Which situations might cause two observers (A and B) to measure different frequencies for the same vibrating object? Select the two correct answers.
A. Observer A is stationary and Observer B is moving.
B. Observer A and Observer B are moving at different speeds relative to each other.
C. Observer A and Observer B are stationary but at different distances from the vibrating object.
D. Observer A and Observer B are both stationary and at the same distance from the object.

Answer:

Repeatability is how much variability in the measurement system is caused by the measurement device. Reproducibility is how much variability in the measurement system is caused by differences between operators.

Answer:

210

Explanation:

A ball rolls horizontally off the cliff at a speed of 30 m/s. It takes 7 seconds for the ball to hit the ground. What is the height of the cliff and the horizontal distance traveled by the ball?

S = (1/2)*9.8 m/s^2 * 7^2 = 240.1 m if the ball is very dense so air resistance, and therefore terminal velocity, can be ignored.

S = v * t = 30 m/s * 7 s = 210 m for the horizontal distance, again assuming negligible air resistance.

Height above the ground is the ball after the ball has fallen for 1 second is 210 m.

The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.

A ball rolls horizontally off the cliff at a speed of 30 m/s. It takes 7 seconds for the ball to hit the ground.

S = (1/2)*9.8 m/s² * 7² = 240.1 m if the ball is very dense so air resistance, and therefore terminal velocity, can be ignored.

S = v * t = 30 m/s * 7 s = 210 m for the horizontal distance, again assuming negligible air resistance.

Height above the ground is the ball after the ball has fallen for 1 second is 210 m.

To learn more about speed refer to the link:

brainly.com/question/28224010

 #SPJ2

According to Newtonʼs Second Law of Motion:

F net = m  x  a

or

a = F net / m

Acceleration = net Force/ Mass = 161 / 70 = 2.3 m/s^2  [W]

If a 70 kg skater is acted upon by an unbalanced force of 161 N [West], his acceleration would be 2.30  m/s² towards the west

Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.

The mathematical expression for Newton's second law is as follows

F = m*a

where F represents the force applied

m is the mass of the object

a is the acceleration of the object

As given in the problem If a 70 kg. skater acted upon by an unbalanced force of 161 N

F =ma

By substituting the values of the force and the mass as 161 N and 70 kg respectively

161 N = 70×a

a= 2.30 m/s²

Thus, If a 70 kg skater is acted upon by an unbalanced force of 161 N, his acceleration would be 2.30  m/s² towards the west

Learn more about Newton's second law, here

brainly.com/question/13447525

#SPJ2

Explanation:

TRUE - Two colliding objects will exert equal forces upon each other. If the objects have different masses, then these equal forces will produce different accelerations. ... FALSE - In any collision, the colliding objects exert equal and opposite forces upon each other as the result of the collision interaction.

Answer:

0.3214 grams per millimetre

Explanation:

Answer: 32

Explanation:

D = m/v

D = 18/56

D = ?

Answer:

An inelastic collision is a collision in which there is a loss of kinetic energy. While momentum of the system is conserved in an inelastic collision, kinetic energy is not.

Explanation:

Answer:

in a direction parallel to the direction that the wave moves

Explanation:

Answer:

parallel to the direction....

La altura máxima alcanzada por el bloque es de 14.471 metros.

En esta pregunta asumimos que la altura inicial del bloque es igual a tres metros por encima del la altura de referencia y la altura final puede ser determinada mediante el principio de conservación de la energía, en cuyo caso, la suma de la energía cinética traslacional inicial ([tex]K[/tex]) y la energía potencial gravitacional inicial ([tex]U_{o}[/tex]), ambos en joules, es igual a la energía potencial gravitacional final ([tex]U_{f}[/tex]), en joules. Matemáticamente hablando, tenemos la siguiente expresión:

[tex]U_{o}+K = U_{f}[/tex]

[tex]m\cdot g\cdot z_{o} + \frac{1}{2}\cdot m\cdot v^{2} = m\cdot g \cdot z_{f}[/tex] (1)

Donde:

A continuación, despejamos la altura final del bloque:

[tex]z_{f} = z_{o}+\frac{1}{2}\cdot \frac{v^{2}}{g}[/tex] (2)

Si sabemos que [tex]z_{o} = 3\,m[/tex], [tex]v = 15\,\frac{m}{s}[/tex] y [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], entonces la altura máxima alcanzada por el bloque es:

[tex]z_{f} = 3\,m + \frac{1}{2}\cdot \left[\frac{\left(15\,\frac{m}{s} \right)^{2}}{9.807\,\frac{m}{s^{2}} } \right][/tex]

[tex]z_{f} = 14.471\,m[/tex]

La altura máxima alcanzada por el bloque es de 14.471 metros.

Invitamos cordialmente a ver esta pregunta sobre el principio de conservación de la energía: https://brainly.com/question/19561287

The resultant of the four forces on the balloon is 1,212.35 N at 62⁰.

The given parameters;

The resultant vertical force is calculated as follows;

[tex]F_y = 5120 \ N - 4050 \ N\\\\F_y = 1,070 \ N[/tex]

The resultant horizontal force is calculated as follows;

[tex]F_x = 1520 \ N - \ 950 \ N\\\\F_x = 570 \ N[/tex]

The resultant of the four forces is calculated as follows;

[tex]F = \sqrt{F_y^2 + F_x^2} \\\\F = \sqrt{(1,070)^2 + (570)^2} \\\\F = 1,212.35 \ N[/tex]

The direction of the force is calculated as follows;

[tex]\theta = tan^{-1} (\frac{1070}{570} )\\\\\theta = 62^0[/tex]

Thus, the resultant of the four forces on the balloon is 1,212.35 N at 62⁰.

Learn more here:https://brainly.com/question/17042556