Joe moves a 10 kg weight 5 meters with a force of 50 N in 10 seconds. Leroy uses the same force to move the same weight the same distance in 7.5 seconds? Who has more power and why

Answer:

48000

Step-by-step explanation:

260000*5%=13000

35000+13000=48000

Answer: x = 7 ft, DO = 25 ft, OG = 35 ft

Step-by-step explanation:

        We will write an equation using the segment addition postulate.

Given by segment addition postulate:

   DO + OG = DG

Substitute known values:

   (4x - 3) ft + (2x + 21) ft = 60 ft

Combine like terms and simplify:

   6x + 18 ft  = 60 ft

Subtract 18 ft from both sides of the equation:

   6x  = 42 ft

Divide both sides of the equation by 6:

   x = 7 ft

        Now, we will "plug" this value in and solve for the segments.

DO ➜ (4x - 3)ft ➜ (4(7) - 3) ft ➜ 28 - 3ft = 25 ft

OG ➜ (2x + 21) ➜ (2(7) + 21) ft ➜ 14 + 21 = 35 ft

well, she really began with "x" total.

then she sold half of that, so hmmm 1/2 of "x" is just x/2 and she's left with half, so she sold x/2 and she was left only with x/2, and then she bought 17 more, we also know that she has 31 now, so

[tex]\stackrel{\textit{leftover}}{\cfrac{1}{2}x}~~ + ~~\stackrel{\textit{more bought}}{17}~~ = ~~\stackrel{\textit{now she has}}{31}\implies \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{2}}{2\left(\cfrac{x}{2}~~ + ~~17 \right)~~ = ~~2(31)}\implies x+34=62\implies \LARGE \begin{array}{llll} x=28 \end{array}[/tex]

As  given Chole and Tinos age , the present age of Tino is equal to 15 years.

As given,

Let x and y be the present age of Chole and Tino. respectively.

Combined age = 48

Given condition,

x + y = 48 _______(1)

Three years ago

x - 3 = 2y

⇒x =2y +3 _______(2)

Substitute the value of x in (1),

2y+3 +y =48

⇒ 3y = 45

⇒ y = 15years

Therefore , as given Chole and Tinos age , the present age of Tino is equal to 15 years.

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The radius of the pool with height as 0.5 cm and volume as 12,000 cm³ is 87.39 cm.

We have that:

Radius of the water pipe = 0.74 cm

r = 0.74 cm

It fills a 12 L bucket in 4 minutes

1 L = 1000 cm³

12 L = 12,000 cm³

Volume of water put in the pool = 12,000 cm³

Height of the pool that rise = 5 mm = 0.5 cm.

H = 0.5 cm

Let the radius of the pool be R.

Volume = π r² h

Substituting the values, we get that:

12,000 = ( 22 / 7 ) R² ( 0.5 )

R² = 7636.36

R = 87.39 cm

Therefore, we get that, the radius of the pool with height as 0.5 cm and volume as 12,000 cm³ is 87.39 cm.

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Answer:

15, 30, 45, 60

Step-by-step explanation:

ALL OF THE MULTIPLES OF 15

15, 30, 45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195, 210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375, 390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, 735

All numbers can be divided or the product of 15 is a multiple of 15.

Answer:

Yes because first ( right to left)  4 is 400,000 while the other 4 is 40,000

Step-by-step explanation:

40,000x 10= 400,000

thanks

Answer: 1: (0,-5) 2: (0.5,1) 3: (1.5, -4.5) 4: (-2.5,-0.5)

Step-by-step explanation:

The correct answer to the exponential expression which is as given in the task content is; 8³.

Based on the given task content, Gina's error from her workings is dividing the bases of the exponent.

Gina's working:

8^12 / 8^9

= 0^12 / 0^9

The Correct workings:

8^12 / 8^9

= 8^(12-9)

= 8³

So therefore, the correct answer to the exponential expression which is given in the above expression is 8³.

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Answer:

It is the size of a cube that is 1 yard on a side. It is about 202 gallons or about 765 liters. A cubic foot is a unit of volume. It is the size of a cube that is 1 foot on a side. It is about 7.5 gallons or about 28.3 liters. Cubic Yards to Cubic Feet Conversions (some results rounded)

Step-by-step explanation:

Given ~

[tex] \: [/tex]

[tex] \tt \: f(x) = −3x² − x – 15[/tex]

[tex] \: [/tex]

now , put x= -8 in the function ~

[tex] \: [/tex]

[tex] \tt \: f( - 8) = −3( - 8)² − ( - 8) – 15[/tex]

[tex] \: [/tex]

[tex] \tt f(-8) = −3(64) − (-8) – 15[/tex]

[tex] \: [/tex]

[tex]\tt f(-8) = −192 − (-8) – 15[/tex]

[tex] \: [/tex]

[tex] \tt f(-8) = −192 − (-8) – 15[/tex]

[tex] \: [/tex]

[tex]\tt f(-8) = −184 – 15 [/tex]

[tex] \: [/tex]

[tex] \underline{\boxed{\red {\tt f(-8) = - 199}}}{\green ✓} [/tex]

[tex] \: [/tex]

hope helps ~

Given that the distance AB is (260), let A be the points (a,2a-1) and B be the places (2a+4,3a+9) where "a" is a constant.

discover the several meanings of "a." noting that an is an integer An integer, pronounced "IN-tuh-jer," is a whole number that can be positive, negative, or zero and is not a fraction. Integer examples include: -5, 1, 5, 8, 97, and 3,043. The following numbers are examples of non-integer numbers: -1.43, 1 3/4, 3.14,.09, and 5,643.1.

Fractions in Math, represent a numerical value that expresses a part of a whole. The whole can be any number, a specific value, or a thing. Fractions are represented in the form of p/q. For example, ¼, ½, ¾, and so on.

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Answer:

Option 3

Step-by-step explanation:

First tke lcm i.e. 6 then multiply the dinominator to make six.

Multiply tje above no. With the same digit the sub. The numerators

Answer:

c) 7/6

Step-by-step explanation:

The difference will be,

→ (5/3) - (1/2)

→ (10/6) - (3/6)

→ (10 - 3)/6

→ 7/6

So, the answer is 7/6.

Answer:

2x-1=3×+8

Step-by-step explanation:

2×-3x=8+1

-x=9

x=-9

In the word "SASSAFRAS", there 2520 permutations can be formed.

A permutation is a mathematical technique that determines the number of possible arrangements in a set when the order of the arrangements matters.

The order of arrangement in permutation is in linear form.

In the given word is “SASSAFRAS”. There are total 9 letters in which some letters appears several times, that is

 S = 4 times.

 A = 3 times.

 F = 1 times.

 R = 1 times.

We can the number of permutation to arrange this letter with the help of :

nPr = n! / (n - r)!

nPr = Permutation

n = Total number of objects

r = Number of objects selected

'!'     =     Factorial

Factorial (noted as “!”) is the product of all positive integers less than or equal to the number preceding the factorial sign. For example, 3! = 1 x 2 x 3 = 6.

So, nPr  =  9!/(4!) (3!) (1!) (1!)

              = (9×8×7×6×5×4×3×2×1)/(4×3×2×1)×(3×2×1)×(1)×(1)

              = 3,62,880/ 24×6×1×1

              = 3,62,880/144

              = 2,520

Hence, 2520 permutations can be formed from the word 'SASSAFRAS'.

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After simplifying the equation we acquire the value of x as:

x = 1.225 or x = ₋12.225

Given the equation is x² ₊ 11x ₊ 15 = 30

arrange the constants on one side.

x² ₊ 11x = 30 ₋ 15

x² ₊ 11x = 15

x² ₊ 11x ₋ 15 = 0

now simplify the equation using the formula: -b±√b²₋4ac / 2a

in the equation we have the values for a = 1 , b = 11 and c = ₋15

substitute the values and get the value of x.

= ₋11 ± √(11)² ₋ 4(1)(₋15) / 2(1)

= ₋11 ± √121 ₊ 60 / 2

= ₋11 ± √181 / 2

= ₋11 ± 13.45 / 2

= ₋11 ₊ 13.45 / 2 or ₋11 ₋ 13.45 / 2

= 2.45/2 or ₋24.45/2

= 1.225 or ₋12.225

Therefore x value is 1.225 or ₋12.225

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The distance between the point A and point B is 9.5 units

The formula for calculating the distance between two points is expressed according to the formula shown below;

AB = √(x₂-x₁)²+(y₂-y₁)²

Using the given coordinates points A(5, -3) and B (-4, -6)

Substitute to have:

AB = √(5-(-4))²+(-3-(-6))²

AB = √(5+4)²+(-3+6))²

AB = √81+9

AB =  √90

AB = 9.5 units

Hence the distance between the point A and point B is 9.5 units

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The difference between the two points ; (-3,10 )

given

(-4,-1)  and (1,-9)

here we have to find the difference between -4 and -1

which is -3 so u go -3 spaces left so it would be -3

then , find the difference between 1 and -9 which is 10 so u go 10 spaces down so the difference between is;

(-3,10).

therefore the distance between two point are (-3,10)

Distance between two points is the length of the line segment that connects the two given points. Distance between two points in coordinate geometry can be calculated by finding the length of the line segment joining the given coordinates.to know more about distance.

We will use the distance formula in order to find the distance between points a and b. By substituting the points A(3, 4) and B(1, 2) in the above formula we get our required distance d. Hence, distance d = 2√2 units

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Answer: D e acute

Step-by-step explanation:

Answer: Non-rectangular Parallelogram

The opposite sides are parallel, but the figure is not a rectangle. It's also not a square either since those figures have an axis of symmetry.

Step-by-step explanation:

a/b = 5/6

a + b = 44

a = 44 - b

so, the first equation is

(44 - b)/b = 5/6

44 - b = 5b/6

264 - 6b = 5b

264 = 11b

b = 24

a = 44 - b = 44 - 24 = 20

the fraction is a/b = 20/24.

Also 2+4 as sum of the digits of the denominator = 6 is correct.

6.8x10^6, 6.6x10^6, 6.1x10^6, 6x10^

Answer:

6 x 10^6, 6.1 x 10^6, 6.6 x 10^6, 6.8 x 10^6

Step-by-step explanation:

Answer: 13512

100332

Step-by-step explanation:

The shortest time for her run is approximately 36 minutes and the longest time is approximately 67 minutes.

To represent Kenzie's situation, we can use an absolute value equation. Let x represent the length of her run in miles.

The equation would then be |x - 6| ≤ 1, which means the distance between x and 6 is less than or equal to 1.

To find the shortest or longest amount of time for Kenzie's run, we need to consider the speed.

The time can be found by dividing the distance by the speed, so the minimum time would be (6 - 1)/6.25 hours,

which is approximately 0.6 hours or 36 minutes.

The maximum time would be (6 + 1)/6.25 hours,

which is approximately 1.12 hours or 67 minutes.

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Answer:

See below

Step-by-step explanation:

The first one scales UP from 4 to 6     F'G'/FG =    factor is  6/4 = 1.5

second one scales DOWN from 4 to 3  

        F'G' / FG = scale factor is 3/4

Third one is scaled DOWN

F'G' / FG =    2/4 = 1/2

Note when scale is DOWN the factor is less than one

  when scale is UP , factor is more than one

We get A' as { 2, 6, 8, 16}. B' as {12, 18}, (AUB)' as ∅ and A' U B' as {2, 6, 8, 12, 16, 18}.

We are given the sets as:

U= { 2, 4, 6, 8, 10, 12, 14, 16, 18}

A = {4, 10, 12, 14, 18}

B = { 2, 4, 6, 8, 10, 14, 16}

We first will find out A':

A' = U - A

A' = { 2, 4, 6, 8, 10, 12, 14, 16, 18}  - {4, 10, 12, 14, 18}

A' = { 2, 6, 8, 16}

Now, we will find B':

B' = U - B

B' = { 2, 4, 6, 8, 10, 12, 14, 16, 18}  - { 2, 4, 6, 8, 10, 14, 16}

B' = { 12, 18}

Now, we have to find:

(AUB)' = U - (AUB)

AUB = {4, 10, 12, 14, 18} U { 2, 4, 6, 8, 10, 14, 16}

AUB = { 2, 4, 6, 8, 10, 12, 14, 16, 18}  = U

(AUB)' = U - U = ∅.

Now, we will find A' U B':

A' U B' = { 2, 6, 8, 16} U { 12, 18}

A' U B' = {2, 6, 8, 12, 16, 18}

Therefore, we get A' as { 2, 6, 8, 16}. B' as {12, 18}, (AUB)' as ∅ and A' U B' as {2, 6, 8, 12, 16, 18}.

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The sphere's equation that passes through the given point is:

To find the equation of the sphere:

So,

Now,

[tex]\begin{aligned}&=\sqrt{\left(x_c-x_p\right)^2+\left(y_c-y_p\right)^2+\left(z_c-z_p\right)^2} \\&=\sqrt{(3-4)^2+(8-3)^2+(1-(-1))^2} \\&=\sqrt{(-1)^2+(5)^2+(2)^2} \\&=\sqrt{1+25+4} \\\therefore r &=\sqrt{30}\end{aligned}[/tex]

Supplement the center point and radius into the standard sphere equation:

[tex]\left(x-x_c\right)^2+\left(y-y_c\right)^2+\left(z-z_c\right)^2=r^2\\(x-3)^2+(y-8)^2+(z-1)^2=(\sqrt{30})^2\\(x-3)^2+(y-8)^2+(z-1)^2=30[/tex]

Therefore, the sphere's equation that passes through the given point is:

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The correct question is given below;

Find an equation of the sphere that passes through the point (4, 3,−1) and has to center (3, 8, 1).

[tex]111.2[/tex]

Step-by-step explanation:

As per the question, 15 times 15 i.e. 225

[tex]15 \times 15 = 225[/tex]

225 divide by 20 i.e. 11.25

[tex] \frac{225}{20} = 11.25[/tex]

take away five from the 11.25 then it will be 11.2

Add 100 to 11.2 i.e

[tex]11.2 + 100 = 111.2[/tex]

Answer: 115

Step-by-step explanation:

[tex]\displaystyle\\\frac{15*15}{20-5} +100=\\\\\frac{15*15}{15} +100=\\\\15+100=\\\\115[/tex]