The surface of the pool table is ℎ=0.790 m from the floor.

The winner of the competition wants to know if he has broken the world speed record for the break shot of 32 mph (about 14.3 m/s ). If the winner's ball landed at a distance of =5.05 m from the table's edge, calculate the speed of his break shot 0. Assume friction is negligible.

At what speed 1 did his pool ball hit the ground?

The change in the tension if the radii r changes from 4.0 cm to 4.1 cm, and R changed from 0.8 cm to 0.9 cm is negative, therefore, tension reduces.

Mass of the yoyo = 0.001 kg

Initial value of the spindle radius, R = 4 cm

Initial length of the radius of the yo–yo, r = 0.8 cm

The final values are;

R2 = 4.1 cm, r2 = 0.9 cm

Which gives;

[tex]T_{r \:R} = \frac{0.001 \cdot g \cdot R }{2 \cdot r^{2} + R^2} [/tex]

Which gives;

[tex]T_{{r _1 \:R _1 }} = \frac{0.001 \times 9.8 \times 0.04 }{2 \times 0.008^{2} + 0.04²} = \frac{49}{216} [/tex]

[tex]T_{{r _2 \:R _2 }} = \frac{0.001 \times 9.8 \times 0.041 }{2 \times 0.009^{2} + 0.041^2} = frac{2009}{9215} [/tex]

Therefore;

[tex] \Delta T_{{r \:R }} = frac{2009}{9215} - \frac{49}{216} = - \frac{17591}{1990440} [/tex]

Given that difference between the final and the initial states is negative, the the value of the tension decreases

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2A

Given ,

Resistance=60

V=12

V=IR

I=V/R

I=120/60=2A

The pace at which electrons flow past a location in a complete electrical circuit is defined as current. At its most fundamental, current Means flow.

An ampere (AM-pir), sometimes known as an amp, is the international unit for measuring current. It denotes the number of electrons (also known as "electrical charge") that pass across a location in a circuit over a specific time period.

A current of one ampere indicates that one coulomb of electrons—that is, 6.24 billion billion (6.24 x 1018) electrons—moves across a circuit in one second. The method is comparable to determining how many gallons move through a single spot in a pipe in one minute (gallons per minute, or GPM).

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Answer:

pascal

energy,

power,

electric charge,

Explanation:

The substances that are altered and the chemicals on the right side of a chemical equation are the results of a chemical reaction. B and D are the appropriate choices.

Reactants are the substance(s) in a chemical equation to the left of the arrow. A component that is present at the outset of a chemical reaction is known as a reactant. Products are the substance(s) to the right of the arrow. A substance that remains after a chemical reaction is complete is known as a product. The creation of products from the reaction of two reactants is known as a chemical reaction. The compounds that result from a reaction are called products. The substances that are original materials are the reactants.

On the left side of the reaction are the reactants, and on the right are the products. B and D are the proper choices as a result.

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Answer:

d. 1-proton 2-nuetron 3-electron 4-nucleus

Answer:

the right answer is d

Explanation:

As per the given question;

On a dry day, a mirror or window polished with a dry cloth quickly develops dust. Dry cloth friction on glass produces charged static electricity, which attracts microscopic non-charged dust particles.

Static electricity can cause problems or even pose a risk. Your hair standing on end energy can also destroy electronics and cause explosions. However, it can also be a huge asset to modern life when properly managed and manipulated.

When the positive and negative charges are out of balance, static electricity is produced. While electrons like to jump all over the place, protons and neutrons don't move around that much. A negative charge is present when an object (or person) has extra electrons.

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A. The car's average velocity (in m/s) in the interval between t = 1.0 s to t = 1.5 s is 1 m/s

B. The car's acceleration (in m/s²) at t = 1.5 s is 0.4 m/s²

C. The speed of the car is increasing with time

Average velocity = total distance / total time

Average velocity = 0.5 / 0.5

Average velocity = 1 m/s

We'll begin by calculating the velocity at t = 1.5 s. This can be obtained as follow:

Velocity = Distance / time

Velocity = 0.9 / 1.5

Velocity = 0.6 m/s

Finally, we shall determine the acceleration . This is shown below:

Acceleration = velocity / time

Acceleration = 0.6 / 1.5

Acceleration = 0.4 m/s²

The acceleration we calculated above (i.e 0.4 m/s²) is positive. This simply indicates that the speed of the car is increasing.

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Missing part of the question:

(a) What is the car's average velocity (in m/s) in the interval between t = 1.0 s to t = 1.5 s?

(b) Using data from t = 1.0 s to t = 2.0 s, what is the car's acceleration (in m/s2) at t = 1.5 s?

(c) Is the car's speed increasing or decreasing with time?

The velocity, if the satellite moves to an orbital radius of 4r is V/√4

We know that,

V = √ ( G M / r )

where,

V = Orbital velocity

G = Gravitational constant

M = Mass of the satellite

r = Radius of the orbit

Given that,

r' = 4r

V' = √ ( G M / r' )

V' = √ ( G M / 4r )

V' = ( 1 / √ 4 ) ( √ ( G M / r ) )

v' = v / √ 4

Orbital Velocity is the velocity at which one object revolves around another object in a orbit in uniform circular motion

Therefore, the velocity of the satellite that moved to an orbital radius of 4r is V/√4

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The block's oscillation frequency is 1.1 Hz.

The block's distance from equilibrium when the speed is 57 cm/s  is 14.2 cm.

The block's distance from equilibrium at t = 7.0 s  is 10.37 cm.

The oscillation frequency of the block is calculated as follows;

f = 1/2π√(k/m)

f = 1/2π √(9/0.19)

f = 1.1 Hz

ω = 2πf

ω = 2π x 1.1

ω = 6.91 rad/s

x(t) = A cos(ωt + Φ)

ωX sin(Ф) = v

6.91 x 29 sin(Ф) = 116

sin(Ф) = 116/200.39

sin(Ф) = 0.579

Ф = arc sin(0.579)

Ф = 0.62 rad

29 = A cos(6.91 x 0  +  0.62)

29 = A cos(0.62)

29 = A(0.814)

A = 35.63 cm

when the speed is 57 cm/s, the distance of the block is calculated as follows;

ωX sin(Ф) = v

(6.91)X sin(0.62) = 57

X(4.015) = 57

X = 57/4.015

X = 14.2 cm

x(t) = A cos(ωt + Φ)

x(7) = 35.63 cos(6.91 x 7   +  0.62)

x(7) = 10.37 cm

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bgGjzbxvbhijhFgavvBbzvghzjznbbgzgh

A. The value of x in the given circular geometry is determined as 9.75.

The value of x can be calculated by applying the following rules of geometry as shown below.

angle AC = angle at the center

angle at center = twice angle at circumference

147 = 2(6x + 15)

147 = 12x + 30

147 - 30 = 12x

117  = 12x

x = 117/12

x = 9.75

Thus, the value of x in the given circular geometry is determined as 9.75.

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There are two electrons close to a proton. The proton's potential energy is

the energy possessed by a body by virtue of its position relative to others, stresses within itself, electric charge, and other factors.

9.216 x 10^-8 N

q1 = 1.6 x 10^-19 C

q2 = - 1.6 x 10^-19 C

r = 5 x 10^-11 m

A source of electrostatic force is

F = k q1 q2 / r^2

F = (5 x 10-11)2 / (9 x 109 x 1.6 x 10-19 x 1.6 x 10-19)

F = 9.216 x 10^-8 N

Due to the nature of the charges being in opposition to one another, this force is appealing.

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The coefficient of kinetic friction is determined as 0.75.

The coefficient of kinetic friction is calculated by applying the newton's second law of motion.

Fsinθ - Ff = ma

where;

W = mg

where;

m = W/g

m = 325/9.8

m = 33.2 kg

425 sin(35.2)   -  Ff = 33.2a

425 sin(35.2)   -  μW = 33.2a

at constant velocity, a = 0

425 sin(35.2)   -  μW= 0

μW = 244.98

μ = 244.98/W

μ = 244.98/325

μ = 0.75

Thus, the coefficient of kinetic friction is 0.75.

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The correct answer is :

P = ρgh yields the hydrostatic pressure, which is accurate.

The pressure a liquid applies to nearby bodies when it is at rest is known as hydrostatic pressure.

Water at rest exerts a force known as hydrostatic pressure. It is caused by the water's continual pressure on the basement walls.

The force that blood applies to blood channel walls is a typical illustration of hydrostatic pressure.

Depending on the liquid's density ('ρ'), the height of the water column ('h'), and the acceleration caused by gravity ('g'), the hydrostatic pressure is indicated by the letter "P" of a liquid column.

Because of this, the parameters and the supplied equation P = gh are both accurate.

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100 grams of oil-heated to 80°C are added to 200 grams of water at 20°C. Then the resulting temperature would be 55.48°C.

It can be defined as the form of the energy in which heat is transferred from one body to another body due to their molecular movements, thermal energy is also known as heat energy.

As given in the problem 100 grams of oil (specific heat capacity 2200 J/kg °C) heated to 80°C is added to 200 grams of water (specific heat capacity 4200 J/kg °C) at 20°C

mCΔT for oil =mCΔT for water

100×2200×(80-T) = 200× 4200×(T-20)

1760-22T = 84 T -1680

62T = 1760+1680

T = 55.48°C

Thus, the resulting temperature of the mixture would be 55.48°C.

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Answer:

In a freezer, the air molecules absorb energy from the water, causing the water molecules to freeze into a solid.

Answer: Water expands when it freezes. As freezing continues, the expanding ice under the surface forces the remaining water up through the hole and it freezes around the edge forming a hollow spike

Explanation:

Water expands when it freezes. As freezing continues, the expanding ice under the surface forces the remaining water up through the hole and it freezes around the edge forming a hollow spike. Eventually, the whole thing freezes and the spike is left.

The ball's velocity after it has travelled a total distance of 50.0 meters is 40.63 m/s

The following data were obtained from the question:

We can obtain the final velocity as illustrated below:

v² = u² + 2gh

v² = 25.9² + (2 × 9.8 × 50)

v² = 670.81 + 980

v² = 1650.81

Take the square root of both sides

v = √1650.81

v = 40.63 m/s

Thus, the velocity after travelling 50 m is 40.63 m/s

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The time taken for the train to stop is 8.9 seconds.

The distance traveled by the train during acceleration is 9,984 m.

The distance traveled by the train during deceleration is 17.8 m.

Use the following kinematic equation to determine the time taken for the train to stop.

v = u + at

where;

0 = 4 - 0.45t

0.45t = 4

t = 4/0.45

t = 8.89 seconds = 8.9 seconds

s = ut + ¹/₂at²

where;

s = (4)(480) +  ¹/₂(0.07)(480)²

s = 9,984 m

s = ut + ¹/₂at²

s = (4 x 8.9) + ¹/₂(-0.45)(8.9)²

s = (4 x 8.9) - ¹/₂(0.45)(8.9)²

s = 17.8 m

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According to the given data initial volume =0.667 L

Boyle observed that the product of the pressure and volume are observed to be nearly constant. For a perfect gas, the result of volume and pressure is a precise constant. Boyle's Law is the name given to the relationship among pressure and volume in his honor.

Boyle was a modern chemical pioneer in the 17th century, best known for his law of gases. Robert Boyle (1627–1691) is credited with discovering the renowned Boyle's law, which states that a gas's volume decreases with rising pressure and vice versa

Since the change occurs at constant temperature (i.e. an isothermal change), Boyle's law applies,

i.e. p[tex]_1[/tex]V[tex]_1[/tex] = p[tex]_2[/tex]V[tex]_2[/tex]        where p[tex]_1[/tex] = 125 kPa,  p[tex]_2[/tex] = 200 kPa  and  V[tex]_2[/tex]=0 .5L

Hence,                 (150)V[tex]_1[/tex] = (200)(0.5)

from which,          volume V[tex]_1[/tex] = 200×0.5/150=0.6667L

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Answer:

Displacement

Explanation:

I think Sam's mom isn't worried with how far away he goes, but will be upset if he isn't home fast enough for dinner.

Answer:

I would interpret it to mean:

Vx = (6 - 0) = 6

Vy = (3.5 - 1) = 2.5

or V = (6, 2.5)

V refers to the vector itself and not its relative position in space

The formula for distance = speed * time

60 m/s is the speed.

60 secs is the time.

Fill them in.

distance = 60 * 60

distance = 3600

please give brainliest

Answer:

3600m

Explanation:

s= vt

= 60m/s × 60sec

=3600m

The statement that is true about mass and weight is as follows: Mass must be in kg and weight in N to do our calculations (option E).

Mass is the quantity of matter which a body contains, irrespective of its bulk or volume. The mass of a substance is measured in kilograms.

On the other hand, weight is the force on an object due to the gravitational attraction between it and the Earth. It is measured in Newtons.

The mass of an object is the same everywhere, however, it's weight is dependent on location. For example, the weight of an apple on Earth will differ from it's weight in Mars.

Therefore, the statement that is true about mass and weight is as follows: Mass must be in kg and weight in N to do our calculations.

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The distance covered by the train will be 75 meters.

Physics equations called equations of motion describe how a physical system acts in terms of how its motion alters over time.

The equations of motion, which are a group of mathematical functions stated in terms of dynamic variables, provide a more thorough description of how a physical system behaves.

Given that a train changes its velocity from 70km / h to 20km / h in 6 s.

Use the first equation of motion:-

V= U + at

20 = 70 + ( 1 / 600)a

-50 = ( 1 / 600)a

a = -30000

Use another equation of motion:-

V² = u² + 2as

20² = 70² + 2 ( -30000)S

400 - 4900 = -60000S

-4500 = -60000S

S = -4500 / -60000

S = 0.075 KM

S = 75 meters

Therefore, the distance covered by the train will be 75 meters.

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Answer:

he intellectual and practical activity encompassing the systematic study of the structure and behaviour of the physical and natural world through observation and experiment.

According to the research, the correct option is to refine the original solution design. It is the last part of the technological design process.

It is the process and problem solving using design as a methodological strategy that allows identifying and solving a problem through inductive procedures and logical reasoning.

In this sense, the last part of this process includes what refers to the production of a first model of the solution, which is tested to evaluate its performance, the result of this evaluation must influence the modification or refinement of the original solution design that is implemented in the solution of the problem that gave rise to the generation of the project.

Therefore, we can conclude that according to the research, the correct option is to refine the original solution design. It is the last part of the technological design process.

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A rope competition is played out between four participants. They both pull on the rope to the right while producing forces between 330 N and 380 N. The other two pull to the left with forces of 320 N and 410 N, respectively.

T2 = 250 and T1 = 250.57 [N] .57[N]

In order to create a free body diagram with all the forces acting on the body, we must first extract all the information they provide about the issue.

The free body diagram and associated forces are shown in the accompanying figure.

The T1 and T2 forces can be found by adding up the forces on the Y-axis; these forces are equal because they are a precondition for the problem. Therefore, this equation can be solved.

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The gravitational pull between the sun and Earth decreases if the sun was farther away from the earth.

Any two bodies' gravitational pull on one another is directly proportional to the product of their masses and inversely proportional to the square of their distance from one another.

How do the planets move in relation to the Sun? The planets' orbits around the Sun are maintained by the gravity of the Sun. The Moon orbits the Earth due to the Earth's gravitational pull on the Moon for the same reason. But if the Earth is being drawn to the Sun, why doesn't it fall into it or the Moon strike the Earth?

The cause of this is because Earth moves at a speed that is perpendicular to the Sun's gravitational pull. The planets are thus kept in their designated orbits by the Sun's attraction as well as their sideways motion. Similar to how the Earth orbits the Moon, the Moon does so without touching it.

F=G(M1M2)/R² where,

F denotes gravitational force between two bodies,

R is the distance between two bodies from their center,

M1 denotes mass of first body and,

M2 denotes mass of second body.

So according to the question, if the distance between two bodies will increase, then the gravitational force between them will also decrease.

Hence, if the sun was farther away from earth, then gravitational pull between the sun and earth will decrease.

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