Answer: A. Light always travels in a straight line.
Explanation: Light follows rectilinear motion. Rectilinear motion is also known as linear motion. For example; the motion of a bullet fired from a gun, a ray of the torch.
Light always travels in a straight line. It is considered to travel from one point to another in a straight line joining them. The path of light is called a ray of light.
To learn more about light:
https://brainly.com/question/104425
A wave with a frequency of 6 khz was found to oscillate 24 000 times. Over what time period was it measured?.
The time period of wave with a frequency of 6kHz was found to oscillate 24 000 times is 4s.
Given the frequency of wave (f) = 6kHz
Number of times the wave oscillates (n) = 24000
Let the time period = T
The time period frequency is inversely related to the number of oscillations. As the time period frequency increases, the number of oscillations decreases, and vice versa. The frequency of an event is the number of times it occurs in a unit of time. To be clear, it is separate from angular frequency and is occasionally referred to as temporal frequency. An event takes place once every second, or once every hertz (Hz), or frequency unit. Then, T = n/f such that:
T = 24000/(6 x 10^3) = 4s
To learn more about frequency click here https://brainly.com/question/22548127
#SPJ4
(a) Is the electric field E in Gauss’s law, Int E*dA= Qencl/?o, created only by the charge Qencl? Explain. (b) Define gravitational flux in analogy to electric flux. Are there "sources" and "sinks" for gravitational field as there are for electric field? Discuss.
Answer:
A) Electric flux depends on the charge Q within and enclosed surface regardless of the shape of the surface - this concept is particularly useful for symmetric surfaces (centralized charge within a sphere) - field outside a uniform cylinder - whenever charges are symmetric with respect to the external environment.
B) Since the gravitational field has the same form as the electric field - F = G M1 M2 / R^2 the same arguments apply to the gravitational field - Field lines passing out thru an enclosed surface are sources of field whereas field lines passing inward thru an enclosed surface are sinks for the field
an object or is placed close to a thin converging lens. The diagram represents three way from the top of all passing through that lens.
Which option is correct A, B, C or D?
The type of image produced by the converging lens when object O is at that position will be virtual and enlarged, Option D.
What is a virtual and enlarged image?A virtual image is an image that is formed when light rays do not actually converge at a single point, but instead appear to converge when they are extended backwards. A virtual image is typically created by objects that are behind a lens or mirror that diverts the light rays in such a way that they appear to come from a different location.
An enlarged image, on the other hand, refers to a visual representation that has been magnified or made larger than the original size of the object being viewed.
Learn more on virtual and enlarged image here: https://brainly.com/question/15553241
#SPJ1
When is vertical velocity zero? Select all the apply
1. when an object changes direction.
2.the moment you kick a football in the air.
3. vertical velocity is zero initially when an object is dropped from a window.
4. the moment a ball rolls off a table.
5. the moment you throw a ball in the air.
Answer:
3
Explanation:
When the projectile reaches a vertical velocity of zero, this is the maximum height of the projectile and then gravity will take over and accelerate the object downward. The horizontal displacement of the projectile is called the range of the projectile, and depends on the initial velocity of the object.
A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes. The friction force on the sled is 1000 N
and the angle between the two ropes is 50 ∘
. Assume both players pull with the same force.
Friction force Force that resists the slidihng or rolliong of one side object over another. As both the players pull with the same force therefore each player pull to drag the coach with force of 520.83
What is Friction?
Friction force on the given sled is 1000 N.
Angle between the two ropes dragging by the players is 50 Celcius.
Friction force Force that resists the slidihng or rolliong of one side object over another.
Let, f be the force applied by each player Pull force applied by the player one is equal to the pull force applied by the player two. Therefore the angle created between the ropes dragged by both the player will be equal and half of the given angle.
Angle created by each player with sled is, To keep this sled in dynamic equilibrium the force applied by both the player must be equal to the friction force on the sled in opposite direction.
Therefore, Hence, each player pull to drag the coach with force of 520.83.
To learn more about friction, refer to the link:
https://brainly.com/question/13000653
#SPJ1
You dive straight down into a pool of water. You hit the water with a speed of 6. 5 m/s , and your mass is 70 kg. Part a assuming a drag force of the form fd = (−1. 10×104 kg/s ) v, how long does it take you to reach 2% of your original speed? (ignore any effects of buoyancy. )
It takes approximately 9.24 seconds to reach 2% of the original speed.
What is the velocity?We can use the equation for velocity with a drag force to solve for the time it takes to reach 2% of the original speed:
[tex]v = v0 e^(-b/m)t + (mg/b)(1 - e^(-b/m)t)[/tex]
where:
v is the velocity at time t
v0 is the initial velocity
b is the drag coefficient
m is the mass of the object
g is the acceleration due to gravity
At 2% of the original speed, the velocity is 0.02 x 6.5 m/s = 0.13 m/s.
Substituting the given values, we have:
[tex]0.13 m/s = 6.5 m/s * e^(-1.10x10^4 kg/s * t/70 kg) + (70 kg * 9.81 m/s^2 / 1.10x10^4 kg/s) * (1 - e^(-1.10x10^4 kg/s * t/70 kg))[/tex]
Simplifying and solving for t using numerical methods, we get:
t ≈ 9.24 seconds
Therefore, it takes approximately 9.24 seconds to reach 2% of the original speed.
Learn more about velocity here:
https://brainly.com/question/17127206
#SPJ1
Submarines change their depth by adding or removing air from rigid ballast tanks, thereby displacing seawater in the tanks. Consider a submarine that has a 700-m3 air-ballast tank originally partially filled with 100 m3 of air at 1650 kPa and 15°C. For the submarine to surface, air at 1650 kPa and 20°C is pumped into the ballast tank until it is entirely filled with air. The seawater leaves the tank at 15°C. Presume that air is added to the tank in such a way that the temperature and pressure of the air in the tank remain constant. Determine the final mass of the air in the ballast tank under this condition. Also determine the total heat transfer while the tank is being filled in this manner. The gas constant of air is R = 0. 287 kPa·m3/kg·K. The specific heats of air at room temperature are cP = 1. 005 kJ/kg·K and cv = 0. 718 kJ/kg·K. The specific volume of water is taken 0. 001 m3/kg
Total heat transfer while the tank is being filled in this manner, Q = ΔH = mCpΔT = 88,147 kJ
What is ideal gas law?Ideal gas law states that pressure, volume, and temperature of gas are directly proportional to each other, as long as number of particles and mass of gas remain constant.
PV = nRT
P is pressure, V is volume, n is number of moles of gas, R is gas constant, and T is temperature.
V = nRT/P
n = PV/RT
n = (1650 kPa)(100 m3)/(0.287 kPa·m3/kg·K)(288 K) = 603.5 kg
V = nRT/P = (603.5 kg)(0.287 kPa·m3/kg·K)(293 K)/(1650 kPa) = 105.5 m3
m = nM = (603.5 kg)(28.97 kg/kmol) = 17,486 kg
Q = ΔH = mCpΔT
ΔH is change in enthalpy, m is mass of air, Cp is specific heat at constant pressure, and ΔT is change in temperature.
ΔH = CpΔT
Q = ΔH = mCpΔT = (17,486 kg)(1.005 kJ/kg·K)(5 K) = 88,147 kJ
To know more about ideal gas law, refer
https://brainly.com/question/27870704
#SPJ1
You have a monometer (a U-shaped object) with water (density=1gr cm-3) filling up to the middle of both arms. The arms have a circular cross section with a diameter of 2cm. You pour 50ml of oil (density = 0.8 gr cm-3) to one arm. Assuming none spilled out, what will be the difference in height between the two arms after the fluid comes to rest (in cm)?
The volume of water from the volume of oil, which yields V_diff = 50,000 cm³ - 6.283 cm³ = 49
What is yield?Yield is a measure of the return on an investment. It is typically expressed as a percentage of the initial investment and is calculated by dividing the annual income generated by an investment by the initial cost of the investment.
The difference in height between the two arms after the fluid comes to rest can be determined using the equation for the volume of a cylinder, which is V=πr²h, where r is the radius of the cylinder and h is the height. Since we know the volume of water and oil that was added to one arm, we can calculate the difference in height.
First we need to calculate the volume of water in one arm. Since we know the radius is 1 cm and the height is half of the U-shaped monometer (2 cm), the volume of water in one arm is V_water = πr²h = π(1 cm)²(2 cm) = 6.283 cm³.
Next we need to calculate the volume of oil. Since we know the volume of oil is 50 ml, we can convert this to cm³ by multiplying it by 1000. This gives us the volume V_oil = 50 ml x 1000 = 50,000 cm³.
Now we can calculate the difference in height between the two arms by subtracting the volume of water from the volume of oil, which yields V_diff = 50,000 cm³ - 6.283 cm³ = 49
To learn more about yield
https://brainly.com/question/30592929
#SPJ1
A light wave has a frequency of 5.4*10^14 cycles per second and a wavelength of 5.5*10^-17 meter. What is the approximate speed of the wave?
A light wave has a frequency of 5.4 x 10⁻¹⁴cycles per second and a wavelength of 5.5 x 10⁻¹⁷ meter so the speed of the wave is 29.7 x 10⁻³m/s.
How to find the speed of the wave?v=λf, or velocity = wavelength x frequency, can be used to calculate a wave's speed. The distance a wave covers in a certain amount of time, such as the number of meters it covers every second, is known as its wave speed.
The formulae of the speed of the wave are,
v=λf, or velocity = wavelength x frequency
Frequency = 5.4 x 10⁻¹⁴ hertz
Wavelength = 5.5 x 10⁻¹⁷ m
v = 5.5 x 10⁻¹⁷x 5.4 x 10⁻¹⁴
= 29.7 x 10⁻³ m/s
Therefore, the speed of the wave is 29.7 x 10⁻³m/s.
Learn more about light, here:
https://brainly.com/question/2660739
#SPJ9
If the diameter of the pie is ten inches, the approximate arc length of one slice of pie is select one.
The arc length of one slice of pie is either 5.24 inches for 6 slices or 3.93 inches for 8 slices.
The arc length of one slice of pie can be found by dividing the circumference of the pie by the number of slices it is cut into.
The circumference of the pie can be found using the formula
C = πd
Where d is the diameter of the pie.
Substituting d = 10 inches,
we get:
C = π × 10 inches ≈ 31.42 inches
If we assume that the pie is cut into n equal slices, then the arc length of one slice is approximately:
Arc length ≈ C/n
If we want an approximate value for the arc length, we can use a value of n that is easy to work with,
such as n = 6 for 6 slices or n = 8 for 8 slices.
For n = 6, the arc length of one slice is approximately:
Arc length ≈ 31.42 inches / 6 ≈ 5.24 inches
For n = 8, the arc length of one slice is approximately:
Arc length ≈ 31.42 inches / 8 ≈ 3.93 inches
Therefore, the approximate arc length of one slice of pie is either 5.24 inches for 6 slices or 3.93 inches for 8 slices.
For a similar questions on arc length,
https://brainly.com/question/28108430
#SPJ4
