Usain Bolt made it to the 100m mark in 9.92s. What was his displacement? The radius of the turn is 36.3m

The correct option is C. Position of the head of the fetus of an extinct animal that gave birth on land or underwater.

In human prenatal development, fetal development starts offevolved from the 9th week after fertilization (or eleventh week gestational age) and maintains till birth.

Prenatal improvement is a continuum, with no clear defining characteristic distinguishing an embryo from a fetus. however, a fetus is characterized by the presence of all the most important body organs, though they will now not yet be completely advanced and practical and some not but situated in their very last anatomical vicinity. An unborn offspring develops and grows within the uterus (womb) of humans and different mammals. In human beings, the fetal duration begins at 9 weeks after fertilization of an egg by using sperm and ends at the time of delivery.

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Complete Question:

1. How can scientists determine whether an extinct animal gave birth on land or underwater?

a. Location of the hind limbs of the fetus

b. Position of the nostrils

c. Position of the head of the fetus

d. Location of the fossils

The ball had a maximum height that was 3.0 meters lower than its initial height (h₀).

Before being thrown down, let's call the ball's initial height h0. The ball's height after it was thrown down and bounced back up is called h1.

After being thrown, the ball takes half as long to reach its maximum height (h1) as it does to bounce back to the ground (2.9 s divided by 2 = 1.45 s).

Using the following equation for vertical displacement under gravity's constant acceleration:

                   y = v₀ × t + (1/2) × a × t²

where:

The initial velocity of the ball, v₀, is negative because it was thrown straight down;

a is the acceleration caused by gravity (9.8 m/s²); and

t is the time it takes for the ball to reach its maximum height (1.45 s).

We can use the equation for velocity under constant acceleration to determine the initial velocity of the ball, v₀ :

                       v = v₀ + a × t

where:

v is the velocity of the ball at time t (0 m/s since it has reached its maximum height)

Combining the two equations:

                     0 = v₀ + 9.8 m/s² × 1.45 s

                 v₀ = -9.8 m/s² × 1.45 s

Substituting the values for v₀ and t into the equation for vertical displacement:

                      h₁ - h₀ = v₀ × t + (1/2) × a × t²

h₁ - h₀ = (-9.8 m/s² × 1.45 s) × 1.45 s + (1/2) × 9.8 m/s² × (1.45 s)²

                       h₁ - h₀ =   -13.8 m + 10.8 m

                           h₁ - h₀

                             = -3.0 m

So, the ball's greatest height above the floor was 3.0 m less than its initial height (h₀).

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The average speed of the school bus while the bus is slowing down is 5m/s.

Initial velocity, u = 15 m/s.

Distance traveled, d = 55 m.

Time is taken, t = 11 s.

Final velocity, v = 0 m/s.

We know, average velocity is given by :

[tex]v_a_v_g= \frac{distance}{time} = \frac{55}{11} = 5m/s[/tex]

Therefore, the average velocity is 5 m/s.

The pace is measured as the ratio of distance to the time wherein the distance is turned into a blanket. the pace is a scalar quantity because it has the most effective course and no importance. For the size of the pace in vehicles, speedometers are used. pace also can be calculated with the assistance of a graph. the space-time graph allows know-how of the rate of an object.

In regular use and in kinematics, the rate of an object is the value of the change of its position over the years or the importance of the alternate of its function per unit of time; its miles as a result a scalar amount. the spot pace is the limit of the common pace because the period of the time c program language period approaches 0. pace isn't always similar to velocity.

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Answer:

D

Explanation:

The mass of the truck remains the same while the velocity of the truck remains the same.

The concept of a closed, isolated system means that the system is considered to be completely enclosed and does not exchange energy or matter with its surroundings. In this case, the truck is spreading sand across the ice, but it is still considered a closed, isolated system because it is not exchanging matter with its surroundings. The mass of the truck, which includes the truck and the sand inside, remains constant.

Therefore, option D, "The mass of the truck remains the same while the velocity of the truck remains the same" is true.

Answer: ~7.94g/cm^3

Explanation: To find the density we first must make sure all the units are correct:

0.500kg x 1000g = 500g

500g / 63 cm^3 will give you units in g/cm^3, and the answer: 7.9365g/cm^3.

The initial vertical velocity needed to raise the center of mass from 1.2 m to a peak height of 1.8 m is approximately 3.43 m/s.

The initial vertical velocity needed to reach a peak height can be calculated using the equation of motion for a projectile under constant gravity:

Vyi = √(2 * g * (yf - yi))

where:

Plugging in the values, we get:

Vyi = √(2 * 9.8 * (1.8 - 1.2))

Vyi = √(2 * 9.8 * 0.6)

Vyi = √(11.76)

Vyi = 3.43 m/s

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Its normalized flux for this configuration while the planet is off to the side is, and the normalized flux whenever the planet equals transiting is, respectively, 1.00000 and 0.99990.

It specifies three requirements for a planet: It must move about a sun. It must be large enough for gravity to pull it in a spherical direction. It must be massive sufficient that its gravity wiped away any other things of a similarly sized in its circle of the Sun.

Earth is formed of rock, as are the three inner planets of the solar system (Mercury, Venus, and Mars), which also contain metals like aluminum and aluminum as well as typical minerals like feldspar.

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Answer:

1.00000,0.99990 (correct)

Explanation:

[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

A wire should have the least resistance possible, because if there is more resistance in wires, there would be a lot of power loss when current flows through it.

Therefore, wires should have lowest resistance.

It will take both pipes working together 2 hours to fill the tank. As in general, when two pipes or machines are working together to complete a task, their combined rate is the sum of their individual rates.

Let's assume that the tank has a volume of 1 unit (you can use any unit you prefer).

The first pipe can fill the tank in 3 hours, which means it can fill 1/3 of the tank in one hour. Similarly, the second pipe can fill the tank in 6 hours, which means it can fill 1/6 of the tank in one hour.

If both pipes are used at the same time, the rate at which they fill the tank is the sum of their individual rates. So, the combined rate at which they fill the tank is:

1/3 + 1/6 = 2/6 + 1/6 = 3/6 = 1/2

This means that both pipes together can fill half of the tank in one hour. To fill the entire tank, we need to multiply this rate by the time it takes to fill the tank, which we'll call "t":

1/2 * t = 1

Solving for "t", we get:

t = 2 hours

Therefore, it will take both pipes working together 2 hours to fill the tank.

This same concept can be applied to many different types of problems involving pipes, machines, or workers working together to complete a task. The key is to find the individual rates of each pipe or machine and add them together to get the combined rate. Then, you can use the combined rate to find the time it takes to complete the task.

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The recoil velocity of the launcher is 5.1 m/s.

option D.

To calculate the recoil velocity of the launcher, we can use the law of conservation of momentum.

According to this law, the total momentum of the system (turkey + launcher) before the launch is equal to the total momentum after the launch.

initial momentum of the turkey = final momentum of the launcher

( 25 kg x 245 m/s ) = 1,200 kg (v)

where;

v = ( 6125 kgm/s) / ( 1,200 kg )

v = 5.1 m/s

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Answer:

The telescope with a 17-inch diameter can gather more than 60 times more light than the one with a 3-inch diameter.

Explanation:

(a) The normal force experienced by the block is 9.8 N.

(b) The maximum static frictional force is 1.96 N.

(c) The minimum force required to move the block is 1.96 N.

(d) The kinetic friction force is 1.862 N.

The normal force experienced by the block is equal to the weight of the block and is given by:

F_normal = mg

where;

F_normal = 1 kg x 9.8 m/s^2 = 9.8 N

The maximum static frictional force is given by:

F_friction_max = μ_s x F_normal

where;

F_friction_max = 0.2  x 9.8 N = 1.96 N

To get the block to move, a horizohntal force greater than the maximum static frictional force must be applied. The minimum force required to move the block is given by:

F_min = F_friction_max + ε

where;

The kinetic friction force is given by:

F_friction_kinetic = μ_k x F_normal

where;

F_friction_kinetic = 0.19 x 9.8 N = 1.862 N

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The hammer travels at 3.9 m/s in its horizontal direction. The roof is at an angle with the horizontal when the hammer is dropped from a height of v along it.

The speed with which something travels in a specific direction is known as its velocity. As an illustration, think of the movement of a car driving north on either a highway or the speed at which a rocket takes off.

The change in displacement is measured in terms of velocity. The speed of change in velocity is known as acceleration. Given that it has both a magnitude and a direction, mass and velocity quantity. Being merely the change in frequency, accelerating is also an vector quantity.

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The initial velocity of the ball is v₀ = (2*2.0)/0.30 = 13.3 m/s. and the height of the ball above the launch position is h = (13.3*1.7) - (0.5*9.81*(1.7)²) = 15.1 m.

Initial velocity is the speed and direction of an object at the start of its motion. It is usually designated by vector notation, with the direction of motion indicated by an arrow.

The initial velocity of the ball can be calculated using the equation v₀ = (2h)/t, where h is the height of the window (2.0 m) and t is the time it took for the ball to reach the top of the window (0.30 s).
Thus, the initial velocity of the ball is v₀ = (2*2.0)/0.30 = 13.3 m/s.

The bottom of the window is 1.7 m above the launch position.
The height of the ball above the launch position can be calculated using the equation h = v₀t - 0.5gt².
Here, v₀ is the initial velocity (13.3 m/s),
t is the time it took for the ball to pass the bottom of the window (1.7 s),
and g is the acceleration due to gravity (9.81 m/s²).
Thus, the height of the ball above the launch position is h = (13.3*1.7) - (0.5*9.81*(1.7)²) = 15.1 m.

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The only force causing the car to slide down the incline is the gravitational force component, or "mg sin," because the surface is frictionless (smooth), or Ff = 0.

a) F = mg sin θ.

F = 50 * 10−3 9.8 * 1/2

= 0.245 N

If the slope is 30 degrees, the top corner will be 90 30 degrees, and the normal to the vertical force will also be 90 60 degrees, thus we will use mg cos 30 perpendicular to the slope.

b) FN = mg cos θ

= m × g × cos θ

= 50 × 10−3 × 9.8 × cos 30

= 0.43N

Therefore, The only force causing the car to slide down the incline is the gravitational force component, or "mg sin," because the surface is frictionless (smooth), or Ff = 0.

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Answer:

no zero error

Explanation:

Two blocks are attached to either end of a light rope that passes over a light, the change in gravitational PE is 11.76, -15.68j,  0.2T, -0.2T and speed is 0.7483 m/s.

partA] change in gravitational PE :

U6 = m1gh = 6*9.8*0.2 = 11.76 J

 U8 = -m2gh = -8*9.8*0.2 = -15.68 J

ANSWER = 11.76, -15.68

partB] W6 = T*0.2 = 0.2T

W8 = T*-0.2 = -0.2T

  answer = 0.2T, -0.2T

partC] WT = 0.2T-0.2T = 0

    deltaUg = 11.76-15.68 = -3.92 J

   increase in KE = 3.92J

   speed v = sqrt(2KE/(m1+m2))= sqrt(2*3.92/14) = 0.7483 m/s

  answer = 0,-3.92, 0.7483

The pace is measured as the ratio of distance to the time wherein the distance is turned into a blanket. the pace is a scalar quantity because it has the most effective course and no importance. For the size of the pace in vehicles, speedometers are used. pace also can be calculated with the assistance of a graph. the space-time graph allows know-how of the rate of an object.

In regular use and in kinematics, the rate of an object is the value of the change of its position over the years or the importance of the alternate of its function per unit of time; its miles as a result a scalar amount. the spot pace is the limit of the common pace because the period of the time c program language period approaches 0. pace isn't always similar to velocity.

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Answer:

The surfaces and structures in an urban area can have a significant influence on the urban heat island effect. For example, paved surfaces like roads and buildings absorb more heat than surfaces covered in vegetation, and structures like high-rise buildings can trap and reflect heat, resulting in higher temperatures in the urban area. Additionally, urban areas usually have less vegetation than their rural counterparts, meaning there is less vegetation to absorb heat from the sun and provide shade, further contributing to the urban heat island effect. Evidence of this can be seen in research at louisvilleky.gov/government/sustainability/urban-heat-island-project.

The 3.3kg  is the mass 1 of block 1 .

What is mass ?

The amount of matter in a body is referred to as its mass. The kilogramme is the kilograms, which is the SI unit of mass (kg). Mass is defined as: Mass = Density/Volume.

What is speed ?

The rate of a directionally changing object's location. The SI unit of speed is created by combining the fundamental units of length and time. Meters per second (m/s) is the unit of speed in the metric system.

Therefore, The 3.3kg  is the mass 1 of block 1 .

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The total work done on the mass as it moves from x1 = 0 m to x2 = 40 m is approximately 515.17 J.

What is Work Done?

Work is a physical quantity that describes the amount of energy transferred when a force acts on an object and causes it to move. When a force acts on an object and causes it to move in the direction of the force, work is said to be done on the object. Mathematically, work is defined as the dot product of force and displacement:

Work = Force x Displacement x cos(theta)

To calculate the total work done on the mass as it moves from position x1 to x2, we need to find the net work done by all the forces on the mass. The net work done by a force is given by the formula:

W = F * d * cos(theta)

where W is the work done, F is the force, d is the displacement of the mass, and theta is the angle between the force and the displacement.

First, we can calculate the work done by each force separately and then add them up to find the total work done.

Work done by F1:

W1 = F1 * (x2 - x1) * cos(0) = 5 N * 40 m * cos(0) = 200 J

Work done by F2:

W2 = F2 * (x2 - x1) * cos(50°) = 6 N * 40 m * cos(50°) ≈ 165.41 J

Work done by F3:

W3 = F3 * (x2 - x1) * cos(20°) = 2 N * 40 m * cos(20°) ≈ 74.88 J

Work done by F4:

W4 = F4 * (x2 - x1) * cos(20°) = 2 N * 40 m * cos(20°) ≈ 74.88 J

The total work done on the mass is the sum of the work done by each force:

W_total = W1 + W2 + W3 + W4 ≈ 515.17 J

Therefore, the total work done on the mass as it moves from x1 = 0 m to x2 = 40 m is approximately 515.17 J.

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a. The force required on the small piston to raise a 10 N load on the large piston is 0.403 N.

b.  The load would be raised to a height of 63.13 cm when the small piston has moved 0.1 m.

The formula is F1 / F2 = A2 / A1

where F1 is the force applied on the small piston, F2 is the force exerted on the large piston, A1 is the area of the small piston, and A2 is the area of the large piston.

A1 = (π / 4) * (1 cm)^2 = 0.0079 cm^2

A2 = (π / 4) * (5 cm)^2 = 0.196 cm^2

F1 / F2 = 0.0079 cm^2 / 0.196 cm^2 = 0.0403

F2 = 10 N

F1 = F2 * (A1 / A2) = 10 N * 0.0403 = 0.403 N

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Answer:

net force

Explanation:

Microevolution refers to the evolution occurring at species-level involves three mechanisms that cause allelic frequencies to change in a population: gene flow, genetic drift, and natural selection.

Changes in the environment can affect population gene pools on both a small- and large-scale. Microevolution is the process of population-level changes in allele frequency. Some alterations take place at the species level or lower. There are hence variations in allele frequencies between or within groups.

Natural selection is one of the mechanisms of microevolution. It serves as an editor for allele frequency in populations to determine whether individuals with particular features have a higher or lower chance of surviving and procreating. Populations' gene pools can occasionally shift as a result of individuals leaving or entering the community. This transfer of alleles between populations is referred to as gene flow. Genes can "flow" from one area to another just like water does in a river.

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The speed of the wave that is propagated is 10 meters per second.

A wave is a disturbance or variation that gradually conducts electricity from point to point in a medium and can take the form of elastic deformation or a change in pressure, electric or magnetic intensity, electric potential, or temperature

The speed of a wave is determined by the frequency of the wave and its wavelength. In this case, the child is sending pulses down the rope at a rate of 2 pulses per second, so the frequency is f = 2 Hz.

The distance between the pulses is 5 meters, which is the wavelength of the wave, represented by lambda (λ).

The speed of the wave (v) is given by the formula:

v = f * λ

Substituting the values we have, we get:

v = 2 Hz * 5 m = 10 m/s

Therefore, the speed of the wave is 10 meters per second.

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Answer:

10 revolutions

Explanation:

By using the equation Δ=Δ, we get that Δ=(4.00rad/s)(15.0s)=60.0rad. Since there are 2 radians per revolution, this angular displacement corresponds to (60.0rad)/(2rad/rev)=9.55rev.

The angular velocity of the wheel is 4 rad/s and the time interval is 15 s. Then the number of rotations in radians is 60 radians. This is equal to 9.5 revolutions.

Angular velocity is a physical quantity that describes the speed of an object in an angular path. It is the rotational o revolutional analogue of of the linear velocity.

The angular velocity of an object is the product of the linear velocity and the radius of the angular path.

Given that, the angular velocity of the wheel = 4 rad/s

time  = 15 s

then, number of radians = 4 rad/s × 15 s = 60 radians.

1 revolution  = 2π radians.

then 60 radians = 60/2π = 9.5 revolutions.

Therefore, the number of revolutions for the wheel in 15 s is 9.5 revolutions.

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"Compression of rock is nothing but squeezing the rock together and shearing is pushing the rock in opposing directions."

It squeezes the boulder as a whole and should cause the pulls to shear. This is because compression causes the weight necessary for rocks to be squeezed. Additionally, the rock's draws shouldn't be spaced apart. It shouldn't be going in opposing ways either.

When rocks are compressed together, they fold, fracture, or even shatter. Compression stress is the most prevalent stress at convergent plate boundaries. There is stress when rocks are being torn apart. Under stress, rocks either lengthen or fragment.

Due to the compression pushing the hanging wall up in relation to the footwall, if the fault arises in a scenario of compression, it will be a reverse fault.

Compressional stresses cause a rock to shorten. A rock elongates or pulls apart as a result of tensional pressures. Shear forces cause rocks to slide past one another.

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Objects at rest tend to stay at rest as per the Newton's laws of motion. The correct option is A.

The basic three fundamental laws of classical mechanics referred to as Newton's laws of motion describe the ways in which an object's motion and the forces acting on it interact.

The first statement of Newton's laws of motion, which states that "Objects at rest tend to stay at rest, and objects in motion tend to stay in motion, with not only the same speed but also in the same direction.

It takes place unless acted upon by an external force," will lead the bowl of apples to remain at rest.

This rule, often known as the law of inertia, holds that unless an outside force acts upon an object, it will continue to move uniformly in a straight line or be at rest. Since no force is operating on the bowl of apples, it will continue to be at rest.

Thus, the right response is A.

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Here, when , the reaction quotient is less than the equilibrium constant, then, the reaction will move to the right. In the first set up, the reaction quotient is less than Keq. Then, the reaction moves to right.

The reaction quotient of a reaction is the ratio of molar concentration of the product to the molar concentration of the reactants.

In the first setup.

Keq = 6.16 x 10⁻³

Q = [0.0064]²/[0.098] = 4.18 × 10⁻⁴

Q<K⇒The reaction moved to the right (products)

Setup 2 :

Q = [0.0304]²/[0.150]

   = 6.16 x 10⁻³

Q=K⇒the system at equilibrium

Setup 3 :

Q =  [0.230]²/[0.420]

   = 0.126

Q>K⇒The reaction moved to the left (reactants)

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Answer: products, equilibrium, reactants

Explanation:

its right on edge 2023

The temperature drops as you go higher into the atmosphere because you are moving away from the Earth's surface, where the majority of the planet's heat is generated.

As you move higher, the air pressure and density decrease, and there is less of the Earth's atmosphere to absorb and retain heat. This results in a lower overall temperature.

Additionally, the sun's rays become more intense at higher altitudes due to the lack of air molecules to scatter the sunlight. This can cause a heating effect, but it's usually not enough to offset the cooling effect caused by the decrease in atmospheric pressure.

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Answer:

[tex]2.60\; {\rm m\cdot s^{-1}}[/tex] to the left.

Explanation:

When an object of mass [tex]m[/tex] travels at a velocity of [tex]v[/tex], the momentum of that object would be [tex]p = m\, v[/tex]. Note that since velocity is a vector quantity (has a direction) while mass is a scalar, the direction of momentum would be the same as that of velocity.

Before the collision:

Immediately after the collision:

Momentum is conserved immediately before and after the collision. In other words, the total momentum immediately after the collision would be the same as that immediately before the collision.

In this example, total momentum was [tex](0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}})[/tex] to the left immediately before the collision. Hence, the total momentum immediately after the collision would also be [tex](0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}})\![/tex] to the left.

Subtract the momentum of the blue marble ([tex]0\; {\rm kg\cdot m\cdot s^{-1}}[/tex]) from the total momentum to find the momentum of the red marble:

[tex]\begin{aligned}& (0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}}) - 0\; {\rm kg\cdot m\cdot s^{-1}} \\ =\; & (0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}}) && (\text{to the left}) \end{aligned}[/tex].

Divide momentum by mass to find velocity:

[tex]\begin{aligned} v &= \frac{p}{m} \\ &= \frac{(0.350\; {\rm kg})\, (2.60\; {\rm m\cdot s^{-1}}) }{0.350\; {\rm kg}}&& \genfrac{}{}{0em}{}{(\text{to the left})}{} \\ &= 2.60\; {\rm m\cdot s^{-1}} && (\text{to the left})\end{aligned}[/tex].

Therefore, the velocity of the red marble would be [tex]2.60\; {\rm m\cdot s^{-1}}[/tex] to the left immediately after the collision.