Answer:
Telescope, Probware, etc,..
Answer: probeware
Explanation:
the answer is probeware
if you mean by the options,
A. a ruler
B. a thermometer
C. a beaker
D. probeware
In 10 seconds a swimmer kicks off one the side of the pool to the other. as the swimmer makes their way across, they slow down at a constant rate until the come to a complete stop. if the width of the pool is 8.0 meters what was their initial velocity when they kicked off.
1.6 ms-1 was their initial velocity when they kicked off.
The velocity at time interval t = 0 is indicated by the symbol u. It is the speed at which the motion begins. Because the length of the pool is not given, the width is used to estimate the distance travelled;
Length of a swimming pool =8 m
A swimmer crosses it and then makes their way across
Total distance covered =8×2=16 m
Time taken =10 seconds
Initial velocity = distance/ time
=16/10
=1.6 ms-1
Therefore, the initial velocity is 1.6 ms-1. Note the question requested initial velocity since it is impossible to estimate the final velocity of the swimmer as he maintains a constant rate across the pool when swimming back.
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An airplane starts from rest and accelerates at 10.8 m/s2 . what is its speed at the end of a 400 m long runway?
The final speed of an airplane is v = 92.95 m/s
The rate of change of position of an object in any direction is known as speed i.e. in other word, Speed is measured as the ratio of distance to the time in which the distance was covered.
Solution-
Here given,
Acceleration a= 10.8 m/s2 .
Displacement (s)= 400m
Then to find final speed of airplane v=?
Therefore from equation of motion can be written as,
v²=u²+ 2as
where, u is initial speed, v is final speed ,a is acceleration and s is displacement of the airplane. Therefore by putting the value of a & s in above equation and (u =0) i.e. the initial speed of airplane is zero.
v²= 2×10.8 m/s²×400m
v²=8640m/s
v=92.95m/s
hence the final speed of airplane v =92.95m/s
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If an object is thrown straight upward with an initial speed of 8.0 m/s and takes 3.0 seconds to strike the ground, from what height was the object thrown?
According to the given statement the height of the object thrown is =20.1m
What is the initial speed?Initial condition, or initial speed, refers to an object's speed at the start of a measurement. The average speed is the average of the initial and final speeds, or the ratio of the distance travelled to the time required. The speed difference between the initial and final speeds is the change in speed.
How can one determine initial speed?Start by dividing the acceleration by the time to determine the beginning velocity. Then, divide that number by 2 and write down the quotient you got. Next, divide the distance by the time and write down that quotient as well. To obtain the beginning velocity, finally remove your first quotient from your second quotient.
The right answer is s= 20.1m
s= -8t+0.5gt^2
t=3
s=20.1 m
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What is the resultant ph if 50 ml of 0.1 m hcl are added to 800 ml of 0.05 m acetate buffer at ph 5.2? the pka of acetic acid is 4.76?
The resultant pH= 4.95
Steps
A weak acid solution and a conjugate base solution can be combined to create a buffer.
Strong acid or strong base addition does not result in a significant pH shift when a weak acid and conjugate base are present in the solution.
A buffer's pH can be determined using the Henderson-Hasselbalch equation:
pH = Pka + log [base] / [acid]
Let 0.05-x represent the amount of acetate in the buffer and x represent the amount of acetic acid in the buffer.
5.2 = 4.75 + log 0.05− x / x
0.05− x = 0.0369 M
HA = 0.0130 M × 800 mL+ 50 mL× 0.1 M = 15.47 mmol
A = 0.0369 M× 800 mL− 50 mL×0.1 M = 24.52 mmol
The new pH is:
pH= 4.75 + log 25.42 / 15.47
pH= 4.95
The resultant pH of the solution= 4.95
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List three equations (relationships) describing free falling objects in gravitational fields.
The three equations for describing free-falling objects in gravitational fields are given below:
h = ut + ¹/₂ g * t²v² = u² + 2 * g * hv = g * tWhat is free fall?Free fall refers to the motion of a body that is at a certain height above the surface of the earth and which is allowed to fall or move vertically downwards under the influence of gravity alone.
Gravity is the attractive force with which the earth attracts objects to its surface.
Objects that are attracted to the surface of the earth by gravity are given an acceleration g, known as acceleration due to gravity.
The value of the acceleration due to gravity, g = 9.8 m/s²
The equations for describing free-falling objects in gravitational fields are given below:
h = ut + ¹/₂ g * t²v² = u² + 2 * g * hv = g * twhere;
h = height above ground
u is the initial velocity
v s final velocity
t is time
g is to acceleration due to gravity
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Calculate the energy of a photon with a wavelength of 410nm.
a) 4.85 x 10-19 j
b) 4.85 x 10-20 j
c) 4.85 x 10-18 j
d) 2.06 x 1019 j
e) 2.06 x 1020 j
Clutch a cart starts at x = 2.0 m and travels towards the origin with a constant speed of 2.0 m/s. what is it the exact cart position (in m) 2.0 seconds later?
When the cart travels towards the origin, the magnitude of its exact position reduces with time.
The cart will be at -2 m (origin) 2s later.
What is it the exact cart position (in m) 2.0 seconds later?
When the cart travels towards the origin, the magnitude of its exact position reduces with time.
The formula of speed is given as
S = d/t ................. (1)
Where S = speed of the cart,
d = distance covered by the cart over a certain time.
t = time taken to cover the distance.
Where d the subject of the equation,
d = St ................. (2)
Given: S = 2.0 m/s, t = 2.0 s
Substitute into (2)
d = 2(2)
d = 4 m.
From the above, the cart covered a distance of 4 m in 2s.
The exact position of the cart = Initial position - distance covered
x' = x - d ............ (3)
Where x' = exact position of the cart 2s later,
x = initial position of the cart, and
d = distance covered by the cart in 2.0 s
Given: x = 2.0 m, d = 4 m.
Substitute into (3)
x' = 2.0 - 4
x' = -2 m.
Therefore the cart will be at -2 m (origin) 2s later.
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TRUE or FALSE
Organs are composed of multiple tissue types.
Answer:
TRUE
Explanation:
Organs are made of two or more tissue types to allow them to function.
Hope this helps! :D
A 100-w light bulb is operated by a 110-v dc source. what is the resistance of this bulb?
By using the power formula, the resistance of the bulb is 121 Ω.
We need to know about dissipated power to solve this problem. Power is energy dissipated to resistance as heat energy. It can be determined as
P = I . V
where P is power, I is current and V is voltage.
From Ohm's Law, we can substitute the current to
I = V / R
Hence, we can write the power equation to
P = (V/R) . V
P = V² / R
From the question above, we know that:
P = 100 watt
V = 110 volt
By substituting the following parameters, we get
P = V² / R
100 = 110² / R
R = 121 Ω
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What does Newton's third law describe?
A parallel plate capacitor of capacitance c0 has plates of area a with separation d between them. When it is connected to a battery of voltage v0, it has charge of magnitude q0 on its plates. While it is connected to the battery, the space between the plates is filled with a material of dielectric constant 3. After the dielectric is added, the magnitude of the charge on the plates and the new capacitance are.
The dielectric strength of a dielectric substance is equal to the greatest magnitude of the external electric field that does not cause electrical breakdown. When an electric field is applied to a dielectric, the dielectric will transform into a conductor at a point known as electrical break down.
Given that
A parallel plate capacitor consists:
Capacitance Co
Plates of Area A
Separation distance between the plates d
Voltage of a battery Vo
Magnitude of charge Qo
Dielectric constant K=3
the capacitance of parallel plate capacitor when there is free space between the plates is given by
Co = εoA/d
Where εo is permittivity of free space.
If the battery is connected to the parallel plate capacitor, the gap between the plates is filled with dielectric constant. The capacitance of the parallel plate capacitor for the medium will then be determined.
a) C=KεoA/d
=3εoA /d
=3 Co
Now, the potential difference between the plates will be
b) Vo =QC
Vo=QC
Hence, the magnitude of charge by adding dielectric medium will be
c) Q= CVo
=3εoA Vo /d
=3 Co Vo
=3 Qo
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A robot used in a pharmacy picks up a medicine bottle at t=0. it accelerates at 0.30 m/s2 for 3.5 s , then travels without acceleration for 74 s and finally decelerates at -0.60 m/s2 for 1.8 s to reach the counter where the pharmacist will take the medicine from the robot.
A constant current of 3.2maflows through anelement. what is the charge that has passed through the elementin thefirst millisecond?
The charge that has passed through the element the first millisecond is 2.3nc.
What is millisecond?Millisecond is a period estimation unit with the image of MS, which is equivalent to a one thousandth of a second. It can likewise be characterized as the span of photograph electric lamp, or as the hour of a cycle for 1kHz recurrence. This unit is at times utilized while estimating extent or making truly exact physical and logical computations. Millisecond is clearly utilized rigorously for logical purposes since estimating this unit of time is very troublesome. This web-based milliseconds to microseconds converter can be exceptionally helpful for understudies, analysts, science fans and the people who are needing making time changes.
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A point located on the second hand of a large clock has a radial acceleration of 0.10 cm/s2. how far is the point from the axis of rotation of the second hand?
The distance of the point from the axis of rotation of the second hand is 9.1 m.
Radius of the clockThe point from the axis of rotation of the second hand is the radius of the rotation of the clock.
a = v²/r
v² = ar
v = √ar
V = [tex]\frac{2\pi r}{T}[/tex]
√ar = [tex]\frac{2\pi r}{T}[/tex]
ar = [tex]\frac{4\pi^2 r^2}{T^2}[/tex]
a = [tex]\frac{4\pi^2r}{T^2}[/tex]
r = [tex]\frac{aT^2}{4\pi^2}[/tex]
r = (0.1 x 60²)/(4π²)
r = 9.1 m
Radial accelerationNewton’s second law states that when a body is subjected to an external force, it begins to accelerate.
The only thing that constitutes acceleration is a change in an object’s velocity over time. It carries both magnitude and direction as a vector quantity.
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The last quarter phase of the moon? rises at sunrise. rises at sunset. sets at sunset. crosses the meridian at sunrise. sets at sunrise.
The correct answer for the The last quarter phase of the moon is it crosses the meridian at sunrise .
A third quarter moon, or last quarter moon, rises around midnight and sets around noon. The Moon is nearly back to the point in its orbit where its dayside faces the Sun directly, and all we see from our vantage point is a thin curve.
The Last or Third Quarter is when we can see half of the Moon's illuminated portion and half of its shadow portion. This is why this phase is commonly referred to as Half Moon. We can only see half of the Moon because it is at a 90-degree angle to the Earth and Sun.
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Think back to the snack food calorimeter. describe an example of each of these occurring in the lab: conduction, convection, and radiation.
An good example would be using a Bunsen burner to heat water in a tin container. The flame initially heats the tin can by radiating heat. Conduction then transfers heat from the tin can to the water. The convection process causes the hot water to then climb to the top.
What is Bunsen Burner?A laboratory piece of equipment known as a Bunsen burner, which bears Robert Bunsen's name, produces a single open gas flame and is used for heating, sterilization, and combustion. Natural gas, liquefied petroleum gas, such as propane, butane, or a combination, are all acceptable choices for the gas.
What three types of flames can you get from a Bunsen burner?Bunsen burner flames come in three primary categories:Because it is simple to notice in a well-lit space, a yellow flame is also referred to as a safety flame.Flaming Blue. A burner's specific flame can reach temperatures of 500 degrees.Blue Flame in Flames The roaring blue flame setting on a Bunsen burner produces the hottest flames.To know more about Bunsen Burner visit:
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For what type of object is the period-luminosity relation used for determining distances?
a. rr lyrae variables
b. t tauri variables
c. cepheids cataclysmic variables
d. planetary nebulae
Cepheids cataclysmic variables object is the period-luminosity relation used for determining distances.
What is Cepheids cataclysmic variables?Cepheid Variables are very bright stars that are 500–300,000 times as bright as the sun. They undergo brief variations every 1–100 days. They are pulsing variables that follow a predetermined pattern and experience rapid expansion and contraction. Other pulsating variables include RR Lyrae stars, which are short period, older stars that are not as massive as Cepheids; and RV Tauri stars, which are super giants with higher light fluctuations. Astronomers may study the variability of a Cepheid's brightness to determine its distance.
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During an adiabatic compression a volume of an air decrease to 1/4 th its original size calculate its final pressure if its original pressure was 1 atm
The final pressure is 6.96 atm.
We know that in an adiabatic process,
[tex]p_{1} V_{1} ^{gamma}[/tex] = [tex]p_{2} V_{2} ^{gamma}[/tex]
where,
p = Pressure
V = Volume
Gamma = Isentropic expansion factor
Given that,
[tex]p_{1}[/tex] = 1 atm
γ = 1.4 ( Assuming the air as an ideal gas )
[tex]V_{2}[/tex] = [tex]V_{1}[/tex] / 4
[tex]V_{1}[/tex] / [tex]V_{2}[/tex] = 4
[tex]p_{1} V_{1} ^{1.4}[/tex] = [tex]p_{2} V_{2} ^{1.4}[/tex]
[tex]p_{2}[/tex] = 1 * [tex]( 4 )^{1.4}[/tex] = 6.96 atm
An adiabatic process is a thermodynamic process without the involvement of heat. Usually it takes place in an insulated box.
Therefore, the final pressure is 6.96 atm
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A vertical spring stretches 3.9 cm when a 10.-g object is hung from it. The object is replaced with a block of mass 25 g that oscillates up and down in simple harmonic motion. Calculate the period of motion.
We drive a distance of 1 kilometer at 20 km/h. then we drive an additional distance of 1 kilometer at 30 km/h. what is our average speed (in km/h)?
The driver drives at a speed of 20km/hr, then the average speed is 24km/hr.
According to the question, they traveled one kilometer at a speed of 20 kilometers per hour. The equation time = distance/speed can be used to determine how long it will take to travel this distance. Thus, the duration of the initial leg of the journey is 1/20, or 0.05 hours.
then proceeded to travel at a speed of 30 km/h for an additional distance of 1 km. Similar to the previous section, this one's travel time is 1/30, or 0.0333 hours.
Now, add the travel times for both legs to get the overall time: 0.05 + 0.0333 = 0.0833 hours.
Now, adding the distances covered in each leg of the journey to get the total distance traveled: 1 + 1 = 2 kilometers.
By dividing the total distance by the total time, we can finally determine the average speed: average speed = total distance/total time = 2/0.0833 24 km/h.
As a result, they travel at a speed of roughly 24 km/h.
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a bag is dropped from a hovering helicopter. the bag has fallen for 1.6 s. what is the bag's velocity?
The bag's velocity when a bag is dropped from a hovering helicopter is 15.68m/s
Its initial velocity is zero. In a free-falling body, the value of the final velocity is obtained through the equation
Vf =u + gt
u = o ( because the bag is dropped, so it falls starting from rest)
Vf = gt
u is initial velocity
Vf is final velocity
t is time
where g is the acceleration due to gravity, 9.8 m/s².
using above values we get
Vf = (9.8 m/s²)(1.6s)
= 15.68m/s
The bag's velocity when a bag is dropped from a hovering helicopter is 15.68m/s
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Measuring human impact and comparing it with the biophysical world's carrying capacity is known as:________-
Measuring human impact and comparing it with the biophysical world's carrying capacity is known as Ecological footprint.
What is Ecological footprint?
The Global Footprint Network promotes the ecological footprint as a way to assess how much nature is needed to sustain a certain number of people or an economy. Through an ecological accounting system, it monitors this demand. The accounts compare the biologically productive areas used by people for consumption to the biologically productive areas available in a region or throughout the world (biocapacity, the productive area that can regenerate what people demand from nature). It measures the effects of humans on the environment, to put it briefly.
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An ohmmeter should be connected to the circuit or component being tested ________.
A bottle has a mass of 35.00 g when empty and 98.44 g when filled with water. When filled with another fluid the mass is 88.78g. What is the specific gravity of this other fluid
Answer:
mass of water = 98.44 - 35.00 = 63.44g
water has a density of 1000g/L
Volume of bottle = 63.44/1000 = .06344L
mass of other liquid = 88.78-35 = 53.78g
density of other liquid = 53.78g/0.06344L = 847.73g/L
Since water has a specific gravity of 1, set up a relation 1000/847.73 =1/sg
sg=.85
In diving to a depth of 374 m, an elephant seal also moves 311 m due east of his starting point. what is the magnitude of the seal's displacement?
The magnitude of the seal's displacement will be 486.41m
What is the concept of displacement?There are an endless number of paths that can be built between two places. The distance is the name given to any specific length of path. There is a path with the shortest distance out of all of these, and the length of that path is determined by the size of a properly specified vector quantity called the displacement.
Given that an elephant seal goes 311 m to the east of his starting location when diving to a depth of 374 m.
Allow the seal to begin at point A and dive deep to reach position B. In the illustration below, his displacement is highlighted in red:
The hypotenuse of the right triangle ABC can be located to determine the displacement's magnitude.
We discover:
displacement of the seal = [tex]\sqrt374^{2} +311^{2} = 486.41m[/tex]
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Describe a situation in which you can accelerate even though your speed doesn’t change.
Acceleration is not the same as speeding up. It refers to any modification of motion's direction or speed. Accelerated motion is any movement that is not constant speed in a straight line.
What is meant by acceleration?In physics, acceleration refers to the rate at which an object's velocity over time changes. They are accelerations and vector quantities. The direction of an object's acceleration is determined by the direction of the net force acting on it.
Depending on whether an object is moving faster, slower, or in a different direction, its velocity may change. Examples of acceleration include a falling apple, the moon orbiting the earth, and a car that has stopped at a stop sign.
Acceleration is the measure of a change in velocity. Acceleration frequently, though not always, denotes a shift in speed. The direction of motion is changing, therefore an object moving at a constant speed in a circular path is still moving ahead.
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The distance from the center of a lens to the point at which light rays converge on the film is known as the ______ of the lens.
The distance from the center of a lens to the point at which light rays converge on the film is known as the focal length of the lens.
In photography, focal length is the distance measured in millimeters (mm) between the optical center of the lens and the camera sensor, where the light information is recorded.
It is important because it dictates the distance your camera will be able to capture. Smaller numbers show more scene and have wider angle while larger numbers show less scene and have tighter angle of view.
What is photography?The process of recording an image on light-sensitive film is known as photography.
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On a circle of radius r, a central angle of radians subtends an arc of length s_____; the area of the sector formed by this angle is a_______.
On a circle of radius r, a central angle of radians subtends an arc of length(s) is r; the area of the sector formed by this angle is a 12r2Θ. The central angle of radians subtends an arc of length(s) that is multiple of radius (r) and central angle().
What is the sector of a circle's area?The concept of area is always associated with two dimensions. Any two-dimensional object can combine to form a plane. As a result, every two-dimensional figure has an area. Every point in a plane that is a particular distance away from some other point forms a circle. The circle's radius and fixed distance are both referred to as the circle's center and radius, respectively.
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Two-pointcharges are 9.0 cm apart. they are moved and the force on each of them is found to have been doubled. how far apart are they now?
After moving, the two point charges are 6.36 cm apart.
We know that,
F = k [tex]q_{1} q_{2}[/tex] / [tex]r^{2}[/tex]
where,
[tex]q_{1} q_{2}[/tex] = two point charges
k = Coulombs constant
r = Distance between two charges
F = Electrostatic force between two charges
Given that,
r = 9 cm
F = k [tex]q_{1} q_{2}[/tex] / [tex]9^{2}[/tex]
[tex]F^{'}[/tex] = 2F
k [tex]q_{1} q_{2}[/tex] / [tex]r'^{2}[/tex] = 2 * k [tex]q_{1} q_{2}[/tex] / [tex]9^{2}[/tex]
[tex]r'^{2}[/tex] = 81 / 2 = 40.5
r' = 6.36 cm
Electrostatic force is the force between two point charges. It can either be positive or negative. If negative the forces are attractive and if positive the forces are repulsive in nature.
Therefore, after moving, the two point charges are 6.36 cm apart.
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A violin string has a length of 0. 350m and is tuned to concert G, with f_G = 392Hz(b) If this position is to remain correct to one-half the width of a finger (that is, to within 0. 600 cm ), what is the maximum allowable percentage change in the string tension?
The maximum allowable percentage change is 3.8% in the string tension
Length of the string lg as given in the question = 0.350m
frequency of concert G f_g as given in the question= 392 Hz
The maximum allowable percentage change in string tension for this frequency remains constant and the given allowed interval of the change of the length
Formulating the equation and solving:
Let f be the frequency, T be the tension and U be the length of the wave
f = 1/2L*[tex]\sqrt{} T/U[/tex]
df = 1/2[tex]\sqrt{} U[/tex]*[tex](1/2\sqrt{}T- Ldt - dL\sqrt{}T)/L^{2}[/tex]
df = 0
dT/T = 2*(dL/L)
= 2*0.6/31.2
dT/T = 0.038
Percentage change in string tension 3.8%
The maximum percentage change in string tension is 3.8%
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