How deep under the surface of a lake would the pressure be double that at the surface?

The time of fall for the two balloons is equal.

Here the conditions given resembles a free fall. Since the air resistance is negligible, gravitational force is the only force acting on both the balloons which means the two balloons are falling in a vacuum. In a vacuum, if two objects of different mass are thrown from the same height, both objects will reach the ground at the same time.

Free fall is nothing but a condition in which an object falls solely under the influence of gravity.

Therefore, the time of fall for both yellow and red water balloons is equal no matter the weight where air resistance is negligible.

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1.22 x 10⁸ nm is the wavelength of radiation.

2.45 x 10⁹ = frequency(v)

3.00 x 10⁸ = speed of light(c)

(3.00 x 10⁸ m/s)/(2.45 x 10⁹ Hz)= 1.22 x 10⁸ nm

1.22 x 10⁸ nm is the wavelength of radiation.

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A. The frisbee will remain in the air for 5.88 s

B. The horizontal distance the frisbee will go is 29.4 m

The time the frisbee will spend in the air can be obtained as illustrated below:

169.2 = ½gt²

169.2 = ½ × 9.8 × t²

169.2 = 4.9 × t²

Divide both side by 4.9

t² = 169.2 / 4.9

Take the square root of both side

t = √(169.2 / 4.9)

Time = 5.88 s

The horizontal distance travelled by the frisbee can be obtained as follow:

s = ut

s = 5 × 5.88

Horizontal distance = 29.4 m

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When modest amounts of strong acids or bases are added to a weak acid (or base), it forms a solution known as a buffer that resists pH changes.

The ammonium buffer, which is an aqueous solution of NH3 (ammonia) and NH4Cl (ammonium chloride), mixed in equal molar ratios, is a typical buffer, as the question implies. This creates an alkaline buffer with a pH of roughly 9.20, or higher than 7. It's interesting to note that as long as your concentrations stay the same, nothing else matters. Since ammonia is a weak base, the equilibrium will be located far to the left:

NH4+(aq) + OH NH3(aq) + H2O(l) (aq)

Additionally, a soluble salt called ammonium chloride will also be present in solution.

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Here is the difference between contact forces and non-contact forces:

Contact forces are forces that result from two objects coming into physical contact with each other. Non-contact forces are forces that result from the interaction of objects that are not in contact with each other.

Wave speed decreases by half while the frequency remains constant.

                           [tex]\begin{aligned}\\\small v_1 &=\small f.\lambda_1\quad\cdots\cdots(1)\\\\\small v_2 &=\small f.\frac{\lambda_1}{2}\quad\cdots\cdots(2)\\\\(2)\div&(1)\\\\\small v_2 &=\small \frac{v_1}{2}\end{aligned}[/tex]

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Answer: Innovations originally designed for space vehicles, including artificial muscle systems, robotic sensors, diamond-joint coatings, and temper foam,

Explanation: make artificial human limbs more functional, durable, comfortable, and life-like.

7.4304*10²⁴ molecules water molecules are present in 222.22 ml sample of water ( molar mass =18.01 g/mol).

Mass of water = density * volume

=1.00gm/mμ*222.22mol

=222.22gn

No of moles of water = mass/molar mass

no of water molecules/Avogadro  no.=12.34 mol

no of water molecules= 12.34 mol * 6.022*10²³ mol

=74.304*10²³ molecules

=7.4304*10²⁴ molecules

so, 7.4304*10²⁴ molecules are present in 222.22 ml of water sample

7.4304*10²⁴ molecules.

One or more atoms make up molecules. They may have the same atoms (for example, an oxygen molecule has two oxygen atoms) or different atoms if they have more than one (a water molecule has two hydrogen atoms and one oxygen atom). Proteins and DNA are examples of biological compounds that can contain thousands of atoms.

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What Newton discovered is that  gravity extends throughout the universe.

The term gravity refers to the force that acts on a body in the universe. It is gravity that makes an object to fall when it is thrown up. The force of gravity acts on every object in the universe and it extends through the universe.

Humans have always known about gravity when they fall from a height and when they threw things up. However, human did not know that gravity extends throughout the universe.

Thus, what Newton discovered is that  gravity extends throughout the universe.

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The position where the package strikes the ground is 136.3m.

Use the following kinematic equation;

h = vt + ¹/₂gt²

179 = 47t  +  ¹/₂(9.8)t²

179 = 47t + 4.9t²

4.9t² + 47t - 179 = 0

solve the quadratic equation using formula method;

a = 4.9, b = 47, c = -179

t = 2.9 seconds

X = vt

X = 47m/s x 2.9 s

X = 136.3 m

Thus, the position where the package strikes the ground is 136.3m.

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The angular frequency of this motion is 5.46 rad/s.

The oscillation of spring is an example of Simple Harmonic Motion(SHM).

The general equation of an SHM is given by the formula.

X = Acos(wt)

Here A is the amplitude

ω is the angular frequency

T is the time

Comparing the above equation with the given condition,

X = 17.4 cm cos(5.46t)

A = 17.4 cm

ω = 5.46 rad/s

T = 1 s

Hence, the angular frequency of this motion is 5.46 rad/s.

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Answer:

4

Explanation:

if there are 1/4 cups and you need to fill a cup, you need 4
4 x 1/4 = 4/1
4/1 = 1

The percentage decomposed in the first order reaction is 69.8%.

Given: rate constant, k = 0.00702 sec -1

time, t = 7.1 s

Since the reaction is first order, we calculate using the formula below:

[A] = [A]₀ [tex]$$e^{(-kt)[/tex]

Where; [A] is the final concentration

[A]₀ is the initial concentration

Finding the ratio of final and initial concentration

[A]/[A]₀ =[tex]$$ e^{(-kt)[/tex]

Substituting the values:

[A]/[A]₀ = [tex]e^{(-0.00702 * 7.1)[/tex]

[A]/[A]₀ = [tex]e^{(-0.0498)[/tex]

[A]/[A]₀ = 0.9514

Percentage decomposed = [A]/[A]₀ [tex]*[/tex] 100%

Percentage decomposed = 0.9514 [tex]*[/tex] 100%

Percentage decomposed = 95.1 %

Therefore, the percentage decomposed in the first-order reaction is 95.1 %.

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Answer: most likely its going to be 5

Explanation:

because you have to keep it the same

It is false that asteroids were recently formed by the collision and breakup of an object orbiting in the asteroid belt.

Asteroids are stony objects that orbit the sun but are too tiny to be classified as planets. They're also referred to as planetoids or small planets. There are millions of asteroids that range in size from hundreds of kilometers to a few feet. The combined mass of all asteroids is less than that of Earth's moon.

The solar system's makeup is fairly uniform. The combined mass of the planets is substantially less than that of the Sun. The majority of comets have short periods and orbit near the ecliptic plane.

The asteroid belt is a torus-shaped area in the Solar System lying roughly between Jupiter and Mars' orbits. It is home to a large number of solid, irregularly shaped things of various sizes, but far smaller than planets, known as asteroids or minor planets. To distinguish it from other asteroid populations in the Solar System, such as near-Earth asteroids and Trojan asteroids, this asteroid belt is sometimes known as the major asteroid belt or main belt.

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The angle in radians is 1/60.

                  [tex]\begin{aligned}\\\small s &= r\theta \\\\\small 1\,cm &=\small 60\,cm\times \theta \\\\\small \theta &=\small \frac{1}{60}\,\text{radians}\end{aligned}[/tex]

According to the following formula, the answer is 2,300 g or 2.3 kg:

Volume (m)/Mass (m) Equals Density (p) (V)

Here, the density is 1.15 g/mL, allowing the formula described above to result in a mass of 2.00 L:

p=m/V

1.15 g/mL is equal to x g/2.00 L or x g/2,000 mL.

2,000 mL of x g = 1.15 g of g/mL

2.3 kg or 2,300 g for x g.

Its active ingredient is glucose. This medication includes 50 g of glucose per 1000 ml (equivalent to 55 g glucose monohydrate). 50 mg of glucose is present in 1 ml (equivalent to 55 mg glucose monohydrate). A transparent, nearly colourless solution of glucose in water is what is used in glucose intravenous infusion (BP) at 5% weight-to-volume.

Patients who are dehydrated or who have low blood sugar levels get glucose intravenously. Other medications may be diluted with glucose intravenous infusion before being injected into the body. Other diseases and disorders not covered above may also be treated with it.

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Bulk modulus of Oxygen is 1.44×10^5 Pa

Given:

mass of Oxygen = 39.9 g

volume of Oxygen = 27.9 l

speed of sound in oxygen = 342 m/s

To Find:

Bulk modulus of Oxygen

Solution:

The density of oxygen gas is

ρ = 0.0399/0.0279 = 1.43 kg/m^3

From v = √B/ρ we find

B = v^2ρ

B = (317 m/s)^2 x (1.43 kg/m^3)

B = 1.44×10^5 Pa

Hence, Bulk modulus of Oxygen is 1.44×10^5 Pa

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Neptune's equatorial diameter is 49,528 kilometers, and as one kilometers is equivalent to 0.6214 miles, its diameter in miles is 30776.69 miles.

The Northern and Southern hemispheres of the planet are separated by the Equator, a circle of latitude with a radius of 40,075 km (24,901 mi). Halfway between the North and South poles, at 0 degrees latitude, is a fictitious line.

The equator of a spinning spheroid, such as a planet, is the parallel (circle of latitude) where latitude is defined to be 0° in astronomical (3D) spatial geometry. It is a fictitious line that divides the spheroid into its northern and southern hemispheres and runs parallel to its poles. In other words, it is the point where the spheroid intersects with the plane that is perpendicular to its axis of rotation and centered between its poles.

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The magnitude of the acceleration of the moon towards the earth is 0.003 [tex]m/s^2[/tex].

The acceleration means the rate with which the velocity of an object changes.

The time the moon takes to complete one revolution, t = 27.3 days = 2358720 s

The distance travelled in circular path, d = [tex]2\pi r[/tex] = [tex]24015\times 10^8[/tex] m

where radius r = [tex]3.844\times 10^8[/tex] m

The formula in circular motion is :

[tex]a=\frac{v^2}{r}[/tex]

[tex]v=\frac{d}{t}[/tex]

So substituting the values:

[tex]a=\frac{(1.024\times 10^3)^2}{3.844\times 10^8}[/tex]

[tex]a\approx 2.8\times 10^{-3} \ m/s^2[/tex]

[tex]\therefore a\approx 0.003 \ m/s^2[/tex]

The value of the acceleration of the moon towards the earth is 0.003 [tex]m/s^2[/tex].

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According to the given statement is  At address 0x8004, the default data word is 0xA7908CEE.

Little Endian method with a word size of 4 Bytes is the default on ARM processors.

Data is stored in the memory bytes at a time, and access is done in words.

The data must be stored in 4 cells because word size is equal to 4 bytes.

i.e., the data word is retrieved in parallel from 4 cells.

Little endian states that lower addresses have lower bytes and higher addresses have higher bytes.

At location 0x8004, the default data word is 0xA7908CEE.

The sequence in which data is stored in memory is referred to as the "little-endian" convention. According to this convention, the least significant bit (or "littlest" end) is placed at address 0 first, followed by the storage of following bits one at a time.

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The final speed of cyclist is 12.27m/s

The following question can be solved using formulas of Motion on one dimension as the motion is in one dimension

We will use the formula

[tex]v^2-u^2=2aS[/tex]

where v is the final velocity

u is the initial velocity

a is the acceleration of the boat

s is the distance in meters

v^2 = 2 x a x S

       = 2 x 46 x a

v^2=92a

v=[tex]\sqrt{92a}[/tex]

where a is the acceleration

Now using the formula v= u+ at

and putting value of v in the equation

[tex]\sqrt{92a}[/tex]=a x7.5

squaring both sides,

92a=56.25a^2

a=92/56.25=1.64 m/s^2

Now we know that v= 7.5 a=7..5 x 1.64 =12.27m/s

Hence her final speed is 12.27m/s

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F is continuous on (2,5) and the range is provided as a bounded interval

Although not true for all functions listed [2,5], this is conceivable. For instance, the unbounded range of the function f(x)=x3 is (), which is defined and continuous on the interval [2,5].

When a function is specified at each point along an interval without any gaps, leaps, or interruptions, the interval is said to be continuous for that function.

We say that a function f(x) is continuous on the interval [a, b] if it meets these requirements from x=a to x=b, for instance.

At the right endpoint b, a function is continuous if. The reasons why the endpoints are defined individually.

Because only one way can be used to check for continuity, the endpoints are defined independently. The values will not be in the domain and won’t apply to the function if the limit of an endpoint is checked from a side that is outside the domain.

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Integrating the velocity equation, we will see that the position equation is:

[tex]$f(t)=\frac{\cos ^3(\omega t)-1}{3}[/tex]

Let the velocity of the particle is:

[tex]$v(t)=\sin (\omega t) * \cos ^2(\omega t)[/tex]

To get the position equation we just need to integrate the above equation:

[tex]$f(t)=\int \sin (\omega t) * \cos ^2(\omega t) d t[/tex]

[tex]$\mathrm{u}=\cos (\omega \mathrm{t})[/tex]

Then:

[tex]$d u=-\sin (\omega t) d t[/tex]

[tex]\Rightarrow d t=-d u / \sin (\omega t)[/tex]

Replacing that in our integral we get:

[tex]$\int \sin (\omega t) * \cos ^2(\omega t) d t$[/tex]

[tex]$-\int \frac{\sin (\omega t) * u^2 d u}{\sin (\omega t)}-\int u^2 d t=-\frac{u^3}{3}+c$[/tex]

Where C is a constant of integration.

Now we remember that [tex]$u=\cos (\omega t)$[/tex]

Then we have:

[tex]$f(t)=\frac{\cos ^3(\omega t)}{3}+C[/tex]

To find the value of C, we use the fact that f(0) = 0.

[tex]$f(t)=\frac{\cos ^3(\omega * 0)}{3}+C=\frac{1}{3}+C=0[/tex]

C = -1 / 3

Then the position function is:

[tex]$f(t)=\frac{\cos ^3(\omega t)-1}{3}[/tex]

Integrating the velocity equation, we will see that the position equation is:

[tex]$f(t)=\frac{\cos ^3(\omega t)-1}{3}[/tex]

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Answer: y(3+z)=x

Explanation:

Assuming that you meant 3=x/y-z without y-z being in parenthesis

3=x/y-z

3+z=x/y

y(3+z)=x

When the Earth's magnetic field reverses, a new stripe, with the new polarity, begins. Such magnetic patterns led to recognition of the occurrence of sea-floor spreading, and they remain some of the strongest evidence for the theory of plate tectonics.

The specific magnetism of basalt rock is determined by the Earth's magnetic field when the magma is cooling. Scientists determined that the same process formed the perfectly symmetrical stripes on both side of a mid-ocean ridge. The continual process of seafloor spreading separated the stripes in an orderly pattern

With this information, we can conclude that A polarity reversal means that the magnetic North flips to where we know the South Pole is. At the mid-ocean ridge spreading axis.

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The correct option is (a)the evening star.

Venus is sometimes called the evening star.

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This means that at the equator, the force of gravity on a body causes its velocity to increase at the rate of 9.78m/s per second because of acceleration of free fall cohesion.

An object that is falling freely is one that is only being affected by gravity. A free-falling object experiences a downward acceleration of 9.8 m/s/s (on Earth). This specific name is given to the numerical value for an object in free fall because it is such an essential value. The acceleration of any object moving solely as a result of gravity is referred to as the "acceleration of gravity."

This means that at the equator, the force of gravity on a body causes its velocity to increase at the rate of 9.78m/s per second because of acceleration of free fall cohesion.

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During the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.

Velocity vector is the rate of change of position of an object. Acceleration vector is the rate of change of velocity of an object.

Therefore, during the ball's flight up its velocity and acceleration vectors are in opposite direction and during the ball's flight down its velocity and acceleration vectors are in same direction.

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Amount of charge passes through a radio battery

is 8 Coulomb

Given:

voltage of battery = V = 9 v

energy = E = 72 j

To Find:

charge passes through a radio battery = Q

Solution: If voltage, (V) equals Joules per Coulombs (V = J/C) and Amperes (I) equals charge (coulombs) per second (A = Q/t)

It is given by the formula

V = E/Q

Q = E/V = 72 j/9 v

Q = 8 Coulomb

Hence, Amount of charge passes through a radio battery is 8 Coulomb

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