The hydrogens and oxygen of a water molecule are held together by ______ bonds. select all that apply.

2 molecules of three carbon pyruvic acid is formed from one molecule of glucose (6-carbon) at the end of glycolysis. There is a net gain of 8 ATP molecules as a result of glycolysis.

Glycolysis is a cytoplasmic pathway which breaks down glucose into two three-carbon compounds and generates energy. Glucose is trapped through phosphorylation, with the assist of the enzyme hexokinase. Adenosine triphosphate (ATP) is used in this reaction and the product, glucose-6-P, inhibits hexokinase.

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Answer:

Explanation:

a. 82,000

b.Metric unit

Frontward thrust the sternum of a patient with pectus carinatum protrudes forward, forcing the surrounding ribs to slant backward. In the funnel chest, the sternum and surrounding cartilages are visible. The natural anatomical location of the sternum is in the midline and in a straight posture. Barrell chest is characterized by a horizontal sternum and an elevated intercostal angle.

What is pectus carinatum?

The word "pectus carinatum" is used to describe a variety of aberrant protrusions of the front chest wall. Depending on where the deformity is most prominent, it can be either chondrogladiolar or chondromanubrial. Additionally conceivable are lateral abnormalities.Hippocrates noted that persons with the carinatum deformity experienced "difficulty breathing" and had a "sharply pointed chest."

Patients with symptoms describe breathlessness and a reduction in stamina. Some people have chest wall stiffness, increasing emphysema, reduced lung compliance, and more respiratory tract infections.

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09/22/2022

1.07×10³Hz  frequency become if the person's breathing passage were filled with helium instead of air

Here, air temp is taken as 37.0°C if the person's breathing passage were filled with helium instead of air then we find out velocity of sound in the helium. here velocity of sound in the helium for 0°C is 965m/s

formula for velocity of sound in the helium :

Vw he=Vw at 0°C×√T/273

Whereas Vw he=965×√273+37/273  

Vw he=1028m/s

Here we find frequency so fundamental freq=fundamental harmonic no 1(velocity/4(length of tube)

=1(1028/4×0.24)

f=1.07×10³Hz

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When a substance exhibits liquid-crystalline qualities, the change from solid to liquid-crystalline state takes place at the solid's melting point.

What are liquid crystals?

The process of turning a liquid substance into a highly structured solid, with its atoms or molecules arranged in a well defined three-dimensional crystal lattice, is known as crystallisation.

A type of substance known as liquid crystal (LC) has qualities halfway between those of solid crystals and regular liquids. For instance, a liquid crystal's molecules may flow like a liquid while still having a crystal-like orientation.

Crystallized liquid. Liquid crystals are a type of substance known as liquid crystals (LCs) exhibits properties that fall somewhere between those of solid crystals and those of regular liquids. For instance, a liquid crystal's molecules may flow like a liquid while still having a crystal-like orientation.Thus, a substance exhibiting liquid-crystalline characteristics, the conversion from liquid-crystal occurs at the solid's melting point.

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It is false that 3-hydroxybutanal can exist in equilibrium as a cyclic hemiacetal.

Hemiacetal is produced when one molecule of aldehyde and one molecule of alcohol react.

3-hydroxybutanal (see the structure in the picture below) has both carbonyl and hydroxyl group, so it can, theoretically, undergo an intramolecular reaction to form a cyclic hemiacetal in aquatic solution.

Stability of cyclic hemiacetals depends on the size of the ring. Five or six membered rings are generally favored.

If 3-hydroxybutanal form a cyclic hemiacetal, it will have four membered ring, so it will be very unstable. It cannot exist in aquatic solution, while 4-hydroxybutanal can (see the picture below).

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The molality of this solution is 0.165 m.

m(glucose) = 4.92 grams; mass of glucose

V(water) = 165.0 mL; volume of water

d(water) = 1.00 g/mL; the density of water

M(glucose) = 180 g/mol; molar mass of glucose

n(glucose) = m(glucose) / M(glucose)

moles of glucose = mass of glucose / Molar mass of glucose

n(glucose) = 4.92 g / 180 g/mol

n(glucose) = 0.027 mol

m(water) = 1.00 g/mL x 165 mL

m(water) = 165 g = 0.165 kg

molality = number of moles / mass of water

b(solution) = 0.027 mol / 0.165 kg

b(solution) = 0.165 mol/kg; molality of the solution

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There are 0.037 NaOH will be needed to raise the pH 6.09.

Henderson equation, convey the pH of a buffer solution as a purpose of the concentration of the weak acid or base and the salt constituents of the buffer.

Formula of Henderson equation

pH = pKa + log10 ([A] / [HA])

Basic buffer has a basic pH and is get ready by blend a weak base and its salt with powerful acid.

According to Henderson equation pH of basic buffer is:

pH + pNaOH = 5.0

6.09 + pNaOH = 5.0

pNaOH = 5.0 - 6.09

pNaOH =  log(1.09)

pNaOH = 0.037

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A p orbital has two regions or lobes of high electron probability, on either side of the nucleus. This gives the orbital dum-bb-ell shape.

The p - orbital is the atomic orbital consist of two sections called lobes  on either side of plane passing trough nucleus and the shape of p - orbital appears as dum-bb-ell.

The region around the nucleus is where the probability of electron finding is high and called as orbital. The p orbital lobed region is where their is high probability of finding an electron. The probability of finding electron in the nucleus is very low .                

Hence, A p orbital has two regions or lobes of high electron probability, on either side of the nucleus. This gives the orbital dum-bb-ell shape.

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The pH of the diluted solution is 5.53.

Henderson–Hasselbalch equation for buffer solution:

pH = pKa + log(c(CH₃COO⁻)/c(CH₃COOH))

pH = 5.0 ⇒ c(H⁺) = 10⁻⁵ M

pKa = 4.75 ⇒ Ka = 1.78×10⁻⁵

log(cs/ck) =  5.0 - 4.75 = 0.25

c(CH₃COO⁻)/c(CH₃COO⁻) = 10∧(0.25) = 1.778

c(CH₃COO⁻) + c(CH₃COOH) = 0.1 mM

c(CH₃COO⁻) + c(CH₃COOH) = 1 × 10⁻⁴M

c(CH₃COOH) = 3.6x10⁻⁵ M; concentration of acetic acid before dilution

c(CH₃COOH) = 3.6x10⁻⁶ M; concentration of acetic acid after 10 times dilution

c(CH₃COO⁻) = 6.4x10⁻⁵ M; concentration of sodium acetate before dilution

c(CH₃COO⁻) = 6.4x10⁻⁶ M; concentration of sodium acetate after dilution

c(H⁺) = 10⁻⁶ M; concentration of hydrogen ions

After buffer solution is diluted to 1 l:

Ka = (c(CH₃COO⁻) + x) × (c(H⁺) + x) / (c(CH₃COOH) - x)

1.78×10⁻⁵ = (6.4x10⁻⁶ M + x) × (10⁻⁶ M + x) / (3.6x10⁻⁶ M - x)

x = 2.12×10⁻⁶ M

c(H⁺) = 10⁻⁶ M + 2.12×10⁻⁶ M

c(H⁺) = 3.12×10⁻⁶ M

pH = -logc(H⁺)

pH = -log3.12×10⁻⁶ M

pH = 5.53

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Taking into account definition of percent yield, 15 grams of HF are produced if 3.00 g of hydrogen react with excess fluorine with a 25 percent yield.

In first place, the balanced reaction is:

H₂ + F₂ → 2 HF

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 2 grams of H₂ form 40 grams of HF, 3 grams of H₂ form how much mass of HF?

mass of HF= (3 grams of H₂× 40 grams of HF)÷ 2 grams of H₂

mass of HF= 60 grams

Then, 3.00 g of hydrogen react with excess fluorine and it forms 60 grams of HF.

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield=(actual yield÷ theorical yield)×100%

where the theoretical yield is the maximum amount of product that could be formed from the given amounts of reagents.

In this case, you know:

Replacing in the definition of percent yields:

25%=(actual yield÷ 60 grams)×100%

Solving:

25%÷100%= actual yield÷ 60 grams

0.25= actual yield÷ 60 grams

0.25× 60 grams= actual yield

15 grams= actual yield

Finally, 15 grams of HF are produced if 3.00 g of hydrogen react with excess fluorine with a 25 percent yield.

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The type of subatomic particles that can be located within the nucleus of an atom is protons and neutrons. The correct option is C.

Subatomic particles are those particles that are present inside the atoms. These are present in different locations inside the atom. They are charged particles.

An electron is a negatively charged particle that rotates around the nucleus and a neutron is neutral, and a proton is a positively charged particle. Proton and neutrons are present inside the nucleus.

Thus, the correct option is C. protons and neutrons.

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20gm of hydrogen will have highest number of hydrogen atoms.

We know that 1 mole of substance contains atoms equal to Avogadro number i.e.  [tex]6.022*10^{23}[/tex]

As molar mass of hydrogen is 1gm there 1 mole of hydrogen contains 1gm of hydrogen and [tex]6.022*10^{23}[/tex] hydrogen atoms

If we take 1020 hydrogen atoms then it is very less than [tex]6.022*10^{23}[/tex] hydrogen atoms.

In 100gm of substance if hydrogen is 2% by mass i.e. we have 2gm of hydrogen atom  which means 2 mole of hydrogen atoms

Mass of 1 mole of water is 18gm

Thus 100 gm of water have 5.55 moles of water

In 1 mole of water we have 2 grams of hydrogen

Therefore 5.55 moles of water contains 11.11gm of water i.e. 11.11 mole of water

11.11gm of water = [tex]11.11* 6.022 * 10^{23}[/tex] atoms

In 20gm of hydrogen we have 20 mole of hydrogen

               i.e. [tex]20* 6.022 * 10^{23}[/tex]

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U-235 is utilized for fuel for nuclear power plants and the nuclear reactors that run naval ships and submarines

U-238 makes up 99.27% of natural uranium, together with 0.72% of U-235 and 0.005% of U-234. U-235 is the most often used isotope of natural uranium in nuclear power plants, but because it only makes up 0.72% of natural uranium, it must be enriched in order to be used as fuel in these facilities. The U-238 uranium isotope is the most prevalent and the heaviest of the three naturally occurring uranium isotopes. The uranium fuel is put together in a nuclear reactor so that a regulated fission chain reaction may occur. By splitting the U-235 atoms, heat is produced. This heat is then utilized to create steam, which spins a turbine and powers an electricity-generating generator.

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An example of a pair of isotopes of the same element is Hydrogen and Deuterium. They are similar because they have same atomic number and they are different because they have different mass number.

Hydrogen is a chemical element with the atomic number 1. It is represented with symbol H. Mass number of hydrogen is 1. Hydrogen belong to group 1. It belongs to period 1. Hydrogen is s-block element.

Deuterium is isotope of hydrogen. The atomic of deuterium is 1. The mass number of deuterium is 2. It is also known as heavy hydrogen. It is represented as D or 2H.

Thus from the above conclusion we can say that a pair of isotopes of the same element is Hydrogen and Deuterium.

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Mass of kool aid required  is 3.42g to make 0.2 mole solution 1 liter

by the formula of molarity we know that molarity = mole/liter

We can enter those values into the equation to determine the necessary number of moles because we know that we want a 0.1Mole solution in 100 mL so by substituting the values 1/ 0.1= 0.01 moles.

We now know that there are 0.01 moles of Kool-Aid powder. Additionally, we are aware that this powder's chemical composition is c12 h22o11

By multiplying the atomic weight from the periodic table by the quantity of atoms in the compound, we may determine the molar weight of this powder. Let's calculate the powder's molar weight:

Find the carbon atomic weight

12 X 12 =144g

Then we have 22 H's, each having an atomic weight of 1.008g

22 X 11= 22g

And finally there are 11 O's, each with an atomic weight of 16g

16 X11 =176g

by adding the atomic weight of atoms 342.19g

now by finding the grams of kool compound  342.19 X 0.01mol = 3.42g.

now we know that we need 0.01 moles of the powder, and we need 3.42g of the powder to make the desired solution

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Axodendritic type of synapse that occurs between the terminal end of the presynaptic cell and the dendrites of the postsynaptic cell is referred to as which kind of synapse

Synapses are part of the circuits that connect the sensory organs of the peripheral nervous system to the brain. B. People who perceive pain and touch. Synapses connect neurons in the brain to neurons in the rest of the body, and from those neurons to muscles.

A synapse is a small gap between two neurons where nerve impulses are carried by neurotransmitters from the axon of a presynaptic (transmitting) neuron to the dendrites of a postsynaptic (receiving) neuron. It is called the synaptic cleft or synaptic cleft.

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Number if atoms in 259 g of [tex]C_12H_2_1O_9[/tex] is  [tex]5.04*10^{23}[/tex]

We know that according to Avogadro's law , number of atoms in one mole of molecule is [tex]6.022*10^{23}[/tex] .

In given question we have to find number of atoms in 259 g of [tex]C_12H_2_1O_9[/tex]

The molar mass of [tex]C_12H_2_1O_9[/tex] is given that is [tex]309.29 g/mol[/tex]

Therefore total number of moles =  [tex]given mass / molar mass[/tex]

Number of moles                         = [tex]259/309.29[/tex]

                                                       =[tex]0.8374[/tex]

Thus, number of atoms in 0.8374 mole of [tex]C_12H_2_1O_9[/tex] is given by

                                                        = [tex]0.8374 * 6.022 * 10^{23}[/tex]

                                                        = [tex]5.04*10^{23}[/tex]

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The formula selenium tetrafluoride will be SeF4 and the formula of oxygen difluoride will be OF2.

In chemistry, compounds generally take prefixes and suffixes to signify the quantity of a particular atom in the molecule. For example, prefixes such as "tri-" could signify three atoms while prefixes such as "di-" could show two atoms. For suffixes, "-ide" could show anions that are nearly all electronegative.

Let's take the glance at the compound names step by step :

(a) Selenium tetrafluoride - As the compound has the prefix "tetra-" while fluoride method the appearance of a fluorine atom, we can write down the chemical formula as [tex]SeF_{4} .[/tex]

(b) Oxygen difluoride - Here we have second time the identical convention of the compound, now with the prefix di- which shows two fluorine atoms. The chemical formula will be here [tex]OF_{2}[/tex]

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A chemical reaction in which bonds are created is usually associated with The consumption of energy

Consumption method using, shopping for, or consuming something. If we do not lessen our power intake, we are able to run out of fuel. Conspicuous intake is shopping for something to expose off. Consumption is associated with the verb consume, which means to eat, use, or buy.

There are four Consumption kinds of client goods. They are comfort goods, distinctiveness goods, purchasing goods, and unsought goods.

Consumption of Food intake is a periodic behavior. It is brought on at diverse moments of the day through some converging factors (time of day, want a state, sensory stimulation, social context, etc.).

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If a capacitor is overcharged, the electrons from the terrible plate may be pulled through the insulation to the high-quality plate. the capacitor is stated to be shorted.

while you join a capacitor to DC voltage, the capacitor will price to this voltage, and the charging current will drop to zero.

You need to make certain the voltage isn't better than the capacitor’s  Shorting.

On AC, the capacitor will comply with the voltage, w/a put off. again, you need to make sure the voltage rating of the capacitor fits the voltage(In this situation peak voltage).

If the voltage is higher in either case-the capacitor may short.

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Carbon skeletons may vary in shape, length, number, location and strenght of covalent bonds between carbon atoms.

Element carbon is in group 14 of Periodic table of elements.

Electron configuration for carbon: ₆C 1s² 2s² 2p².

Valence electrons are in 2s and 2p orbitals. There is one pair of electrons in 2s orbital and two lone electrons in 2p orbital with the same electron spin.

A carbon atom has four covalent bonds with other carbon atoms in an organic compound.

Carbon also has different type of hybridization (sp, sp2 and sp3).

The strenght of carbon-carbon bond is approximately 350 kJ/mol.

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The potency of acetylcholine after replacing the acetyl group with propionyl or butyrly group decreases.

Its is a organic chemical that function in the brain and body fofmany types of animal ,and humans also as neurotransmitter.

It act as a messenger , that plays a very important role in the central and peripheral nervous system.

The acetylcholine is important for autonomic body functions, muscle control and memory , learning and attention.

Lack of acetycholine cause no contraction in muscles.

Excess of acetylcholine causes cramps , muscular weakness blurry vision, diarrhea etc.

Propionyl or butyryl  is higher homologus group than acetyl , this is the reason the potency will decreases or reduces its activity.

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The  coordinates of B'  is (2,1)​ if the triangle below is reflected across the y-axis .

Hence , option D is correct one .

A reflection is a transformation of the graph of a function over x - axis or the y - axis ( or both ) . The x-coordinate of each point must be negated while reflecting across the Y-  axis, but the  value must remain unchanged .

Each point in a figure is transformed into a reflection by reflecting it over a line. This reflection translates the ABC triangle (A, B, and C) . The outcome is a brand-new figure known as the picture .

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3.08*10^23 ions of Na+ and Cl- will be present in 30g of NaCl.

Weight of NaCl is equal to sum of weight of one mole of sodium and one mole of chloride.

Mathematically, it can be represented as -

1 mol (Na) + 1 mol (Cl)

= 23.0+ 35.5

= 58.5 g/mol

In 58.5  gram of NaCl, there is one mole of Na or 6.02*10^23 ions

In one gram of NaCl, there will be

  =6.02*10^23/58.5 sodium ions

In 30 grams of  NaCl, the number of sodium ions will be -

(6.02*10^23*30)/ 58.5

=3.08*10^23 ions

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Triplet multiplicity would expect in a 1h NMR spectrum for the indicated proton(s).

The spectrum is the invisible radio frequencies that radio signals pass through. These signals let you make phone calls from your mobile device, tag your friends on  call an Uber, and get directions to your destination, all from your mobile device.

Spectrum management is the art and science of managing the use of the radio spectrum to minimize interference and ensure that the radio spectrum is used in the most efficient manner possible for the public good. For USDOT, this focuses on supporting safe, efficient, and economical transportation. Spectrum Networks is a suite of news and sports networks owned and operated by Charter Communications, Inc.

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The distance between the two hydrogen atoms in a molecule of water is 0.000000000172 m,1.72x10 ^-10m is the distance in scientific notation.

Distance is the overall movement of an object, regardless of direction. The distance can be defined as the amount of ground an object has moved, regardless of its start or end point. An object's distance can be defined as the complete distance an object travels. for example. If the car drives 5 km east and then turns 8 km north, the total distance traveled by car is 13 km.

Distance is defined as the distance, or separation, between two objects. An example distance is 5 feet between two tables. An example of distance is the difference between both sides of the problem. noun.

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The density of a material is an intensive property.

An intensive property of matter is one that does not change with the amount of matter. It is a bulk property, which means that it is a physical property that is independent of sample size or mass. An extensive property, on the other hand, is one that is affected by sample size.

Intensive properties are those that are determined solely by the characteristics of the material and not by its quantity - for example, density, temperature, refractive index, color, and pressure. Intensive properties are not additive, which means their value does not change when the amount of material is changed.

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Hydrogen sulfide gas is reacted with dioxygen gas to produce gaseous sulfur dioxide and water. It is false.

When hydrogen sulfide gas reacts with dioxygen gas, it produces water and solid Sulphur and not gaseous sulfur. The chemical equation of the given substances is :

                   2H2S +  O2 → 2S + 2H20

It is a redox reaction as both Oxidation and reduction happens in it. Oxidation of hydrogen sulphur to sulphur happens and reductions of oxygen to water takes place.  

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Density of the unknown metal is 4.82 g/mL

Given,

mass of block is 83 g

When the block was placed in a graduated cylinder containing water, the volume of the block was 17.2 mL.

we have to find density with the help of these two terms,

As we know,

Density = Mass/volume

therefore,

Density = 83 / 17.2

= 4.82 g/mL

thus, density of unknown metal block is 4.82g/mL

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