0}[/tex]

The electric flux on the Gaussian cylinder is

Φ = E 2 π r l

On equating both,

σ 2 π R l / ε[tex]_{0}[/tex] = E 2 π r l

E = σ R / ε[tex]_{0}[/tex] r

This is the equation for electric field at a point outside the cylinder.

To calculate electric field at a point inside the cylinder, a gaussian surface is considered inside the cylinder with a radius r ( < R ) and length l.

E 2 π r l = 0 ( Since there is no flux created inside a closed cylinder )

E = 0

This is the equation for electric field at a point inside the cylinder.

Gauss law states that the total flux outside a closed surface is directly proportional to net charge enclosed by the surface.

Therefore, the algebraic expression for the electric field for a point

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The time taken for the APUSH textbook to hit the ground is determined as 0.55 seconds.

The time of motion of an object is the time taken for the object to travel from its initial point to the final point.

The time taken for the APUSH textbook to hit the ground is calculated as follows;

t = √(2h/g)

where;

t = √(2 x 1.5/9.8)

t = 0.55 seconds

Thus, the time taken for the APUSH textbook to hit the ground is determined as 0.55 seconds.

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Its nucleus has eleven protons.

The nucleus of it has 12 neutrons.

The nucleus is surrounded by 10 electrons.

Net charge, proton (+1), and electron charges are used to calculate the number of electrons (-1).

Calculated from the atomic number of 11 and the mass number of 23, are 12 neutrons.

What are mass number and atomic number?

The total number of protons or electrons in an element is known as its atomic number. Therefore, using the atomic number to distinguish one element from another is helpful. The total number of protons and neutrons in an element is known as the mass number.

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Question:

An atom of sodium-23 (Na-23) has a net charge of +1. Identify the number of protons, neutrons, and electrons in the atom. Then, explain how you determined the number of each type of particle. Use the periodic table to help you.

Answer: Oxygen, silicon, iron and aluminum

Explanation: Oxygen, which composes about 49.5% of the total mass of the Earth’s crust, waters and atmosphere, according to the textbook “Modern Chemistry.” Silicon is second at 28%. Aluminum is a distant third, at only 8%. Compounds of silicon and oxygen make up 87% of the materials in the Earth’s crust.

The following question can be solved using formulas of Motion on one dimension as there is no updrift or downdrift

We will use the formula

[tex]v^{2}-u^2=2aS[/tex]

where v is the final velocity

u is the initial velocity

a is the acceleration of the boat

s is the distance in meters

u=0 as the initially the boat is at rest

S=12meter

acceleration is 5 m/s^2

[tex]v^{2}=[/tex]2 x 5 x 12

v^2=120

therefore final velocity is [tex]\sqrt{120}[/tex]=10.95m/s

Now using the formula v=u+at

v=[tex]\sqrt{120}[/tex]

[tex]\sqrt{120}[/tex]=0+5 x t

t= [tex]\sqrt{ 120[/tex]/5

t = 2.20 seconds

t is the time taken

Hence the boat takes 2.20seconds

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Here the total time of flight is used to determine how long it will take the ball. it takes 5s to the ball to hit the ground.

u = 25 m/s

h= 1.90 m

so tine of ascent = v= u + at

so u = gt so we have t =u/g

putting up the values we have,

t = 2.5 s

so total time of flight = 5s = time taken by the ball to hit the ground.

An object is said to be in free fall if there are no external forces acting on it other than gravity, which has the determined constant value of g = -9.8 m/s2. The object’s height, or h, is equal to ½ gravity times the square of the falling time. Horizontal projectile motion equations

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If a hypothetical planet is twice as far from the sun as the earth, it should have a time period of 1032 days.

In the early 17th century, Johannes Kepler observed planetary motions and researched them to give three laws known as Kepler’s Laws.

These laws are:

(1) Law of orbits

(2) Law of Areas

(3) Law of Periods

According to the third law, the square of the time period of revolution of a planet around the sun is proportional to the cube of the distance between the sun and the planet, represented by the following  formula

T^2 = r^3

Let T1 be the time period of the revolution of Earth and T2 be the time period of the revolution of the hypothetical planet.

Let r1 be the distance between Earth and the sun and r2 be the distance between the hypothetical planet and the sun.

From the above equation

T1^2 = r1^3

T2^2 = r2^3

Dividing the above equations,

(T1/T2)^2 = (r1/r2)^3

We are given that,

r2 = 2 x r1

And T1 = 365 days

So,

(365/T2)^2 = (r1/2r1)^3

Solving the above equation,

T2 comes out to be 1032 days.

Hence, if a hypothetical planet is twice as far from the sun as the earth, it should have a time period of 1032 days.

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The horizontal force p must a worker, new tension is P= 122.62 N

The tension in the rope is

[tex]T_{1}=W_{create} g[/tex]

T1=50×9.81

T1=490.5 N

And the rope is in vertical position

When a worker exert a horizontal force P on the rope, new tension is

[tex]T_{2} =\sqrt{T1^{2} +P^{2} }[/tex]

[tex]T_{2} =\sqrt{490.5}^{2}+P^{2}[/tex]

Since T1 is vertical component to the tension T2

[tex]T_{1} =T_{2} cos \alpha[/tex]

[tex]490.5^{2} /cos^{2} 14.036=490.5^{2} +P^{2}[/tex]

[tex]P^{2} =490.5^{2} /cos^{2} 14.036 - 490.5^{2}[/tex]

P= 122.62 N

As long as no horizontal applied forces are present, the horizontal response force is zero. A single-support cantilever beam has a response force and reaction moment. The total applied forces on the beam are equal to the reaction force.

When the compression pressures are removed, the distortion may either be permanent or reversible. In the latter scenario, the deformation creates reaction forces that compete with the compression forces and may ultimately bring them into balance.

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The photon energy excite the hydrogen atom when its electron is in the ground state −13.6eV.

The second energy level is -3.4 eV.

Therefore, if we calculate the energy levels E₁ & E₂

E₂ − E₁ = -3.4 eV − -13.6 eV = 10.2 eV

Hence, the above expression shows, to excite the electron from the ground state to the first excited state. Similarly

The energy of the electron in ground state is −13.6eV.and the energy required to move electrons from ground state to third excited state is 12.75eV.

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The visible light spectrum is bounded by these two types of radiation: ultraviolet and near infrared.

In physics, electromagnetic radiations are kind of waves that carry electromagnetic field and travel through space.

These waves transport electromagnetic energy while traveling through space.

Different types of electromagnetic waves are radio waves, infrared light, microwaves, gamma rays, UV radiations, and x-rays. While visible light is made up of only infrared and UV.

All these waves have different wavelengths, frequency and energy and make definite part of the electromagnetic spectrum.

These waves have dual nature and also exhibit dual particle nature and travel with light speed.

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The only dissimilarity between Coulomb's law and Newton's law of gravitation other than the type of force considered is Newton's law only considers negative force while Coulomb's law considers both forces.

In these contexts, it is considered that repulsive forces are positive and attractive forces are negative. So, Newton's law of gravitation considers gravitational force which only attracts. So, Newton's law of gravitation takes only negative force into account while Coulomb's law considers both electric charges.

According to Newton's law of gravitation,

F = G [tex]m_{1} m_{2}[/tex] / [tex]r^{2}[/tex]

According to Coulomb's law

F = k [tex]q_{1} q_{2}[/tex] / [tex]r^{2}[/tex]

Therefore, the only dissimilarity between Coulomb's law and Newton's law of gravitation other than the type of force considered is Newton's law only considers negative force while Coulomb's law considers both positive and negative forces.

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Charge must pass by a point in a wire is 5 Coulomb

Given:

time = 10 s = t

current = 0.50 A = I

To Find:

charge = q

Solution: Current is defined as amount of charge passing through a region per unit time. It is given by the formula

I = q/t

q = I x t = 0.50 A x 10 s = 5 Coulomb

Hence, charge must pass by a point in a wire is 5 Coulomb

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Water serves as a lubricant and a shock absorber as part of body fluids.

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The net forces on the first car is zero, the middle car is zero, and the last car is also zero.

In mechanics, the net force is the vector sum of all forces acting on a particle or object. The original forces' impact on the particle's motion is replaced by the net force, which is a single force. It causes the particle to accelerate at a rate equal to the sum of all those actual forces, as stated by Newton's second law of motion.

It is possible to figure out the torque connected to the point at which a net force is applied in order to keep the object's jets moving in the direction of the initial force field. Its resulting torque, the net force, has the same impact on the object's rotational motion as all actual forces combined.

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Olympus mons can be found on Mars planet.

In the Tharsis Montes region, close to the Martian equator, Olympus Mons is one of a dozen large volcanoes, many of which are ten to one hundred times taller than their terrestrial counterparts. The massive Martian mountain towers high above the surrounding plains of the red planet and may be waiting for the next eruption. The highest of them all runs about 374 miles (624 km), or about as far as the state of Arizona, and rises 16 miles (25 km) over the plains below. Olympus Mons rises three times higher than Mount Everest, which has a peak elevation of 5.5 miles above sea level and is the tallest mountain on Earth.

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The minimum speed the ball must be served so as to clear the net is 25.69 m / s

We know that,

Speed = Distance / Time

In order to calculate the time, we can use one of the equations of motion,

y = [tex]y_{0}[/tex] + [tex]v_{0}[/tex]t + 1/2 a[tex]t^{2}[/tex]

where,

y = Initial height

[tex]y_{0}[/tex] = Final height

[tex]v_{0}[/tex] = Initial velocity

a = Acceleration due to gravity

t = Time

Given that,

y = 2.7 m

[tex]y_{0}[/tex] = 1.08 m

[tex]v_{0}[/tex] = 0

a = -9.81 m / [tex]s^{2}[/tex] (Due to gravity)

Distance = 14.9 m

y = [tex]y_{0}[/tex] + [tex]v_{0}[/tex]t + 1/2 a[tex]t^{2}[/tex]

2.7 = 1.08 + 0 + 1/2  * ( -9.81 ) * [tex]t^{2}[/tex]

[tex]t^{2}[/tex] = 1.62 / ( - 4.9 ) = 0.33

t = 0.58 s

Speed = 14.9 / 0.58

Speed = 25.69 m / s

Velocity (speed) is the rate of change of distance with respect to time. It is denoted as V.

Therefore, the minimum speed the ball must be served so as to clear the net is 25.69 m / s

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4.89g of solid magnesium nitrate (148.3 g/mol) should be added to 500 ml of 0.118 m of sodium nitrate in order to produce an aqueous 0.25 m solution of nitrate ions.

From the given info, we know that there is already the presence of nitrate already mixed in the solution. then we have to find out how more is required to be added to it.

first, we find moles of NaNO3

0.500L x 0.118 M = 0.059 moles NaNO3

this means there are 0.059 moles of[tex]NO^{-} _{3}[/tex]

Here volume is not changing, so amount of moles needed to make this concentration = 0.25M x 0.5L = 0.125 moles

0.125 - 0.059 moles = 0.066 moles of [tex]NO^{-} _{3}[/tex] required to be added in the solution.

for every 1 mole of Mg[tex](NO^{-} _{3} )_ {2}[/tex], there are 2 moles of [tex]NO^{-} _{3}[/tex].

so, we will only need half of the total moles of magnesium nitrate.

converting moles to grams,

0.033 moles Mg[tex](NO^{-} _{3} )_ {2}[/tex] x 148.3 g/mol = 4.89g Mg[tex](NO^{-} _{3} )_ {2}[/tex]

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The airplane lands with a velocity of 150 m/s and its rate of deceleration is constant at -3 m/s^2,

[tex]u = 150 m/s[/tex]

[tex]a = -3 m/s^{2}[/tex]

[tex]v = 0[/tex]

According to the Equation of motion , [tex]v^{2} = u^{2} + 2as[/tex]

s = 3750 m

Equations of motion are the mathematical formula that describes the position, velocity, or acceleration of a body relative to a given frame of reference.

The airplane will have to travel 3750 m until it stops if its rate of deceleration is constant at -3 m/s^2.

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The correct answer is 5.6 Newton is the force on the egg .

Using newtons 2 law of motion

force  = mass  * accelaration

now accelaration =10 m / s^2

mass = 0.56 kg

force  = 0.56 * 10

force  = 5.6 newton

Newton's second law of motion governs the behavior of objects when all available forces are not balanced. The second law states that an object's acceleration is determined by two variables: the net force acting on the object and the object's mass. The acceleration of an object is proportional to the net force acting on it and inversely proportional to its mass. The acceleration of an object increases as the force acting on it increases. The acceleration of an object decreases as the mass of the object increases.

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Answer:

See below

Explanation:

It will be 1 PM distance (27km)  + 2 1/2 hrs of 98 km/hr

   =     27   +      2 1/2 * 98 = 272 km west of school

Answer:

c

Explanation:

The texture of the string. I took this test a week ago I got a 90% it is c!

To find the electron and hole concentrations and fermi levels in silicon at 300 k for boron, fermi level is 9.3 x [tex]10^4 cm^-3[/tex].

Ionization energy for boron in Si, 0.045 eV

Fermi level in silicon,

300 K at [tex]10^{15} cm^{-3}[/tex] (Boron atoms)

All boron impurities are ionized, 300K

Electron, hole concentrations and Fermi levels is found out,

The value of Na = [tex]10^{15} cm^{-3}[/tex]

np = [tex]\frac{ni^2}{nA}[/tex]

np = [tex]\frac{(9.65 x 10^9)^2}{10^15}[/tex]

np= 9.3 x [tex]10^4 cm^-3[/tex]

Fermi level is calculated,

Ef - Ev = kT ln(NV/ND)

value of kT = 0.0259 eV (300° K)

So, substitution the values

Ef - Ev = kT ln(NV/ND)

Ef - Ev = 0.0259ln (2.66 x [tex]10^{19} / 10^{15}[/tex] )

Ef - Ev = 0.0259ln (26600)

Ef - Ev = 0.0259 x 10.18

Ef - Ev = 0.263 eV

What is ionization energy?

Ionization energy, also known as ionization energy (IE) or ionization energy (British English spelling), is the minimal amount of energy needed to free the most loosely bonded electron from an isolated gaseous atom, positive ion, or molecule in physics and chemistry.

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The left hand plays a steady one-two beat in duple meter, while the right hand emphasizes notes that fall in between these beats. The name for this technique is syncopation.

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Given, Force = 390 N

Diameter of piston (1) = 4 cm

Diameter of piston (1) = 10 cm

now,

By using Pascal's Law which that states that " a pressure change at any point in a confined incompressible fluid is transmitted throughout the fluid such that the same change occurs everywhere", i.e. force per unit area is constant at any point in a confined incompressible fluid flow.

Mathematically, [tex]p=\frac{F1}{A1} = \frac{F2}{A2}[/tex]

where P is pressure at any point in a confined incompressible fluid

F1 and F2 = Force at point 1 and 2 respectively

A1 and A2 = Area of point 1 and 2

So,  [tex]F2 = \frac{F1}{A1} * A2[/tex]

[tex](A1 = \frac{\pi D1^{2} }{4} )\\(A2= \frac{\pi D2^{2} }{4} )[/tex]

[tex]F2 = 390 * \frac{\frac{\pi D2^{2} }{4} }{\frac{\pi D1^{2} }{4} }[/tex]

[tex]F2 = \frac{390}{4*4} * 10^{2}[/tex]

F2 = 2437 N

The magnitude of the force f2 is 2437 N

The given question is complete, complete question is...

"If a 390 N force F1 is applied to the piston with the 4 cm diameter, what is the magnitude of the force F2 that can be resisted by the piston with the 10 cm diameter? Neglect the weights of the pistons."

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Answer:

Telescope, Probware, etc,..

Answer: probeware

Explanation:

the answer is probeware

if you mean by the options,

A. a ruler

B. a thermometer

C. a beaker

D. probeware

The cart's speed is 0.5 m/s and the puck's speed is 0.45 m/s is 0.05 and .95m/s

Given:

A=The cart's speed is 0.5 m/s

B=The puck's speed is 0.45 m/s

Relative velocity formula =

[tex]V_{AB}=V_{A}-V_{B}[/tex]

[tex]V_{AB}=.5-.45=.05\\[/tex]

[tex]V_{BA}=V_{B}-V_{A}[/tex]

=.5+.45=0.95

The velocity of an object in respect to another object is defined as relative velocity. It is a measure of how rapidly two items move in relation to each other. In physics, relative velocity is significant because it explains how objects move and interact with one another. Many different sorts of interactions can have their relative velocity quantified. The velocity of an object in respect to another object is defined as relative velocity. It is a measure of how rapidly two items move in relation to each other. In physics, relative velocity is significant because it explains how objects move and interact with one another.

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The final velocity of the ball, given the data is –13.8 m/s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

The final velocity of the ball can be obtained as follow:

a = (v – u) / t

–2 = (v – 0.2) / 7

Cross multiply

v – 0.2 = –2 × 7

v – 0.2 = –14

Collect like terms

v = –14 + 0.2

v = –13.8 m/s

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A kangaroo will stay 0.699s in the air when he jumps.

A projectile is an object that is launched vertically into the air and moves while being pulled by gravity. A projectile is an object that is launched into the air horizontally and moves regardless of gravity.

G = -9.81 m/s2 is the acceleration of gravity close to the earth. Simply multiply the acceleration of gravity by the period since the object was released to determine the object's speed (or velocity). In other words, velocity is equal to -9.81 m/s2 * time, or V = gt.

From the conversion of energy  =[tex]h=\frac{g t^2}{2}[/tex]

                                                 t = √(2h/g)

                                                   =  √((2 x 2.40) / 9.8)

                                                  =0.699 s

A kangaroo will stay 0.699s in the air when he jumps.

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The work done to haul up the rope is Nm.

We need to know about work to solve this problem. Work can be defined as the energy transferred to or from an object via the application of force along a displacement. It can be written as

W = F x s

where W is work, F is force and s is the displacement.

From the question above, we know that

λ = N/m

s = m

Find the force applied

F = λ . s

F = N/m . m

F = N

Find the work done

W = F . s

W = N . m

W = Nm

Hence, the work done to haul up the rope is Nm.

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