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Find the scale if:

The angles EFG and GFH are 71 and 109 degrees

The given parameters are:

EFG =2n + 25

GFH = 4n + 17

Linear pair angles are supplementary angles

So,we have

2n + 25 +4n + 17 = 180

Evaluate the like terms

6n= 138

Divide by 6

n = 23

Substitute n = 23 in EFG =2n + 25 and GFH = 4n + 17

EFG = 2 * 23 + 25 =71

GFH = 4 * 23 + 17 = 109

Hence, the angles EFG and GFH are 71 and 109 degrees

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Based on the given parameters, the numerical length of PT is 9 units

The given parameters are:

P is a point on ST such that P is between S and T.

SP = x + 3,

PT = 2x - 1

ST = 17

The statement "P is a point on ST such that P is between S and T" implies that

ST = SP + PT

Substitute the known values in the above equation

17 = x + 3 + 2x - 1

Evaluate the like terms

17 = 3x + 2

Add 2 to both sides of the equation

3x = 15

Divide both sides of the equation by 3

So, we have

x = 5

Substitute x = 5 in PT = 2x - 1

So, we have

PT = 2 x 5 - 1

Evaluate

PT = 9

Hence, the numerical length of PT is 9 units

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Answer:

Commutative property because it states that the numbers can be moved around or swapped from their position without making any difference to the answer.

Answer: -12 7/24

Step-by-step explanation:

Convert the mixed numbers to fractions (59/8 and -5/3) then multiply across to get -295/24. Simplify for -12 7/24.

Hope this helps :)

Answer: decimal -12.29  fraction -295/24

Step-by-step explanation:

Answer: 0.05t ==> 1st blank

1 ==> 2nd blank

-0.1t+6 ==> 3rd blank

Step-by-step explanation:

The Distance between city C and city D is 5405 miles.

Given that Distance from city a to city b is 3003 miles less than the Distance fron city c to city d, the total of these two Distance is 7807 miles and asked to find Distance between  city C and city D.

Given that,

(d-c)-(b-a)=3,003 miles { (Distance between city D and city C)-(Distance between city A and city B)} Let's assume it as equation A

(d-c)+(b-a)=7,807 miles { (Distance between city D and city C)+(Distance between city A and city B)} Let's assume it as equation B

Add equation A and B

2(d-c)=10,810

(d-c)=5,405

Hence,Distance between city D and city C is 5,405

Therefore,The Distance between city C and city D is 5405 miles.

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Given the mass and volume of the sample, the density of the copper sample is approximately 8.91 g/cm².

The density of a substance is simply the mass of that substance per unit of its volume.

Density is expressed mathematically as;

Density = Mass / Volume.

Given the data in the question;

Plug the given values into the formula above and solve for density.

Density = Mass / Volume

Density = 15.6 g / 1.75 cm³

Density = 8.91 g/cm²

Given the mass and volume of the sample, the density of the copper sample is approximately 8.91 g/cm².

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Answer:

[tex]\frac{27}{20}[/tex]

Step-by-step explanation:

[tex]\frac{3}{5} + \frac{6}{8}[/tex]

adjust the denominators;

= [tex]\frac{3*8}{5*8} + \frac{6*5}{8*5}[/tex]

[tex]=\frac{24}{40} + \frac{30}{40} \\\\=\frac{24+30}{40} \\\\=\frac{54}{40} \\\\simplify\\\\=\frac{27}{20}[/tex]

Step-by-step explanation:

Replace x with y and y with x.

Then, try to isolate the y.

x=12y+7

x-7=12y

(x-7)/12=y

f^-1(x)=(x-7)/12

Answer: x ≤ 0. Interval Notation: (-∞, 0]

Answer:

Answer

Step-by-step explanation:

Answer times the power of infinity

The equation of the polynomial with the given roots of 2, -2, and 4 is x³ - 4x² - 4x + 16 = 0.

Roots are the points where the graph intercepts with the x-axis ( y = 0 ).

Given the roots in the question;

x = 2, -2, 3

Now, the root of x = 2 was found solving for x when x - (2) = y but y = 0.

Hence, (x - 2) is a factor.

Next, the root of x = -2 was found solving for x when x - (-2) = y but y = 0.

Hence, (x + 2) is a factor

And the root of x = 4 was found solving for x when x - (4) = y but y = 0.

Hence, (x + 2) is a factor

Now, combine all the factors into a single equation and simplify.

( x-2 )( x + 2 )( x - 4 ) = y

( x² + 2x - 2x - 4 )( x - 4) = 0

( x² - 4 )( x - 4) = 0

x( x² - 4 ) -4( x² - 4 ) = 0

x³ - 4x - 4x² + 16 = 0

x³ - 4x² - 4x + 16 = 0

x³ - 4x² - 4x + 16 = 0

Therefore, the equation of the polynomial with the given roots of 2, -2, and 4 is x³ - 4x² - 4x + 16 = 0.

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The coordinate of point X such that the ratio of MX to XJ is 3:1 is 12

The coordinates are given as:

M = 2

J = 18

The ratio is given as:

Ratio = 3 : 1

The location of the point X is then calculated as:

X = Ratio * (J - M)

This gives

X = 3/(3 + 1) * (18 - 2)

Evaluate

X = 3/4* 16

This gives

X = 12

Hence, the coordinate of point X such that the ratio of MX to XJ is 3:1 is 12

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Step-by-step explanation:

show how to work out the question

==============================================================

Explanation:

Recall that the opposite sides of any rectangle are the same length.

This means the top and bottom sides are the same length

top = bottom

2x+17 = 6x+9

2x-6x = 9-17

-4x = -8

x = -8/(-4)

x = 2

Then we can find each side:

We get the same length for top and bottom (21), which confirms the correct x value.

This is a 7 by 21 rectangle with area = length*width = 7*21 = 147 square units.

The sales tax on this computer in 62 dollars and 93 cents

The given parameters

Price = $899

Tax rate = 7%

The sales tax on this computer in dollars and cents is calculated as

Sales tax = Price * Tax rate

This gives

Sales tax = $899 * 7%

Evaluate

Sales tax = $62.93

Hence, the sales tax on this computer in 62 dollars and 93 cents

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Due to length restrictions, we kindly invite to check the explanation of this question for further details on equations.

In this problem we find equations that have got to be cleared with respect to a given variable, this can be done by taking advantage of algebra properties:

14) b / c = a → c = b / a

15) k = a - y → y = a - k

16) d · f · g = h → f = h / (d · g)

17) 2 · x + 3 · y = 12 → 3 · y = 12 - 2 · x → y = 4 - (2 / 3) · x

18) 2 · n = 4 · x + 2 · y → n = 2 · x + y

19) a · b · c = 1 / 2 → b = 1 / (2 · a · c)

20) y = 3 / (5 · u) + 5 → y - 5 = 3 / (5 · u) → 5 · u = 3 / (y - 5) → 3 / [5 · (y - 5)]

21) 8 · (x - a) = 2 · (2 · a - x) → 8 · x - 8 · a = 4 · a - 2 · x → 10 · x = 12 · a → x = (6 / 5) · a

22) 12 · (m + 3 · x) = 18 · (x - 3 · m) → 12 · m + 36 · x = 18 · x - 54 · m → 66 · m = - 18 · x → m = - (3 / 11) · x

23) V = (π / 3) · r² · h → h = [3 · V / (π · r²)]

24) V = (π / 3) · r² · (h - 1) → h - 1 = [3 · V / (π · r²)] → h = 1 + [3 · V / (π · r²)]

25) y · (a - b) = c · (y + a) → a · y - b · y = c · y + a · c → (a - b - c) · y = a · c → y = (a · c) / (a - b - c)

26) x = [3 · (y - b)] / m → (m · x) / 3 = y - b → y = b + (m · x) / 3

27) F = - (G · m) / r² → G = - (F · r²) / m

28) The area formula of the baking sheet is l · w = 117.

29) The temperature formula is T = (7 / 30) · n + 40.

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Answer:

Step-by-step explanation:

you can't really solve for x because there is no equal sign to determine how much x needs to be in order to get the sum.

Answer:

24

Step-by-step explanation:

First, we know the total number of students: 135

Then we can see that 22+31+28 students like two flavours: 81

Then we can see how many students like all three flavours: 15

Because the students who like two flavours are counted twice, we need to subtract them once.

Because the students who like three flavours are counted three times, we need to subtract them twice.

So we get 135-81-15*2

135-81-30

24

24 students do not like any of the given flavours

if this was helpful pls give me brainliest <3

Answer: 24 students dislike any of the flavors

Step-by-step explanation:

Soo since you have the diagram without any error it the other question soo at the start of the question they have told that in total there are 135 students.

so at the all the number of students with the different types of flavors then you will get the total amount of students who like 2 kinds of flavors and all three flavors.

31+22+28+15+15= 111 students  (since the students who like three flavors are counted three times, we need to subtract them twice, I add it here to make it easier *15+15*)

so next you should subtract that amount from the total amount of students  who likes multiple flavors in order to get the number of students who dislikes and of the flavors.

135-111= 24 students dislike any of the flavors

I hope this helped you I tried my best... I hope this is understandable and good luck!

The perimeter of the given rectangle is a 3.31 meter.

According to the statement

We have to find that the perimeter of rectangle.

So, For this purpose, we know that the

Perimeter is the distance around the edge of a shape.

From the given information:

The length of the tabletop is 1.83 meters and the width is 0.74 meter.

Then the formula to find the perimeter is a

P =l +2w

Here substitute the values then

P =l +2w

P = 1.83 +2*0.74

Now add the terms to get a perimeter of the rectangle.

Then

P = 1.83 +1.48

P = 3.31.

So, The perimeter of the given rectangle is a 3.31 meter.

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Answer: 7x -4

Step-by-step explanation:

The average rate of change of the function over the interval is -9.25

The given parameters are

h(x) = x^2 - 5x + 11

−8 ≤ x ≤ 4

Calculate h(4) and h(-8)

So, we have

h(4) = (4)^2 - 5(4) + 11 = 7

h(-8) = (-8)^2 - 5(-8) + 11 = 115

The average rate of change of the function over the interval is then calculated as

Rate = [h(4) - h(-8)]/[4 - -8]

This gives

Rate = [7 - 118/[12]

Evaluate

Rate = -9.25

Hence, the average rate of change of the function over the interval is -9.25

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Step-by-step explanation:

parallel means it has the same slope.

the slope of a line is always the factor of x (5 in our case).

so, we have already

y = 5x + ?

we resolve the "?" by using the point coordinates as x and y and solve :

1 = 5×-2 + ?

1 = -10 + ?

? = 11

so, the equation is

y = 5x + 11

well, we know it's a rectangle, so we know the opposite sides are perpendicular, so if we just get say the sides AD as its length and BA as its width, that'd give us its area, since it'll just be AD * BA.

[tex]~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-1}~,~\stackrel{y_1}{4})\qquad D(\stackrel{x_2}{-3}~,~\stackrel{y_2}{-4}) ~\hfill AD=\sqrt{(~~ -3- (-1)~~)^2 + (~~ -4- 4~~)^2} \\\\\\ ~\hfill AD=\sqrt{( -2)^2 + ( -8)^2}\implies \boxed{AD=\sqrt{68}} \\\\\\ B(\stackrel{x_1}{3}~,~\stackrel{y_1}{3})\qquad A(\stackrel{x_2}{-1}~,~\stackrel{y_2}{4}) ~\hfill BA=\sqrt{(~~ -1- 3~~)^2 + (~~ 4- 3~~)^2}[/tex]

[tex]~\hfill BA=\sqrt{( -4)^2 + (1)^2} \implies \boxed{BA=3} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\LARGE Area}}{(\sqrt{68})(3)\implies (\sqrt{2^2\cdot 17})(3)}\implies (2\sqrt{17})( 3)\implies \LARGE \begin{array}{llll} 6\sqrt{17} \end{array}[/tex]

Answer:

Step-by-step explanation:

25. 5 < x < 7

Answer:

1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25

enter the correct letters in the boxes on the left with the negative statements on the right

E    Apples make good pies      A  seven is not a prime number

F    the sun is hot today             B   a line does not contain at least two points

D    3+2=7                                   C a right angle does not measure < 90degre

C    a right angle measure < 90  D  3+2[tex]\neq[/tex]7

 A  seven is a prime number       E apples does not make good pies

 B   a line contain at least two points   F  the sun is not hot today

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