what's -3(x-1)^2+3 in standard form and vertex form?

Step-by-step explanation:

[(3x − 6) (4x² − 1)] – [(2x − 4) (4x² + 4x + 1)]

>[3(x-2) (2x+1)(2x-1)]-[2(x-2)(4x²+2x+2x+1)

>[3(x-2)(2x+1)(2x-1)]-[2(x-2){2x(2x+1)+1(2x+1)}]

> 3(x-2)(2x+1)(2x-1)-2(x-2)(2x+1)²

> (x-2)(2x+1) [3(2x-1)-2(2x+1)]

> (2x²-3x-2)(6x-3-4x-2)

> (2x²-3x-2)(2x-5).

hope this helps you.

Answer:

3 ballons

Step-by-step explanation:

47-35=12

4x3=12

Answer:

[tex]6x[/tex] + [tex]3[/tex]

Answer:

3x+4y-24=0.

Step-by-step explanation:

if the common form of the required equation is

[tex]\frac{x}{a} +\frac{y}{b} =1, \ where \ a;b \ are \ x-intercept;y-intercept,[/tex]

then the required equation is:

[tex]\frac{x}{8} +\frac{y}{6} =1[/tex]

or 3x+4y-24=0.

Fractions are integers that have both a numerator and a denominator. They are represented as;  [tex]\frac{x}{y}[/tex]

Where:

x = Numerator

y = Denominator.

To solve the above question, we would be applying the operations of the addition of fractions.

It will take both of them  [tex]27\frac{3}{11}[/tex]  hours if they worked together.

From the question,

Nyesha takes 50 hours a week to render services to her customers.

Shantese takes 60 hours a week to do the same amount of work.

Let us represent the number of hours it will take them both to decorate the room working together as "T"

Hence,

1/T = 1/50 + 1/60

Lowest Common Denominator for (50, 60 ) = 300

Hence,

1/T = 6 + 5 / 300

1/T = 11/300

Find the reciprocal of both sides

T = 300/11 hours

T = [tex]27\frac{3}{11}[/tex] hours

Therefore, it will take them both of them [tex]27\frac{3}{11}[/tex] hours in they both work together.

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Answer:

12

Step-by-step explanation:

So, she practices 12 hrs per week, and already has practiced 3 hrs this week.

This means she has 9 hrs left to practice.

3/4 of an hour is one session, so to find out the number of sessions she needs, you have to do (9 hours)/(one session)

which is basically 9 / ( 3/4)

[tex]\frac{9}{3/4}=\frac{9}{1} / \frac{3}{4} = \frac{9}{1} * \frac{4}{3} = \frac{36}{3} = 12[/tex]

She needs 12 more sessions.

Answer:

x=9

Step-by-step explanation:

180 =120+5x+15

60=5x+15

45=5x

9=x

Answer: y=4x-5

Step-by-step explanation:

The slope of y=4x+23 is:4 m=4  

The parallel line needs to have the same slope of 4

Solve it using the "point-slope" equation of a line:   y− y1 = 2(x − x1)

substitute or put in the point (2,3):

y − (3) = 4(x − 2)

y - 3 = 4x - 8      

 put it in slope intercept form y = mx + b  

y  = 4x − 5

Answer:

(x + 2y)(x − 2y)

Step-by-step explanation:

x² - 4y²

(x + 2y)(x − 2y)

Answer:

domain = all real numbers

Step-by-step explanation:

An inequality is unnecessary in this situation... nor logically required.

Answer:

273.62

Step-by-step explanation:

Student A is wrong and Student B is correct.

How?

Answer:  x = 6

Step-by-step explanation:

The perimeter of the isosceles triangle = 2 leg + base

Since the perimeter = 60

then 60 = 2(5x - 3) + x

       60 = 10x - 6 + x

 60 + 6 = 11x

         6 = x

Answer:

correct the answer is 6.13

Step-by-step explanation:

The required current balance in Maggie's bank account is 6.13.

Given that,
Maggie has a bank account balance of -18.37 as soon as she realizes this she deposits 24.50 in the account.

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication and division,

here,
initial balance in Maggies's bank account = -18.37
She deposited 24.50 in her bank account,
The current balance in her bank account = Initial balance + money deposited
Current = 24.50 - 18.37
Current balance = 6.13

Thus, the required current balance in Maggie's bank account is 6.13.

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Answer:

Secant, cosecant and cotangent.

Step-by-step explanation:

Step-by-step explanation:

There are three reciprocal trigonometric functions, making a total of six including cosine, sine, and tangent. The reciprocal cosine function is secant: sec(theta)=1/cos(theta). The reciprocal sine function is cosecant, csc(theta)=1/sin(theta). The reciprocal tangent function is cotangent, expressed two ways: cot(theta)=1/tan(theta) or cot(theta)=cos(theta)/sin(theta).

Answer:

The 2nd answer would be the correct option.

Step-by-step explanation:

Hope this helps:) Also can I have brainliest if possible:) It is ok if you can not.

-3x + 6 = 2x - 24

Value of 'x' term

[tex] -3x + 6 = 2x - 24 [/tex]

[Bringing 2x to left side and 6 to right side]

[tex] = > - 3x - 2x = - 24 - 6 \\ \\ = > - 5x = - 30 \\ \\ = > x = \cancel \frac{ - 30}{ - 5} \\ \\ = > x = 6[/tex]

[tex] \fbox \red{Hope This Helps}[/tex]

The modification that has the least cuts to her current expenses will be C. Caitlin can eliminate $54 from Food/Clothes and $120 from Entertainment.

It should be noted that current expenses are the simply the expenses that keep an individual or business going.

In this case, the modification with the least cuts to her current expenses that will allow Caitlin to pay off her balance in 20 months is that Caitlin can eliminate $54 from Food/Clothes and $120 from Entertainment.

This is important in order for her to cut her cost.

Learn more about expenses on:

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Answer:

-4/12

Step-by-step explanation:

Answer:

slope intercept form is "y= -3/2+6"

Answer:

https://brainly.com/question/14113265

Step-by-step explanation:

Answer:

30

Step-by-step explanation:

2/5+1/5=3/5 sold

1-3/5=2/5 unsold

2/5*75=150/5=30 houses left to sell

[tex]\\ \sf\longmapsto a+\dfrac{1}{a}=\sqrt{3}[/tex]

[tex]\\ \sf\longmapsto \left(a+\dfrac{1}{a}\right)^3=\sqrt{3}^3[/tex]

[tex]\\ \sf\longmapsto a^3+\dfrac{1}{a^3}+\dfrac{3a^2}{a}+\dfrac{3a}{a^2}=3\sqrt{3}[/tex]

[tex]\\ \sf\longmapsto a^3+\dfrac{1}{a^3}+3a+\dfrac{3}{a}=3\sqrt{3}[/tex]

[tex]\\ \sf\longmapsto a^3+\dfrac{1}{a^3}=3\sqrt{3}-3a-\dfrac{3}{a}[/tex]

[tex]\\ \sf\longmapsto a^3+\dfrac{1}{a^3}=3\left(\sqrt{3}-a-\dfrac{1}{a}\right)[/tex]

[tex]\\ \sf\longmapsto a^3+\dfrac{1}{a^3}=3(0)[/tex]

[tex]\\ \sf\longmapsto a^3+\dfrac{1}{a^3}=0[/tex]

Answer:

Tn=a+(n−1)d, where a= First term, d= Difference between terms ... (2)

Equating (1) and (2)

6n+5=a+(n−1)d

6n+5=a+nd−d ..... (3)

Equating n terms:6n=nd

d=6 ...... (4)

Substituting (4) in (3)

6n+5=a+6n−6

5=a−6

a=11 ..... (5)

Now

Sn=2n(2a+(n−1)d)

Sn=2n(a+Tn) ....... (6)

Substituting (1) and (5) in (6)

Sn=2n(11+6n+5) 

Sn=2n(16+6n) 

Sn=n(8+3n) 

Tn=a+(n−1)d, where a= First term, d= Difference between terms ... (2)

Equating (1) and (2)

6n+5=a+(n−1)d

6n+5=a+nd−d ..... (3)

Equating n terms:6n=nd

d=6 ...... (4)

Substituting (4) in (3)

6n+5=a+6n−6

5=a−6

a=11 ..... (5)

Now

Sn=2n(2a+(n−1)d)

Sn=2n(a+Tn) ....... (6)

Substituting (1) and (5) in (6)

Sn=2n(11+6n+5) 

Sn=2n(16+6n) 

Sn=n(8+3n) 

Tn=a+(n−1)d, where a= First term, d= Difference between terms ... (2)

Equating (1) and (2)

6n+5=a+(n−1)d

6n+5=a+nd−d ..... (3)

Equating n terms:6n=nd

d=6 ...... (4)

Substituting (4) in (3)

6n+5=a+6n−6

5=a−6

a=11 ..... (5)

Now

Sn=2n(2a+(n−1)d)

Sn=2n(a+Tn) ....... (6)

Substituting (1) and (5) in (6)

Sn=2n(11+6n+5) 

Sn=2n(16+6n) 

Sn=n(8+3n) 

Answer:

[tex] \frac{ {( - 3)}^{7} {(11)}^{9} {(13)}^{ - 3} }{ {( - 3)}^{5}(11) {(13)}^{ - 3} } \\ \\ \\ \\ \frac{ {( - 3)}^{2} {(11)}^{8} {(13)}^{ - 3} }{ {(13)}^{ - 3} } \\ \\ \\ \frac{ {( - 3)}^{2} {(11)}^{8} }{ {(13)}^{3}( \frac{1}{ {(13)}^{3} }) } \\ \\ \\ \frac{ {( - 3)}^{2} {(11)}^{8} }{1} \\ \\ \\ = {( - 3)}^{2} {(11)}^{8} [/tex]

I hope I helped you^_^

Answer:

y-2=-x-7

Step-by-step explanation:

i think this helps

Answer:

Step-by-step explanation:

The standard form of linear equation:

Convert the given from point- slope to standard form:

Answer:

8.2263565e+21

Step-by-step explanation:

im smart

Answer:

1. Evaluate the function at an input value of zero to find the y-intercept.

2. Identify the slope. (change of y/change of x)

3. Plot the point represented by the y-intercept.

4. Use rise over run (rise/run) to determine at least two more points on the line.

5. Draw a line that passes through the points.

Answer:

The answer is D

Step-by-step explanation:

multiply by reciprocal