The amount of charge built up on your fingertip is approximately 10.08 x 10^-5 C.
How did we get the value?The spark length of 2 cm is equal to the breakdown field strength in air, so the electric field strength between your fingertip and the doorknob is 3 x 10^6 N/C.
The electric potential difference between the two points is given by the equation:
V = Ed
Where V is the potential difference, E is the electric field strength, and d is the distance between the two points.
In this case, d is equal to 2 cm, so we can calculate the potential difference:
V = (3 x 10^6 N/C) x (2 cm) = 6 x 10^6 N m/C = 6 x 10^6 V
Next, we can calculate the charge q on your fingertip using the formula:
q = CV
Where C is the capacitance of your fingertip.
The capacitance of a sphere is given by the formula:
C = 4πε_0r
Where C is the capacitance, ε_0 is the permittivity of free space, and r is the radius of the sphere.
The diameter of your fingertip is 1.59 cm, so the radius is 0.795 cm. Plugging these values into the formula for capacitance, we get:
C = 4πε_0 * 0.795 cm = 4π * 8.85 x 10^-12 * 0.795 cm = 1.68 x 10^-11 F
Finally, we can calculate the charge on your fingertip by plugging in the values for q and C into the equation:
q = C x V = 1.68 x 10^-11 F x 6 x 10^6 V = 10.08 x 10^-5 C
So the amount of charge built up on your fingertip is approximately 10.08 x 10^-5 C.
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A natural-gas pipeline with a diameter of .220 m delivers 1.44 m^3 of gas per second. What is the flow speed of the gas?
A natural-gas pipeline with a diameter of .220 m .The pipeline's gas flows at a speed of approximately 38.00 m/s.
How can the gas's speed be determined?We need to divide the gas's volume flow rate by the pipeline's cross-sectional area to determine the gas's flow speed in the pipeline. The given volume flow rate is 1.44 m3/s. The following formula can be used to determine the pipeline's cross-sectional area:
A = π × r²
A is the cross-sectional area
π is approximately equal to 3.14
r is the radius of the pipeline (half of the diameter)
Substituting the diameter of the pipeline into the formula for the radius:
r = d / 2
r = 0.220 m / 2
r = 0.110 m
A = π × r²
A = 3.14 × (0.110 m)²
A = 0.0381 m²
Now that we have the cross-sectional area of the pipeline, we can divide the volume flow rate by the area to find the flow speed:
v = Q / A
v = 1.44 m³/s / 0.0381 m²
v = 38.00 m/s
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the earth has a much larger mass than the moon. how many moons would it take to equal the mass of earth?
Answer: 81 1/2 moons would be needed to equal the amount of mass of Earth
Explanation:
the temperature of the filament of an incandescent lightbulb is 2800 k. treating the filament as a blackbody, determine the fraction of the radiant energy emitted by the filament that falls in the visible range. also, determine the wavelength at which the emission of radiation from the filament peaks
The peak wavelength of radiation from a 2800 K incandescent bulb is 1.035 μm, outside the visible range. Most energy is infrared.
The fraction of the radiant energy emitted by the filament that falls in the visible range can be calculated using Wien's displacement law and the Stefan-Boltzmann law.
Wien's displacement law states that the peak wavelength of the radiation emitted by a blackbody is inversely proportional to its temperature. The formula is:
peak wavelength = constant / temperature
where the constant is approximately equal to 2.898 × [tex]10^(-3)[/tex] meters-kelvin.
Substituting the temperature of the filament (2800 K) into the formula, we get:
peak wavelength = 2.898 × [tex]10^(-3)[/tex]m-K / 2800 K = 1.035 × [tex]10^(-6)[/tex] meters
This means that the peak wavelength of the radiation emitted by the filament is in the infrared range, and is not visible to the human eye.
The fraction of the radiant energy emitted by the filament that falls in the visible range can be approximated by integrating the Planck radiation law over the visible spectrum (approximately 400-700 nm) and dividing by the total radiant energy emitted by the filament. The formula for the radiant flux density emitted by a blackbody is:
radiant flux density = σ[tex]T^4[/tex]
where σ is the Stefan-Boltzmann constant ([tex]5.67 *10^(-8) W/m^2-K^4[/tex]) and T is the temperature of the filament in kelvin.
Integrating this formula over the visible spectrum, we get:
radiant flux in visible range = ∫(400 nm to 700 nm) [2πh[tex]c^2 / λ^5[/tex]] / [exp(hc/λkT) - 1] dλ
where h is Planck's constant, c is the speed of light, and k is the Boltzmann constant.
Evaluating this integral gives the radiant flux in the visible range. Dividing this by the total radiant flux emitted by the filament (which is just σ[tex]T^4[/tex]), we can find the fraction of the radiant energy emitted by the filament that falls in the visible range. This calculation is quite involved, and would require numerical integration, but in general, only a small fraction of the energy emitted by a filament at 2800 K falls in the visible range. Most of the energy is emitted in the infrared and ultraviolet ranges.
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I put a velocity of 5m/s up on a 2kg mass on a spring with a k value of 150N/m. What is the PE of the spring at the maximum, and what is the amplitude? What is the T?
The PE of the spring at the maximum is [tex]375J[/tex] and Temperature T is [tex]0.907s[/tex]
The potential energy of the spring at the maximum is the elastic potential energy. This is equal to the work done on the spring (the product of force and displacement) and is given by the equation:
[tex]PE =\frac{ 1}{2}kx^2[/tex], where k is the spring constant, and x is the displacement.
In this case, the displacement is equal to the amplitude of the spring, given by the equation:
[tex]A = (\frac{v^{2}}{k})^{1/2}[/tex], where v is the velocity.
Substituting this into the equation for PE, we get:
[tex]PE =\frac{ 1}{2}k(\frac{v^{2}}{k})^{2 }\\\\=\frac{ 1}{2}kv^{2}[/tex]
Plugging in the values for k and v given in the question, we get [tex]PE = \frac{1}{2}*150N/m*(5m/s)^2\\ \\PE= 375J.[/tex]
The equation provides the spring's duration:
[tex]T = 2\pi (m/k)^{1/2}[/tex]
where m is the mass of the object.
Substituting the values for m and k given in the question, we get:
[tex]T = 2\pi(\frac{2kg}{150N/m})^{1/2}\\\\ T= 0.907s.[/tex]
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A. 36,000 Joules
B. 73,000 Joules
C. 146,000 Joules
D. 292,000 Joules
Option B is correct.
Kinetic energy is the energy that a body possesses as a result of its movement. Potential energy is the energy that a body possesses as a result of its location or state.
While an object's kinetic energy is relevant to the state of other items in its environment, potential energy is fully independent of its surroundings. As a result, the acceleration of an item is not visible in the movement of a single object when other objects in the same environment are also moving.
Here potential energy is being used so work done will be mgh
Where,
M = mass
G = acceleration due to gravity
H = height
Since there is no change in kinetic energy,
So,
W1/W2 = mgh1/mgh2
Now, here mass and acceleration due to gravity are the same
Therefore,
W1/W2 = h1/h2
W2 = 0.5 × 146000J = 73000J
Therefore, the work done to lift the block halfway to the top is 73,000 joules.
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in the book example concerning the figure above, a force of 0.086 n from an external agent was required to keep the rod moving at a constant speed. suppose the light bulb in the figure is unscrewed from its socket. how much force would now be needed to keep the rod moving at a constant speed? justify your answer.
The correct answer is 0 N.
There will be no current in the rod and thus no magnetic force resisting the motion. Without any resistance, it will keep moving until acted on by an outside force according to Newton's first law.
What is motion?
Numerous physical systems, including objects, bodies, matter particles, matter fields, radiation, radiation fields, and radiation particles, as well as curvature and space-time, are affected by motion. One can also talk about how borders, shapes, and pictures move. A physical system's configuration or locations continuously changing in space is what is often meant by the term "motion." For instance, one can discuss the motion of a wave or a quantum particle, where the configuration is made up of the probabilities that the wave or particle would occupy particular places.To know more about motion, click the link given below:
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oil droplets may gain electrical charges as they are projected through a nozzle. which quantity of charge is not possible on an oil droplet?
Electric charge is not possible on an oil droplet
How do charged oil drops form?
When radiation (such as X-rays) ionizes the area between the metal plates, electrons from the air attach to the falling oil droplets and give them a negative charge.
They could only gain or lose electrons, which are the only charged particles. The "elementary charge" of an electron is 1.60 • 10-19 C, and it is present on every electron. Therefore, any oil droplet's charge needs to be a multiple of this quantity. Due to their typically low conductivity, lubricants can act as insulators in transformers and switches. Oils can conduct electrical current, though. Their conductivity is influenced by a number of variables, including as the base oil, additives, and polarity.
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the ________ is perhaps the most dramatic force now shaping our world.
The technology is perhaps the most dramatic force now shaping our world.
The rapid pace of technological advancement, driven by the emergence of new technologies such as artificial intelligence, machine learning, big data, and the internet, is arguably the most dramatic force shaping our world. This digital revolution has transformed the way we live, work, and communicate with one another, ushering in a new era of unprecedented connectivity and information exchange. With the rise of e-commerce and online marketplaces, the digital revolution has also brought about a significant shift in global economic power, as more and more businesses move to the online sphere. The digital revolution has also transformed our societies and political systems, as social media has become a powerful tool for activism and political mobilization.To know more about forces visit:
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If a 240 volt voltage source is connected to a wire with 10
ohms of resistance, what is the current?
If a 240 volt voltage source is connected to a wire with 10 ohms of resistance, then the current is 24 amp.
Given data as per the question is:
Voltage given - 240 V
Resistance = 10 ohm
The formula to be used in such numerical is,
V=IR --------------------- (A)
where V in the equation is the voltage, I in the equation is the current and R in the equation is the resistance.
Substituting the values in the equation (A)
240=I(10)
I= 240/10 = 24 amp
The current is 24 amp.
The formula V=IR is the ohm's law. The current which is flowing through the wire is directly proportional to the potential difference applied across its ends of it ,provided that the temperature and all the other physical conditions of the wire like stresses and strains remains absolutly constant.
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Which gas has the highest average kinetic energy?
Nitrogen and helium have the highest average kinetic energy because they are maintained at the highest temperature.
Kinetic energy is the energy possessed by molecules in motion. Average kinetic energy corresponds to the total kinetic energy of the molecules of a gas. Now, as temperature has a direct influence on the motion of the particles in a gas, it therefore, influences the average kinetic energy. Thus, nitrogen and helium, when at 100° C, have the highest average kinetic energy.
We can now say that hotter objects tend to have greater average kinetic energy and also the higher temperatures, and vice-versa. The average energy of the gas particles impacting the container walls grows as the temperature rises. The force the particles per unit area apply to the container is known as pressure. Pressure must increase as the temperature does.
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Two friends are playing with a toy telephone. Which of the points P,Q and R will vibrate if one of the friends speak into the cup? Justify your answer
The point that will vibrate the most when one of the friends speaks into the cup is point Q as vibration dampens and energy is lost due to friction.
In a toy telephone, sound is transmitted through a string that connects two plastic cups. When one person speaks into one cup, the sound waves vibrate the cup, which in turn vibrates the string and causes the other cup to vibrate as well.
Assuming that the string is held taut, the vibration of the cups will depend on the placement of the points P, Q, and R, as shown in the figure. If the string is not taut, the cups may not vibrate at all, or the vibrations may be too weak to transmit the sound effectively.
Point P is located at the midpoint of the string, and it will not vibrate much because the two cups are attached to it and there is no space for it to move.
Point Q is located at one end of the string, and it will vibrate the most when one of the friends speaks into the cup. This is because the cup will vibrate the string, and the vibration will be transmitted all the way to the other end of the string, where point Q is located.
Point R is located between P and Q, and it will vibrate to some extent, but not as much as point Q. This is because the vibration will be damped as it travels along the string, and some of the energy will be lost due to friction.
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What is the magnitude of the acceleration of a skydiver who is currently falling at one-half his eventual terminal speed?
When a skydiver jumps out of a plane, the force of gravity causes the skydiver to accelerate toward the ground. However, as the skydiver falls, the air resistance or drag increases, which eventually balances the gravitational force, and the skydiver reaches terminal velocity, where the acceleration becomes zero.
What is gravitational force?Gravitational force is the attractive force that exists between any two objects in the universe that have mass. This force is directly proportional to the mass of the objects and inversely proportional to the square of the distance between them.
Gravitational force is one of the fundamental forces of nature, and it plays a crucial role in determining the motion of objects in the universe. For example, the gravitational force of the Earth on an object determines the object's weight, which is the force that the object exerts on the ground.
The formula for calculating the gravitational force between two objects is given by:
F = G * (m1 * m2) / [tex]r^{2}[/tex]
Where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.
The gravitational constant, denoted by G, is a physical constant that is used to relate the gravitational force to the masses of the objects and the distance between them. It has a value of approximately 6.67 x 10^-11 N * [tex]m^{2}/kg^{2}[/tex]
The gravitational force is always an attractive force, meaning that it pulls objects together. This is why the Earth's gravitational force attracts all objects towards its center and keeps them in orbit around it. The force of gravity also plays a key role in the motion of planets, stars, and galaxies, as well as in the formation of the universe itself.
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0.68 m/s² is the magnitude of the acceleration of a skydiver who is currently falling at one-half his eventual terminal speed.
What is gravitational force?Gravitational force is the attractive force that exists between any two objects in the universe that have mass. This force is directly proportional to the mass of the objects and inversely proportional to the square of the distance between them.
Gravitational force is one of the fundamental forces of nature, and it plays a crucial role in determining the motion of objects in the universe. For example, the gravitational force of the Earth on an object determines the object's weight, which is the force that the object exerts on the ground.
The formula for calculating the gravitational force between two objects is given by:
F = G * (m1 * m2) /
Where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between them.
The gravitational constant, denoted by G, is a physical constant that is used to relate the gravitational force to the masses of the objects and the distance between them. It has a value of approximately 6.67 x 10⁻¹¹ N *
The gravitational force is always an attractive force, meaning that it pulls objects together. This is why the Earth's gravitational force attracts all objects towards its center and keeps them in orbit around it. The force of gravity also plays a key role in the motion of planets, stars, and galaxies, as well as in the formation of the universe itself.
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the depth of water in tank oscillates sinusoidally once every 6 hours. if the smallest depth is 7.6 feet and the largest depth is 10.4 feet, find possible formula for the depth in terms of time in hours assume that at the water level is at the average of the depth and is rising
The water level is not rising at t=0, then we need to add a phase shift term to formula to account for initial position of oscillation.
Depth of water in tank oscillates sinusoidally once every 6 hours and the smallest depth is 7.6 feet and largest depth is 10.4 feet,
d(t) = A sin (ωt + φ) + C
[tex]A = (10.4 - 7.6)/2 = 1.4[/tex]
[tex]C = (10.4 + 7.6)/2 = 9[/tex]
Substituting these values:
d(t) = 1.4 sin (π/3 t) + 9
d(t) = 1.4 sin (π/3 t) + 9
This formula assumes that water level is at the average of the depth and rising at t=0, as stated in the problem. If water level is not rising at t=0, then we would need to add a phase shift term to the formula to account for the initial position of the oscillation.
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The Density Of Mercury Is 13600 Kg/M3 At 0 OC. What Would Its Density Be At 166 OC? Coefficient Of Volume Expansion For Mercury Is 182x10-6(O C)The density of mercury is 13600 kg/m3 at 0 oC.What would its density be at 166 oC?Coefficient of volume expansion for mercury is 182x10-6(o C)
The density of mercury at 166 °C would be approximately 13203 kg/m³.
What is the density of a substance?A substance's density is a physical characteristic that indicates how much mass there is per unit volume. In other terms, it is a measurement of how close together a substance's particles are packed. The density equation is:
Mass / Volume equals density.
Where an object's volume is the amount of space it takes up and its mass is the amount of substance it contains.
Depending on the measurement system being used, the units for density may vary. The unit of density in the International System of Units (SI) is kilograms per cubic meter (kg/m3). However, additional measurements can also be made, such as grams per cubic centimeter (g/cm3) or pounds per cubic foot (lb/ft3).
To calculate the density of mercury at 166 °C, we can use the following formula:
ρ2 = ρ1 / [1 + β (T2 - T1)]
where:
ρ1 = 13600 kg/m³ is the density of mercury at 0 °C
β = 182 x 10^-6/°C is the coefficient of volume expansion for mercury
T1 = 0 °C is the initial temperature
T2 = 166 °C is the final temperature
Substituting these values into the formula, we get:
ρ2 = 13600 kg/m³ / [1 + (182 x 10^-6/°C) x (166 °C - 0 °C)]
ρ2 = 13600 kg/m³ / [1 + (182 x 10^-6/°C) x (166 °C)]
ρ2 = 13600 kg/m³ / 1.030012
ρ2 = 13203 kg/m³
Therefore, the density of mercury at 166 °C would be approximately 13203 kg/m³.
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Solve problems 1 and 2.
Answer:
both questions are B
Explanation:
I observed the photo and I saw two Bs circled in the photo. Hope this helps!
a 50-kilogram child running at 6 meters per second jumps onto a stationary 10-kilogram sled. the sled is on a level frictionless surface. 9. calculate the speed of the sled with the child after she jumps onto the sled. [show all work, including the equation and substitution with units.]
Based on height and weight, the BMI calculates a person's leanness or corpulence and attempts to quantify tissue mass.
What is BMI?It is frequently used as a broad indicator of a person's body weight in relation to their height.
According on the range the value falls within, a person is classified as being underweight, normal weight, overweight, or obese based on the value received from the BMI calculation.
These BMI ranges are sometimes further broken down into subgroups like severely underweight or very severely obese, depending on variables like geography and age. Despite the fact that BMI is an imperfect indicator of healthy body weight, it is a useful tool for determining if a person is overweight or underweight.
Therefore, Based on height and weight, the BMI calculates a person's leanness or corpulence and attempts to quantify tissue mass.
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The speed of the sled with the child after she jumps onto the sled is 5 m/s.
What is conservation of momentum?We can use conservation of momentum to solve this problem, which states that the total momentum of a system is conserved in the absence of external forces. Since there are no external forces, the total momentum before and after the child jumps onto the sled should be the same.
The initial momentum of the system is:
[tex]p_i = m_child * v_child = (50 kg) * (6 m/s) = 300 kg m/s[/tex]
The final momentum of the system is:
[tex]p_f = (m_child + m_sled) * v_final[/tex]
where [tex]v_final[/tex] is the speed of the sled with the child after she jumps onto the sled.
Since momentum is conserved, we can equate the initial and final momenta:
[tex]p_i = p_f[/tex]
Substituting the values of [tex]p_i[/tex] and [tex]p_f[/tex], we get:
[tex]m_child * v_child = (m_child + m_sled) * v_final[/tex]
Solving for[tex]v_final,[/tex] we get:
[tex]v_final = (m_child * v_child) / (m_child + m_sled)[/tex]
Substituting the values of [tex]m_child, v_child,[/tex] and [tex]m_sled[/tex] , we get:
[tex]v_final = (50 kg * 6 m/s) / (50 kg + 10 kg) = 5 m/s[/tex]
Therefore, the speed of the sled with the child after she jumps onto the sled is 5 m/s.
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A 5 kg box is attached to a spring that has an elastic coefficient of 110 N/m. The spring is compressed to a distance of 0. 65 meters. What is the velocity of the box after it is released from the spring?
The required velocity of the box after it is released from the spring is 5.35 m/s.
The mass of the box m is given as 5 kg.
Elastic coefficient k is given as 110 N/m.
Compression of the spring x is given as 0.65 m.
We know the expression for force as,
F = k x
where,
k is the elastic coefficient
x is the compression in spring
Entering the values we have,
F = k x = 110 × 0.65 = 71.5 N ----(1)
Force is nothing but the tension in the spring which is given by the expression,
F = T = 1/2 m v² = 1/2 (5)v² = 2.5 v² ----(2)
Equating (2) and (1), we have,
2.5 v² = 71.5
v² = 28.6
v = 5.35 m/s
Thus, the velocity of the box after it is released from the spring is 5.35 m/s.
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Which scenario shows how to use collaborative learning to explore potential energy?
Answer:
Members of a team work together to create a plan, and then members choose different tasks to carry out the plan.
a close inspection of an electric circuit reveals that a 480 ohm resistor was inadvertrently soldered in the place where a 350 ohm resistor is needed. how can this be fixed without removing anything from the exsiting circuit?
A resistance of 140 ohm is needed to be added in parallel connection with 480 ohm resistor to fix the existing circuit.
It was revealed in the close inspection of an electric circuit that a 480 ohm resistors was inadvertently soldered in the place where 350 ohm resistor was needed.
Now because the 480 ohm resistor cannot be removed we have to fix the existing circuit by adding an another resistance in parallel with the 480 ohm resistance to make it equal to 350 ohm.
So, we write, let us say we added R in parallel,
1/350 = 1/R + 1/480
R = 1400ohm.
So, we need to add a 1400 ohm resistor in the existing circuit.
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What is the specific heat of a 3. 78 kg object that absorbs 678 J as the temperature increases by 4. 25 K?
The specific heat of a 3. 78 kg object that absorbs 678 J is 42.2 J/(kg-K).
As per the given information in the question:
Specific heat = 3.78 kg
Absorption of the object = 678 J
Temperature increase = 4.25 K
Specific heat has units of J / (kg C).
Substituting the values in the formula,
Specific Heat = 678 / 3.78 kg * 4.25 C) = 42.2 J/(kg-K)
The specific heat is defined as the amount required to raise the temperature of a unit mass of a substance by 1 degree Celsius.
This is expressed mathematically as
Q= mc∆T
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the tractor pull a sled loaded with wood (total weight 14700) a distance 20 malong a level ground the total wokndone on the sled is 10 kj. Suppose the sled's internal speed is 2.0
9968.4 Joule is the correct answer .
What is speed ?
In physics, "speed" typically refers to the rate at which an object moves or travels through space is measured in units of distance per unit of time, such as meters per second (m/s) or miles per hour (mph). The speed of an object can be calculated by dividing the distance traveled by the time it took to travel that distance. In addition to speed, physics also considers other concepts related to the motion of objects, such as velocity (which includes the direction of motion), acceleration (the rate of change of velocity), and momentum (the product of an object's mass and velocity.
Weight = w = 14700N
s = 20m
F = 5000N
Friction force = f = 3500N
THETA = 36.9
s = 20m
Work done by Horizontal force = 3998.4*20 = 79968.4 Joule
Work done by frictional force = -3500 *20 =- 70000Joule
Work done by vertical force = 0
Total work done = 79968.4-70000 = 9968.4 Joule
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The robot arm is elevating and extending simultaneously. At a given instant. theta = 30 degree, theta with dot = 10 deg/s = constant, l = 0.5 m, i = 0.2 m/s, and l with dieresis = -0.3 m/s2. Compute: express v right words arrow and a right words arrow in terms of unit vectors I with Hat and j with Hat. the magnitudes of the velocity v and acceleration a of the gripped part P.
The velocity of the gripped part P is -0.4i_hat + 0.293j_hat m/s, and the acceleration is -0.05i_hat - 3.93j_hat m/s^2. The magnitude of the velocity is 0.5 m/s, and the magnitude of the acceleration is 3.93 m/s^2.
What is tangential acceleration?Tangential acceleration is the component of acceleration that is parallel to the instantaneous velocity of an object moving along a curved path. It represents the rate of change of the magnitude of the velocity vector of the object. Mathematically, the tangential acceleration at any instant is given by the formula:
a_t = r * d²(theta)/dt²
To compute the velocity and acceleration of the gripped part P, we can use the equations for velocity and acceleration of a particle in planar motion:
v = v_i + a_t, where v_i is the initial velocity and a_t is the tangential acceleration a = a_t + a_n, where a_n is the normal acceleration
First, let's find the position of the gripped part P at the given instant. We can use the law of cosines to find the length of the arm:
l² = i² + 2ilcos(theta) + l² cos(theta) = (l² + i² - l²)/(2il) = (i²)/(2il) = 0.2/(20.5) = 0.2
Therefore, theta = arccos(0.2) = 78.46 degrees.
Next, let's find the position vectors of the gripped part P at the given instant. We can use the polar coordinates of P:
r = l theta = theta x = rcos(theta) = 0.5cos(78.46) = 0.13 m y = rsin(theta) = 0.5sin(78.46) = 0.47 m
Now, let's find the velocity vector v. We can find the tangential acceleration using the formula:
a_t = ld^2(theta)/dt^2 = l(-0.3)*cos(theta) = -0.15 m/s^2
Therefore, the velocity vector is:
v = v_i + a_t = ltheta_dot(-sin(theta)*i_hat + cos(theta)j_hat) + (-0.15(-sin(theta)*i_hat + cos(theta)j_hat)) = (-0.25(-sin(30)*i_hat + cos(30)j_hat)) + (-0.15(-sin(30)i_hat + cos(30)j_hat)) = (-0.4i_hat + 0.293j_hat) m/s
The magnitude of the velocity is:
|v| = sqrt((-0.4)^2 + (0.293)^2) = 0.5 m/s
Next, let's find the acceleration vector a. We can find the normal acceleration using the formula:
a_n = l × (d^2(theta)/dt^2)sin(theta) = -0.30.5×sin(78.46) = -0.145 m/s^2
Therefore, the acceleration vector is:
a = a_t + a_n = (-0.15*(-sin(30)*i_hat + cos(30)j_hat)) + (-0.145sin(78.46)*cos(30)i_hat + (-0.145sin(78.46)sin(30) - 9.81)j_hat) = (-0.05i_hat - 3.93j_hat) m/s²
The magnitude of the acceleration is:
|a| = √((-0.05)² + (-3.93)²) = 3.93 m/s²
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A positive charge is located at the center of a cube. a. Are the intersections of the field lines with a side of the box uniformly distributed across that side? Explain. b. We can consider the left side of the box as composed of many small surface elements of equal area.i. Is the number of field lines through surface element A greater than, less than, or equal to the number of field lines through surface element B? Explain. ii. Is the flux through surface element A greater than, less than, or equal to the flux through surface element B? Explain. c. Consider the surface element A itself as composed of many even smaller pieces. Would the number of field lines through each of those new small surface elements vary much from one to another? Explain. Describe how the field lines for the positive point charge appear to be distributed when the region over which you look becomes sufficiently small.
a. The intersections of the field lines with a side of the cube are not uniformly distributed due to the symmetry of electric field lines that converge near the corners of the cube.
b. i. The number of field lines passing through surface element A and surface element B is the same due to the symmetry of electric field lines.
ii. The flux passing through surface element A and surface element B is equal due to the relationship between flux and the number of field lines.
c. The element will be roughly the same, but as the surface area becomes smaller, the number of field lines passing through each element will become increasingly random and difficult to predict.
What does symmetry of electric field mean?
The symmetry of an electric field refers to the property that the electric field at a point in space is the same regardless of the direction in which it is measured. In other words, if you rotate the coordinate system or change the direction in which you are measuring the electric field, the electric field will have the same magnitude and direction.
For example, the electric field generated by a point charge is spherically symmetric, meaning it has the same magnitude and direction at all points on a spherical surface centered on the charge. This is because the electric field lines emanate radially from the charge in all directions, and the magnitude of the field decreases with the square of the distance from the charge. The symmetry of the electric field can simplify calculations and help predict the behaviour of charges in electric fields.
a. The intersections of the field lines with a side of the cube are not uniformly distributed across that side. This is because the electric field lines emanate from the positive charge in all directions, and as they approach the sides of the cube, they bend and converge toward the corners of the cube. Therefore, the electric field is stronger near the corners of the cube, and the field lines are more closely spaced there. This means that the density of field lines intersecting a given surface area on the cube will be greater near the corners than it is elsewhere.
b. i. The number of field lines through surface element A is equal to the number of field lines through surface element B. This is because the electric field lines emanating from the positive charge are symmetrical in all directions. Therefore, if we consider a small area element on the left side of the cube (such as surface element A), the same number of field lines will pass through that element as will pass through an equal area element on the opposite side of the cube (such as surface element B).
ii. The flux through surface element A is equal to the flux through surface element B. This is because the flux is proportional to the number of field lines passing through a given area, and as stated in (b.i), the number of field lines passing through equal area elements on opposite sides of the cube is equal.
c. If considering the surface element A itself as composed of many even smaller pieces, the number of field lines passing through each small surface element will be roughly the same. This is because the electric field lines are symmetrical and emanate from the point charge in all directions, and so the field lines will be distributed fairly uniformly over the surface area of the element. However, as the surface area of each small element becomes very small, the number of field lines passing through each element will become increasingly random and difficult to predict, due to the statistical nature of electric field lines.
When the region over which looked becomes sufficiently small, the field lines for the positive point charge appear to be radially distributed, emanating from the charge in all directions like the spokes of a wheel. The closer we look to the charge, the more tightly spaced the field lines will become, until they appear to converge toward the charge itself.
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can a negatively-charged electroscope be used to determine whether an object is positive or negative? explain.
Indeed, through a method known as induction, a negatively-charged electroscope can be used to identify whether an object is positive or negative.
When a negatively-charged object is brought near the electroscope, the negative charges in the electroscope will be repelled by the negative charges on the object, and move to the far end of the electroscope. This will leave the near end of the electroscope with a net positive charge.
If the object is then brought into contact with the electroscope, some of the negative charges on the object will flow onto the electroscope, neutralizing the positive charge on the near end of the electroscope. However, some of the negative charges on the object will remain on the far end of the electroscope, leaving a net negative charge on the electroscope.
At this point, the electroscope has a negative charge that is due in part to the negative charges on the object. If the object is then moved away from the electroscope, the negative charges on the far end of the electroscope will be less strongly repelled, and will move back towards the near end of the electroscope. This will leave the near end of the electroscope with a net positive charge again, but the charge will be less than the original positive charge. The net charge on the electroscope after this process will depend on the initial charge on the object. If the object is positively charged, it will attract negative charges to the near end of the electroscope, leaving a net negative charge on the electroscope. If the object is negatively charged, it will repel negative charges to the far end of the electroscope, leaving a net negative charge on the electroscope.
Therefore, by observing the final charge on the electroscope after this process, one can determine whether the object is positive or negative.
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a plane flies 72 x 105 m north and then another 15 x 105 m west in a total time of 6 h. the magnitude of your average velocity for the entire trip is
A plane flies 72 x 105 m north and then another 15 x 105 m west in a total time of 6 h. the magnitude of your average velocity for the entire trip is 340 m/s.
Displacement = [(72 x 10⁵]² + [15 x 10⁵]²
= 10⁵ x √72² + 15²
= 10⁵ x √5.409
= 73.545 x 10⁵
Time = 6 hours = 6 x 3600 sec
Velocity = 73.545x10⁵/36x6x100
V= 0.34044 x 10³
V = 340.49
V = 340 m/s
Magnitude of average velocity is 340 m/s.
The terms haste and speed give us an idea of how fast or decelerate an object is moving. relatively frequently, we come across situations where we need to identify which of the two or further objects is moving briskly. One can fluently tell the faster of the two if they're moving in the same direction on the same road. still, if their direction of stir is in the contrary direction, also it's delicate to determine the fastest.
In similar cases, the conception of haste is helpful. In this composition, let us learn the haste meaning, the unit of haste, the illustration of haste, and the difference between speed and haste.
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An elevator suspended by a cable is descending at constant velocity SU Previous Answers ✓ Correct Part B Name these forces Check all that apply. Thrust Fehru Tension T Gravity Fc Normal forcen Force of motion Function Submit Bequest Answer Provide Feedback HE Type here to search G DALL
Since the elevator is moving at a constant speed, the only forces acting on it are gravity and the tension force that the rope that pulls it up places on it.
What does elevator cable tension mean?
Total tension is equal to the weight plus the force of acceleration when lift is upward. Total tension equals the difference between weight and force caused by acceleration as lift decreases.
The force communicated through a rope, string, or wire when two opposing forces draw on it is known as tension. The tension force draws energy equally on the bodies at the end and is applied along the length of the wire.
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In which state of matter, do the particles have the maximum energy?
A
Solid
B
Liquid
C
Gas
D
None of these
a solid ok thank you
hope it helps
The full range of frequencies of electromagnetic radiation is called
A. Visible light
B. Radio waves
C. The electromagnetic spectrum
D. Invisible radiation
The full range of frequencies of electromagnetic radiation is called the electromagnetic spectrum. So, the correct answer is C.
The electromagnetic spectrum includes all types of electromagnetic radiation, including visible light, radio waves, microwaves, infrared radiation, ultraviolet radiation, X-rays, and gamma rays. Each type of electromagnetic radiation has a different frequency and wavelength, and they all travel at the speed of light in a vacuum. Each type of electromagnetic radiation has a unique wavelength and frequency, which determine its properties and the way it interacts with matter. Radio waves have the longest wavelength and the lowest frequency in the electromagnetic spectrum, followed by microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.
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Write down the equation needed to calculate the charge flow
The equation needed to calculate the charge flow Q = I x t
The formula can be utilised to compute current.The electric current,
,in a wire can be found using the formula
=/,
where represents an amount of charge that passes a point in the wire over some amount of time, .
Electric current is the movement of an electric charge. Amperes are the units used to measure electric current. The ampere has the unit sign A.
When studying electricity, both coulombs and amperes are frequently utilised, but it's vital to keep in mind that they measure distinct things. Charge is measured by the coulomb, while the flow of charge is measured by the ampere.
One coulomb of charge passes a spot in a wire in one ampere of current in one second.
Any amount of time can be used to gauge how much charge is transferred; just that it cannot exceed one second.
Simply dividing a charge's amount by the length of time it was measured yields current.
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Your boss has assigned you the task to make a ball appear red. You have the following available to accomplish the task:
• a ball that appears white in white light that can be turned either ON or OFF
.
.
red, green, and blue lights.
cyan, magenta, and yellow filters
Describe at least three ways that you can make the ball look red.
Here are three ways to make the ball look red:
Use a red light: Shine a red light directly onto the white ball while the ball is in the ON position. This will cause the ball to reflect only the red light and appear red.
What of the other response?In regards to the Use a magenta filter: Shine a white light onto the white ball while the ball is in the ON position, and place a magenta filter in front of the light source. This will cause the ball to reflect both red and blue light, which will combine to create the appearance of red.
Lastly, Combine green and blue light with a yellow filter: Shine a white light onto the white ball while the ball is in the ON position, and use green and blue lights to illuminate the ball. Place a yellow filter in front of the ball, which will absorb the green and blue light and allow only red light to pass through. This will create the appearance of a red ball.
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