Use an integer to describe the
situations.
6 meters
above sea level
sea level

Answers

Answer 1

An integer to describe 6 meters above the sea level would be [tex]+6[/tex] meters.

As per the question statement, We are supposed to use an integer to describe the following situation "6 meters above sea level".

We assume that sea level is the datum line and anything above that would be positive and below that would be negative.

So 6 meters above the sea level can be described as [tex]=6meters[/tex].

Integers: Set of whole number containing both positive and negative values of it.

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Related Questions

192 students in 4 buses
________ in each bus

Answers

Answer:

48

Step-by-step explanation:

use a calculator

48 for each bus

192/4=48 or 48+48+48+48=192

To two decimal places,
√70
must lie between ____
and _____.

Answers

To two decimal places,

√70

must lie between 8.3

and 8.4

the temperature was 75 degrees. at noon, the temperature increased by 7. by evening the temperature decreased by 7

Answers

Answer:

75

Step-by-step explanation:

75 + 7 = 82


82 - 7 = 75

Solving systems by substitution
y=x+3
2x-2y = -6

Answers

y = x + 3

2x -2y = - 6

2x - 2( x +3 ) = -6

2x - 2x -6 = -6
-6 = -6

y = x + 3

Answer:

All Real Numbers

Step-by-step explanation:

Hello!

We have to find the intersection of the two lines algebraically using substitution.

Given that y is x + 3, substitute x + 3 for y in the second equation to solve for x.

Solve for x2x - 2y = -6; y = x + 32x - 2(x + 3) = -62x - 2x - 6 = -6-6 = -6

The solution for x is all real numbers, indicating that the solution to the system is also all real numbers.

What does this mean graphically?

A solution to the system is the point of intersection from all the lines.

If there are infinite solutions (all real numbers), there are an infinite number of intersections, or they are the same line.

Solving for y in the second equation:

2x - 2y = -6-2y = -2x - 6y = x + 3

Both equations are the same.

Which of the following is a whole number? Select all correct answers.

Select all that apply:

15
0
439
−9
−10
5

Answers

Answer:

15, 0, 439, 5

Step-by-step explanation:

-9 and -10 are negative integers. Whole numbers can't be negative.

Answer:

15,0,439,5 are whole numbers. eg: when we count the number of students we use 1,2,3 etc we won't use any decimal or fractions or negative values. like that whole numbers are like the numbers we count number of students

Identify the lower class limits, upper class limits,
class width, class midpoints, and class boundaries for
the given frequency distribution. Also identify the
number of individuals included in the summary.
Age (yr) when
award was won
20-29
30-39
40-49
50-59
60-69
70-79
80-89
Frequency
27
32
15
3
5
1
1

Answers

The upper class limits are- 29, 39, 49, 59, 69, 79, 89

The lower class limits are- 20, 30, 40, 50, 60, 70, 80

The class midpoints are- 24.5, 24.5, 44.5, 54.5, 64.5, 74.5, 84.5

The class boundaries are- 29.5, 39.5, 49.5, 59.5, 69.5, 79.5

And the number of individuals included in the summary is 84.

Here, we are given the following dataset-

Age (yr) when          Frequency

award was won

20-29                       27

30-39                       32

40-49                       15

50-59                       3

60-69                       5

70-79                        1

80-89                       1

Upper class limit is the largest data value that can go in a class.

Thus, the upper class limits are- 29, 39, 49, 59, 69, 79, 89

Lower class limit is the smallest data value that can go in a class.

Thus, the lower class limits are- 20, 30, 40, 50, 60, 70, 80

The class midpoint is the average of the upper and lower limits of a class. Class midpoint = (upper limit + lower limit)/ 2

Thus, the class midpoints are- 24.5, 24.5, 44.5, 54.5, 64.5, 74.5, 84.5

Class boundary is the midpoint of the upper class limit of a class and the lower class limit of the previous class.

Thus, the  class boundaries are- 29.5, 39.5, 49.5, 59.5, 69.5, 79.5

Frequency gives us the number of individuals/ objects belonging to a particular class.

Thus, the number of individuals included in the summary = 27 + 32 + 15 + 3 + 5 + 1 + 1 = 84

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r = 10 units and h = 7 units, then what is the volume of the cylinder shown above?

Answers

Answer:

radious:10

height:7

volume:?

we know that

volume of cylinder:2pie×r²×h

=22/7×10²×7

=2200unit³

refer to the image pls!! Will give brainliest

Answers

Step-by-step explanation:

hmmm, it is all there, you only need to write it up.

so, please, let me know what you don't understand about such equations and variables.

(a)

2x + 5y = 45

8x + 3y = 44

(b)

to solve this we try to use either one equation to express one variable by the other. and solve for that remaining variable (and then drive the second one from that), or to combine both equations directly to eliminate one variable and solve.

I think the second option is best here.

so, we multiply the 1st equation by -4, and then we add both equations :

-8x - 20y = -180

8x + 3y = 44

-------------------------

0 - 17y = -136

-17y = -136

17y = 136

y = 8

2x + 5y = 45

2x + 5×8 = 45

2x + 40 = 45

2x = 5

x = 2.5

to rent a chair costs $2.50.

to rent a table costs $8.00.

Robert spends $30.45, before tax, at the bookstore. If the sales Tax rate in his city is 7.25%, and Robert started with $40, how much does Robert have left?

Answers

The amount of money Robert has left given the amount he started with and after deducting tax is approximately $7.34

How much does Robert have left after deducting tax?

Tax can be defined as the compulsory levy paid by citizens of a particular country on their income, goods and be services.

Amount Robert started with = $40Amount Robert spent before tax = $30.45Tax rate = 7.25%

Amount of tax = Tax rate × Amount Robert spent before tax

= 7.25% × $30.45

= 7.25/100 × 30.45

= 0.0725 × 30.45

= $2.207625

Total amount Robert spent = Amount Robert spent before tax + Amount of tax

= $30.45 + $2.207625

= $32.657625

Amount Robert has left = Amount Robert started with - Total amount Robert spent

= $40 - $32.657625

= $7.342375

Approximately,

$7.34

Therefore, the amount Robert has left after deducting tax is $7.34

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Consider the function f,g:[tex]\mathbb{R} \to\mathbb{R}[/tex] defined by
[tex] \rm f(x) = {x}^{2} + \frac{5}{12} \: and \: g(x) = \begin{cases}2 \bigg( \rm 1 - \dfrac{4 |x| }{3} \bigg), \: \: \: \: |x| \leq \dfrac{3}{4}, \\ \\ 0, \: \: \: \: \: \rm \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: |x| > \dfrac{3}{4} .\end{cases} [/tex]
If [tex]\alpha[/tex] is the area of the region
[tex] \rm \bigg \{(x,y) \in \mathbb{R} \times \mathbb R : |x| \leq \dfrac{3}{4} ,0 \leq y \leq min \{f(x),g(x) \} \bigg \}[/tex]
then the value of 9[tex]\alpha[/tex]​

Answers

Suppose [tex]x>0[/tex]; then the curves meet when

[tex]x^2 + \dfrac5{12} = 2 - \dfrac83 x \implies x^2 + \dfrac83 x - \dfrac{19}{12} = \left(x + \dfrac{19}6\right) \left(x - \dfrac12\right) = 0 \\\\ \implies x = \dfrac12[/tex]

By symmetry, they intersect at [tex]x=\pm\frac12[/tex].

We also see that [tex]\min\left\{f(x):|x|\le\frac34\right\} = \frac5{12}[/tex] and [tex]\max\left\{g(x):|x|\le\frac34\right\} = 2[/tex] at [tex]x=0[/tex]. [tex]f[/tex] and [tex]g[/tex] are continuous, so it follows that

[tex]\min\left\{f(x),g(x) :|x|\le\frac34\right\} = \begin{cases} f(x) & \text{if } |x| < \frac12 \\ g(x) & \text{if } |x| > \frac12 \\ f\left(\pm\frac12\right) = g\left(\pm\frac12\right) = \frac23 & \text{if } x = \pm\frac12 \end{cases}[/tex]

Compute the area [tex]\alpha[/tex]. Taking advantage of symmetry again, we have

[tex]\alpha = \displaystyle 2 \int_0^{1/2} \int_0^{f(x)} dy\,dx + 2 \int_{1/2}^{3/4} \int_0^{g(x)} dy \, dx \\\\ ~~~~ = 2 \int_0^{1/2} f(x) \, dx + 2 \int_{1/2}^{3/4} g(x) \, dx \\\\ ~~~~ = \left. 2 \left(\frac{x^3}3 + \frac{5x}{12}\right) \right\vert_0^{1/2} + \left. 2 \left(2x - \frac{8x^2}6\right) \right\vert_{1/2}^{3/4} \\\\ ~~~~ = \left(\frac12 - 0\right) + \left(\frac32 - \frac43\right) = \frac23[/tex]

and it follows that [tex]9\alpha = \boxed{6}[/tex].

Point B is between points A and C. AC-10x+6, AB=5x, and BC-4x+12, Find AB.​

Answers

The value of AB that is 5x is equal to 30.

It is given that the points A, B and C are collinear. Collinear points may be defined as three or more points which lie on a straight line.

Here B lies between A and C and the three points A, B and C are collinear. Thus, according to property of collinear points:

AB+BC=AC

Now, according to question AB=5x, BC= 4x+12 and AC= 10x+6.

So, 5x+4x+12=10x+6

Taking the like terms on one side;

12-6 = 10x+9x

=> x=6

Now, AB=5x, thus AB= 5×5=30

Therefore, the value of AB is 30.

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Complete question:

Three points A, B and C are collinear. Point B is between points A and C. AC=10x+6, AB=5x, and BC=4x+12, Find AB.

Which of the expressions are equivalent to the one below? Check all that
apply.
(6.1)-8
A. 6-(1-8)
B. (1-8) (6-8)
C. 8- (1.6)
D. (1.6)-8

Answers

Answer:

C. & D.

Step-by-step explanation:

I believe it is C & D because, They both are in the same order just switched around, combine like like terms on both sides of the equation then if they are identical then they're equivalent.

What would the Median of 112 113 116 118 119 124 be?

Answers

117
Check out the attached photo


Solve.
c = kny, for y

Answers

The solution of the equation c = kny, for y is y = c/kn

How to solve the equation c = kny, for y?

The equation is given as

c = kny

Divide both sides of the given equation by k

So, we have

c/k = kny/k

Evaluate the quotient on both sides of the above equation

So, we have

c/k = ny

Divide both sides of the above equation by n

So, we have

c/kn = ny/n

Evaluate the quotient on both sides of the above equation

So, we have

c/kn = y

Rewrite as

y = c/kn

Hence, the solution of the equation c = kny, for y is y = c/kn

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If anyone can help me to solve this!!​

Answers

Answer:

[tex]\textsf{1.} \quad x=-6, \quad x=6[/tex]

[tex]\textsf{2.} \quad x=-5, \quad x=2[/tex]

[tex]\textsf{3.} \quad x=-3, \quad x=7[/tex]

[tex]\textsf{4.} \quad x=\dfrac{-5 +\sqrt{57} }{4}, \quad x=\dfrac{-5 -\sqrt{57} }{4}[/tex]

[tex]\textsf{5.} \quad x=\dfrac{7+ \sqrt{309} }{10}, \quad x=\dfrac{7-\sqrt{309} }{10}[/tex]

Step-by-step explanation:

Question 1

Method: Extracting the Square Root

[tex]\begin{aligned}& \textsf{Given}: & x^2 & = 36\\& \textsf{Square root both sides}: & \sqrt{x^2} & = \sqrt{36}\\& \textsf{Simplify}: & x & = \pm 6\\&\textsf{Solution}:&x& = -6, 6\end{aligned}[/tex]

Question 2

Method: Factoring

[tex]\begin{aligned}& \textsf{Given}: & x^2+3x-10 & = 0\\& \textsf{Split the middle term}: & x^2+5x-2x-10 & = 0\\& \textsf{Factor the first two and the last two terms}: & x(x+5)-2(x+5)&=0\\& \textsf{Factor out the common term $(x+5)$}: & (x-2)(x+5)&=0\\& \textsf{Apply the zero-product property}: & (x-2)=0 \implies x&=2\\ &&(x+5)=0 \implies x&=-5\\ & \textsf{Solution}: & x&=-5,2\end{aligned}[/tex]

Question 3

Method: Factoring

[tex]\begin{aligned}& \textsf{Given}: & x^2-4x-21 & = 0\\& \textsf{Split the middle term}: & x^2-7x+3x-21 & = 0\\& \textsf{Factor the first two and the last two terms}: & x(x-7)+3(x-7)&=0\\& \textsf{Factor out the common term $(x-7)$}: & (x+3)(x-7)&=0\\& \textsf{Apply the zero-product property}: & (x+3)=0 \implies x&=-3\\&&(x-7)=0 \implies x&=7\\& \textsf{Solution}: & x & = -3, 7\end{aligned}[/tex]

Question 4

Method: Quadratic  Formula

[tex]\boxed{\begin{minipage}{4 cm}\begin{center}\underline{Quadratic Formula}\end{center}\\\\\begin{center}$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$\end{center}\\\\\\\begin{center}when $ax^2+bx+c=0$\end{center}\end{minipage}}[/tex]

Given:

[tex]5x-4=-2x^2[/tex]

Rearrange into standard form by adding 2x² to both sides:

[tex]\implies 2x^2+5x-4=0[/tex]

Therefore:

[tex]a=2, \quad b=5, \quad c=-4[/tex]

Substitute the values into the quadratic formula and solve for x:

[tex]\implies x=\dfrac{-5 \pm \sqrt{5^2-4(2)(-4)} }{2(2)}[/tex]

[tex]\implies x=\dfrac{-5 \pm \sqrt{25+32} }{4}[/tex]

[tex]\implies x=\dfrac{-5 \pm \sqrt{57} }{4}[/tex]

Therefore, the solutions are:

[tex]x=\dfrac{-5 +\sqrt{57} }{4}, \quad x=\dfrac{-5 -\sqrt{57} }{4}[/tex]

Question 5

Method: Quadratic  Formula

[tex]\boxed{\begin{minipage}{4 cm}\begin{center}\underline{Quadratic Formula}\end{center}\\\\\begin{center}$x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}$\end{center}\\\\\\\begin{center}when $ax^2+bx+c=0$\end{center}\end{minipage}}[/tex]

Given:

[tex]5x^2-7x-13=0[/tex]

Therefore:

[tex]a=5, \quad b=-7, \quad c=-13[/tex]

Substitute the values into the quadratic formula and solve for x:

[tex]\implies x=\dfrac{-(-7) \pm \sqrt{(-7)^2-4(5)(-13)} }{2(5)}[/tex]

[tex]\implies x=\dfrac{7 \pm \sqrt{49+260} }{10}[/tex]

[tex]\implies x=\dfrac{7 \pm \sqrt{309} }{10}[/tex]

Therefore, the solutions are:

[tex]x=\dfrac{7+ \sqrt{309} }{10}, \quad x=\dfrac{7-\sqrt{309} }{10}[/tex]

_____= 240 mL
Group of answer choices

4 oz

4 pints

1 cup

8 drams

Answers

The volume 240 ml to oz is 8 oz.

How to find volume in different units?

The volume is in millilitres. Therefore, we have to convert to other units.

1 ml = 0.033814 oz

1 ml = 0.00175975 pints

1 ml = 0.00422675 cup

1 ml = 0.57 grams

Hence, lets convert the volume to the various units.

1 ml = 0.033814 oz

240 ml = ?

cross multiply

volume = 240 × 0.033814 = 8.11536 oz = 8 oz

1 ml = 0.00175975 pints

240ml = ?

volume = 0.00175975 × 240 = 0.42216 = 0.4 pints

1 ml = 0.00422675 cup

240 ml = ?

volume =  0.00422675 × 240 = 10.1442 cups

1 ml = 0.57 grams

240 ml = ?

volume = 0.57 × 240 = 136.8 grams

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According to a survey conducted by a city’s chamber of commerce, approximately 41.5% of city residents prefer local businesses over national chains. The survey had a margin of error of ±3.8%. Round to the nearest tenth, if necessary.

Answers

The values in percentages will be 37.7% and the maximum will be: 45.3%

How to illustrate the information?

From the information, approximately 41.5% of city residents prefer local businesses over national chains and the survey had a margin of error of ±3.8%.

Therefore, the minimum number will be:

= 41.5% - 3.8%

= 37.7%

The maximum will be:

= 41.5% + 3.8%

= 45.3%

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Need help with this was will off 30 points

Answers

The solution of the simultaneous equations is given by: x=0.60 and

y = 0.80 .

A system of equations or simultaneous equations, usually referred to as an equation system, is a collection of finite equations for which common solutions are sought.

The elimination approach, which involves taking one of the unknowns out of each equation, is the most popular technique for solving simultaneous equations. The final step is to calculate the remaining unknown. If the coefficient of one of the letters is the same, regardless of sign, this is possible.

The given pair of simultaneous equations are:

6 x + 8 y = 10

9 x + 6 y = 10.20

Now let us multiply the first equation by 6 and the second equation by 8 and subtract it from the first.

   36 x + 48 y = 60

   72 x + 48 y = 81.60

⇒ 36 x  = 21.60

⇒ x = 21.60 ÷ 36

⇒ x = 0.60

Substituting the value in the first equation we get:

y= 0.80.

Hence the solution of the simultaneous equation is x=0.60 and

y = 0.80 .

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Solve the formula of the indicated variable C=xw+x, for w

Answers

C-X = XW
(C-X)/(X) = W

Simplify 2.67 + (−8.9).

Answers

Answer:

-6.23 is the answer

HOPE IT'S HELPS YOU

Answer:

-6.23

Step-by-step explanation:

The solution will be,

→ 2.67 + (−8.9)

→ 2.67 - 8.9

→ -6.23

So, the answer is -6.23.

Question 13 (1 point)
Saved
Given the following definitions:
U= (a, b, c, d, e, f, g)
A = {a, c, e, g)
B = (a, b, c, d]
Find A U B'

Answers

Answer:

{a, c, e, f, g}

Step-by-step explanation:

[tex]B'=\{a,b,c,d,e,f,g\}-\{a,b,c,d\}=\{e,f,g\} \\ \\ A \cup B=\{a,c,e,f,g\}[/tex]

Can I please get help?

Answers

Answer:

a) 9

b)3

c)22

Step-by-step explanation:

a)13+14/8-5 =27/3 =9

b) 9+9/4+2= 18/6 = 3

c) 12+16-6=22

Answer:

A- 9

B-3

C-22

Step-by-step explanation:

A-13+7*2/8-(3+2)

13+14/8-5

27/3

9.

B-9+3^2/2^2+2

9+9/4+2

18/6

3.

C-(10+2)+(4^2-6)

(12)+(16-6)

12+10

22

which is the graph of the function y=4x^2-8x+7

Answers

26-56-67-46-57-57-635

Which of these are a correct application of the Identity Property of Addition? Select all correct answers.

Select all that apply:

−26+26=0
26−26=0
0+26=26
26×0=0
26+0=26

Answers

Answer:

0+26=26, 26+0=26

Step-by-step explanation:

When you add 0 to a number and get the same number, that's the Identity Property of Addition.

Find the missing coordinate (x,5) and (3,3) m= 1/2

Answers

The missing coordinate of the points is 7

What are linear equations?

Linear equations are equations that have constant average rates of change. Note that the constant average rates of change can also be regarded as the slope or the gradient

How to determine the missing coordinate?

The given parameters are

Slope, m = 1/2

Points (x1, y1) = (x, 5) and (x2, y2) = (3, 3)

The slope of a linear equation is calculated as

m = (y2 - y1)/(x2 - x1)

So, we have

1/2 = (3- 5)/(3 - x)

Evaluate the differences

So, we have

1/2 = -2/(3 - x)

Cross multiply

So, we have

3 - x = -4

This gives

x = 3 + 4

Evaluate the sum

x = 7

Hence, the missing coordinate of the points is 7

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Jane and Jim spend the same amount of money today. If Jim spent 5.25 on food and rode the train three times and Jane spent 12.45 on food and rode the roller coaster twice, then how much does a token cost?

Answers

The cost of a Token from the question is; $7.2

How to solve Algebra Word Problems?

We are told that Jane and Jim spend the same amount of money today.

Now, Jim spent 5.25 dollars on food and rode the train 3 times, and Jane spent 12.45 dollars on food and rode the roller coaster twice.

Assuming cost of a token is T, the the algebraic expression formed is;

5.25 + 3T = 12.45 + 2T.

3T - 2T = 12.45 - 5.25

T = $7.2

Thus, we conclude that the cost of a Token is; $7.2

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Question 14 of 20
K
The table below shows the frequency distribution of the rainfall on 52 consecutive Mondays in a
certain city. Use the frequency distribution to construct a histogram. Do the data appear to have a
distribution that is approximately normal?
Class
0-0.19
0.20-0.39
0.40-0.59
0.60-0.79
0.80-0.99
1.00-1.19
1.20-1.39
Frequency
21
12
5
3
8
2
1
CID
+
possib
This question: 5 points) possible
Choose the correct histogram below
OA
OC.
10-
00 02 04 06 08 10 12 14
30-
20-
10-
of
00 02 04 06 08 10 12
10-
00 02 04 06 08 10 12 14
Do the data appear to have a distribution that is approximately normal?
OA No, it is not symmetric
OB. No, it is approximately uniform
OC. Yes, it is approximately normal
OD. No, it has no obvious maximum

Answers

1. The correct histogram (attached) that captures the frequency distribution is Option C.

2. Whether the data appear to have a distribution that is approximately normal, A. No, it is not symmetric.

What is a symmetric distribution?

A symmetric distribution is a distribution in which the left and right sides mirror each other and it is a normal distribution, with a distinct bell shape.

In a symmetrical distribution, mean = median = mode.  It is a skewed distribution when it is not symmetrical.

Data and Calculations:

Class             Frequency

0-0.19                  21

0.20-0.39            12

0.40-0.59             5

0.60-0.79             3

0.80-0.99             8

1.00-1.19                2

1.20-1.39               1

Thus, the frequency histogram shows a skewed distribution of rainfall, where one tail is longer than the other.

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I need help with this

Answers

Answer: last one

Step-by-step explanation:

I think it's the last one because the value of 8 is negative and the value of 1 is positive. however, rita changes the negative and positive numbers and thats why she is wrong.

Exit This table reflects the result of a survey conducted in a town to find out the number of cars of a particular color. Which of the following ranges would be appropriate to use in order to represent the numerical data on the vertical axis of a Bar Graph? A. 10 to 20 B. 20 to 100 C. 0 to 50 D. 0 to 30

Answers

The range that would be the most approx to represent the numerical data on the vertical axis is B. 20 to 100.

Bar graph :

Bar graphs are the pictorial representation of data (generally grouped), in the form of vertical or horizontal rectangular bars, where the length of bars is proportional to the measure of data

The range that would be the most approx to represent the numerical data on the vertical axis is B. 20 to 100.

because

it is not possible to have zero number of cars that have a particular color,

in That way, we can eliminate options C and D .

in option A the range is too small which is not possible.

the table is not included but the range of 20 to 100 is most appropriate for the number of cars in town with a particular color.

this is because towns would normally have between hundreds and thousands of cars which means that cars of a particular color would be between 20 and 100 at least.

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The range that would be the most approx to represent the numerical data on the vertical axis is B. 20 to 100.

Bar graph :

Bar graphs are the pictorial representation of data (generally grouped), in the form of vertical or horizontal rectangular bars, where the length of bars is proportional to the measure of data

The range that would be the most approx to represent the numerical data on the vertical axis is B. 20 to 100.

because

it is not possible to have zero number of cars that have a particular color,

in That way, we can eliminate options C and D .

in option A the range is too small which is not possible.

the table is not included but the range of 20 to 100 is most appropriate for the number of cars in town with a particular color.

this is because towns would normally have between hundreds and thousands of cars which means that cars of a particular color would be between 20 and 100 at least.

PLEASE HELP DUE TOMORROWW

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