lim f(x) x-3 lim f(x) x-1– lim f(x) x-17+ lim f(x) x3 lim f(x) x5
how do I find the limits using graphs

Lim F(x) X-3 Lim F(x) X-1 Lim F(x) X-17+ Lim F(x) X3 Lim F(x) X5how Do I Find The Limits Using Graphs

Answers

Answer 1

Explanation:

try this option (all the details are in the attachment).

Lim F(x) X-3 Lim F(x) X-1 Lim F(x) X-17+ Lim F(x) X3 Lim F(x) X5how Do I Find The Limits Using Graphs

Related Questions

Ibuprofen can be found in 800 mg doses in over-the-counter analgesics, such as Advil and Motrin. How many grams of iburofen
does such a tablet contain?
800 mg =
g

Answers

The grams of iburofen does such a tablet contain 800 mg =   0.8g Ibuprofen

1 g = 10^-3g = .001g

Ibuprofen has  800 mg doses in over-the-counter analgesic

800g = 800 × .001

        = 0.8g

Ibuprofen is Nondteriodal Anti-inflammatory Drug (NSAID)Ibuprofen's Mechanism of Action is Decreases inflammation, pain, and fever through inhibition of cyclooxygenase activity and prostaglandin synthesisnonsteroidal anti-inflammatory medication (NSAID) used for pain relief and to reduce fever by stops inflammation and  by blocking formation of cyclo-oxygenase (COX-2) a chemical mediator of inflammatory chemicals. i.e prostaglandinsIt comes under the Class analgesic (reduce pain) and antipyretic (FIRE - reduce fever)e side effects of ibuprofen NSAID are peripheral edema, fluid retention with edema, tinnitus, purpura, petechiae, anorexia, diarrhea, rash, nausea, vomiting, fatigue, dizziness, lightheadedness, anxiety, confusion

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Calculate the density in g/ml of 2.0 L of gasoline that weighs 1.32 kg

Answers

Answer: 0.66 g/mL

Explanation: The formula for density is d= m/v where m=mass and v=volume.

The mass was given in the problem, m= 1.32kg

The volume was also given in the problem, v= 2.0L

d= m/v ---> d= 1.32kg/2.0L ---> d=0.66kg/L

The problem calls for the answer to be written in g/mL, so we must convert the units. 1 kg contains 1000g and 1 L contains 1000 mL.

1000g/1000mL = 1 so the units change but the 0.66 does not. Therefore, your answer is 0.66g/mL (Two significant figures because 2.0 only has 2 significant figures).

Help help help please

Answers

For the first question the 1 kg block would float and the 3 and 4 kg block would sink, I think this because the 2 kg block is floating but it’s mostly underwater meaning that something heavier would sink but the lighter block would float

Step 3.
Drag lone pairs of electrons to each terminal atom until each has an octet of electrons, or until all electrons are used. You may remove a lone pair by clicking on it. Check your answer.

Answers

There is a double bond between the carbon atoms and a lone pair on oxygen.

What is Lewis structure?

The term Lewis structure has to do with the structure that shows the arrangement of atoms in a compound. It is normal that the structure would be composed of the symbols of the elements and the bonds that they form as dots or sometimes as a single line to show shared electrons.

Now we can see that the compound C2H2O is a compound that contains a double bond between the carbon atoms. There is a lone pair of electron that resides on the oxygen atom. The structure of this compound is shown in the image attached.

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How many moles (of molecules or formula units) are in each sample?

Express your answer in moles to three significant figures.


1) 18.0 g NO2

2) 1.35 kg CO2

3) 46.1 g KNO3

4) 191.8 kg Na2SO4

Answers

The number of moles in each sample will be 0.391 moles, 30.7 moles, 0.456 moles, and 1350 moles

What is the number of moles?

The number of moles of a substance is the ratio of the mass of the substance to the molar mass.

In other words; mole = mass/molar mass.

Thus:

moles of 18.0 g [tex]NO_2[/tex] = 18.0/46

                                   = 0.391 moles

moles of 1.35 kg [tex]CO_2[/tex] = 1350/44

                                         = 30.7 moles

moles of 46.1 g [tex]KNO_3[/tex] = 46.1/101.1

                                          = 0.456 moles

moles of 191.8 kg [tex]Na_2SO_4[/tex] = 191800/142

                                                 = 1350 moles

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What is concentration of N2O5 in the following first order reaction in which the rate is 2.4*10^-5 mole/L and rate constant is 3 * 10 ^ - 5 * S ^ - 1 ?​

Answers

0.8mole/L is concentration of N2O5.

As the reaction is first order ,

so the order with respect to N2O5 is 1.

general,

Rate of equation is written as

rate = k [N2O5]^1

k is the rate constant = 3 * 10 ^ - 5 * S ^ - 1

rate = 2.4*10^-5 mole/L

N2O5 is concentration term

2.4*10^-5 mole/L  = 3 * 10 ^ - 5 * S ^ - 1 [  N2O5]

 N2O5 = [0.8 mole/L]

=0.8mole/L

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Determine the type of investigation.


How does an iPod receive messages?


comparative

none is correct

experimental

descriptive

Answers

Answer:

comparative

Explanation:

The massage just pop on the ipod

how can we apply our knowledge about matter in our lives]

Answers

Answer:

The answer is

Explanation:

by studying the matter and its parts and also discovering the wonders of our earth

How many miles can you drive, if your car gets 20.30 miles per gallon
and you have 12.00 gallons of gas?

Answers

Answer:

243.60 miles

Explanation:

Multiply miles per gallon times number of gallons.  Both starting numbers are given to two decimal places so our answer is as well.

If you have a sample of 3.5 × 1022 atoms of tin (Sn), how many moles of tin do you have?

The correct answer according to the text is 0.058 mol Sn but no matter how I work it, I get 5.8 X 10^-2 mol Sn. I am using a scientific calculator. How did they get that answer?

Answers

The number of mole of tin (Sn) that you have is 0.058 mole

Avogadro's hypothesis

6.02×10²³ atoms = 1 mole of tin (Sn)

With the above information, we can obtain the number of mole ot tin. Details below

How to determine the mole of tin that contains 3.5×10²² atoms

We can obtain the number of mole of tin as follow:

6.02×10²³ atoms = 1 mole of tin (Sn)

Therefore,

3.5×10²² atoms = (3.5×10²² atoms × 1 mole) / 6.02×10²³ atoms

3.5×10²² atoms = 0.058 mole of tin (Sn)

Thus, the number of mole of tin (Sn) you have is 0.058 mole

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The amount of heat absorbed by the calorimeter in this reaction must be determined before you can calculate the enthalpy of the reaction that occurs inside of it.
To do this, suppose that you measure exactly 43.5 mL of cool water at 22.0°C and
place it into a calorimeter. Then you add 21.0 mL of warm water (initial temperature
of 37.0°C) to the calorimeter. The final temperature of the entire system is 25.5°C.
Compute the heat capacity of the calorimeter in J K–1 assuming that no heat leaks
into or out of the calorimeter.

Answers

The heat capacity of the calorimeter is 16.8 J/K.

What is the heat capacity of the calorimeter?

Now we know that the calorimeter is a device from which there is no heat loss or gain. In this case, the heat lost by the hot water is equal to the heat gained by the calorimeter.

Thus;

cwθ = ccθ

Where;

cc= heat capacity of the calorimeter

cw = heat capacity of water

θ == temperature change

Hence;

4.2  * (37 - 25) = cc (25 - 22)

cc = 4.2  * (37 - 25)/(25 - 22)

cc = 16.8 J/K

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The same type of engine is placed in two different airplanes. The first airplane is twice as heavy as the second airplane
Which statement is correct about the mass of the airplane and its acceleration, assuming a constant net force? (1 point)
O Increasing the acceleration of the airplane causes the engine to provide more force.
O Decreasing the mass of the airplane will result in the airplane accelerating less.
O Increasing the acceleration of the airplane causes the engine to provide less force.
O Decreasing the mass of the airplane will result in the airplane accelerating more.

Answers

If the engines in both airplanes are at the same weight, the engines in both airplanes would still have the same mass because mass is constant everywhere.

What is mass?

Mass can be experimentally defined as a measure of the body's inertia, meaning the resistance to acceleration (change of velocity) when a net force is applied.

In the question, the same type of engine is placed in two different air-planes of which the first airplane is twice as heavy as the second.

We can then conclude that the  correct statement about the mass of the airplane and its acceleration, assuming a constant net force is that Increasing the acceleration of the air-plane causes the engine to provide more force.

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Paulo is experimenting with H2O in its different states. He would like to present all the information he collected in one place. He thinks he should use a phase change diagram, but he isn't sure. What information could you give Paulo to encourage him to use a phase change diagram?

Answers

Paulo  needs to use a phase diagram to show how much stable each of the various phases of water is.

What is the phase diagram?

The phase diagram could be used to obtain the changes in a substance at different phases of matter. We know that water could exist as solid, liquid or gas. The state in which the water is a function of the pressure and the temperature of the system.

The phase diagram could be used to see the various conditions of temperature and pressure where we can trace to the liquid, solid and gaseous phases of the substance that is under study. On this phase diagram, we can also locate the triple point of water.

Given that the pressure and the temperature changes of water could be shown on a phase diagram, it then follows that Paulo  needs to use a phase diagram to show the various phases of water.

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A student is given a metal block and told to calculate the density of the object. The student measures the block on each side (LxWxH) 4 times each.
He then calculates the average measurement for each side. Those average values are:
Average Length = 6.51 cm
Average Width = 4.34 cm
Average Height = 7.17 cm
Calculate the volume of the block
to be rounded to the nearest supported value)
cm^3 (Select the answer closest to what you calculated. Significant Figures requires all answer

Answers

The volume of the metal block is 201 [tex]cm^3[/tex]

What is average volume?

The volume of an object is the multiplication of all the sides of the object.

The average volume, on the other hand, is the multiplication of the average sides of objects.

In this case, the object has length, width, and height.

Average length = 6.51 cm

Average width = 4.34 cm

Average height = 7.17 cm

Volume of the metal block = 6.51 x 4.34 x 7.13

                                            = 201 [tex]cm^3[/tex]

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Water has a density or a mass per unit volume corresponding to 1.000 g/mL at
4°C. This means that one gram of water corresponds to one milliliter of volume.
Obtain the mass of a clean, dry 100-mL graduated cylinder on the electronic
balance. Add 50 mL of deionized water to the graduated cylinder and remeasure
its mass. Calculate the mass of the water by subtracting the mass of the empty
cylinder from the mass of the cylinder plus the added water. Find the density of
water by dividing the mass of water by the volume of water. Enter the values in
the following table:
Mass of the graduated cylinder plus water (9) 72.6979
Mass of empty graduated cylinder (g)
123,5469
49.161 9
Mass of water (g)
Density of watek(g/mL)
Temperature (°C)
22.39 °C

Answers

Answer:

b

Explanation:

ason solved this problem by changing 6/4 to 1.2. He then added 1.2 to 0.68 and got 1.88.

This answer is incorrect. What did he do wrong?

Question 9(Multiple Choice Worth 2 points)
(03.01 LC)
Which of the following is an example of matter?
O Electricity
O Heat
O Sound
O Water

Answers

Electricity, is an example of matter. Since, all matter is made up from atoms. Atoms contain a nucleus which that has protons and neutrons which are forms of energy.

A 4.000-mL urine sample from a person suffering from diabetes mellitus has a mass of 4.007 g.
Express your answer using four significant figures.

Answers

The concentration of the urine is determined as 1.002 g/ml.

What is concentration?

The concentration of a chemical substance expresses the amount of a substance present in a mixture.

What is the urine concentration?

The concentration of the urine is determined from the ratio of mass to volume of the urine or density of the urine.

Urine Concentration = mass / volume

Urine concentration = 4 .007 g / 4 ml

Urine concentration = 1.002 g/ml

Thus, the concentration of the urine is determined as 1.002 g/ml.

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The complete question is below:

determine the concentration of the urine.

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