How many milliliters are in 3.2 L? (1000 mL = 1L)

The final velocity of the ball is16.66 m/s.

Given the following data:

We know that acceleration due to gravity (a) for a ball in free fall is equal to 9.8 meter per seconds square.

To find how fast (velocity) the ball is moving, we would use the first equation of motion:

Mathematically, the first equation of motion is calculated by using the formula;

[tex]V = U + at[/tex]

Where:

Substituting the given parameters into the formula, we have;

[tex]V = 0 + 9.8(1.7)[/tex]

[tex]V = 9.8[/tex] × [tex]1.70[/tex]

Final velocity, V = 16.66 m/s.

Therefore, the final velocity of the ball is16.66 m/s.

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Answer:

The key difference between ionic bonding and metallic bonding is that the ionic bonding takes place between positive and negative ions whereas the metallic bonding takes place between positive ions and electrons.

Explanation:

About (metallic bonding) → Metallic bonding is a type of chemical bonding that arises from the electrostatic attractive force between conduction electrons and positively charged metal ions.

About (ionic bonding) → Ionic bonding is a type of chemical bonding that involves the electrostatic attraction between oppositely charged ions, or between two atoms with sharply different electronegativities, and is the primary interaction occurring in ionic compounds

I hope this helps!

Answer: peeps

Explanation: meaning “people” or “the friends you hang out with”

Answer: Defriend (meaning "to remove someone from a friends list").

Explanation: Just in case someone comes by again like I did..

By Newton's second law, the net vertical force on the block is

∑ F = N - mg = 0

so that the normal force exerted by the surface has magnitude

N = mg = (2.52 kg) (9.80 m/s²) = 24.7 N

Then as the block slides over the surface, it feels a frictional force of

f = µ (24.7 N)

where µ is the coefficient of kinetic friction.

As the block is pushed by the spring to its equilibrium position, friction performs

µ (-24.7 N) (0.0973 m) = -2.40µ J

of work (which is negative because it opposes the block's motion).

In compressing the spring by 9.73 cm = 0.0973 m, we store

1/2 (116 N/m) (0.0973 m)² = 0.549 J

of energy. This energy is released and partially converted to kinetic energy, while the rest is lost to friction.

By the work-energy theorem, the total work performed on the block as the spring pushes it towards the equilibrium position is equal to the change in its kinetic energy:

W = ∆K

0.549 J - 2.40µ J = 1/2 (2.52 kg) v ² - 0

where v is the speed of the block at the equilibrium position. Solving for v, we get

v = 0.891 √(0.549 - 2.40µ) m/s

After the block is released, the only force acting on it as it slides freely is friction. It comes to a stop after 0.537 m, so that friction performs

µ (-24.7 N) (0.537 m) = -13.3µ J

of work.

Using the work-energy theorem again, we have

W = ∆K

-13.3µ J = 0 - 1/2 (2.52 kg) v ²

Substitute the velocity we found in terms of µ, and solve for µ :

-13.3µ J = -1/2 (2.52 kg) (0.891 √(0.549 - 2.40µ) m/s)²

===>   µ = 0.0350

We have that the balanced chemical equation   is mathematically given as.

2Ti_3N + 3MgO → Mg_3N_2 +3Ti_2O

From the question we are told

Ti3N + MgO → Mg3N2 +Ti2O balance chemical equation.

Generally the way to balance an equation is by making all elements present on the Left hand side(LHS) same with the right hand side RHS.

Therefore

The equation is mathematically given as.

We consider the Left hand side(LHS) first.

Then we consider the right hand side RHS.

Therefore the balanced chemical equation   is mathematically given as.

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Answer:

The four types of thermodynamic process are isobaric, isochoric, isothermal and adiabatic.

Answer:

Change volume / volume = .5 / 30 = .01666

coefficient of volume expansion = 3 * 24E-6 = 72E-6

Change in temp = .0167 / 24E-6 = 232 deg C

Final temp = 232 + 30 = 262 deg C

Change in volume / volume = 3 * coeff linear expansion * change in deg C

Answer:

Kelvin is a unit of temperature, whereas ampere is a unit of current.

True or False

Explanation:

true

Answer:

The acceleration is g.

Taking the upward direction as positive

V = Vy y - 1/2 g t^2

Taking the downward direction as positive

V = -V y + 1/2 g t^2

One can choose either direction as positive, but the acceleration is

the same as g (it is g) while the projectile is in the air.

When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). Thus, the correct option is D.

Projectile motion is the motion of an object which is thrown or projected high into the air. After the initial force applied on the object that launches the object, the object only experiences the gravitational force. The object is called a projectile and the path of the object is called trajectory.

When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). When the object achieves highest point, then the vertical acceleration of a projectile is zero meter per second square when it is at the peak of its trajectory motion.

Therefore, the correct option is D.

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#SPJ2

a) Las balas de cañon disparadas desde el puerto deben tener una ángulo de 27.39° para que puedan impactar al barco, con una velocidad inicial de 82 m/s.

b) El tiempo de vuelo de las balas de cañon para alcanzar al barco que está a 560 m de distancia es de 7.69 s.

c) Sabiendo que el ángulo calculado en el inciso a) es para una distancia de 560 m, el barco debe estar a una distancia mayor para que las balas no lo alcancen.

a)

Podemos usar las ecuaciones de tiro parabólico para encontrar el ángulo que permita derribar al barco invasor.

[tex]x=\frac{v_{i}^{2}sin(2\alpha)}{g}[/tex] (1)

Donde:

Lo que debemos hacer es depejar α de la ecuación 1

[tex]sin(2\alpha)=\frac{xg}{v_{i}^{2}}[/tex]

[tex]sin(2\alpha)=\frac{560*9.81}{82^{2}}[/tex]

[tex]sin(2\alpha)=0.82[/tex]

[tex]\alpha=\frac{sin^{-1}(0.82)}{2}[/tex]

[tex]\alpha=27.39^{\circ}[/tex]

Por lo tanto, el ángulo para que el cañón impacte en el barco es de 27.39 °.

b)

Sabemos que la componente de la velocidad en el eje x es constante, así que podemo usar la siguiente ecuación.

[tex]v_{x}=\frac{x}{t}[/tex]

La componente x de la velocidad es V(x) = V(i)cos(α) y sabiendo la distancia total de 560 m, el tiempo será:

[tex]v_{i}cos(\alpha)=\frac{x}{t}[/tex]

[tex]t=\frac{x}{v_{i}cos(\alpha)}[/tex]

[tex]t=\frac{560}{82cos(27.39)}[/tex]

[tex]t=7.69\: s[/tex]

El tiempo total de vuelo de las balas de cañon es de 7.69 s.

c)

Sabemos que el ángulo calculado en el inciso a) es de 27.39 °, y ese valor fue calcualdo para una distancia de 560 m, por lo tanto el barco debe estar a una distancia mayor que esa para que las balas no lo alcancen.

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Espero te haya sido de ayuda!

Answer:

1. Increasing

2. Decreasing

3. Increasing

Explanation:

Answer:

I don speak communism. Could you answer in English?

Explanation:

Answer:

Explanation:

F = mg

F = 75(9.8)

F = 735 N

Answer:

Special Relativity/Newtonian Physics

Explanation:

Well in Newtonian physics you could say your mass is pushing you down and the floor is pushing you up. But rather in Special relativity only to floor is pushing up on you.

In this theory the word inertial observer matters and proves several matters throughout science. So exploring is a huge important thing to do. A person cleaning the window falls, while doing so the person feel weightless while falling. Objects that fall down with the person would remain stationarily, relative to the person. Similar to a person in space. Far away from any large masses the person would be an inertial observer. With no acceleration the person is also not close to gravitational fields and all laws of physics in the person's reference frame. The man falling off the roof is an inertial observer too. Because of this both of the matters about the rocket man and the person falling off the roof are the same.But you would think that the person falling off the roof is accelerating. But the equivalence principle tells us wrong.

The equivalence principle has made it easy to prove both people in the  situations are inertial observers. People watching would think that he is accelerating, but he is not. But he is accelerating? The equivalence principle tells us to focus on the experience of the observer and the person feels weightless so they are an inertial observer. If a person in Space comes across a planet, the person's  rocket will start heading towards a planet. But the Space person would be oblivious. The person would not feel any acceleration. The spaceship would not sense any acceleration nor would it sense that it is turning. A person outside the spaceship may see the slight curving motion and the person inside would not notice until the instant it crashes into the planet. Explaining this is geodesics and spacetime it equally links and connects with this in an obvious and common way.

Spacetime is a model that makes 4D, it joins space and time, ‘Space-time’. Now people can say how it perfectly describes gravity with it’s queer way of curving.

But how does this happen without gravity? Space is 4D with width, breadth, height and time. There is a model called spacetime.  Einstein along with many other people visualise it as woven along with time. Space- time. It  curves by mass distribution. The person is still traveling in a straight line. Just straight through spacetime. It is traveling along the geodesics of spacetime.  This is actually quite common, it is just an object travelling straight on a curved surface. Like an airplane travels straight to get quicker to a different place. But it appears curved because obviously the Earth is curved. So if you unfolded the earth the path would be curved, but the plane  is  still traveling in a straight line. Let’s also say you and your friend were standing on the equator. You are 1000 kilometers  apart from your friend. As you move towards the north direction you would eventually meet with your friend. You are not being pushed by gravity but simple as that you are just traveling on the geodesics of Earth.  Matter tells spacetime how to curve, Spacetime tells matter how to move-John Wheeler.

The man falling off the roof was accelerating so what happens if the rocket man accelerates?

Now once the rocket man accelerates the floor accelerates into rocket man. Objects remain stationary but the floor also accelerates into the objects. The situation is just like on earth except you are not an inertial observer because you do not feel weightless. The observer inside the rocket would feel a force pushing up on the feet. Same on earth. You are accelerating in order to remain stationary. However you can not see yourself accelerating. In Newton’s rule the force of Gravity would be pushing you down and the ground pushing you up. However in special relativity gravity does not exist so it’s just the force of the ground pushing up on you. Just like the rocket accelerating. You look like you are not accelerating up but only in your frame of reference. To measure your speed of acceleration you must get an inertial observer to measure your acceleration speed. Like the man falling off the roof. Let’s say you are in the building and the man falls off the roof. To him you would appear accelerating upwards. So you have to accelerate just to stand still. Why all objects fall at the same rate is a mystery to Newtonian Physics but it is not a mystery to Special relativity because the objects are not accelerating just the floor accelerating into it.

So I hope you understand now, I think you know what I'm getting at. Might of misunderstood your question.

Answer:

I want to say a because you want to subtract and simplify

1. 5 WBC's per cubic millimeter.

3. 50 to 80 mg/100 mL

4. 15 to 60 milligrams per deciliter (mg/dL) or 0.15 to 0.6 milligrams per milliliter (mg/mL)

If a test were to be performed here are normal results:

Normal values typically range as follows:

Pressure: 70 to 180 mm H2O

Appearance: clear, colorless

CSF total protein: 15 to 60 mg/100 mL

Gamma globulin: 3% to 12% of the total protein

CSF glucose: 50 to 80 mg/100 mL (or greater than two thirds of blood sugar level)

CSF cell count: 0 to 5 white blood cells (all mononuclear), and no red blood cells

Chloride: 110 to 125 mEq/L

(Source: https://medlineplus.gov/ency/article/003428.htm)

Answer:

98.7 seconds

Explanation:

I believe the answer is not 0.055s

Both trains have the same speed and are approaching each other.

They both have to cover 8.5km, and since they are going the same speed they need to cover half the distance each (4.25km)

So, how long will it take a train going 155km/h to travel 4.25km?

The ratio of

There are 60 x 60 seconds in one hour (3600 seconds)

[tex]\frac{155km}{3600 seconds} = \frac{4.25km}{x seconds}[/tex]

Solve for x to get 98.7 seconds

We can do this by flipping both sides of the ratio

[tex]\frac{3600 s}{155 km} = \frac{x seconds}{4.25 km}[/tex]

Multiply both sides by 4.25km

4.25 ×  [tex]\frac{3600 s}{155 km} ={x seconds}[/tex]

Our unknown x = 98.7 seconds

Answer:

C

Explanation:

C

Answer:

Taking force, length and time as fundamental quantity.

Momentum=mv(Force/acceleration)×Velocity =[F/LT

−2

]×[LT

−1

]=[FT]

The displacement of your motion during the entire motion is 22.5 m

The given parameters;

The displacement of your motion during the entire motion is calculated from your average velocity and time of motion.

This magnitude of this displacement is calculated  as follows;

[tex]s = (\frac{u+ v}{2} )t\\\\s = (\frac{1.5 + 3}{2} ) \times 10\\\\s = 22.5 \ m[/tex]

Thus, the displacement of your motion during the entire motion is 22.5 m.

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Elliptical galaxies are galaxies that are shaped like an ellipse. An ellipse is oval in shape, which means elliptical galaxies are oval in shape.

The two correct statements that describe elliptical galaxies are:

B. They are the most common galaxy type.

C. They typically contain very little gas and dust.

Therefore, from the above explanation, we can see that option B and C is the correct option.

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The statements which describes elliptical galaxies are Choice B and Choice C:

Ultimately, elliptical galaxies are the oldest and are the most common galaxy type and they typically contain very little gas and dust.

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Answer:

Explanation:

F = kQq/r²

r = √(kQq/F)

a)  r = √(8.899(10⁹)(8)(4) / 18(10¹³)) = 0.0397749... m

  r = 40 mm

b) r = √(8.899(10⁹)(12)(3) / 18(10¹³)) = 0.0421876... m

   r = 42 mm

The characteristics of the Big Bang allow you to find the correct answers for the different questions are:

1.  The galaxies are moving away from each other.

2.  There is a large amount of weak background radiation in the universe

3. The temperature of the universe has cooled over time

The Big Bang model says that initially the universe was born from a great initial explosion about 14 10⁹ years ago, with this idea several facts arise:

Let's apply these ideas to the different questions, to find the correct answers.

1) What phrase about galaxies provides evidence of the expansion of the universe proposed by the Big Bang

the correct answer is:

As there is no friction, the initial forces create a speed in the galaxies, therefore they must move away from each other at this speed

2) What phrases give evidence of the expansion of the universe

the correct answer is:

3) What evidence of expansion

In conclusion with the characteristics of the Big Bang we can find the correct answers for the different questions are:

    1.  The galaxies are moving away from each other.

    2.  There is a large amount of weak background radiation in the universe

   3. The temperature of the universe has cooled over time

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Answer:

short teeth, short hair, camoflauge, and speed

Explanation:

Answer:

speed and awareness

Explanation:

Answer:

None of the above

Explanation:

None of the above