On a map the distance between two towns is 2.6 cm to scale of the map is 1 cm 50 km what is the actual distance between two

Answers

Answer 1

The answer to this question is:

The actual distance between the two towns = 130 km

Given that according to  the map scale,

Distance between two towns = 2.6cm

Given that the scale of map =

                                           1cm = 50km

So, we are asked to find the actual distance between them.

For finding the distance between two towns, we have to multiply the distance from the map by the scale of the map.

Distance between two towns * scale of the map

= 2.6 * 50 km

= 130 km

Therefore, actual distance between the two towns = 130 km

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Related Questions

Ryan collects rainwater in a barrel for his garden. The barrel is filled with 18 gallons of water. Ryan used 9.7 gallons to water his garden in June and 3 and one eighth gallons in July. How much water is left in the barrel?

24.575 gallons
5.175 gallons
3.168 gallons
3.125 gallons

Answers

The quantity of water left in the barrel is 5.175 gallons. The correct option is the second option 5.175 gallons

Calculating quantity

From the question, we are to determine how much water is left in the barrel

From the given information,

"The barrel is filled with 18 gallons of water"

and

"Ryan used 9.7 gallons to water his garden in June"

After this time,

The quantity of water that would be left in the barrel will be 18 gallons - 9.7 gallons

= 8.3 gallons

Then,

3 and one eighth gallons in July

3 and one eighth = 3 1/8 = 3.125 gallons

The quantity of water that would be left is 8.3 gallons - 3.125 gallons

= 5.175 gallons

Hence, the quantity of water left in the barrel is 5.175 gallons. The correct option is the second option 5.175 gallons

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Answer:

b

Step-by-step explanation:

Evaluate the expression when m= -4
m2 +6m +9

Answers

Answer:

41

Step-by-step explanation:

because if m=-4 that means (-4)2+6(-4)+9=41

asha saves coins in a jar. The table shows how the amount of money was in the jar at the end of every three-month period. A line of best fit for this
ata is B= 0.45m + 1.93.
Month, m
Balance, B
($)
3
6
9
3.24 4.63 5.97 7.26
12
Which value is the best estimate of the amount of money in the jar at the end of the first month?
A $0.45
OB. $1.08
OC. $1.93
OD. $2.3

Answers

If A line of best fit for the data is  B= 0.45m + 1.93. The value that is the best estimate of the amount of money in the jar at the end of the first month is: D.  $2.38.

Best estimate of the amount of money

Given:

B= 0.45m + 1.93.

Where:

m= 1 month (First month)

Hence:

B= 0.45(1) + 1.93

B= 0.45+ 1.93

B=$2.38

Therefore if A line of best fit for the data is  B= 0.45m + 1.93. The value that is the best estimate of the amount of money in the jar at the end of the first month is: D.  $2.38.

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Real number root for V-49

Answers

Step-by-step explanation:

there is no real number solution for the square root of a negative number.

a sqare root multiplied by itself had to deliver exactly the number inside the square root.

so for sqrt(-49), what can be the answer ?

which number multiplied by itself gives -49 ?

it any negative number at that.

because

a × a = a²

and

-a × -a = a² but definitely not -a².

we get a negative number only, when we multiply a positive number with a negative number or vice versa.

the only solution is complex or imaginary (based on the imaginary number i):

i² = -1

i = sqrt(-1)

so, sqrt(-49) = sqrt(49 × -1) = 7×sqrt(-1) = 7i

but again, no real solution.

Calculators were purchased at $100 per dozen and sold at $30 for three calculators. What is the profit on six dozen calculators?
The profit is $

Answers

Answer:

30x100= 3000

Step-by-step explanation:

f (a) = 3a + 2, When
f(a) = 11

Answers

3a+2=11
3a=9
a=3

. . . .

Answer:

3

Step-by-step explanation:

Think of "f(a)" like "y" in this context.   You can set that equal to 11 and solve for a:

f(a) = 3a + 2

11 = 3a + 2

9 = 3a

3 = a

the numbers being multiplied in a product are called

Answers

Answer:factors

Step-by-step explanation:

the numbers being multiplied in a product are called : factors

Last week, a chocolate shop sold 9 ounces of white chocolate. It sold 9 9/10 times as much milk chocolate as white chocolate. How many ounces of milk chocolate did the shop sell?

please answer asap

Answers

Key IdeasWord problemsSolving with fractions

Solving the Question

We're given:

9 ounces of white chocolate sold[tex]9\dfrac{9}{10}[/tex] times as much milk chocolate as white chocolate sold

If the shop sold " [tex]9\dfrac{9}{10}[/tex]  times as much milk chocolate as white chocolate", we must multiply [tex]9\dfrac{9}{10}[/tex] by the amount of white chocolate sold to find the amount of milk chocolate sold.

Multiply [tex]9\dfrac{9}{10}[/tex] by 9 ounces:

[tex]9\dfrac{9}{10}\times9[/tex]

Convert the fraction into an improper fraction:

[tex]=\dfrac{99}{10}\times9[/tex]

Multiply:

[tex]=\dfrac{891}{10}[/tex]

Answer

The shop sold [tex]\dfrac{891}{10}[/tex] ounces of milk chocolate.

Laura is completing a 15-week exercise program where she increases the amount of time she works out by the same amount. She exercised 20 minutes per day the third week, 50 minutes per day the ninth week, and 60 minutes per day the eleventh week.


What is the function that represents the sequence?

Answers

The logical function that represents the amount of workout Laura does in each week along with her simultaneous increase in workout can be given by Arithmetic Progression.

It is represented as An = A + (n-1)d. Here, A represents the first term, or the amount of workout done in first week, d represents common difference or the difference in workout done in next week to its previous week, n represents the number of terms or the number of weeks for which data is to be calculated and An represents the workout done in nth week.

Arithmetic progression refers to the sequence of numbers such that each succeeding number increases with respect to previous number by fixed/ constant value. Thus, there exists constant amount of difference between each consecutive pair of number.

Since, Laura's workout pattern varies such that the amount of workout she does in one week increases by same amount in next week, so we get an arithmetic progression of her workout pattern.

Hence, her workout pattern can be traced as A, A+d, A+2d, A+3A, ..., An.

Thus, An = A + [(n-1)*d]

A3 = A +[(3-1)*d] = A + [2d] = 20 ...(1)

A9 = A +[(9-1)*d] = A + [8d] = 50 ...(2)

A11 = A +[(11-1)*d] = A + [10d] = 60 ...(3)

Solving equation (1) and (2), we get d = 5 and A = 10.

Thus, we conclude by saying that the function of her exercise routine is given by arithmetic progression and the amount of workout that she increases each week is given by 'd' that is 5 minutes.

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What is the slope of y = arcsin(x) when x=0.4?

(You can compute arcsin(x) = sin-1(x) by pressing the “inverse” or “second function key”then pressing the “sin" key. Do this calculation in degrees, so arcsin(1)=90.)

Answers

Answer: about 0.41

Step-by-step explanation:

Use calculator

[tex]arcsin=sin^{-1}x\\\\\boxed{sin^{-1}(0.4) = 0.41151684}[/tex]

Como puedo resolver estas funciones y saber su tipo?

Answers

Comp outdo resolve y veinte y cinco

If the tangent line to y = f(x) at (6, 4) passes through the point (0, 3), find f(6) and f'(6).
f(6) =
f'(6) =

Answers

Answers:

f(6) = 4

f ' (6) = 1/6

===========================================================

Explanation:

f(6) = 4 since the point (6,4) is on the f(x) curve. This is where the tangent is touching.

The tangent line also goes through (0,3)

Let's find the slope of the line through those two points.

[tex](x_1,y_1) = (6,4) \text{ and } (x_2,y_2) = (0,3)\\\\m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\\\\m = \frac{3 - 4}{0 - 6}\\\\m = \frac{-1}{-6}\\\\m = \frac{1}{6}\\\\[/tex]

The slope of the tangent line is 1/6. This is the value of f ' (6) because the derivative measures the tangent at the given x value. It's useful to determine the instantaneous rate of change.

Find the value of x.
(4x12)°
(7x-28)

Answers

The value of x in the angles is 20

How to determine the value of x?

The angles are given as

4x - 12 and 7x - 28

These angles are same side interior angles

So, we have

4x - 12 + 7x - 28 = 180

Collect the like terms

So, we have

4x + 7x  - 12 - 28 = 180

Evaluate the like terms

So, we have

11x  = 220

Divide both sides by 11

x= 20

Hence, the value of x in the angles is 20

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Choose all degrees of rotation that will carry the regular pentagon onto itself.
A. 72°
B. 90°
C. 108°
D. 144°
E. 216°

Answers

Answer:

A. 72°

D. 144°

E. 216°

Step-by-step explanation:

I just answered this.

in short : we rotate each vertex on a circle arc. the center of that circle being P.

so, at the end of every 1/5 of the circle arc there is a vertex of the polygon.

therefore, with every 1/5 of a full circle rotation we move the pentagon visually onto itself.

that is starting at

360/5 = 72°

and then every additional 72°

144°

216°

288°

360°

so, A, D and E are correct

If anyone can help me to solve this!!​

Answers

Answer:

[tex]\begin{array}{|l|l|c|c|c|}\cline{1-5} \textbf{Equation} & \textbf{Standard Form} & \textbf{a} & \textbf{b} & \textbf{c}\\\cline{1-5} \text{1.}\:\:x^2+x=20 & x^2+x-20=0 & 1 & 1 & -20\\\cline{1-5} \text{2.}\:\:4x^2-2x=28 \phantom{)))}& 4x^2-2x-28=0 \phantom{)))}& 4 & -2 & -28\\\cline{1-5} \text{3.}\:\:5x^2=225 & 5x^2-225=0 & 5 & 0 & -225\\\cline{1-5} \text{4.}\:\:x^2-x=36 & x^2-x-36=0 & 1 & -1 & -36\\\cline{1-5} \text{5.}\:\:3x^2-4=7x & 3x^2-7x-4=0 & 3 & -7 & -4 \\\cline{1-5}\end{array}[/tex]

Step-by-step explanation:

Standard form of a quadratic equation:

[tex]\boxed{ax^2+bx+c=0}[/tex]

Question 1

Given:

[tex]x^2+x=20[/tex]

Rearrange to standard form by subtracting 20 from both sides:

[tex]\implies x^2+x -20=20-20[/tex]

[tex]\implies x^2+x -20=0[/tex]

Therefore:

a = 1b = 1c = -20

Question 2

Given:

[tex]4x^2-2x=28[/tex]

Rearrange to standard form by subtracting 28 from both sides:

[tex]\implies 4x^2-2x-28=28-28[/tex]

[tex]\implies 4x^2-2x-28=0[/tex]

Therefore:

a = 4b = -2c = -28

Question 3

Given:

[tex]5x^2=225[/tex]

Rearrange to standard form by subtracting 225 from both sides:

[tex]\implies 5x^2-225=225-225[/tex]

[tex]\implies 5x^2-225=0[/tex]

Therefore:

a = 5b = 0c = -225

Question 4

Given:

[tex]x^2-x=36[/tex]

Rearrange to standard form by subtracting 36 from both sides:

[tex]\implies x^2-x-36=36-36[/tex]

[tex]\implies x^2-x-36=0[/tex]

Therefore:

a = 1b = -1c = -36

Question 5

Given:

[tex]3x^2-4=7x[/tex]

Rearrange to standard form by subtracting 7x from both sides:

[tex]\implies 3x^2-4-7x=7x-7x[/tex]

[tex]\implies 3x^2-4-7x=0[/tex]

[tex]\implies 3x^2-7x-4=0[/tex]

Therefore:

a = 3b = -7c = -4

5 divisible my 3 and 9

Answers

Answer:

5 is not divisible by 3 and 9 .

Round the decimal to the given place value.

124.123474
hundred-thousandth

Answers

Answer: 124.12347

Step-by-step explanation:

Pls help it’s due soon

Answers

The movie lasted 1 hour and 30 minutes

Mustafa's soccer team is planning a school dance as a fundraiser. The DJ charges $200 and decorations cost $100.
The team decides to charge each student $5.00 to attend the dance. If n represents the number of students attending
the dance, which equation can be used to find the number of students needed to make $1,500 in profit?

Answers

Answer:

Step-by-step explanation:

Mustafa's soccer team is planning a school dance as a fundraiser. The DJ charges $200 and decorations cost $100.

The team decides to charge each student $5.00 to attend the dance. If n represents the number of students attending

the dance, which equation can be used to find the number of students needed to make $1,500 in profit?

Answer:

Step-by-step explanation:

This article is about the basic inequality {\displaystyle z\leq x+y}{\displaystyle z\leq x+y}. For other inequalities associated with triangles, see List of triangle inequalities.

Three examples of the triangle inequality for triangles with sides of lengths x, y, z. The top example shows a case where z is much less than the sum x + y of the other two sides, and the bottom example shows a case where the side z is only slightly less than x + y.

In mathematics, the triangle inequality states that for any triangle, the sum of the lengths of any two sides must be greater than or equal to the length of the remaining side.[1][2] This statement permits the inclusion of degenerate triangles, but some authors, especially those writing about elementary geometry, will exclude this possibility, thus leaving out the possibility of equality.[3] If x, y, and z are the lengths of the sides of the triangle, with no side being greater than z, then the triangle inequality states that

{\displaystyle z\leq x+y,}z\leq x+y,

with equality only in the degenerate case of a triangle with zero area. In Euclidean geometry and some other geometries, the triangle inequality is a theorem about distances, and it is written using vectors and vector lengths (norms):

{\displaystyle \|\mathbf {x} +\mathbf {y} \|\leq \|\mathbf {x} \|+\|\mathbf {y} \|,}\|\mathbf {x} +\mathbf {y} \|\leq \|\mathbf {x} \|+\|\mathbf {y} \|,

Please explain this

Determine the domain and range of the graph

Answers

Domain : x is element of R
Range: y is an element of [2,infinty]

Stretched 1 cm beyond its natural length, a rubber band exerts a restoring force of magnitude 2 newtons. Assuming that Hooke's Law applies, answer the following questions:

(a) How far will a force of 3 newtons stretch the rubber band?

(b) How much work does it take to stretch the rubber band this far?

Answers

A) The distance that a force of 3 newtons would stretch the rubber band is; 0.015 m

B) The amount of work it takes to stretch the rubber band this far is; 0.0225 J

How to solve Hooke's Law?

From Hookes's law, as long as the elastic limit is not exceeded the extension is directly proportional to the force applied.

F = Ke

Where;

F = force

K = force constant

e = extension

Thus,  for a restoring force of magnitude 2 newtons ;

2 N = K(1 × 10⁻²) m

K = 2 N /(1 × 10⁻²) m

K = 200 N/m

a) For a force of 3 newtons, we have;

3N = 200 N/m × a

Where a is the extension in meters

a = 3N/200 N/m

a = 0.015 m

b) The formula to find the work done is;

P.E = ¹/₂Ke²

P.E = ¹/₂ * 200 * 0.015²

P.E = 0.0225 J

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What is the slope of the line represented by the equation y = -x +?
0-1/2
HELP

Answers

in the equation y= -x-1/2

the slope is -1/1 which can also be shown as -1.

Find the value of x.
to
75°
125°

x =

Answers

Answer:

USE AIR MATH!!

Step-by-step explanation:

hope that helps

Evaluate
3(x+4)(x+1)
(x+2)(x-2)
for x = 4.

Answers

Answer:

1440

Step-by-step explanation:

3(4+4)(4+1)(4+2)(4-2)

3*8*5*6*2

1440

If Thomas has 92 donuts and the box requires 3 donuts each box, once each donut is put in the boxes how many donuts would be left over?

Answers

Answer:

2

Step-by-step explanation:

Take 92 and divide by 3

3*30 = 90

92-90 = 2

There are 2 donuts left over

What inequality is shown by a number line that shows 12 to the right of −2?

Answers

The inequality shown by a number line which describes that 12 is to the right of -2 is; 12 > -2.

What inequality is shown by the number line that shows that 12 is to the right of 2?

It follows from the task content that the inequality which represents the number line as described in the task content is to be determined

On this note, it follows that since, numbers are arranged from left to right in increasing order on the number line, then;

Since 12 is to the right of -2, the inequality which represents the situation is; 12 > -2.

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Use units to help you answer the question. If​ necessary, round your answer to two decimal places.
An acre is equal to​ 43,560 square​ feet, and there are 5280 feet in a mile. If a farm has the shape of a rectangle measuring 0.9 miles by 1.5​ miles, what is the area of the farm in​ acres?

Answers

The area of the farm in acres is 864 acres.

How to find the area of a farm?

An acre is equal to​ 43,560 square​ feet, and there are 5280 feet in a mile.

Therefore,

1 mile = 5280 feet's

The farm has the shape of a rectangle measuring 0.9 miles by 1.5​ miles. Therefore, let's convert to feet's

1 mile = 5280 feet's

0.9 miles = ?

cross multiply

length = 0.9 × 5280 = 4752 feet

1 mile = 5280 feet's

1.5 miles = ?

width = 1.5 × 5280 = 7920 feet's

Hence,

area of the farm = 4752 × 7920

area of the farm = 37635840

Therefore, the area of the farm in acres can be calculated as follows:

43560 ft = 1 acre

37635840 ft = ?

cross multiply

area of farm = 37635840 / 43560

area of the farm = 864 acres.

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Identify a pattern in each list of numbers. Then use this pattern to find the next number.

5, 12, 33, 96, 285, ___

Answers

Answer:  852

=====================================================

Explanation:

The given sequence is 5, 12, 33, 96, 285, ...

The jump from 5 to 12 is +7The jump from 12 to 33 is +21The jump from 33 to 96 is +63The jump from 96 to 285 is +189

The sequence of increases is: 7, 21, 63, 189

Then notice,

The jump from 7 to 21 is "times 3"The jump from 21 to 63 is also "times 3"The jump from 63 to 189 is also "times 3".

Assuming this pattern keeps up, the next increment will be 189*3 = 567

We add this increment to the last term of the original sequence

285+567 = 852

The sequence is now 5, 12, 33, 96, 285, 852, ...

16 40/50 in decimal form

Answers

[tex]\huge\textsf{Hey there!}[/tex]

[tex]\mathsf{16 \dfrac{40}{50}}[/tex]

[tex]\mathsf{= \dfrac{16\times50 + 40}{50}}[/tex]

[tex]\mathsf{= \dfrac{800 + 40}{50}}[/tex]

[tex]\mathsf{= \dfrac{840}{50}}[/tex]

[tex]\mathsf{= 840\div50}[/tex]

[tex]\mathsf{= 16.8}[/tex]


[tex]\huge\textbf{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\mathsf{16.8}}\huge\checkmark[/tex]


[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]


~[tex]\frak{Amphitrite1040:)}[/tex]

Please type the answers please help

Answers

Answer:

Step-by-step explanation:

哇,我喜歡吃很多食物,因為我喜歡並喜歡它。

Wa, wǒ xǐhuān chī hěnduō shíwù, yīnwèi wǒ xǐhuān bìng xǐhuān tā.

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