Name the units for each electrical quantity. a. potential difference (electrical pressure) _____ b. electrical current ______ c. electrical resistance ______​

Crushing increases the ice's surface area. Additionally, cooling from ice happens as a result of convection, which is proportional to area. Thus, breaking up the ice expedites the cooling process.

When precise and consistent temperature control inside a process is necessary, this sort of cooling is used. Because they can offer cooling capacity independent of variations in the ambient temperature, heat load, and flow needs of the application, chillers are frequently employed to remove heat from a process.

It's important to properly regulate the heat load in many industrial operations. Different components of the whole application might need to be cooled.

Major locations for cooling include:

Direct product cooling

During the molding process, plastic

milling metal products

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The angular frequency of this motion is 5.46 rad/s.

The oscillation of spring is an example of Simple Harmonic Motion(SHM).

The general equation of an SHM is given by the formula.

X = Acos(wt)

Here A is the amplitude

ω is the angular frequency

T is the time

Comparing the above equation with the given condition,

X = 17.4 cm cos(5.46t)

A = 17.4 cm

ω = 5.46 rad/s

T = 1 s

Hence, the angular frequency of this motion is 5.46 rad/s.

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Amount of charge passes through a radio battery

is 8 Coulomb

Given:

voltage of battery = V = 9 v

energy = E = 72 j

To Find:

charge passes through a radio battery = Q

Solution: If voltage, (V) equals Joules per Coulombs (V = J/C) and Amperes (I) equals charge (coulombs) per second (A = Q/t)

It is given by the formula

V = E/Q

Q = E/V = 72 j/9 v

Q = 8 Coulomb

Hence, Amount of charge passes through a radio battery is 8 Coulomb

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The resultant internal loading acting on the cross section of C are Normal force of 0 N, Shear force of 233.33 N and Bending moment of 433.325 N.

We know that Moment = Force * Distance.

Given that,

Force along span C = 600 N / m

First chart a free body diagram as shown in Fig 1.

The distributed load along span c is replaced by a point load F at its midpoint.

Force at midpoint of span C = 600 * 2 N

Take moments about point A

Σ [tex]M_{A}[/tex] = 0

-600 * ( 2 ) * [ 1 + ( ( 1 + 1 ) / 2 ) ] + [tex]B_{y}[/tex] ( 4.5 ) - 900 ( 6 ) = 0

- 2400 + 4.5 [tex]B_{y}[/tex] - 5400 = 0

[tex]B_{y}[/tex] = 1733.33 N

Consider a section at Point C and draw a free body diagram as shown in Fig 2.

In fig 2,

[tex]V_{C}[/tex] = Shear force at point C

[tex]N_{C}[/tex] = Normal force at point C

[tex]M_{C}[/tex] = Bending moment at point C

Applying equilibrium condition to the system. Consider equilibrium of Forces along X direction

Σ [tex]F_{x}[/tex] = 0

[tex]N_{C}[/tex] = 0 N

Consider equilibrium of Forces along Y direction

Σ [tex]F_{y}[/tex] = 0

[tex]V_{C}[/tex] - 600 ( 1 ) + [tex]B_{y}[/tex] - 900 = 0

[tex]V_{C}[/tex] = 600 - 1733.33 + 900

[tex]V_{C}[/tex] = 233.33 N

Take moment about point C

Σ [tex]M_{C}[/tex] = 0

- [tex]M_{C}[/tex] - 600 ( 1 ) ( 1 / 2 * 1 ) +  [tex]B_{y}[/tex] ( 2.5 ) - 900 ( 4 ) = 0

- [tex]M_{C}[/tex] - 300 + 2.5 ( 1733.33 ) - 3600 = 0

[tex]M_{C}[/tex] = 433.325 N

The resultant internal loading acting on the cross section are Normal force, Shear force and Bending moment

Therefore, The resultant internal loading acting on the cross section of C are as follows

Normal force [tex]N_{C}[/tex] = 0 N

Shear force [tex]V_{C}[/tex] = 233.33 N

Bending moment [tex]M_{C}[/tex] = 433.325 N

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Answer:

4

Explanation:

if there are 1/4 cups and you need to fill a cup, you need 4
4 x 1/4 = 4/1
4/1 = 1

From the sun to Alpha Centauri than from the sun to Jupiter it is 105 times further. The age of Alpha Centauri is 5.3 billion years older. It also moves in a totally different way. Even though it is close by, it is only passing.

Alpha Centauri A is around 100,000 miles farther away, 10% more massive, and a little bigger than our Sun. All of the planets' orbits will become more elliptical as a result of the increased mass. The reality that Alpha Centauri A is 50% brighter than our star, placing Earth slightly inside the habitable zone, is much worse for the Earth. Most of Earth's surface is currently uninhabitable due to its average surface temperature of 43 degrees Celsius, according to Universe Sandbox 2. It has been clearly stated to us, though, that a temperature so high would most likely lead to an uncontrollable greenhouse effect by increasing the amount of water vapor in the atmosphere.

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The correct answer for  the volume v of the solid obtained by rotating the region bounded by the given curves about the specified line. y = x2, y = 4x is 128/3 * π.

Volume of Solid of Revolution by Shell method is given by

V = 2π * integrate x(height) dx Here, height = 4x-x2

(1)& x-varies from x = 0 to x = 4 then from eqn(1)  V = 2π * integrate x(4x - x ^ 2) dx from x = 0 to 4 = 2π * integrate (4x ^ 2 - x ^ 3) dx from x = 0 to 4

Basic Rule(1) ∫ x^n dx =x^ n+1/ n+1

V=2 π [4((x ^ 3)/3) - (x ^ 4)/4] 0 ^ 4 =2 π[ 4/3 x^ 3 - x^ 4/4 ] 0 ^ 4

V = 2π [4/3 * 4 ^ 3 - (4 ^ 4)/4} - 0]

V = 128/3 * π.

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The final speed of cyclist is 12.27m/s

The following question can be solved using formulas of Motion on one dimension as the motion is in one dimension

We will use the formula

[tex]v^2-u^2=2aS[/tex]

where v is the final velocity

u is the initial velocity

a is the acceleration of the boat

s is the distance in meters

v^2 = 2 x a x S

       = 2 x 46 x a

v^2=92a

v=[tex]\sqrt{92a}[/tex]

where a is the acceleration

Now using the formula v= u+ at

and putting value of v in the equation

[tex]\sqrt{92a}[/tex]=a x7.5

squaring both sides,

92a=56.25a^2

a=92/56.25=1.64 m/s^2

Now we know that v= 7.5 a=7..5 x 1.64 =12.27m/s

Hence her final speed is 12.27m/s

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Neptune's equatorial diameter is 49,528 kilometers, and as one kilometers is equivalent to 0.6214 miles, its diameter in miles is 30776.69 miles.

The Northern and Southern hemispheres of the planet are separated by the Equator, a circle of latitude with a radius of 40,075 km (24,901 mi). Halfway between the North and South poles, at 0 degrees latitude, is a fictitious line.

The equator of a spinning spheroid, such as a planet, is the parallel (circle of latitude) where latitude is defined to be 0° in astronomical (3D) spatial geometry. It is a fictitious line that divides the spheroid into its northern and southern hemispheres and runs parallel to its poles. In other words, it is the point where the spheroid intersects with the plane that is perpendicular to its axis of rotation and centered between its poles.

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The correct option is (a)the evening star.

Venus is sometimes called the evening star.

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A small change in the atmospheric condition can create a different weather pattern. Each weather pattern has a domino effect, creating a ripple effect around the world.

Weather is the state of the atmosphere with respect to heat or cold, wet or dry, calm or stormy, clear or cloudy.

The exchange of energy between the surface of the earth, the atmosphere, and space causes weather.

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When selected randomly without replacement the probability that the first 2 selected are white and the last 2 black is 6/91

Given that,

No. of white balls = 6

No. of black balls = 9

Total number of balls = 15

Probability of 1st ball being white = 6/15

Probability of 2st ball being white = 5/14

(Since one white ball is already picked)

Probability of 3rd ball being black = 9/13

(Since two white balls are already picked)

Probability of 4th ball being black = 8/12

(Since two white balls and one black ball is already picked)

The probability that the first 2 selected are white and the last 2 black

= 6/15 * 5/14 * 9/13 * 8/12

= 6/91

Therefore, when selected randomly without replacement the probability that the first 2 selected are white and the last 2 black is 6/91

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Answer: Innovations originally designed for space vehicles, including artificial muscle systems, robotic sensors, diamond-joint coatings, and temper foam,

Explanation: make artificial human limbs more functional, durable, comfortable, and life-like.

If the time interval during which it falls is cut in half, the distance it fall will be decreased by a factor of 4.

When there is an uniform acceleration,

s = vt - 1/2 a[tex]t^{2}[/tex]

where,

s = Displacement or distance travelled

v = Final velocity ( Here v = 0 )

a = Acceleration

t = Time

[tex]s_{1}[/tex] = - 1/2 a[tex]t_{1} ^{2}[/tex]

[tex]s_{2}[/tex] = - 1/2 a[tex]t_{2} ^{2}[/tex]

Given that,

[tex]t_{2}[/tex] = [tex]t_{1}[/tex] / 2

[tex]t_{1}[/tex] = 2 [tex]t_{2}[/tex]

Rate of change of displacement [tex]s_{2}[/tex] / [tex]s_{1}[/tex] = ( - 1/2 a[tex]t_{2} ^{2}[/tex] ) / ( - 1/2 a[tex]t_{1} ^{2}[/tex] )

                                                                = [tex]t_{2} ^{2}[/tex] / 4[tex]t_{2} ^{2}[/tex]

                                                            [tex]s_{2}[/tex] = [tex]s_{1}[/tex] / 4

The equation s = vt - 1/2 a[tex]t^{2}[/tex] is an equation of motion. Equations of motion describes a physical system's motion with respect to time.

Therefore, If the time interval during which it falls is cut in half, the distance it fall will be decreased by a factor of 4

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The percentage decomposed in the first order reaction is 69.8%.

Given: rate constant, k = 0.00702 sec -1

time, t = 7.1 s

Since the reaction is first order, we calculate using the formula below:

[A] = [A]₀ [tex]$$e^{(-kt)[/tex]

Where; [A] is the final concentration

[A]₀ is the initial concentration

Finding the ratio of final and initial concentration

[A]/[A]₀ =[tex]$$ e^{(-kt)[/tex]

Substituting the values:

[A]/[A]₀ = [tex]e^{(-0.00702 * 7.1)[/tex]

[A]/[A]₀ = [tex]e^{(-0.0498)[/tex]

[A]/[A]₀ = 0.9514

Percentage decomposed = [A]/[A]₀ [tex]*[/tex] 100%

Percentage decomposed = 0.9514 [tex]*[/tex] 100%

Percentage decomposed = 95.1 %

Therefore, the percentage decomposed in the first-order reaction is 95.1 %.

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Wave speed decreases by half while the frequency remains constant.

                           [tex]\begin{aligned}\\\small v_1 &=\small f.\lambda_1\quad\cdots\cdots(1)\\\\\small v_2 &=\small f.\frac{\lambda_1}{2}\quad\cdots\cdots(2)\\\\(2)\div&(1)\\\\\small v_2 &=\small \frac{v_1}{2}\end{aligned}[/tex]

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The all components of force is F = ( -3.4 i + 7 j ) N  which has magnitude of | F | = 7.78 N.

We need to know about vectors to solve this problem. Force is included in the vector which has magnitude and direction. Force can be written as

F = Fx i + Fy j

where F is force, Fx is the force component on the x-axis, Fy is the force component on the y-axis.

From the question above, we know that

F = (-3.4 , 7.0)

Hence the force can be written as

F = ( -3.4 i + 7 j )N

The magnitude of this force can be determined as

| F | = √(Fx² + Fy²)

| F | = √((-3.4)² + 7²)

| F | = √(11.56 + 49)

| F | = 7.78 N

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The calculated value is 13963.42 g/mol

Protein Molecular Weight determines the molecular weight from a protein sequence. Using the provided list, you can append copies of frequently used epitopes and fusion proteins. The Rubisco monomer is a typical soluble protein, and a basic rule of thumb for thinking about soluble proteins is that they are 3-6 nm in diameter, which demonstrates not only Rubisco but many other significant proteins that are essential for cell function.

Mass of protein (w2) =0.1g

R=0.082 L atm/ (k mol)

T=298K

π=13.33 mm of Hg = 760/13.33

 =0.0175 atm

volume of solution =0.01L

Using,

M2= πVW2RT

We get M2

​= 0.0175×0.01/0.1×0.082×298

​=13963.42 g/mol

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The angle in radians is 1/60.

                  [tex]\begin{aligned}\\\small s &= r\theta \\\\\small 1\,cm &=\small 60\,cm\times \theta \\\\\small \theta &=\small \frac{1}{60}\,\text{radians}\end{aligned}[/tex]

According to the given statement is  At address 0x8004, the default data word is 0xA7908CEE.

Little Endian method with a word size of 4 Bytes is the default on ARM processors.

Data is stored in the memory bytes at a time, and access is done in words.

The data must be stored in 4 cells because word size is equal to 4 bytes.

i.e., the data word is retrieved in parallel from 4 cells.

Little endian states that lower addresses have lower bytes and higher addresses have higher bytes.

At location 0x8004, the default data word is 0xA7908CEE.

The sequence in which data is stored in memory is referred to as the "little-endian" convention. According to this convention, the least significant bit (or "littlest" end) is placed at address 0 first, followed by the storage of following bits one at a time.

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According to the following formula, the answer is 2,300 g or 2.3 kg:

Volume (m)/Mass (m) Equals Density (p) (V)

Here, the density is 1.15 g/mL, allowing the formula described above to result in a mass of 2.00 L:

p=m/V

1.15 g/mL is equal to x g/2.00 L or x g/2,000 mL.

2,000 mL of x g = 1.15 g of g/mL

2.3 kg or 2,300 g for x g.

Its active ingredient is glucose. This medication includes 50 g of glucose per 1000 ml (equivalent to 55 g glucose monohydrate). 50 mg of glucose is present in 1 ml (equivalent to 55 mg glucose monohydrate). A transparent, nearly colourless solution of glucose in water is what is used in glucose intravenous infusion (BP) at 5% weight-to-volume.

Patients who are dehydrated or who have low blood sugar levels get glucose intravenously. Other medications may be diluted with glucose intravenous infusion before being injected into the body. Other diseases and disorders not covered above may also be treated with it.

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This means that at the equator, the force of gravity on a body causes its velocity to increase at the rate of 9.78m/s per second because of acceleration of free fall cohesion.

An object that is falling freely is one that is only being affected by gravity. A free-falling object experiences a downward acceleration of 9.8 m/s/s (on Earth). This specific name is given to the numerical value for an object in free fall because it is such an essential value. The acceleration of any object moving solely as a result of gravity is referred to as the "acceleration of gravity."

This means that at the equator, the force of gravity on a body causes its velocity to increase at the rate of 9.78m/s per second because of acceleration of free fall cohesion.

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Answer: y(3+z)=x

Explanation:

Assuming that you meant 3=x/y-z without y-z being in parenthesis

3=x/y-z

3+z=x/y

y(3+z)=x

Integrating the velocity equation, we will see that the position equation is:

[tex]$f(t)=\frac{\cos ^3(\omega t)-1}{3}[/tex]

Let the velocity of the particle is:

[tex]$v(t)=\sin (\omega t) * \cos ^2(\omega t)[/tex]

To get the position equation we just need to integrate the above equation:

[tex]$f(t)=\int \sin (\omega t) * \cos ^2(\omega t) d t[/tex]

[tex]$\mathrm{u}=\cos (\omega \mathrm{t})[/tex]

Then:

[tex]$d u=-\sin (\omega t) d t[/tex]

[tex]\Rightarrow d t=-d u / \sin (\omega t)[/tex]

Replacing that in our integral we get:

[tex]$\int \sin (\omega t) * \cos ^2(\omega t) d t$[/tex]

[tex]$-\int \frac{\sin (\omega t) * u^2 d u}{\sin (\omega t)}-\int u^2 d t=-\frac{u^3}{3}+c$[/tex]

Where C is a constant of integration.

Now we remember that [tex]$u=\cos (\omega t)$[/tex]

Then we have:

[tex]$f(t)=\frac{\cos ^3(\omega t)}{3}+C[/tex]

To find the value of C, we use the fact that f(0) = 0.

[tex]$f(t)=\frac{\cos ^3(\omega * 0)}{3}+C=\frac{1}{3}+C=0[/tex]

C = -1 / 3

Then the position function is:

[tex]$f(t)=\frac{\cos ^3(\omega t)-1}{3}[/tex]

Integrating the velocity equation, we will see that the position equation is:

[tex]$f(t)=\frac{\cos ^3(\omega t)-1}{3}[/tex]

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During the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.

Velocity vector is the rate of change of position of an object. Acceleration vector is the rate of change of velocity of an object.

Therefore, during the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.

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Answer: most likely its going to be 5

Explanation:

because you have to keep it the same

The angular resolution for horizontally separated mice is 1.00×10−3 rad

The Rayleigh criterion for the diffraction limit to resolution states “that two images are just resolvable when the center of the diffraction pattern of one is directly over the first minimum of the diffraction pattern of the other”. This criterion is based on the fact that Light diffracts as it moves through space, bending around obstacles, interfering constructively and destructively.

We assume Rayleigh's criterion applies to the cat's eye with pupil narrowed. For a single slit (not a round aperture), for small angles

θ ≈ sin θ =λ/a

= 500×10−9m / 0.500 × 10−3m

=1.00×10−3 rad

Hence, the angular resolution for horizontally separated mice is 1.00×10−3 rad

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The velocity, acceleration and speed are -

v(t) = - 7sin t [tex]i[/tex] + 6cos t [tex]j[/tex]

a(t) =  - 7cos t [tex]i[/tex] - 6sin t [tex]j[/tex]

s(t) =  [tex]\sqrt{(7cos\;t) ^{2} +(6sin\;t)^{2} }[/tex]

We have the position vector → r(t) = 7cos(t) i +  6sin(t) j

We have to determine the velocity, acceleration and speed of particle.

The instantaneous velocity and acceleration can be calculated using -

v = [tex]$\frac{dx}{dt}[/tex]

a = [tex]$\frac{dv}{dt}[/tex]

According to the question, we have -

r(t) = 7cos(t) i +  6sin(t) j

The velocity can be calculated using -

v(t) = [tex]$\frac{dr(t)}{dt} = \frac{d}{dt}\;(7 cos\;t \;i + 6 sin\;t\;j)[/tex] = - 7sin t [tex]i[/tex] + 6cos t [tex]j[/tex]

The acceleration can be calculated using -

a(t) = [tex]$\frac{dv(t)}{dt} = \frac{d}{dt}\;(-7 sin\;t \;i + 6 cos\;t\;j)[/tex] = - 7cos t [tex]i[/tex] - 6sin t [tex]j[/tex]

The speed at time t can be found out as follows -

|r(t)| = [tex]\sqrt{(7cos\;t) ^{2} +(6sin\;t)^{2} }[/tex]

Hence, the velocity, acceleration and speed are -

v(t) = - 7sin t [tex]i[/tex] + 6cos t [tex]j[/tex]

a(t) =  - 7cos t [tex]i[/tex] - 6sin t [tex]j[/tex]

s(t) =  [tex]\sqrt{(7cos\;t) ^{2} +(6sin\;t)^{2} }[/tex]

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According to the given statement  the pulse pressure = 70mm Hg.

The correct option is 2.

Systolic, as well as diastolic blood pressure, as well as diastolic blood pressure, is divided to create pulse pressure. Mercury millimeters are used to measure it (mmHg).It represents the contractional force of the beating heart. Normal rested blood pressure is about 120/80 mmHg, which results in a pulse pressure of about 40 mmHg.

Diastolic blood pressure is subtracted from systolic blood pressure to determine pulse pressure. Age-related changes in the aorta and minor arteries' compliance result in elevated systolic pressure and decreased diastolic pressure, which raises pulse pressure.

Diastolic and systolic blood pressure differences are used to compute pulse pressure.

So, 150 - 80

= 70.

According to the given statement  the pulse pressure = 70mm Hg

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I understand that the question you are looking for is:

A nurse is calculating the pulse pressure for a client who has a blood pressure of 150/80. What is the pulse pressure?

1. 230 mm Hg

2. 70 mm Hg

3. 1.875 mm Hg

4. 140 mm Hg

2. 70 mm Hg

80 step it will take to stop under the same conditions if its initial velocity is 38 mi/h.

Speed is the directional speed of an item moving as a sign of its pace of progress ready as seen from a specific edge of reference and as estimated by a specific norm of time (for example 60 km/h northward). Speed is an essential idea in kinematics, the part of old-style mechanics that portrays the movement of bodies. Velocity is characterized as the pace of progress of position concerning time, which may likewise be alluded to as the immediate speed to stress the qualification from the typical speed. In certain applications the typical speed of an item may be required, in other words, the steady speed that would give a similar resultant relocation as a variable speed.

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