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2x – у = 3
19x - 6y = 6

The equations ordered from the least to greatest is

y = (-3/4)x + 2

y - 3 = 1/2(x - 4)

3x - 4y = 7

y = 12(x - 19) + 5

From the question, we are to order the equations from least to greatest by the value of the slope

The given equations are

y = (-3/4)x + 2

3x - 4y = 7

y = 12(x - 19) + 5

y - 3 = 1/2(x - 4)

To determine the slopes of the line, we will compare the equations to the general form of the equation of a line

The general form of the equation of a line is

y = mx + b

Where m is the slope

and b is the y-intercept

By comparison,

m = -3/4

∴ Slope = -3/4

First, rearrange

3x - 7 = 4y

4y = 3x - 7

y = (3/4)x - 7/4

By comparison,

m = 3/4

∴ Slope = 3/4

First, simplify

y = 12x - 228 + 5

y = 12x - 223

By comparison,

m = 12

∴ Slope = 12

y - 3 = 1/2(x - 4)

First, simplify

y - 3= (1/2)x - 2

y = (1/2)x -2 + 3

y = (1/2)x + 1

By comparison,

m = 1/2

∴ Slope = 1/2

Now,

The slopes ordered from the least to greatest is

-3/4 < 1/2 < 3/4 < 12

Thus,

The equations ordered from the least to greatest is

y = (-3/4)x + 2

y - 3 = 1/2(x - 4)

3x - 4y = 7

y = 12(x - 19) + 5

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Answer:

Simplify the expression, Your answer would be :

Step-by-step explanation:

And to find the Value of the following expression, Your answer would be :

hopefully this helps you ! ~

Answer: It is 3.5

Step-by-step explanation:

I think this because 2/2x=3/2=1.5 but you have 2 left to add which=3.5

The area of parallelogram ABCD is found to be 2√3 square units.

A quadrilateral is known as a parallelogram in geometry. The opposite sides of a parallelogram are parallel & equal in length. Rhombus, rectangle, & square are a few examples of parallelograms.

We know that diagonal of such a parallelogram divides it into two equal triangles.

So, parallelogram area,

ABCD = 2× area of ΔABC (equation 1)

The area pf the triangle is found through the vertices are (x₁,y₁), (x₂,y₂), (x₃,y₃) is;

Area = (1/2)×[x₁(y₂ - y₃) + x₂(y₃ - y₁) + x₃(y₁ - y₂)]

The vertices of the triangles are given as;

A(2,4), B(2+ √3 ,5) and C(2,6)

Area = (1/2)×[2(5−6) + (2+√3)(6−4) + 2(4−5)]

Area = (1/2)×[−2+2(2+ √3)−2]

Area = √3

When we plug this value into equation (1),

Parallelogram area,

ABCD = 2×the area of ABC

ABCD = 2×√3

ABCD = 2√3

Thus, the area of the parallelogram ABCD id estimated as 2√3 square units.

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The correct question is -

Find the area of a parallelogram ABCD if three of its vertices are A(2,4), B(2+ √3 ,5) and C(2,6)

By isolating the variable, we will see that the solution of the linear equation is v = -9

Here we have the following linear equation:

v/9 - 7 = -8

Where we can see that the variable is v. To solve this, we need to perform operations in both sides of the linear equation in a way such that the variable is isolated in one of the sides.

Adding 7 in both sides we get:

v/9 - 7 + 7 = -8 + 7

v/9 = -1

Now we multiply both sides by 9:

(v/9)*9 = -1*9 = -9

v = -9

We conclude that the solution of the linear equation is v = -9.

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Answer: -.5 OR -.1, -.2, -.3, -.4, -.5, -.6,-.7,-.8,-.9

Step-by-step explanation: The simple answer is -.5, it is right in the middle of 0 and -1. The answer number is everything in between.

An equation having variables on both sides can be solved by bringing all variables to one side.

An equation with all variables on one side can be solved by simply keeping the variables on the left and simplifying the value on the right. For example,

5x = 6 + 2x;

3x = 6;

x = 2.

For an equation with variables on both sides, just bring all variables on one side. After that, the same process like above is to be followed. For example,

5y - 3 - 3y = 3y + 5 - 3y;

5y - 3y - 3y + 3y = 5 + 3;

2y = 8;

y = 4;

Thus, methods for solving both kinds of equations is similar.

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An equation having variables on both sides can be solved by bringing all variables to one side.

An equation with all variables on one side can be solved by simply keeping the variables on the left and simplifying the value on the right. For example,

5x = 6 + 2x;

3x = 6;

x = 2.

For an equation with variables on both sides, just bring all variables on one side. After that, the same process like above is to be followed. For example,

5y - 3 - 3y = 3y + 5 - 3y;

5y - 3y - 3y + 3y = 5 + 3;

2y = 8;

y = 4;

Thus, methods for solving both kinds of equations is similar.

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Answer:

Step-by-step explanation:

Mistake in step 3 the (2x+1) and the (x-1) both cancel out but the other binomials (x + 3) and (x - 3) are different so don't cancel out.

Step 3 should be 3(x-3) / 4(x+3)

3 should not be an excluded value.

Answer:

20

Step-by-step explanation:

the line equals 180 degrees total.

so subtract the angle we already know from the total...

180- 100=80

then, make an equation with the last two variables since we know both of them added together should equal 80

80=x +3x

Combine like terms

80=4x

Divide by 4

20=x

nxhudkdodisuhaiioavsbos

The total interest earned at the end of first year is $250 and the percentage of interest for his total investment is 6.25%.

Given, Chau invested his money by purchasing the following:

a certificate of deposit for $1000 at the rate of 2% per year, and

corporate bonds for $3000 at the rate of 7% per year.

we know that simple interest is calculated by multiplying the amount invested P by the interest rate r times the number of years invested t.

therefore, I = P × r × t

a. The first investment has a principal of P = $1,000, r = 2% = 0.02, t = 1 yr

I₁ = 2000 × 0.04 × 1

I₁ = 40

The second investment has a principal P = $3,000, interest rate r = 7% = 0.07 and time t = 1yr

I₂ = 3000 × 0.07 × 1

I₂ = 210

Therefore, total interest  = I₁ ₊ I₂

= 40 ₊ 210

= $250

b. The overall rate of interest can be found by dividing:

Total interest/Total amount invested × 100

= 250/(1000 ₊ 3000) × 100

= 250/4000 × 100

= 25/4

= 6.25%

Hence we get the total interest earned at the end of first year as $250 and its overall rate of interest as 6.25%

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Your question was incomplete. Please find the missing content here.

Last year, Chau invested his money in two purchases. He purchased a certificate of deposit for $1000 that paid 2% interest per year and purchased $3000 in corporate bonds paying 7% interest per year.

(a) What was the total investment earned at the end of 1 year?

(b) What was the percentage interest for her total investment?

Answer:

18000

Step-by-step explanation:

We can multiply the number of students by the number of flowers per student.

[tex](1.2 \times 10^2)(1.5 \times 10^3) \\ \\ =(1.2)(1.5)(10^5) \\ \\ =1.8 \times 10^5 \\ \\ =18000[/tex]

When the relationship between the unit of measurement of a scale (strength) and an outcome (pounds lifted) can be described by a linear equation y = a bx, the scale is said to have a property of equal intervals.

Therefore, when the relationship between the unit of measurement of a scale (strength) and an outcome (pounds lifted) can be described by a linear equation y = a bx, the scale is said to have a property of equal intervals.

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Answer:

-2 <= y <= 4

Step-by-step explanation:

-3 <= 2y + 1 <= 9

-4 <= 2y <= 8

-2 <= y <= 4

Answer:

-2 <= y <= 4

Step-by-step explanation:

-3 <= 2y + 1 <= 9

-4 <= 2y <= 8

-2 <= y <= 4

Answer:

- 6x² + 8x

Step-by-step explanation:

- 2x(3x - 4) ← multiply each term in the parenthesis by - 2x

= - 6x² + 8x

domain = { 3,1,4,6} and range = { 2, 2 , 3 ,-2} are each relation is a function.

Describe domain.

Describe Range?

Range is the difference between the largest and lowest values in a dataset in statistics and mathematics. One indicator of data dispersion is the range.

function = ((3, 2), (1,2), (4,3), (6, -2)}

domain = { 3,1,4,6}

range = { 2, 2 , 3 ,-2}

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By critically observing the graph shown above, the set of ordered pairs include the following:

A graph can be defined as a type of chart that's commonly used to graphically represent data on both the horizontal and vertical lines of a cartesian coordinate, which are the x-axis and y-axis.

An ordered pair can be defined as a pair of two elements that are typically written in a fixed order within parentheses as (x, y), which represents the x-axis (abscissa) and the y-axis (ordinate) on a coordinate plane.

By critically observing the graph shown above, we can logically deduce that the set of ordered pairs include the following:

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Interval and ratio scales of data measurement are associated with quantitative data.

Data measurement:- Data measurement is the way in which data can be subcategorized to analyze the data properly. Data can be classified into two types-

Thus we can conclude that, Interval and ratio scales of data measurement are associated with quantitative data.

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Answer:18.2055

Step-by-step explanation:−6.87(−2.65)=−6.87*−2.65=18.2055

To simplify the indices expression x⁵y⁵z³, we can conclude that; A. bases are different, so this can't be done.

We want to simplify the indices given as;

x⁵y⁵z³

Now, we can see that the bases are different and as such it means they cannot be simplified using laws of indices on the exponents.

This is because when the bases are different, the expression cannot be factored with the exponents being added, subtracted, divided or multiplied.

Thus, we will conclude that the bases are different, so this can't be done.

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Answer:

∠T and ∠STP

Step-by-step explanation:

You can name an angle by their middle vertex letter which, in this case, is T.

And you can name an angle using the three letters provided. P, T, and S are the three letters provided. However, the vertex letter always has to be in the middle. So, it could be ∠STP or even ∠PTS.

Let me know if you don't understand or need more explanation.

Answer:

Step-by-step explanation:

y=csc(x)      x∈ [-2,2]

[tex]A.\\\displaystyle\\Increasing: \ [-2,-\frac{\pi }{2})U(\frac{\pi }{2},2]\\\\Decreasing:\ (-\frac{\pi }{2},0)U(0,\frac{\pi }{2} ) \\\\B.\\\\Relative\ min:\ 1\\\\Relative \ max:\ -1[/tex]

                                           Watching the graph:

Answer:

[tex]\textsf{Increasing}:\left[-2,-\dfrac{\pi}{2}\right) \textsf{ and }\left(\dfrac{\pi}{2},2\right][/tex]

[tex]\textsf{Decreasing}:\left(-\dfrac{\pi}{2}, 0\right) \textsf{ and }\left(0, \dfrac{\pi}{2}\right)[/tex]

[tex]\textsf{Relative min}: \left(\dfrac{\pi}{2},1 \right)[/tex]

[tex]\textsf{Relative max}: \left(-\dfrac{\pi}{2},-1 \right)[/tex]

Step-by-step explanation:

Part A

Given function:

[tex]f(x)=\csc (x), \quad -2\leq x\leq 2[/tex]

[tex]\csc(x)=\dfrac{1}{\sin(x)}[/tex]

Therefore, the function f(x) is undefined when sin(x) = 0, leading to vertical asymptotes at the value of x where sin(x) = 0.

[tex]\sin(x) = 0 \textsf{ at }x = 0\pm 2 \pi n, \pi \pm 2 \pi n[/tex]

Therefore, f(x) has a vertical asymptotes at x = -2π, -π, 0, π, 2π etc.

Where the graph of the sine function increases, the graph of the cosecant function decreases.

Where the graph of the sine function decreases, the graph of the cosecant function increases.  

The sine function increases on the intervals:

[tex]\left(-\dfrac{\pi}{2}\pm 2 \pi n, \dfrac{\pi}{2}\pm 2 \pi n\right)[/tex]

and decreases on the intervals:

[tex]\left(\dfrac{\pi}{2}\pm 2 \pi n, \dfrac{3\pi}{2}\pm 2 \pi n\right)[/tex]

Therefore, for the interval -2 ≤ x ≤ 2, the cosecant function f(x):

Increases on the intervals:

[tex]\left[-2,-\dfrac{\pi}{2}\right) \textsf{ and }\left(\dfrac{\pi}{2},2\right][/tex]

Decreases on the intervals:

[tex]\left(-\dfrac{\pi}{2}, 0\right) \textsf{ and }\left(0, \dfrac{\pi}{2}\right)[/tex]

Part B

The relative minimums of the graph of the sine function are the relative maximums of the graph of the cosecant function.

The relative maximums of the graph of the sine function are the relative minimums of the graph of the cosecant function.

The sine function has a range of -1 ≤ sin(x) ≤ 1.

Therefore, its minimum points are when sin(x) = -1 and its maximum points are when sin(x) = 1.

[tex]\sin(x)=-1 \implies x=\dfrac{3\pi}{2}\pm 2 \pi n \implies \textsf{Minimum points}: \left(\dfrac{3\pi}{2}\pm 2 \pi n ,-1 \right)[/tex]

[tex]\sin(x)=1 \implies x=\dfrac{\pi}{2}\pm 2 \pi n \implies \textsf{Maximum points}: \left(\dfrac{\pi}{2}\pm 2 \pi n,1 \right)[/tex]

Therefore, the minimum and maximum points of the cosecant function in the given interval -2 ≤ x ≤ 2 are:

[tex]\textsf{Relative min}: \left(\dfrac{\pi}{2},1 \right)[/tex]

[tex]\textsf{Relative max}: \left(-\dfrac{\pi}{2},-1 \right)[/tex]

Note in the attached graph:

Answer:

y2 = m*(x2 - x1) + y1

Step-by-step explanation:

m = (y2 - y1) / (x2 - x1)

y2 - y1 = m*(x2 - x1)

y2 = m*(x2 - x1) + y1

Answer: $48.17

Step-by-step explanation:$148.68-$24.32=  $124.36

$124.36-$37.53=  $86.83

$135 -$86.83=$48.17

So he needs forty-eight dollars and 17 cents.                                            

Answer:

Step-by-step explanation:

Let x represent the number of weeks a population of the bacteria increases. Then, we have the number of bacteria is molded by the expression of 900*3^x. By, the given expression and when we assigned a value of x=2. Then we have 900*3² .

Answer:

111111111/200000000