Solve for X

A- 68


B- 2


C- 17


D- 34

If 18.1 percent of the solution is acid, 64.07 milliliters of acid are there.

What is a percentage?

As per the question,

18.1 Percent of 357 ml of solution used is acid, therefore,

=(18.1/100)*357

= 64.07 ml of acid

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18018

Given:

Number of cans = 14

Number of cans of carrots = 5

Number of cans of beets = 1

Number of cans of corn = 8

When there are n  objects to be arranged in order, out of which  r1 objects are of one kind,  r2 objects are of another and so on, then the number of different arrangement is given as:

[tex]\frac{n!}{r_{1!*rx_{2 }! }.......r_{n} ! }[/tex]

n=14, r1= 5 ,r2=8

therefore 14!/(5!*8!)

            =18,018

Therefore, the distinct orders in which the cans can be arranged is 18018

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Answer:

Step-by-step explanation:

Solve for x

7/8 of x is 14

7/8x = 14

x = 14 : 7/8

x = 14 * 8/7

x =16

----------------

check

7/8 * 16 = 14

14 = 14

the answer is good

Answer:

1,4

Step-by-step explanation:

7/5

Esto es una división, solo divide y ya

The number of students that score within the range μ ± 2σ is; 190 students

The empirical rule is a tool for finding the ranges that are 1 standard deviation, 2 standard deviations, and 3 standard deviations from the mean, in which you'll find 68, 95, and 99.7% of the normally distributed data respectively.

This means that 2 standard deviations from the mean would indicate that 95% of the students would score within the given range.

Thus, number of students that score within the range μ ± 2σ is;

95% * 200 = 190 students

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The solution by substitution of values to 4 ) is ( - 8 ) / 14 and 6 ) is - 213 .

4 ) Using substituition

By replacing values of c and d in given equation

( 5 [tex]c^{2}[/tex] - [tex]d^{2}[/tex] + 3 ) / ( 2 c - 4 d )

c = - 1 and d = - 4

( 5 [tex]( - 1 )^{2}[/tex] - [tex]( - 4 )^{2}[/tex] + 3 ) / ( 2 ( - 1 ) - 4 ( - 4 ) )

= ( 5 - 16 + 3 )  / ( - 2 + 16 )

= ( - 8 ) / 14

6 ) Using substituition

By replacing values of x and y in given equation

3 [tex]| x + y |^{2}[/tex] - [tex]( x y )^{2}[/tex]

x = 3 and y = - 5

3 [tex]| 3 + ( - 5 ) |^{2}[/tex] - [tex]( 3 * ( - 5 ) )^{2}[/tex]

( 3 * 4 ) - 225

= - 213

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Answer:

The first set is a set of linear equations.

The way to figure this out is pretty easy. If you want to see it visually, go search up desmos graphing calculator and put in these equations.

A linear equation is a function that has a constant slope, meaning that the rate it increases or decreases will never change. The first one is a set of linear equations because it is 2 equations with constant slopes, meaning that the slopes will never change no matter what y and x are.

The second set is not, because while the first equation is linear, the second is an inequality. While it is a straight line, it doesn't count as a linear equation.

The third set, both equations have exponents on the x, which means that the slope will change depending on x. This means that both of these are not linear equations.

The only set that is a linear set is the one that has only linear equations.

Answer: -13 °C.

Step-by-step explanation:

Answer:

4,000

Step-by-step explanation:

Rounding rule:

"4 or less, round down / keep the same."

"5 or more, round up."

Since the hundreds place has a 3, that means we round the thousands place to 4,000, because the hundreds place is lower than 5.

Answer:

The two solutions are

5 and 9

-5 and -9

Step-by-step explanation:

Let x and y be the numbers

x-y = 4

x*y = 45

Using substitution

x = 4+y

(4+y)y =45

4y + y^2 = 45

Subtract 45 from each side

y^2 +4y -45 =0

Factor

(y - 5) ( y+9) = 0

Using the zero product property

y -5 =0    y+9 =0

y=5    y = -9

Now we can find x

y=5

x = 4+y

x =4+5

x=9

y = -9

x = 4+y

x = 4+-9

x = -5

The two solutions are

5 and 9

-5 and -9

The 73rd term of  the arithmetic sequence 18,30,42 = 882.

An arithmetic sequence seems to be a series of numbers that are ordered and share a common difference amongst each succeeding term. There are arithmetic sequences 3, 9, 15, 21, and  27, for example, the common difference is 6. An arithmetic progression is another name for an arithmetic sequence.

The sequence is not arithmetic if the difference between subsequent terms is not constant. Subtracting two consecutive elements from the sequence yields a common difference.

Let us now look for the explicit rule for with this arithmetic sequence. We have the following:

aₙ = a₁ + (n - 1) * d

  = 18 + 12 * (n - 1)

  = 12n + 6.

The 73rd term is 12 (73) + 6 = 882.

The 73rd term of  the arithmetic sequence 18,30,42 = 882.

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Answer: Sue fills 32/3 (Decimal form = 10.6667 containers)

Step-by-step explanation: 8 divided by 3/4 equals 32/3. If you need it in decimal form it's 10.6667

Please heart this or rate it :)

Answer:

10 2/3 containers BUT can only fully fill 10 containers

Step-by-step explanation:

to solve this equation you need to divide 8 by 3/4

8 / 3/4

that is

8/1 / 3/4

when dividing fractions you must flip the second number and multiply both numbers together

8/1 * 4/3

32/3 is your answer

or

10 2/3

she can fully fill 10 containers

Answer: (3, -1)

Step-by-step explanation:

y = |x-3|-1

When y=|x|, vertex is (0, 0).

Now, let's translate the graph so it becomes y = |x-3|-1.

|x| ==> |x-3|         Translate the graph 3 units to the right

Vertex: (0+3, 0) ==> (3, 0)

|x-3| ==> |x-3|-1     Translate the graph 1 unit down

Vertex: (3, 0-1) ==> (3, -1)

Vertex: (3, -1)

The perimeter of the triangle will be 26 + 2c + 20b + 11d.

It should be noted that the perimeter of the triangle will be the addition of all the sides.

This will be:

26 + 5c + 10b + 7d + 4d - 3c

Collect like terms

26 + 5c - 3c + 10b + 11d

= 26 + 2c + 20b + 11d

Therefore, the perimeter of the triangle will be 26 + 2c + 20b + 11d.

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A triangle has side lengths of (26 +5c) centimeters, (10b + 7d) centimeters, and

(4d-3c) centimeters. Which expression represents the perimeter, in centimeters,

of the triangle?

4c + 26d

b + d + 26

26 + 2c + 20b + 11d.

The angle measures are;

Angle 7  is 40° = Angles 8 : supplementary

Angle 3 is 40° = Angles 8: supplementary angles

Angle 5 = 140°  = Angle 8; corresponding angles

Angle 1 = 140°  = Angle 8; corresponding angles

Angle 6 = 40°  = Angle 8; supplementary angles

Angle 2 = 140°  =  Angle 8; corresponding angles

Angle 4 = 140°  Angle 8; corresponding angles

Given that angle 8 measures 140 degrees

It is important to note that angles on a straight line equals 180 degrees

Then,

angle 7 + angle 8 = 180°

Substitute the values of angle 8

Angle 7 + 140 = 180

Angle 7 = 180 - 140

Angle 7 = 40°

Thus, If angle 7  is 40° then angle 3 is 40°, corresponding angles

Angle 5 = Angle 8; corresponding angles

Angle 1 = Angle 8; corresponding angles

Angle 6 = Angle 7; corresponding angles

Angle 2 = Angle 8; corresponding angles

Angle 4 = Angle 8; corresponding angles

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Acasa's expected value loss  be per customer who chooses plan A

Assumption

Fill customers choose plan A

The  average payout is the same for plans A & B

Expected value = net payment in -Net payment out

⇒ 1000% × 700$ - 5% ×[27000$ - 3000$]

⇒ 700$ - 1200$

⇒ -500$

What are a profit and loss?

A profit and loss statement is a record of revenue and expenses incurred by a business in a given period of time. A profit and loss statement is also called a P&L, an income statement, a statement of profit and loss, and income and expense statement, or a statement of financial results.

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The definition of the symbolic statement r → ~s is:

If we go to Venice, then we will not go to Florence.

First, we have to look at the definition of the events.

In this problem, the statement is:

If r then not s.

Considering events r and s, the correct option is:

If we go to Venice, then we will not go to Florence.

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The class width of the histogram is 5000.

It should be noted that the class width is the distance that can be found between the lower limits of consecutive classes.

The range is the difference between the maximum and minimum data entries.

class width of a histogram is given by the equation

Therefore, class width:

= maximum of a class - minimum of a class

In the given histogram, first-class start at 2500 and ends at 7500..Therefore considering first class,.minimum =2500 and maximum=7500.

Therefore, class width will be:

= 7500-2500

= 5000

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The left over sand is a 3/10 bag of the colored sand.

According to the statement

We have to find that the how much sand does she use for the project.

So, For this purpose, we know that the

Left over is a something that remains unused or unconsumed

From the given information:

amber has a 4/5 pound bag of colored sand she use 1/2 of the bag for an art project

then it means

Total sand is = 4/5 pound bag of colored sand

Used sand is = 1/2 of the bag of colored sand

Then

Left over sand is = Total sand - Used sand

Left over sand is = 4/5 - 1/2

Left over sand is = 8 - 5/10

Left over sand is = 3/10.

So, The left over sand is a 3/10 bag of the colored sand.

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The line has a slope of 9 and y-intercept of -9

A linear equation is a equation that has a linear degree of 1.

Given the inequality expression 9x-y<9

Write in slope-intercept form

-y < -9x + 9

y > 9x - 9

From the equation, we can see that the line has a slope of 9 and y-intercept of -9

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Answer:

400 students, 1/8 are left handed

Step-by-step explanation:

Using translation concepts, we have that the table of values for the function p(x) = x - 7 is given by:

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

In this problem, the parent function is:

y = f(x).

A translation down 7 units is represented by a subtraction by 7 in the range, that is:

p(x) = f(x) - 7 = x - 7.

The numeric values to be inserted in the table are given by:

In the graph at the end of the exercise, both functions are shown.

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Answer:

24

Step-by-step explanation:

you multiplied 6 by 2 so you have to multiply 12 times 2 and you will get 24

The square root of one hundred forty is less than one hundred five ninths. So, option D is correct.

According to this question we have to compare the square roots of both numbers One Hundred Forty and One Hundred Five Ninths. So, we have to calculate their square roots.

The square root of One hundred Forty: √140

The square root of One hundred Forty:  11.832

The square root of One Hundred Five Ninths: √159

The square root of One Hundred Five Ninths: 12.609

Comparing both of their square roots we can clearly see that :

           (11.832) < (12.609)

The square root of 140 < Square root of 159

Hence, option D is correct. The square root of 140 is less than 159.

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Answer:

17.7 m

Step-by-step explanation:

57 m / 30 m/s = time in the air = 1.9 s

vertical drop for 1.9 s

 vertical d = 1/2 a t^2 = 17. 7 m

Answer:

===============================

Parallel lines have equal slopes.

Find the slope of the first line, mn:

Find the slope of the second line, ab:

Compare the slopes and find the value of k:

Answer:

[tex]k=\dfrac{3}{2}[/tex]

Step-by-step explanation:

[tex]\boxed{\begin{minipage}{4.3 cm}\underline{Slope formula}\\\\$m=\dfrac{y_2-y_1}{x_2-x_1}$\\\\where $(x_1,y_1)$ and $(x_2,y_2)$ \\ are points on the line.\end{minipage}}[/tex]

Segment MN

[tex]\implies \textsf{slope}=\dfrac{y_N-y_M}{x_N-x_M}=\dfrac{1-0}{5-0}=\dfrac{1}{5}[/tex]

Segment AB

[tex]\implies \textsf{slope}=\dfrac{y_B-y_A}{x_B-x_A}=\dfrac{k-2 \frac{1}{4}}{-2\frac{1}{4}-1\frac{1}{2}}=\dfrac{k-2 \frac{1}{4}}{-2\frac{1}{4}-1\frac{2}{4}}=\dfrac{k-2 \frac{1}{4}}{-3\frac{3}{4}}[/tex]

Parallel lines have the same slope.  

Therefore, equate the found slopes for the two segments and solve for k:

[tex]\implies \dfrac{k-2 \frac{1}{4}}{-3\frac{3}{4}}=\dfrac{1}{5}[/tex]

Cross multiply:

[tex]\implies 5 \left(k-2 \frac{1}{4}\right)=-3\frac{3}{4}[/tex]

[tex]\implies 5k-10 \frac{5}{4}=-3\frac{3}{4}[/tex]

[tex]\implies 5k-11 \frac{1}{4}=-3\frac{3}{4}[/tex]

Add 11 ¹/₄ to both sides:

[tex]\implies 5k-11 \frac{1}{4}+11 \frac{1}{4}=-3\frac{3}{4}+11 \frac{1}{4}[/tex]

[tex]\implies 5k=(-3+11)+\left(-\frac{3}{4}+\frac{1}{4}\right)[/tex]

[tex]\implies 5k=8-\frac{1}{2}[/tex]

[tex]\implies 5k=7\frac{1}{2}[/tex]

Divide both sides by 5:

[tex]\implies 5k \div 5=7\frac{1}{2} \div 5[/tex]

[tex]\implies 5k \div 5=\dfrac{15}{2} \div 5[/tex]

[tex]\implies k=\dfrac{3}{2}[/tex]

Therefore, the value of k for which the two segments are parallel is ³/₂.

Solution :

Repeating or recurring decimals :

Repeating or recurring decimals are those decimal expansions that do not terminate or end after a specific number of digits. Such numbers have an infinite number of digits after the decimal point. And there is a repetitive pattern in those digits.

Decimal numbers can be converted to fractions by dividing the number with a power of 10 which is equal to the number of decimal places. For example, 1.5 = 15/10 = 3/2. But with repeating decimals, it is impossible to count the number of decimal places as it is infinite. So, there are some specific steps to be followed to convert repeating decimals to fractions.

The repeating decimal to fraction steps of conversion are given below:

Step 1: Identify the repeating digits in the given decimal number.

Step 2: Equate the decimal number with x or any other variable.

Step 3: Place the repeating digits to the left of the decimal point by multiplying the equation obtained in step 2 by a power of 10 equal to the number of repeating digits. This way you will get another equation.

Step 4: Subtract the equation obtained in step 2 from the equation obtained in step 3.

Step 5: Simplify to get the answer.

Let us take an example to understand the conversion of repeating decimals to fractions in a better way. Convert 0.77777... to a fraction.

Step 1: We can observe that 7 is repetitive in the given decimal number.

Step 2: Let x = 0.7777...

Step 3: There is only 1 repetitive digit, so multiply this equation by 10. We get, 10x = 7.7777...

Step 4: Subtract x = 0.7777... from 10x = 7.7777... We will get 9x = 7.

Step 5: x = 7/9. Therefore, 0.7777... = 7/9.

Hence,

you multiply 10 by the repeating decimal to make a fraction

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​

The total spent amount on water is $220

The total area is 37.5=75/2

The number of lots is 75/2/3/4=50 nos

Total rent is 50×50=2500

So 3/5 will go to david 2500×3/5=1500

2/5 will go to john 2500×2/5=1000

So 60% Renters choose 100 gallons

Total renters is 50

60% renters is 50×60%=30 nos

40% renters choose 70 gallons

40% of 50 is 20 nos

The tank fills twice

100×30+70×20=4400 to be filled

Per gallon cost is $0.05

So the total cost is 4400×0.5=$220

So they spent $220 on water

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