Answer:
this is actually
Explanation:
6 points
Answer:
helppppp
Explanation:
Bonus points for helpers
If a 70 kg. skater acted upon by an unbalanced force of 161 N [West], what is
its acceleration?
According to Newtonʼs Second Law of Motion:
F net = m x a
or
a = F net / m
Acceleration = net Force/ Mass = 161 / 70 = 2.3 m/s^2 [W]
If a 70 kg skater is acted upon by an unbalanced force of 161 N [West], his acceleration would be 2.30 m/s² towards the west
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
The mathematical expression for Newton's second law is as follows
F = m*a
where F represents the force applied
m is the mass of the object
a is the acceleration of the object
As given in the problem If a 70 kg. skater acted upon by an unbalanced force of 161 N
F =ma
By substituting the values of the force and the mass as 161 N and 70 kg respectively
161 N = 70×a
a= 2.30 m/s²
Thus, If a 70 kg skater is acted upon by an unbalanced force of 161 N, his acceleration would be 2.30 m/s² towards the west
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10. Four forces act on a hot-air balloon, shown from
the side in the figure below. Find the magnitude and
direction of the resultant force on the balloon.
enollsugano
mu
5120 N
1520 N
nomina
coat
950 N
Bideo
bi
biswerwobler
SI
vo
4050 N
The resultant of the four forces on the balloon is 1,212.35 N at 62⁰.
The given parameters;
Force applied to the north = 5120 NForce applied to the west = 1520 NForce applied to the east = 950 NForce applied to the south = 4050 NThe resultant vertical force is calculated as follows;
[tex]F_y = 5120 \ N - 4050 \ N\\\\F_y = 1,070 \ N[/tex]
The resultant horizontal force is calculated as follows;
[tex]F_x = 1520 \ N - \ 950 \ N\\\\F_x = 570 \ N[/tex]
The resultant of the four forces is calculated as follows;
[tex]F = \sqrt{F_y^2 + F_x^2} \\\\F = \sqrt{(1,070)^2 + (570)^2} \\\\F = 1,212.35 \ N[/tex]
The direction of the force is calculated as follows;
[tex]\theta = tan^{-1} (\frac{1070}{570} )\\\\\theta = 62^0[/tex]
Thus, the resultant of the four forces on the balloon is 1,212.35 N at 62⁰.
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what is the difference between reproducibility and repeatability
Answer:
Repeatability is how much variability in the measurement system is caused by the measurement device. Reproducibility is how much variability in the measurement system is caused by differences between operators.
I NEED HELP I AM SO CONFUSED, WILL GIVE BRAIN.
A man is on a 30m cliff and throws a ball down with a speed of 7 m/s.
A) With what velocity does the ball hit the ground? B) How high above the ground is the ball after the ball has fallen for 1 second?
Answer:
210
Explanation:
A ball rolls horizontally off the cliff at a speed of 30 m/s. It takes 7 seconds for the ball to hit the ground. What is the height of the cliff and the horizontal distance traveled by the ball?
S = (1/2)*9.8 m/s^2 * 7^2 = 240.1 m if the ball is very dense so air resistance, and therefore terminal velocity, can be ignored.
S = v * t = 30 m/s * 7 s = 210 m for the horizontal distance, again assuming negligible air resistance.
Height above the ground is the ball after the ball has fallen for 1 second is 210 m.
What is speed?The speed of an object is the magnitude of the change of its position over time or the magnitude of the change of its position per unit of time; it is thus a scalar quantity.
A ball rolls horizontally off the cliff at a speed of 30 m/s. It takes 7 seconds for the ball to hit the ground.
S = (1/2)*9.8 m/s² * 7² = 240.1 m if the ball is very dense so air resistance, and therefore terminal velocity, can be ignored.
S = v * t = 30 m/s * 7 s = 210 m for the horizontal distance, again assuming negligible air resistance.
Height above the ground is the ball after the ball has fallen for 1 second is 210 m.
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How do interaction forces act on different masses and on different objects?
Dosen't make sense
Explanation:
TRUE - Two colliding objects will exert equal forces upon each other. If the objects have different masses, then these equal forces will produce different accelerations. ... FALSE - In any collision, the colliding objects exert equal and opposite forces upon each other as the result of the collision interaction.
Si se impulsa un bloque con una velocidad de 15m/s sobre el piso sin rozamiento mostrado. Determinar la altura “h” que alcanzará, no existe rozamiento.
PORFAAA AYUDA URGENTE
La altura máxima alcanzada por el bloque es de 14.471 metros.
En esta pregunta asumimos que la altura inicial del bloque es igual a tres metros por encima del la altura de referencia y la altura final puede ser determinada mediante el principio de conservación de la energía, en cuyo caso, la suma de la energía cinética traslacional inicial ([tex]K[/tex]) y la energía potencial gravitacional inicial ([tex]U_{o}[/tex]), ambos en joules, es igual a la energía potencial gravitacional final ([tex]U_{f}[/tex]), en joules. Matemáticamente hablando, tenemos la siguiente expresión:
[tex]U_{o}+K = U_{f}[/tex]
[tex]m\cdot g\cdot z_{o} + \frac{1}{2}\cdot m\cdot v^{2} = m\cdot g \cdot z_{f}[/tex] (1)
Donde:
[tex]m[/tex] - Masa del bloque, en kilogramos.[tex]g[/tex] - Aceleración gravitacional, en metros por segundo al cuadrado.[tex]z_{o}[/tex], [tex]z_{f}[/tex] - Alturas inicial y final, en metros.[tex]v[/tex] - Rapidez inicial del bloque, en metros por segundo.A continuación, despejamos la altura final del bloque:
[tex]z_{f} = z_{o}+\frac{1}{2}\cdot \frac{v^{2}}{g}[/tex] (2)
Si sabemos que [tex]z_{o} = 3\,m[/tex], [tex]v = 15\,\frac{m}{s}[/tex] y [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], entonces la altura máxima alcanzada por el bloque es:
[tex]z_{f} = 3\,m + \frac{1}{2}\cdot \left[\frac{\left(15\,\frac{m}{s} \right)^{2}}{9.807\,\frac{m}{s^{2}} } \right][/tex]
[tex]z_{f} = 14.471\,m[/tex]
La altura máxima alcanzada por el bloque es de 14.471 metros.
Invitamos cordialmente a ver esta pregunta sobre el principio de conservación de la energía: https://brainly.com/question/19561287
if an inelastic collision takes place, during the collision, what is conserved?
Answer:
An inelastic collision is a collision in which there is a loss of kinetic energy. While momentum of the system is conserved in an inelastic collision, kinetic energy is not.
Explanation:
