The discovery of ribozymes provide evidence that life on the early earth may have been based on:_________

Here is the difference between contact forces and non-contact forces:

Contact forces are forces that result from two objects coming into physical contact with each other. Non-contact forces are forces that result from the interaction of objects that are not in contact with each other.

When the Earth's magnetic field reverses, a new stripe, with the new polarity, begins. Such magnetic patterns led to recognition of the occurrence of sea-floor spreading, and they remain some of the strongest evidence for the theory of plate tectonics.

The specific magnetism of basalt rock is determined by the Earth's magnetic field when the magma is cooling. Scientists determined that the same process formed the perfectly symmetrical stripes on both side of a mid-ocean ridge. The continual process of seafloor spreading separated the stripes in an orderly pattern

With this information, we can conclude that A polarity reversal means that the magnetic North flips to where we know the South Pole is. At the mid-ocean ridge spreading axis.

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The vector v with the given magnitude and the same direction as u. magnitude direction v = 4 u =< 1, 1>

=4/[tex]\sqrt2{^{2} }[/tex] i + 4/[tex]\sqrt2{^{2} }[/tex] j

Vector, in physics, a quantity that has both magnitude and the direction. It is a typically represented by an arrow whose direction is the same as that of the quantity and whose length is proportional to the quantity’s magnitude. Although vector has magnitude and direction, it does not have the position. That is, as long as its length is not changed, vector is not altered if it is displaced parallel to itself.

In contrast to vectors, ordinary quantities that have a magnitude but not a direction are called the scalars. For example, displacement, velocity, and acceleration are vector quantities, while the speed (the magnitude of velocity), time, and mass are scalars.

To qualify as a vector, a quantity having magnitude and direction must also obey certain rules of the combination.

Therefore,

A vector a with given magnitude in the direction of b, is given by:

(||a||.b)/||b||

||u||=[tex]\sqrt{1^{2}+1^{2} }= \sqrt{2^{2} }[/tex]

||v||=4

[4(1+1)]/[tex]\sqrt{2^{2} }[/tex]= 4/[tex]\sqrt2{^{2} }[/tex] i + 4/[tex]\sqrt2{^{2} }[/tex] j

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The position where the package strikes the ground is 136.3m.

Use the following kinematic equation;

h = vt + ¹/₂gt²

179 = 47t  +  ¹/₂(9.8)t²

179 = 47t + 4.9t²

4.9t² + 47t - 179 = 0

solve the quadratic equation using formula method;

a = 4.9, b = 47, c = -179

t = 2.9 seconds

X = vt

X = 47m/s x 2.9 s

X = 136.3 m

Thus, the position where the package strikes the ground is 136.3m.

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What Newton discovered is that  gravity extends throughout the universe.

The term gravity refers to the force that acts on a body in the universe. It is gravity that makes an object to fall when it is thrown up. The force of gravity acts on every object in the universe and it extends through the universe.

Humans have always known about gravity when they fall from a height and when they threw things up. However, human did not know that gravity extends throughout the universe.

Thus, what Newton discovered is that  gravity extends throughout the universe.

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Bulk modulus of Oxygen is 1.44×10^5 Pa

Given:

mass of Oxygen = 39.9 g

volume of Oxygen = 27.9 l

speed of sound in oxygen = 342 m/s

To Find:

Bulk modulus of Oxygen

Solution:

The density of oxygen gas is

ρ = 0.0399/0.0279 = 1.43 kg/m^3

From v = √B/ρ we find

B = v^2ρ

B = (317 m/s)^2 x (1.43 kg/m^3)

B = 1.44×10^5 Pa

Hence, Bulk modulus of Oxygen is 1.44×10^5 Pa

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The fusion of hydrogen nuclei in stars produced all of the helium in the Universe.

However, most stars undergo an internal transformation after turning a considerable percentage of their hydrogen to helium. The interior core compresses and warms up until it is hot enough to fuse helium into bigger atoms, for as by fusing three helium atoms into carbon. At the same time, some helium will combine with the carbon to generate oxygen. Outside the core, in what is known as the envelope, there is still enough hydrogen to fuse into additional helium. However, the center starts fusing heavier nuclei. This, by the way, is the transition from a 'regular' star like our Sun to a Red Giant.

After the red giant phase, the Sun will shed its outer layers, leaving behind a helium-rich core that will gradually cool throughout the course of the Universe. After the red giant phase with stars more massive than the Sun, it becomes practically a free for all for producing heavier and heavier atoms. When the helium in the core runs out, the star collapses again, heats up, and begins fusing carbon and oxygen into bigger atoms. If the star is large enough, this will continue until iron is fused. At such time, a hotter core will still not result in fusion. The star falls, becomes unstable, and explodes, resulting in supernovae and neutron stars (or black hole).

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Charge enter a length of the axon during this process is 1.2544C

CHARGE : It is a physical property of matter that causes it to experience a first, then it placed in between the electromagnetic field.

During the inflow part of a cycle in the neurons approximately

5.6× 10¹¹Na ions per meter,

each with a charge of +e enter the axon.

Therefore, ions will be (5.6 ×10¹¹) × (1.4/100)

                                 =  7.84 × 10⁸  Na ions

Charge of an electron is 1.6 × 10⁻¹⁹Coulombs

Thus; 7.84 ×10⁸ ×1.6 ×10⁻¹⁹

= 1.2544×10⁻¹⁰ coulombs

Charge enter a length of the axon during this process is 1.2544C

The given question is incomplete the complete question is  

How many coulombs of charge enter a 1.4 cm length of the axon during this process?

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The percentage decomposed in the first order reaction is 69.8%.

Given: rate constant, k = 0.00702 sec -1

time, t = 7.1 s

Since the reaction is first order, we calculate using the formula below:

[A] = [A]₀ [tex]$$e^{(-kt)[/tex]

Where; [A] is the final concentration

[A]₀ is the initial concentration

Finding the ratio of final and initial concentration

[A]/[A]₀ =[tex]$$ e^{(-kt)[/tex]

Substituting the values:

[A]/[A]₀ = [tex]e^{(-0.00702 * 7.1)[/tex]

[A]/[A]₀ = [tex]e^{(-0.0498)[/tex]

[A]/[A]₀ = 0.9514

Percentage decomposed = [A]/[A]₀ [tex]*[/tex] 100%

Percentage decomposed = 0.9514 [tex]*[/tex] 100%

Percentage decomposed = 95.1 %

Therefore, the percentage decomposed in the first-order reaction is 95.1 %.

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The rate at which F is decreasing is 0.12 mol / L s

Given that,

2 D(g) + 3 E(g) + F(g) → 2 G(g) + H(g)

Rate of reaction = - ΔD / 2 Δt = - ΔE / 3 Δt = - ΔF / Δt = ΔG / 2 Δt = ΔH / Δt

Given that,

- ΔE / Δt = 0.36 mol / L s

- ΔE / 3 Δt = - ΔF / Δt

- 0.36 / 3 = - ΔF / Δt

- ΔF / Δt = - 0.12 mol / L s

The rate of reaction is the measure of how quickly or slowly that a reaction proceeds.

Therefore, the rate at which F is decreasing is 0.12 mol / L s

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It is false that asteroids were recently formed by the collision and breakup of an object orbiting in the asteroid belt.

Asteroids are stony objects that orbit the sun but are too tiny to be classified as planets. They're also referred to as planetoids or small planets. There are millions of asteroids that range in size from hundreds of kilometers to a few feet. The combined mass of all asteroids is less than that of Earth's moon.

The solar system's makeup is fairly uniform. The combined mass of the planets is substantially less than that of the Sun. The majority of comets have short periods and orbit near the ecliptic plane.

The asteroid belt is a torus-shaped area in the Solar System lying roughly between Jupiter and Mars' orbits. It is home to a large number of solid, irregularly shaped things of various sizes, but far smaller than planets, known as asteroids or minor planets. To distinguish it from other asteroid populations in the Solar System, such as near-Earth asteroids and Trojan asteroids, this asteroid belt is sometimes known as the major asteroid belt or main belt.

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1.22 x 10⁸ nm is the wavelength of radiation.

2.45 x 10⁹ = frequency(v)

3.00 x 10⁸ = speed of light(c)

(3.00 x 10⁸ m/s)/(2.45 x 10⁹ Hz)= 1.22 x 10⁸ nm

1.22 x 10⁸ nm is the wavelength of radiation.

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The time of fall for the two balloons is equal.

Here the conditions given resembles a free fall. Since the air resistance is negligible, gravitational force is the only force acting on both the balloons which means the two balloons are falling in a vacuum. In a vacuum, if two objects of different mass are thrown from the same height, both objects will reach the ground at the same time.

Free fall is nothing but a condition in which an object falls solely under the influence of gravity.

Therefore, the time of fall for both yellow and red water balloons is equal no matter the weight where air resistance is negligible.

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7.4304*10²⁴ molecules water molecules are present in 222.22 ml sample of water ( molar mass =18.01 g/mol).

Mass of water = density * volume

=1.00gm/mμ*222.22mol

=222.22gn

No of moles of water = mass/molar mass

no of water molecules/Avogadro  no.=12.34 mol

no of water molecules= 12.34 mol * 6.022*10²³ mol

=74.304*10²³ molecules

=7.4304*10²⁴ molecules

so, 7.4304*10²⁴ molecules are present in 222.22 ml of water sample

7.4304*10²⁴ molecules.

One or more atoms make up molecules. They may have the same atoms (for example, an oxygen molecule has two oxygen atoms) or different atoms if they have more than one (a water molecule has two hydrogen atoms and one oxygen atom). Proteins and DNA are examples of biological compounds that can contain thousands of atoms.

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The integers can be arranged in the form of 10p - 1 such that p = 1-7 in the was as follows:

10p-1 = (10*1) - 1 = 9 = [tex]3^{2}[/tex] = 3x3

10p-1 = (10*2) - 1 = 19 = [tex]19^{1}[/tex]

10p-1 = (10*3) - 1 = 29 = [tex]29^{1}[/tex]

10p-1 = (10*4) - 1 = 39 = 3x13

10p-1 = (10*5) - 1 = 49 = [tex]7^{2}[/tex] = 7x7

10p-1 = (10*6) - 1 = 59 = [tex]59^{1}[/tex]

10p-1 = (10*7) - 1 = 69 = 3x23

Here we see that not all are in the form of 2^n x 5^m where n and m are non-negative integers.

As per the rule, if A =p/q be a rational number such that p and q are co-prime and the prime factorization of q is not in the form of 2^n x 5^m where n and m are non-negative integers, then A has a decimal expansion which is non-terminating recurring decimal.

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A solution is prepared by adding 1.43 mol of KCL to 889 g of water. The concentration of KCL is 1.61 molal.

Molar concentration, also known as molarity, quantity concentration, or substance concentration, is a unit used to describe the amount of a substance in a solution expressed as a percentage of its volume.

The number of moles per liter, denoted by the unit symbol mol/L or mol/dm3 in SI units, is the most often used unit denoting molarity in chemistry. One mol/L of a solution’s concentration is referred to as one molar or 1 M.

Mol of Kcl (potassium chloride) = 1.43

water = 889 g = 0.889kg

Molality = Moles of solute/kilograms of solvent

So, it comes as m = 1.43/0.889 = 1.61 molal

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The ribbon replaces the menus and toolbars in previous versions. The Ribbon makes available most of the functions that were previously hidden in the File menus.

The ribbon is a command panel that organizes program functions into a series of tabs at the top of the screen. Ribbon tabs consist of groups of closely related commands to help users quickly find the commands they want. Each ribbon is a bar across the page.

The advantages of using the ribbons are:

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The presentation layer is sometimes known as the syntax layer since it is in charge of ensuring that the data it either receives or transmits to other layers has the correct syntax. Data sent across the network is formatted and encrypted by the presentation layer.

The presentation layer, which is layer 6 in the seven-layer OSI model of computer networking, acts as a network's data translator. It is referred to as the syntactic layer at times.

The communication is given to the top layer in a defined format thanks to the presentation layer (Layer 6). It deals with the messages' syntax and meaning. Communication across disparate systems, encrypts messages from the user-dependent format to the common format and vice versa.

The presentation layer, which is located at Layer 6 of the Open Systems Interconnection (OSI) communications architecture, makes sure that all communications passing through it are in the right format for the destination application. In other words, from the application layer's point of view, it provides the data in a comprehensible format.

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F is continuous on (2,5) and the range is provided as a bounded interval

Although not true for all functions listed [2,5], this is conceivable. For instance, the unbounded range of the function f(x)=x3 is (), which is defined and continuous on the interval [2,5].

When a function is specified at each point along an interval without any gaps, leaps, or interruptions, the interval is said to be continuous for that function.

We say that a function f(x) is continuous on the interval [a, b] if it meets these requirements from x=a to x=b, for instance.

At the right endpoint b, a function is continuous if. The reasons why the endpoints are defined individually.

Because only one way can be used to check for continuity, the endpoints are defined independently. The values will not be in the domain and won’t apply to the function if the limit of an endpoint is checked from a side that is outside the domain.

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32.9%, is the percentage of compound left after 6.07 minutes.

We utilize the equation A(t) = A0e-kt for decomposition, where A0 is the beginning amount of the decomposed substance at time t = 0, k is the decay constant, t is the passing of time, and A(t) is the amount at the end of time t.

The original amount, [A0], multiplied by 100 to get [A(t)], or A/A0*100, is the fraction of the decomposed molecule that is still present after time t:

A = A0e-kt

Divide both sides by A0, k = 0.00299, and A/A0 = e-0.00299t.

A/Ao is equal to e-0.00299*372, where

t = 6.2 min*(60 sec/ 1 min)

= 372 sec.

A/A0 = .3288 = 32.9%,

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The analysts at techno infosystems are considering the four-model approach to system development for a new client. if they make use of the four-model approach, the outcome will be the time taken to develop the model increases.

With a commitment to giving Government PSUs, Educational Institutions, and All Organizations across the country a competitive advantage by making current operations efficient & cost-effective, Techno is a brand name of Richa Infosystems Limited, which is working under the government's initiative to support "Vocal for Local."

The speed of techno, a kind of electronic dance music, frequently ranges between 120 and 150 beats per minute and is typically generated for usage in a continuous DJ set. Common time is usually used for the core rhythm, which is frequently distinguished by a repeating four on the floor beat.

Electronic dance music without vocals or a typical popular song structure, with a quick pace and artificial noises.

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A. The frisbee will remain in the air for 5.88 s

B. The horizontal distance the frisbee will go is 29.4 m

The time the frisbee will spend in the air can be obtained as illustrated below:

169.2 = ½gt²

169.2 = ½ × 9.8 × t²

169.2 = 4.9 × t²

Divide both side by 4.9

t² = 169.2 / 4.9

Take the square root of both side

t = √(169.2 / 4.9)

Time = 5.88 s

The horizontal distance travelled by the frisbee can be obtained as follow:

s = ut

s = 5 × 5.88

Horizontal distance = 29.4 m

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The charge of the ion is +3. Because there are 3 extra or +3 when you subtract 83 from 80, bismuth is Bi+3 (plus 3 is the ion charge)

Conventionally, the charge of an electron is thought to be negative; this charge is equal to and opposite to the charge of a proton, which is thought to be positive. Because the total number of electrons in an ion is more than the total number of protons, the net charge of an ion is not zero.

In contrast to an anion, which is negatively charged but has more electrons than protons, a cation is an ion that is positively charged but has fewer electrons than protons.

Electrostatic force causes opposite electric charges to be drawn towards one another, causing cations and anions to attract one another and easily form ionic compounds.

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The resultant voltage is calculated as 0.315 V

It is given that

E = 91.9 mj

Q = 2.91c

V = E/Q

=91.9 x [tex]10^{-3}[/tex] / 2.91

= 31.58 mV

= 0.03158 V

Thus, the resultant voltage is calculated as 0.315 V

The difference in electric potential between two points, which is defined as the work required per unit of charge to move a test charge between the two points, is known as voltage, electric potential difference, electric pressure, or electric tension.

Voltage can also be described as the pressure from an electrical circuit's power source that helps to push the charged electrons (current) through a conducting loop, that enables them to do work such as illuminating a light.

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The correct option is (a)the evening star.

Venus is sometimes called the evening star.

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The force resultant is 10N.

We need to know about force resultant to solve this problem. The force resultant can be described as the sum of force according to the magnitude and direction. It can be written as

∑F = F1 + F2 + .... + Fn

where ∑F is force resultant, F1 is the first force and Fn is the n-force.

From the question above, the parameter given is

F1 = 5 N

F2 = 5 N

Because of the same direction, the force will be added up each other.

∑F = F1 + F2

∑F = 5 + 5

∑F = 10 N

Hence, the force resultant is 10N.

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When modest amounts of strong acids or bases are added to a weak acid (or base), it forms a solution known as a buffer that resists pH changes.

The ammonium buffer, which is an aqueous solution of NH3 (ammonia) and NH4Cl (ammonium chloride), mixed in equal molar ratios, is a typical buffer, as the question implies. This creates an alkaline buffer with a pH of roughly 9.20, or higher than 7. It's interesting to note that as long as your concentrations stay the same, nothing else matters. Since ammonia is a weak base, the equilibrium will be located far to the left:

NH4+(aq) + OH NH3(aq) + H2O(l) (aq)

Additionally, a soluble salt called ammonium chloride will also be present in solution.

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The magnitude of the acceleration of the moon towards the earth is 0.003 [tex]m/s^2[/tex].

The acceleration means the rate with which the velocity of an object changes.

The time the moon takes to complete one revolution, t = 27.3 days = 2358720 s

The distance travelled in circular path, d = [tex]2\pi r[/tex] = [tex]24015\times 10^8[/tex] m

where radius r = [tex]3.844\times 10^8[/tex] m

The formula in circular motion is :

[tex]a=\frac{v^2}{r}[/tex]

[tex]v=\frac{d}{t}[/tex]

So substituting the values:

[tex]a=\frac{(1.024\times 10^3)^2}{3.844\times 10^8}[/tex]

[tex]a\approx 2.8\times 10^{-3} \ m/s^2[/tex]

[tex]\therefore a\approx 0.003 \ m/s^2[/tex]

The value of the acceleration of the moon towards the earth is 0.003 [tex]m/s^2[/tex].

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Answer:

Option C

Explanation:

Initial frequency of rotation ν

i

=1800 rpm =1800/60=30 rps

Thus initial angular frequency w

i

=2πν

i

=60π rad/s

Final frequency of rotation ν

f

=3000 rpm =3000/60=50 rps

Thus final angular frequency w

f

=2πν

f

=100π rad/s

∴ Angular acceleration α=

t

w

f

−w

i

OR α=

20

100π−60π

=2π rad/s

2

The angle in radians is 1/60.

                  [tex]\begin{aligned}\\\small s &= r\theta \\\\\small 1\,cm &=\small 60\,cm\times \theta \\\\\small \theta &=\small \frac{1}{60}\,\text{radians}\end{aligned}[/tex]