Required wavelength is λ = 0.0119 nm
The Compton effect in physics is defined as the phenomenon that arises when a specific beam is dispersed on a specific particle with an increase in wavelength.
Equation :Given;
The campton scattering is k = 30 kev
The speed of light is c = 2.9979 X 10 ⁸ m/s
The planck's constant is h = 6.626 X 10⁻³⁴
The expression from Campton shift is given by,
λ' - λ = λc (1 - Cos∅)
Here, ∅ is the angle of scattering whose value is 180° for maximum energy transfer and λc is the campton wavelength whose value is
λc = h/mc
substitute the values in the above expression
λ' - λ = λc (1 - Cos 180°)
λ' - λ = 2 (h/mc)
Here, m is the mass of electron
On rearing the above expression
λ' = λ + 2 (h/mc)
The expression from conservation of energy is given by,
E - E' = k
(hc/λ) - (hc/λ') = k
hc((λ' - λ)/λλ') = k
hc ((λ' - λ)/k) = λλ'
Here E and E' are the initial and final energy of electron
substitute the values in the above equation
hc (2(h/mc)/k)) = λ (λ + 2 (h/mc))
λ² + (2h/mc)λ - 2h²/mk = 0
λ² + [tex]\frac{2(6.626X10^{-34}Js)}{(9.11X10^{-31}kg) (2.997X10^{8}m/s ) }[/tex] λ - [tex]\frac{2(6.626X10^{-34}Js)}{(9.11X10^{-31}kg) (30X10^{3}evX\frac{1.6X10^{-19} }{1ev} J) }[/tex] = 0
λ² + (4.85X10⁻¹²)λ - (2X10⁻²²) = 0
On solving the above expression
λ = 1.19 X 10⁻¹¹ m
λ = (1.19 X 10⁻¹¹ m X 10⁹ nm/1m)
λ = 0.0119 m
Thus, required wavelength is λ = 0.0119 nm
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I need some serious help, i do not understand this question!!
An Alaskan rescue plane traveling 47 m/s
drops a package of emergency rations from
a height of 179 m to a stranded party of
explorers.
The acceleration of gravity is 9.8 m/s^2
Where does the package strike the ground
relative to the point directly below where it
was released?
Answer in units of m.
The position where the package strikes the ground is 136.3m.
Time of motion of the package
Use the following kinematic equation;
h = vt + ¹/₂gt²
179 = 47t + ¹/₂(9.8)t²
179 = 47t + 4.9t²
4.9t² + 47t - 179 = 0
solve the quadratic equation using formula method;
a = 4.9, b = 47, c = -179
t = 2.9 seconds
Horizontal distance traveled by the packageX = vt
X = 47m/s x 2.9 s
X = 136.3 m
Thus, the position where the package strikes the ground is 136.3m.
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In a first order decomposition, the constant is 0.00702 sec-1. what percentage of the compound has decomposed after 7.1 minutes?
The percentage decomposed in the first order reaction is 69.8%.
What percentage of the compound has decomposed after 7.1 seconds?Given: rate constant, k = 0.00702 sec -1
time, t = 7.1 s
Since the reaction is first order, we calculate using the formula below:
[A] = [A]₀ [tex]$$e^{(-kt)[/tex]
Where; [A] is the final concentration
[A]₀ is the initial concentration
Finding the ratio of final and initial concentration
[A]/[A]₀ =[tex]$$ e^{(-kt)[/tex]
Substituting the values:
[A]/[A]₀ = [tex]e^{(-0.00702 * 7.1)[/tex]
[A]/[A]₀ = [tex]e^{(-0.0498)[/tex]
[A]/[A]₀ = 0.9514
Percentage decomposed = [A]/[A]₀ [tex]*[/tex] 100%
Percentage decomposed = 0.9514 [tex]*[/tex] 100%
Percentage decomposed = 95.1 %
Therefore, the percentage decomposed in the first-order reaction is 95.1 %.
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The equatorial diameter of neptune is 49,528 kilometers. if a kilometer equals 0.6214 mi, what is neptune's diameter in miles?
Neptune's equatorial diameter is 49,528 kilometers, and as one kilometers is equivalent to 0.6214 miles, its diameter in miles is 30776.69 miles.
What is an equator?The Northern and Southern hemispheres of the planet are separated by the Equator, a circle of latitude with a radius of 40,075 km (24,901 mi). Halfway between the North and South poles, at 0 degrees latitude, is a fictitious line.
The equator of a spinning spheroid, such as a planet, is the parallel (circle of latitude) where latitude is defined to be 0° in astronomical (3D) spatial geometry. It is a fictitious line that divides the spheroid into its northern and southern hemispheres and runs parallel to its poles. In other words, it is the point where the spheroid intersects with the plane that is perpendicular to its axis of rotation and centered between its poles.
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What is the magnitude of the acceleration of the moon towards the earth? 3.0 m/s2 0.003 m/s2 30 km/s2 3.0 km/s2
The magnitude of the acceleration of the moon towards the earth is 0.003 [tex]m/s^2[/tex].
The acceleration means the rate with which the velocity of an object changes.
The time the moon takes to complete one revolution, t = 27.3 days = 2358720 s
The distance travelled in circular path, d = [tex]2\pi r[/tex] = [tex]24015\times 10^8[/tex] m
where radius r = [tex]3.844\times 10^8[/tex] m
The formula in circular motion is :
[tex]a=\frac{v^2}{r}[/tex]
[tex]v=\frac{d}{t}[/tex]
So substituting the values:
[tex]a=\frac{(1.024\times 10^3)^2}{3.844\times 10^8}[/tex]
[tex]a\approx 2.8\times 10^{-3} \ m/s^2[/tex]
[tex]\therefore a\approx 0.003 \ m/s^2[/tex]
The value of the acceleration of the moon towards the earth is 0.003 [tex]m/s^2[/tex].
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A particle moves in a straight line with the velocity function v ( t ) = sin ( w t ) cos 3 ( w t ) . find its position function x = f ( t ) if f ( 0 ) = 0 .
Integrating the velocity equation, we will see that the position equation is:
[tex]$f(t)=\frac{\cos ^3(\omega t)-1}{3}[/tex]
How to get the position equation of the particle?Let the velocity of the particle is:
[tex]$v(t)=\sin (\omega t) * \cos ^2(\omega t)[/tex]
To get the position equation we just need to integrate the above equation:
[tex]$f(t)=\int \sin (\omega t) * \cos ^2(\omega t) d t[/tex]
[tex]$\mathrm{u}=\cos (\omega \mathrm{t})[/tex]
Then:
[tex]$d u=-\sin (\omega t) d t[/tex]
[tex]\Rightarrow d t=-d u / \sin (\omega t)[/tex]
Replacing that in our integral we get:
[tex]$\int \sin (\omega t) * \cos ^2(\omega t) d t$[/tex]
[tex]$-\int \frac{\sin (\omega t) * u^2 d u}{\sin (\omega t)}-\int u^2 d t=-\frac{u^3}{3}+c$[/tex]
Where C is a constant of integration.
Now we remember that [tex]$u=\cos (\omega t)$[/tex]
Then we have:
[tex]$f(t)=\frac{\cos ^3(\omega t)}{3}+C[/tex]
To find the value of C, we use the fact that f(0) = 0.
[tex]$f(t)=\frac{\cos ^3(\omega * 0)}{3}+C=\frac{1}{3}+C=0[/tex]
C = -1 / 3
Then the position function is:
[tex]$f(t)=\frac{\cos ^3(\omega t)-1}{3}[/tex]
Integrating the velocity equation, we will see that the position equation is:
[tex]$f(t)=\frac{\cos ^3(\omega t)-1}{3}[/tex]
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By default setting, the word stored at address 0x8004 is: _______________________
According to the given statement is At address 0x8004, the default data word is 0xA7908CEE.
Briefing:Little Endian method with a word size of 4 Bytes is the default on ARM processors.
Data is stored in the memory bytes at a time, and access is done in words.
The data must be stored in 4 cells because word size is equal to 4 bytes.
i.e., the data word is retrieved in parallel from 4 cells.
Little endian states that lower addresses have lower bytes and higher addresses have higher bytes.
At location 0x8004, the default data word is 0xA7908CEE.
What is little endian data?The sequence in which data is stored in memory is referred to as the "little-endian" convention. According to this convention, the least significant bit (or "littlest" end) is placed at address 0 first, followed by the storage of following bits one at a time.
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make x the subject of 3=x/y-z
Answer: y(3+z)=x
Explanation:
Assuming that you meant 3=x/y-z without y-z being in parenthesis
3=x/y-z
3+z=x/y
y(3+z)=x
Is it possible to have a function f defined on 2,5 and meets the given conditions? f is continous on (2,5) and he range is a bounded interval
F is continuous on (2,5) and the range is provided as a bounded interval
Although not true for all functions listed [2,5], this is conceivable. For instance, the unbounded range of the function f(x)=x3 is (), which is defined and continuous on the interval [2,5].
How do you tell if a function is ongoing over time?When a function is specified at each point along an interval without any gaps, leaps, or interruptions, the interval is said to be continuous for that function.
We say that a function f(x) is continuous on the interval [a, b] if it meets these requirements from x=a to x=b, for instance.
Is the endpoint of a function continuous?At the right endpoint b, a function is continuous if. The reasons why the endpoints are defined individually.
Because only one way can be used to check for continuity, the endpoints are defined independently. The values will not be in the domain and won’t apply to the function if the limit of an endpoint is checked from a side that is outside the domain.
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A ball is thrown vertically upward and then comes back down. During the ball's flight up and down, its velocity and acceleration vectors are?
During the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.
The velocity vector is always in the direction of motion of the object. So, during the ball's flight up its velocity vector is in the upward direction (90°) and during the ball's flight down its velocity vector is in the downward direction (270°).When there is a positive acceleration in the object the acceleration vector is in the direction of motion of the object. When there is a negative acceleration in the object the acceleration vector is in the opposite direction of motion of the object. So, during the ball's flight up its acceleration vector is in the downward direction (270°) and during the ball's flight down its acceleration vector is in the upward direction (90°).Velocity vector is the rate of change of position of an object. Acceleration vector is the rate of change of velocity of an object.
Therefore, during the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.
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A red water balloon is thrown horizontally from the top of a bridge. At the same instant, a yellow water balloon is dropped off the bridge from the same height. Compare the time of fall for the two balloons. Assume air resistance is negligible.
The time of fall for the two balloons is equal.
Here the conditions given resembles a free fall. Since the air resistance is negligible, gravitational force is the only force acting on both the balloons which means the two balloons are falling in a vacuum. In a vacuum, if two objects of different mass are thrown from the same height, both objects will reach the ground at the same time.
Free fall is nothing but a condition in which an object falls solely under the influence of gravity.
Therefore, the time of fall for both yellow and red water balloons is equal no matter the weight where air resistance is negligible.
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positivephysics
A bicyclist, initially at rest, begins pedaling and gaining speed steadily for 7.50s during
which she covers 46.0m.
PREMIUM
What was her final speed?
The final speed of cyclist is 12.27m/s
The following question can be solved using formulas of Motion on one dimension as the motion is in one dimension
We will use the formula
[tex]v^2-u^2=2aS[/tex]
where v is the final velocity
u is the initial velocity
a is the acceleration of the boat
s is the distance in meters
v^2 = 2 x a x S
= 2 x 46 x a
v^2=92a
v=[tex]\sqrt{92a}[/tex]
where a is the acceleration
Now using the formula v= u+ at
and putting value of v in the equation
[tex]\sqrt{92a}[/tex]=a x7.5
squaring both sides,
92a=56.25a^2
a=92/56.25=1.64 m/s^2
Now we know that v= 7.5 a=7..5 x 1.64 =12.27m/s
Hence her final speed is 12.27m/s
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5) In the picture to the right, a wave source is
moving to the right. Measure the wavelengths
recorded by observer A, on the left, and
observer B, on the right.
Do this by measuring 5 wavelengths and
dividing by 5 to get a precise average.
Answer: most likely its going to be 5
Explanation:
because you have to keep it the same
F = (-3.4,7.0), where all components are in newtons. what is the magnitude (in newtons) of f?
The all components of force is F = ( -3.4 i + 7 j ) N which has magnitude of | F | = 7.78 N.
We need to know about vectors to solve this problem. Force is included in the vector which has magnitude and direction. Force can be written as
F = Fx i + Fy j
where F is force, Fx is the force component on the x-axis, Fy is the force component on the y-axis.
From the question above, we know that
F = (-3.4 , 7.0)
Hence the force can be written as
F = ( -3.4 i + 7 j )N
The magnitude of this force can be determined as
| F | = √(Fx² + Fy²)
| F | = √((-3.4)² + 7²)
| F | = √(11.56 + 49)
| F | = 7.78 N
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How many 1/4 cups are in a cup
Answer:
4
Explanation:
if there are 1/4 cups and you need to fill a cup, you need 4
4 x 1/4 = 4/1
4/1 = 1
What is the bulk modulus of oxygen if 39.9 g of oxygen occupies 27.9 l and the speed of sound in the oxygen is 342 m/s?
Bulk modulus of Oxygen is 1.44×10^5 Pa
Given:
mass of Oxygen = 39.9 g
volume of Oxygen = 27.9 l
speed of sound in oxygen = 342 m/s
To Find:
Bulk modulus of Oxygen
Solution:
The density of oxygen gas is
ρ = 0.0399/0.0279 = 1.43 kg/m^3
From v = √B/ρ we find
B = v^2ρ
B = (317 m/s)^2 x (1.43 kg/m^3)
B = 1.44×10^5 Pa
Hence, Bulk modulus of Oxygen is 1.44×10^5 Pa
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The seafloor spreads in opposite directions as magma forces its way upward. Geologists have observed matching, reversed magnetic bands on both sides of this ridge. Which is the best explanation of these matching, reversed bands?
When the Earth's magnetic field reverses, a new stripe, with the new polarity, begins. Such magnetic patterns led to recognition of the occurrence of sea-floor spreading, and they remain some of the strongest evidence for the theory of plate tectonics.
d. the earth experiences cycles of magnetic poles reversingWhy are the magnetic stripes on the sea floor parallel to and symmetrical across the mid-ocean ridge?The specific magnetism of basalt rock is determined by the Earth's magnetic field when the magma is cooling. Scientists determined that the same process formed the perfectly symmetrical stripes on both side of a mid-ocean ridge. The continual process of seafloor spreading separated the stripes in an orderly pattern
With this information, we can conclude that A polarity reversal means that the magnetic North flips to where we know the South Pole is. At the mid-ocean ridge spreading axis.
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Homework Help!! Thsnkyouu
A. The frisbee will remain in the air for 5.88 s
B. The horizontal distance the frisbee will go is 29.4 m
A. How to determine the time the frisbee will remain in the airThe time the frisbee will spend in the air can be obtained as illustrated below:
Height (h) = 169.2 mAcceleration due to gravity (g) = 9.8 m/s²Time (t) =?169.2 = ½gt²
169.2 = ½ × 9.8 × t²
169.2 = 4.9 × t²
Divide both side by 4.9
t² = 169.2 / 4.9
Take the square root of both side
t = √(169.2 / 4.9)
Time = 5.88 s
How to determine the horizontal distanceThe horizontal distance travelled by the frisbee can be obtained as follow:
Initial velocity (u) = 5 m/sTime (t) = 5.88 sHorizontal distance (s) =?s = ut
s = 5 × 5.88
Horizontal distance = 29.4 m
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What is the mass of 2000 ml of an intravenous glucose solution with a density of 1.15 g/ml?
According to the following formula, the answer is 2,300 g or 2.3 kg:
Volume (m)/Mass (m) Equals Density (p) (V)
Here, the density is 1.15 g/mL, allowing the formula described above to result in a mass of 2.00 L:
p=m/V
1.15 g/mL is equal to x g/2.00 L or x g/2,000 mL.
2,000 mL of x g = 1.15 g of g/mL
2.3 kg or 2,300 g for x g.
How many grams of glucose are in a 1000ml bag of glucose 5?Its active ingredient is glucose. This medication includes 50 g of glucose per 1000 ml (equivalent to 55 g glucose monohydrate). 50 mg of glucose is present in 1 ml (equivalent to 55 mg glucose monohydrate). A transparent, nearly colourless solution of glucose in water is what is used in glucose intravenous infusion (BP) at 5% weight-to-volume.
Patients who are dehydrated or who have low blood sugar levels get glucose intravenously. Other medications may be diluted with glucose intravenous infusion before being injected into the body. Other diseases and disorders not covered above may also be treated with it.
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How much charge passes through a radio battery of 9 v if the energy expended is 72 j?
Amount of charge passes through a radio battery
is 8 Coulomb
Given:
voltage of battery = V = 9 v
energy = E = 72 j
To Find:
charge passes through a radio battery = Q
Solution: If voltage, (V) equals Joules per Coulombs (V = J/C) and Amperes (I) equals charge (coulombs) per second (A = Q/t)
It is given by the formula
V = E/Q
Q = E/V = 72 j/9 v
Q = 8 Coulomb
Hence, Amount of charge passes through a radio battery is 8 Coulomb
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Ammonia (nh3) and ammonium ion (nh4 ) can work together as a buffer in living systems. how do they carry out this function?
When modest amounts of strong acids or bases are added to a weak acid (or base), it forms a solution known as a buffer that resists pH changes.
The ammonium buffer, which is an aqueous solution of NH3 (ammonia) and NH4Cl (ammonium chloride), mixed in equal molar ratios, is a typical buffer, as the question implies. This creates an alkaline buffer with a pH of roughly 9.20, or higher than 7. It's interesting to note that as long as your concentrations stay the same, nothing else matters. Since ammonia is a weak base, the equilibrium will be located far to the left:
NH4+(aq) + OH NH3(aq) + H2O(l) (aq)
Additionally, a soluble salt called ammonium chloride will also be present in solution.
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The position of an object that is oscillating on a spring is given by the equation x = (17.4 cm) cos[(5.46 s-1)t]. what is the angular frequency for this motion?
The angular frequency of this motion is 5.46 rad/s.
The oscillation of spring is an example of Simple Harmonic Motion(SHM).
The general equation of an SHM is given by the formula.
X = Acos(wt)
Here A is the amplitude
ω is the angular frequency
T is the time
Comparing the above equation with the given condition,
X = 17.4 cm cos(5.46t)
A = 17.4 cm
ω = 5.46 rad/s
T = 1 s
Hence, the angular frequency of this motion is 5.46 rad/s.
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How many water molecules are present in 222.22 ml sample of water ( molar mass =18.01 g/mol)
7.4304*10²⁴ molecules water molecules are present in 222.22 ml sample of water ( molar mass =18.01 g/mol).
Mass of water = density * volume
=1.00gm/mμ*222.22mol
=222.22gn
No of moles of water = mass/molar mass
no of water molecules/Avogadro no.=12.34 mol
no of water molecules= 12.34 mol * 6.022*10²³ mol
=74.304*10²³ molecules
=7.4304*10²⁴ molecules
so, 7.4304*10²⁴ molecules are present in 222.22 ml of water sample
7.4304*10²⁴ molecules.
Describe a molecule:One or more atoms make up molecules. They may have the same atoms (for example, an oxygen molecule has two oxygen atoms) or different atoms if they have more than one (a water molecule has two hydrogen atoms and one oxygen atom). Proteins and DNA are examples of biological compounds that can contain thousands of atoms.
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Newton did not discover gravity, for early humans discovered that whenever they fell. what newton did discover is that gravity _______.
What Newton discovered is that gravity extends throughout the universe.
What is gravity?The term gravity refers to the force that acts on a body in the universe. It is gravity that makes an object to fall when it is thrown up. The force of gravity acts on every object in the universe and it extends through the universe.
Humans have always known about gravity when they fall from a height and when they threw things up. However, human did not know that gravity extends throughout the universe.
Thus, what Newton discovered is that gravity extends throughout the universe.
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explain the statement, the acceleration of free fall due to gravity on the Earth's equator is 9.78m/s²
This means that at the equator, the force of gravity on a body causes its velocity to increase at the rate of 9.78m/s per second because of acceleration of free fall cohesion.
What is acceleration of free fall cohesion?An object that is falling freely is one that is only being affected by gravity. A free-falling object experiences a downward acceleration of 9.8 m/s/s (on Earth). This specific name is given to the numerical value for an object in free fall because it is such an essential value. The acceleration of any object moving solely as a result of gravity is referred to as the "acceleration of gravity."
This means that at the equator, the force of gravity on a body causes its velocity to increase at the rate of 9.78m/s per second because of acceleration of free fall cohesion.
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Asteroids were recently formed by the collision and breakup of an object orbiting in the asteroid belt. True or false?.
It is false that asteroids were recently formed by the collision and breakup of an object orbiting in the asteroid belt.
Asteroids are stony objects that orbit the sun but are too tiny to be classified as planets. They're also referred to as planetoids or small planets. There are millions of asteroids that range in size from hundreds of kilometers to a few feet. The combined mass of all asteroids is less than that of Earth's moon.
The solar system's makeup is fairly uniform. The combined mass of the planets is substantially less than that of the Sun. The majority of comets have short periods and orbit near the ecliptic plane.
The asteroid belt is a torus-shaped area in the Solar System lying roughly between Jupiter and Mars' orbits. It is home to a large number of solid, irregularly shaped things of various sizes, but far smaller than planets, known as asteroids or minor planets. To distinguish it from other asteroid populations in the Solar System, such as near-Earth asteroids and Trojan asteroids, this asteroid belt is sometimes known as the major asteroid belt or main belt.
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What is the wavelength (in nm) of radiation having a frequency of 2.45 x 1015 hz?
1.22 x 10⁸ nm is the wavelength of radiation.
Steps2.45 x 10⁹ = frequency(v)
3.00 x 10⁸ = speed of light(c)
(3.00 x 10⁸ m/s)/(2.45 x 10⁹ Hz)= 1.22 x 10⁸ nm
1.22 x 10⁸ nm is the wavelength of radiation.
What wavelength is it?A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm) (mm).What is an example of a wavelength?Here are some wavelength examples: Yellow Light is a prime example.The wavelength range of all visible light is 400 to 700 nanometers (nm). The wavelength of yellow light is 570 nanometers or such.
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which four items were invented for moving and working in space This is astrology but it didn't give me an option to put that as the subject.
Answer: Innovations originally designed for space vehicles, including artificial muscle systems, robotic sensors, diamond-joint coatings, and temper foam,
Explanation: make artificial human limbs more functional, durable, comfortable, and life-like.
Juanita's fingertip is 1 centimeter wide and her arm is 60 cm long. what angle, in radians, does her fingertip span in her field of view? (use the formula you chose in the previous step.)
The angle in radians is 1/60.
The corresponding angle should describe a length of 1 cm at a distance of 60 cm from the point of view and that is the sole idea behind this question.To calculate the angle numerically a formula is needed and that should be [tex]s = r \theta[/tex] in which [tex]s[/tex], [tex]r[/tex] & [tex]\theta[/tex] represent the length described at the given distance from the view, that distance just mentioned and the angle the [tex]s[/tex] length subtends at the viewing point.Therefore, simply substituting the available data in that formula yields the required result.[tex]\begin{aligned}\\\small s &= r\theta \\\\\small 1\,cm &=\small 60\,cm\times \theta \\\\\small \theta &=\small \frac{1}{60}\,\text{radians}\end{aligned}[/tex]
Radian is a dimensionless quantity.
Venus is sometimes called:_____.
a. the evening star
b. the early star
c. the late star
The correct option is (a)the evening star.
Venus is sometimes called the evening star.
Briefing :Venus is the final celestial body to withdraw from view at sunrise and the first to appear in the evening sky. It is referred to as the Morning and the Evening star for this reason. Three factors account for Venus's brightness. First of all, it approaches Earth more closely than any other planet. Second, compared to other inner planets, it is very huge, with a diameter that is nearly twice that of Mars and three times that of Mercury. Thirdly, Venus' dense cloud cover entirely scatters much of the light back into space. Venus really reflects more sunlight than any other planet, at 77%. Venus is so brilliant that it may even be seen during the day.Learn more about the venus with the help of the given link:
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1. if a wave traveling through air decreases its wavelength by half, what happens to the wave speed and frequency?
Wave speed decreases by half while the frequency remains constant.
For any wave the equation [tex]v = f \lambda[/tex] holds true.The frequency is a quality of a given wave and it does not change with the external parameters.So, the possibility is for the [tex]v[/tex] and [tex]\lambda[/tex] to change accordingly.Therefore, [tex]v[/tex] and [tex]\lambda[/tex] are directly proportional to each other. Thus when the wavelength decreases by half the speed also decreases by half.This can be shown as follows as well.
[tex]\begin{aligned}\\\small v_1 &=\small f.\lambda_1\quad\cdots\cdots(1)\\\\\small v_2 &=\small f.\frac{\lambda_1}{2}\quad\cdots\cdots(2)\\\\(2)\div&(1)\\\\\small v_2 &=\small \frac{v_1}{2}\end{aligned}[/tex]
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