the GCF of 30m^4 and 36m^6 is 6m^?
the missing exponent is ____

Answers

Answer 1

9514 1404 393

Answer:

  4

Step-by-step explanation:

The exponents of m in the two terms are 4 and 6. The exponent of the common factor can be no greater than the smallest of these. (It is the smallest of these.)

  GCF(30m^4, 36m^6) = 6m^4 . . . . exponent is 4


Related Questions

What single decimal multiplier would you use to decrease by 2% followed by a 7% decrease?

Answers

9514 1404 393

Answer:

  0.9114

Step-by-step explanation:

That multiplier would be ...

  (1 -2%)×(1 -7%)

  = (1 -0.02)(1 -0.07)

  = 0.98×0.93 = 0.9114

If y varies directly as x and as the square of z, and y =25/9 when x=5 and z=1, find y when x =1 and z=4

Answers

Answer:

y= 80/9

Step-by-step explanation:

Given

" y varies directly as x" and "as the square of z" so y = x* z²* some number

if y =25/9 when x= 5, z= 1 and y = x*z²* some number

then 25/9  = 5 * 1² * some number

      5*(5/9) = 5 * some number

therefore y = x* z²* (5/9)

y= ? when x=1 , z= 4

y = x * z² * (5/9)

y = 1 * 4² * (5/9)

y = 16*5 / 9

y = 80/9

Hello, i'm looking for someone to help me with my missing math hw?

Answers

Answer:

Hello! I can help you with it :)

Well, I do not know where you live, so I do not know what nooks and crannies your hm could be hiding.

After 12 years I shall be three times as old as I was 34years ago. Determine my present age

Answers

Answer:

the 34 yrs Is wrong it will be 4yrs only.

Step-by-step explanation:

Let my present age=x years

After 12 years my age=x+12 years

4 years ago my age =x−4 years

According to the question,

x+12=3(x−4)

⇒x+12=3x−12

⇒3x−x=12+12

⇒2x=24

or x= 24/2 =12 years.

∴ my present age is 12 years.

hope this helps you.

Let the present age of let’s say todd be X

Todd’s age (x+12) will be 3 times as old as he was 4 years ago [3(x-4)]

i.e



x+12=3(x-4)
x+12=3x-12

2x=24
X=12.
Hence Todd’s present age is 12.


Please help me!!

The formula to find the kinetic energy of an object measured in joules,E, is E=1/2mv2, where m represents the mass of the object in kilograms and v represents the velocity (or speed) of the object in meters per second. What is the equation to find m in terms of E and v ?

Thank you very much!!

Answers

Answer:

E=1/2mv2, v/10./17

Step-by-step explanation:

i need brainlest <3

if f(x)=4x-2/3 what would f(a+3) be​

Answers

Answer:

it will look like this 4(a+3)-2/3

Step-by-step explanation:

look since the equation "a+3" replaced for the place of "x" in f(x), you replace it on the equation "4x- 2/3" and just solve

Answer:

Step-by-step explanation:

Id..k how to help u sorry

22/7 - 4/7
A)2
B)2 4/7
C)2 5/7
D)3​

Answers

Answer:

None of the option is correct.

The right answer is 18/7 or 2.57

Step-by-step explanation:

Calculus, second derivative. Please help! Show work, if possible please. Thanks! :)

Answers

Answer:

y''=sec^3(x)*csc(x)+sec^2(x)*tan(x)-2cot(x)*csc(x)*sec(x)*tan(x)+cot^2(x)*csc(x)*sec(x)+csc^3(x)*sec(x)

Step-by-step explanation:

we are given y= csc x sec x

We use the rule for multiplying derivatives and the knowledge that the derivative of csc is -csc*cot and the derivative of sec is sec*tan to get

csc(x)*sec(x)*tan(x)+sec(x)*-csc(x)*cot(x)

which simplifies to

csc(x)*sec(x)*tan(x)-sec(x)*csc(x)*cot(x)

Using the same rules again (in tedium so they are not listed but can be inferred) we find the second derivative is

sec^3(x)*csc(x)+sec^2(x)*tan(x)-2cot(x)*csc(x)*sec(x)*tan(x)+cot^2(x)*csc(x)*sec(x)+csc^3(x)*sec(x)

I will give brainliest
How many electrons in an atom can share the quantum numbers n = 2, l = 1, ml = −1?

1
2
3
6

It's not B

Answers

Answer:

Answer is: two electrons.

n - principal quantum number, indicating relative overall energy of each orbital, n=1,2,3,...

l - angular momentum quantum number, shape of the orbital, l = 0,1,...,n−1.      

l =1 for the p orbitals.

ml - magnetic quantum number, ml = 0,±1,...,±l.

This is 2px orbital, in every orbital there is two electrons with different spin.

Step-by-step explanation:

Mark Brainliest Please

A survey asked 50 students if they play an instrument and if they are in band.
1.25 students play an instrument.
2. 20 students are in band.
3. 30 students are not in band.
Which table shows these data correctly entered in a two-way frequency table?

Answers

Answer:

I believe it is D

Step-by-step explanation:

If I am correct please mark Brainlyiest

The table that shows these data correctly entered in a two-way frequency table is:

                    In Band Not in Band Total

Play                   15                10       25

Do Not Play    5               20       25

Total           20               30       50

What is a two-way frequency table?

A two-way frequency table is a way of organizing and displaying data that shows the frequency of occurrences of two categorical variables.

In such a table, the rows represent one variable, the columns represent the other variable, and the cells show the number (or frequency) of times that each combination of categories occurs.

We have,

A two-way frequency table shows how many times each combination of two categorical variables occurs.

In the table, the rows represent the "play an instrument" variable, the columns represent the "are in band" variable, and the totals are shown at the end of each row and column.

The entries in the table represent the frequency, or the number of students who belong to each combination of categories.

In this case, the two variables are "play an instrument" and "are in band". Based on the given information, we can create the following table:

Thus,

The table that shows these data correctly entered in a two-way frequency table is:

                    In Band Not in Band Total

Play                   15                10       25

Do Not Play    5               20       25

Total           20               30       50

Learn more about two-way frequency here:

https://brainly.com/question/31189964

#SPJ7

The ABC manufacturing firm, the average withdrawal rate for product A is 20
cartons per day, safety stock is 5 days, order lead time is 10 days, and the
order quantity is 45 days.

Requirement: What are the maximum and average quantities of unit loads to be
stored? (Please help me solve this exercise in detail about the requirements of the question)

Answers

???????????????????????

Step-by-step explanation:

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Answer:

Answer:J is between H and K. If HJ=6x-5, JK=4x-6 and KH= 129, find the value of HJ

Explanation:J is between H and K. If HJ=6x-5, JK=4x-6 and KH= 129, find the value of HJ

Step-by-step explanation:

mark me as the brainliest

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