Chemistry High School

What is the molarity of 930 mL of LiCl solution that contains 139.9 g of LiCl?
O A. 3.5 mol/L
O B. 150 mol/L
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O C. 3.3 mol/L
O D. 3.5 x 10-3 mol/L

What Is The Molarity Of 930 ML Of LiCl Solution That Contains 139.9 G Of LiCl?O A. 3.5 Mol/LO B. 150

Answers

Answer 1

Answer:

3.5 mol/L

Explanation:

First convert the 139.9g of LiCl into moles of LiCl.  Don't do the sig fig rule until the very end.

Second, take 930mL of LiCl and divide it by 1000 to convert it to liters.

Third use the molarity formula which is M=mol/L and divide 0.930L by 3.300773877mol and you will get 3.549219223.  This is where the sig fig rule will come into play.  3.5mol/L is a reasonable answer for this problem.

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Explanation:

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Answers

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Answers

Answer:

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Answers

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Answers

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H2F5BLi

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Answers

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HELP ASAP!!!
What is the molarity of 930 mL of LiCl solution that contains 139.9 g of LiCI?
A. 3.5 mol/L
B. 150 mol/L
C. 3.3 mol/L
D. 3.5 x 10-3 mol/L

Answers

Answer:  A) 3.5 mol/L

Explanation:

To determine the molarity, we have to find the number of moles in the volume given, and then extrapolate to find the number of moles that would be in 1 L.

Determine the moles in the given volume

moles of LiCl = mass ÷ molar mass

                       = 139.9 g ÷ 42.39 g/mol

                       = 3.30 mol

Find the moles in 1 L

    Since 930 mL of LiCl    =   3.30 mol

    then 1000 mL of LiCl    =   (3.30 mol × 1000 mL/L) ÷ 930 mL

                                           =  3.55 mol/L

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make me brainiest if helped!
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