Answers
Check out the attached photo
Related Questions
Find the measure of angle X.
Answers
Answer:
x = 23 degrees
Because if you look at diagram x is vertical to angle FBC, and angle FEC and angle EBA are alternate interior angles so they are equal to each other, and AC is a straight line which means it equals to 180 degrees.
[tex]4x+65+x = 180[/tex]
x = 23 degrees
Find the smallest value of k if 360k is a perfect square
Answers
Answer:
k = 1
Step-by-step explanation:
since 360 = 60² , a perfect square , then
360 × 1 ← is a perfect square
that is 360k with k = 1 is a perfect square
Which is true?
5/4 > 5/6
3/3 > 4/3
3/3 < 3/6
Answers
Answer:
5/4 > 5/6
Step-by-step explanation:
need help on 11-17 pls. Thank u
Answers
12) 72 and 108 degrees (left to right)
14) b=-3/2
I don’t have the rest I’m sorry
What is the number of combinations on a lock. (for a 40-number lock, no successive repeating numbers)
(permutations or combinations).
Answers
The lock in the challenge requires that you choose from 40 different numbers, three different times. Therefore, there are 40 × 40 × 40, or 64,000 different combinations.
The point N lies on the segment MP.
Find the coordinates of N so that the ratio of MN to NP is 6 to 1.
M(-13, 20)
N (?, ?)
P(1-1)
Answers
If the point N lying on the Line segment MP, divides MP such that the ratio of MN to NP is 6 to 1, and the coordinates of M(-13, 20) and P(1-1), then the coordinates of "N" is
As per the question statement, N lying on the Line segment MP, divides MP such that the ratio of MN to NP is 6 to 1.
We are required to find out the coordinates of "N".
To solve this question, we need to know the formula to calculate the coordinates of a point (Say "c") that divides a line segment AB in the ratio of (m:n).
The formula goes as:
Abscissa of c [tex](x_{3})=\frac{mx_{2}-nx_{1} }{m-n}[/tex]
and, Ordinate of c [tex](y_{3})=\frac{my_{2}-ny_{1} }{m-n}[/tex]
where, [tex](x_{1}, y_{1})[/tex] are the coordinates of point A, while
[tex](x_{2}, y_{2})[/tex] are the coordinates of point B.
Using our given data in the above formulae, we get
Abscissa of N = [tex]\frac{(6*1)-[1*(-13)]}{6-1} =\frac{6-(-13)}{5}=\frac{6+13}{5}=\frac{19}{5}[/tex]
And, Ordinate of N = [tex]\frac{[6*(-1)-(1*20)}{6-1} =\frac{(-6)-20}{5}=\frac{-(20+6)}{5}=\frac{-26}{5}[/tex].
Hence, our concerned point N = [tex](\frac{19}{5}, \frac{-26}{5})\\[/tex].
Line Segment: In Euclidean geometry, a line segment is a part of a straight line that is bounded by two distinct end points, and contains every point on the line that is between its endpoints and it's length is given by the Euclidean distance between its endpoints.To learn more about Line Segments, click on the link below.
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If it is given that m ∠ J K L = m ∠ X Y Z and m ∠ X Y Z = m ∠ Q R S , then concluding that m ∠ J K L = m ∠ Q R S is an example of:
Answers
Concluding that m∠ J K L = m ∠ Q R S is an example of: substitution property of equality
What is Substitution Property of Equality?The substitution property of equality states that 'If a variable x is equal to another variable y, then x can be substituted in place of y in any equation/expression and y can be substituted in place of x in any equation/expression.
Now, we are told that m ∠ J K L = m ∠ X Y Z and m ∠ X Y Z = m ∠ Q R S.
Thus, concluding that m ∠ J K L = m ∠ Q R S is an example of: substitution property of equality
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A high school student decides to apply four of six famous colleges. I’m how many possible ways can the four colleges be selected
Answers
If a high school student decides to apply four of six famous colleges, then the four colleges can be selected in as many as 15 different combinations.
As per question statement, a high school student decides to apply four of six famous colleges.
We are required to calculate the number of combinations in which the four colleges can be selected.
To solve this question, we need to know the formula of Combination which goes as [tex](nCr)=\frac{n!}{r!(n-r)!}[/tex]
, i.e., we are to select a set or "r" from a set of "n".
Here, we have to select a combination of 4 from a set of 6.
Therefore applying (nCr) formula with (n = 6) and (r = 4), we get,
[tex](6C4)=\frac{6!}{4!(6-4)!} =\frac{6!}{4!2!}=\frac{4!*5*6}{4!*2}=\frac{5*6}{2}=(5*3)=15[/tex].
Combinations: In mathematics, a combination is a method of selecting items from a particular set, where the order of selection does not matter, i.e., if we have a set of three P, Q and R, then in how many ways we can select two numbers from each set, can be easily defined by combination.To learn more about combinations, click on the link below.
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5000 nails in five boxes. the first and second boxes have 2700 nails all together. the second and the third boxes have 2000 nails all together. the third and fourth boxes have 1800 nails all together. the fourth and the fifth boxes have 1700 nails all together. how many nails are in each box
Answers
The number of nails in each box is: 1300, 1400, 600, 1200, and 500
Given 5000 nails in five boxes.
Let X denote the universal set.
Then n(X) = 5000.
Let A denote the first box,
B denote the second box,
C denote the third box,
D denote the fourth box, and
E denotes the fifth box.
The first and second boxes have 2700 nails altogether.
⇒n(A ∪ B) = 2700
The second and third boxes have 2000 nails altogether.
⇒n(B ∪ C) = 2000
The third and fourth boxes have 1800 nails altogether.
⇒n(C ∪ D) = 1800
The fourth and fifth boxes have 1700 nails altogether.
⇒n(D ∪ E) = 1700
We need to find out how many nails are there in each box.
That is to find out: n(A), n(B), n(C), n(D), and n(E).
Note that all these five sets are disjoint. This means that the intersection is empty.
n(A ∪ B ∪ C ∪ D) = n(A ∪ B) + n(C ∪ D) = 2700 + 1800 = 4500
n(E) = n(X) - n(A ∪ B ∪ C ∪ D) = 5000 - 4500 = 500
n(D) = n(D ∪ E) - n(E) = 1700 - 500 = 1200
n(C) = n(C ∪ D) - n(D) = 1800 - 1200 = 600
n(B) = n(B U C) - n(C) = 2000 - 600 = 1400
n(A) = n(A U B) - n(B) = 2700 - 1400 = 1300
Therefore, the number of nails in each box is 1300, 1400, 600, 1200, and 500.
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Under her cell phone plan, Morgan pays a flat cost of $54 per month and $5 per gigabyte, or part of a gigabyte. (For example, if she used 2.3 gigabytes, she would have to pay for 3 whole gigabytes.) She wants to keep her bill under $70 per month. What is the maximum whole number of gigabytes of data she can use while staying within her budget?
Answers
Answer: She can use 4 gigabyte while remaining in her budget.
Step-by-step explanation:
You would first subtract 54 from 70 which leaves you with 16,
Then you would divide 16 by 4 to find how many gigabytes she could use which gives you 4
So she can use 4 gigabyte while remaining in her budget.
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Answer: Answer is 3
Step-by-step explanation:
let the maximum number of gigabytes of data is x
total budget is $70
then, flat cost is $54 and $5per gigabyte
we get:
54 +5 × x= 70
5x =70 - 54
x = [tex]\frac{16}{5}[/tex] = 3.2 ≈ 3
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Estimate the quotient of
68)6080
Express any remainder beginning with an R.
Answers
Your final estimated answer is 89 R 28
(aka 89, 28 Remainder)
[tex] \boxed{\begin{gathered} \rm Let \: \psi_1 : [0, \infty ) \to \mathbb{R} , \psi_2 : [0, \infty ) \to \mathbb{R},f :[0, \infty )\to \mathbb{R} \: and \: g :[0, \infty) \to \mathbb{R} \: be \\ \rm functions \: such \: that \: f(0) = g(0) = 0, \\\\ \rm \psi_{1}(x) = {e}^{ - x} + x, \: \: x \geq0, \\ \rm \psi_{2}(x) = {x}^{2} - 2x - 2 {e}^{ - x} + 2, \: \: x > 0, \\ \rm f(x) = \int_{ - x}^{x} ( |t| - {t}^{2} ) {e}^{ - {t}^{2} } \: dt, \: \: x > 0 \\\\ \rm g(x) = \int_0^{ {x}^{2} } \sqrt{t} \: {e}^{ - t} \: dt, \: \: x > 0 \end{gathered}}[/tex]
Which of the following is True?
[tex] \rm (A) \: \rm \: f ( \sqrt{ \ln 3 } )+ g( \sqrt{ \ln3} ) = \dfrac{1}{3} [/tex]
(B) For every x>1, there exists an α ∈ (1,x) such that ψ₁(x)=1+ax
(C) For every x>0, there exists a β ∈ (0,x) such that ψ₂(x)=2x(ψ₁(β)-1)
(D) f is an increasing function on the interval [tex] \bigg [0 , \dfrac{3}{2} \bigg][/tex]
Answers
(A) is false. By symmetry,
[tex]\displaystyle f(x) = \int_{-x}^x (|t|_t^2) e^{-t^2} \, dt = 2 \int_0^x (t-t^2) e^{-t^2} \, dt[/tex]
where [tex]|t|=t[/tex] since [tex]x>0[/tex]. Substitute [tex]s=t^2[/tex] to get the equivalent integral,
[tex]\displaystyle f(x) = \int_0^{x^2} (1 - \sqrt s) e^{-s} \, ds[/tex]
Then
[tex]\displaystyle f(x) + g(x) = \int_0^{x^2} e^{-s} \, ds[/tex]
[tex]\displaystyle f(\sqrt{\ln(3)}) + g(\sqrt{\ln(3)}) = \int_0^{\ln(3)} e^{-s} \, ds = \frac23 \neq \frac13[/tex]
(B) is false. Note that [tex]1+\alpha x[/tex] is linear so its derivative is the constant [tex]\alpha[/tex] at every point. We then have
[tex]{\psi_1}'(\alpha) = -e^{-\alpha}+1 = \alpha \implies 1-\alpha = e^{-\alpha}[/tex]
But this has no solutions, since the left side is negative for [tex]\alpha>1[/tex] and the right side is positive for all [tex]\alpha[/tex].
(C) is true. By the same reasoning as in (B), the line [tex]2x(\psi_1(\beta)-1)[/tex] has constant derivative, [tex]2\psi_1(\beta)-2 = 2e^{-\beta+2\beta-2[/tex]. Then
[tex]{\psi_2}'(\beta) = 2\beta-2+2e^{-\beta} = 2e^{-\beta}+2\beta-2[/tex]
holds for all values of [tex]\beta[/tex].
(D) is false. We use the first derivative test. By the fundamental theorem of calculus,
[tex]\displaystyle f(x) = 2 \int_0^x (t-t^2)e^{-t^2}\,dt \implies f'(x) = 2(x-x^2)e^{-x^2}[/tex]
Solve for the critical points.
[tex]f'(x) = 0 \implies x-x^2 = 0 \implies x = 0 \text{ or } x = 1[/tex]
[tex]e^{-x^2}>0[/tex] for all [tex]x[/tex], so the sign of [tex]f'[/tex] depends on the sign of [tex]x-x^2[/tex]. It's easy to see [tex]f'>0[/tex] for [tex]x\in(0,1)[/tex] and [tex]f'<0[/tex] for [tex]x\in\left(0,\frac32\right)[/tex]
2 and 3 50 points and Brainlyest
Answers
AAnswer:
AB (-1, 4) = 34^ and B = (3,-1) 249*32 = 20
Step-by-step explanation:
Answer:
[tex]AB=\sqrt{53}\:\sf units[/tex]
[tex]EF=\sqrt{349}\:\sf units[/tex]
Step-by-step explanation:
Distance between two points
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]\textsf{where }(x_1,y_1) \textsf{ and }(x_2,y_2)\:\textsf{are the two points}.[/tex]
Given:
A = (-4, 1)B = (3, -1)Substitute the given points into the distance formula and solve for AB:
[tex]\begin{aligned}\implies AB & =\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}\\& =\sqrt{(3-(-4))^2+(-1-1)^2}\\& =\sqrt{(7)^2+(-2)^2}\\& =\sqrt{49+4}\\& = \sqrt{53}\end{aligned}[/tex]
Given:
E = (-7, -2)F = (11, 3)Substitute the given points into the distance formula and solve for EF:
[tex]\begin{aligned}\implies EF & =\sqrt{(x_F-x_E)^2+(y_F-y_E)^2}\\& =\sqrt{(11-(-7))^2+(3-(-2))^2}\\& =\sqrt{18^2+5^2}\\& =\sqrt{324+25}\\& =\sqrt{349}\end{aligned}[/tex]
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10x-15=15x+50 ise x kaçtır?
Answers
10x = 15x + 65
-5x = 65
x'i izole etmek:
65/-5 = -13
x = -13
Bu yardımcı olur umarım! :)
Combine like terms
10x-15x=50+15
-5x=65
Divide both sides by -5
x=13
Helppp!
h(x)=x^2-6
Evaluate h(-3)
Answers
Answer:
3
Step-by-step explanation:
input -3 into h(x)=x^2-6
h(-3)=-3^2-6=9-6=3
PLEASE HELP 4/z>3; z=2
Answers
answer and steps to get it in the picture
Convert the following temperatures from Fahrenheit to Celsius or vice versa.
C= F-32/1.8
F = 1.8C+32
a. 50°F
b. 75°C
c. -40°C
Answers
Answer:
10°C
Step-by-step explanation:
c = [tex]\frac{F - 32}{1.8}[/tex] Plug in 50 for F and solve for C
c = [tex]\frac{50-32}{1.8}[/tex]
C = [tex]\frac{18}{1.8}[/tex] Divide
c = 10
Determine if the following relations represent a function
1. {(-1, -2), (0, -2), (1, -2), (2, -2)}
2. {(1, 0), (1,1), (1, 2), (1, -2)}
Answers
1) Yes, because each value of x maps onto only one value of y.
2) No, because the x-value of 1 maps onto 4 different y values.
Answer:
yes, a function.no, not a function.Step-by-step explanation:
You want to know if the given sets of ordered pairs represent a function.
FunctionA function is a relation that maps an input value to a single output value. On a graph, this means no two points are vertically aligned. For a table or set of ordered pairs, it means no input (x) value is repeated.
1.The input (x) values are {-1, 0, 1, 2} with no repeats. This relation is a function.
2.The input values are {1, 1, 1, 1} with repeats. This relation is not a function.
(3, 4, 5, ...} is finite or infinite
Answers
The given set is (3, 4, 5, ...} is infinite set.
A set with an infinite number of elements is one that cannot be numbered. A set that has no last element is said to be endless. A set that can be put into a one-to-one correspondence with a suitable subset of itself is said to be infinite. No issue with the in-class assignment.
The stars in the clear night sky, water droplets, and the billions of cells in the human body are just a few examples of endless sets of objects that surround us. A set of natural numbers, however, serves as the best illustration of an infinite set in mathematics. There is no limit to the amount of natural numbers.
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2(x-1)+5(x-9) Show your work please!
Answers
Step-by-step explanation:
2(x-1) + 5(x-9)
2x - 2 + 5x - 45
2x + 5x - 2 - 45
7x - 47
Answer:
2x -2 + 5x -45 7x -47
Step-by-step explanation:
2*x = 2x
2*-1 = -2
5*x =5x
5*-9 = -45
An 8-ounce cup of juice costs $1.20. A 12-ounce cup of the same juice costs
$1.44. Can the relationship between cost and ounces of juice be described
by a constant rate? Explain.
Answers
Answer: It can.
Step-by-step explanation:
If an 8 oz. cup of juice cost $1.20 and a 12 oz. cup of juice cost $1.44, there is a $0.24 difference between the money and cups of juice in ounces. If there were to be a constant rate of change, a 16 oz. cup of juice MUST cost $1.68
No, the relationship between cost and ounces of juice cannot be described by a constant rate.
What is Algebra?Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.
The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.
We are given that;
Cost of 8 ounce juice= $1.20
Cost of 12 ounce juice= $1.44
Now,
If the relationship between cost and ounces of juice was described by a constant rate, then the cost per ounce would be the same for both the 8-ounce cup and the 12-ounce cup. However, we can see that the cost per ounce is different for each cup:
For the 8-ounce cup: cost per ounce = $1.20 / 8 ounces = $0.15 per ounce
For the 12-ounce cup: cost per ounce = $1.44 / 12 ounces = $0.12 per ounce
Therefore, by algebra the cost per ounce is different for each cup, the relationship between cost and ounces of juice cannot be described by a constant rate.
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If f(x) = 2ax + b/x-1, lim x→0 f(x) = -3, lim x→∞ f(x)=4, prove that: f(2)= 11.
Answers
If
[tex]f(x) = \dfrac{2ax+b}{x-1}[/tex]
Note that
[tex]f(2) = \dfrac{4a+b}{2-1} = 4a+b[/tex]
From the given information we have
[tex]\displaystyle \lim_{x\to0} f(x) = \lim_{x\to0} \frac{2ax+b}{x-1} = \frac{0+b}{0-1} = -b = -3 \\\\ ~~~~ \implies b=3[/tex]
and
[tex]\displaystyle \lim_{x\to\infty} f(x) = \lim_{x\to\infty} \frac{2ax+b}{x-1} = \lim_{x\to\infty} \frac{2a+\frac bx}{1-\frac1x} = \frac{2a+0}{1-0} = 2a = 4 \\\\ ~~~~ \implies a=2[/tex]
It follows that
[tex]f(2) = 4\cdot2+3 = 11[/tex]
as required.
Help me ASP SHOW UR WORK THANK YOU!!
Answers
The value of x is 4 , 12 , - 1 resp. in eq 1 , 2 and 3 .
Finding values of unknown variable x .
Following are linear equations in one variable .
On solving them we get ,
1 ) 2 ( 3 x - 5 ) = - 4 x + 30
6 x - 10 = - 4 x + 30
10 x =40
x = 4
2 ) 5 x - 6 - 3 x = 18
2 x = 18 + 6
2 x = 24
x = 12
3 ) - 11 - 5 x = 6 ( 5 x + 4 )
- 11 - 5 x = 30 x + 24
- 35 x = 35
x = - 1
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What is the slope of a line parallel to the line whose equation is 2x - 5y = 30. Fully simplify your answer.
Answers
Answer: [tex]\boxed{y=\frac{2}{5} x-7}\ as\ an\ example[/tex]
Step-by-step explanation:
Find the slope-intercept form:
[tex]2x-5y=30\\\\-5y=-2x+30\\\\y=\frac{-2x+30}{-5} \\\\y=\frac{2}{5} x-6[/tex]
Therefore the slope is 2/5
An example of a line parallel to this line is
[tex]y=\frac{2}{5} x-7[/tex]
Round 1803.2684 to the nearest thousandth
Answers
Answer:
1,803.268
Step-by-step explanation:
so thousandths place is three number after the decimal just see the fourth number after the decimal and if it 5 or greater round the (in this case) 8 but since the fourth number was 4 it stays the same but only three numbers
The third number after the decimal is the thousandth place meaning you need to round the 8. Since the last number is under 5 you round down
The perimeter of the pentagon below is 63 units. Find the length of side AB.
Write your answer without variables.
Answers
Answer:
15
Step-by-step explanation:
The sides add to 63, so:
[tex]11+3x+11+x+2+2x+3=63 \\ \\ 6x+27=63 \\ \\ 6x=36 \\ \\ x=6 \\ \\ \implies AB=2(6)+3=15[/tex]
Alonso's family rented a car when they flew to
Orlando for a 4-day vacation. They paid $39
per day and $0.09 for each mile driven. How
much did it cost to rent the car for 4 days and
drive 350 miles, not including tax?
Answers
Answer:
$187.5
Step-by-step explanation:
39 (4) + 0.09 (350)
156 + 31.5
$187.5
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Answer:
$187.5
Step-by-step explanation:
You need to multiply the daily cost by the days. In this case, 39*4 = 156. Then, we can get the cost for the miles driven, being 0.09*350 = 31.5.
We can now add the two numbers together:
156 + 31.5 = $187.5
What is 5+3 72 times
Answers
Answer: 576
Step-by-step explanation:
5+3 = 8
8*72=576
Answer:576
Step-by-step explanation: just add and multiply
An automobile purchased for $28,000 is worth $2500 after 5 years. Assuming that the car's value depreciated steadily from year to year, what was it worth at the end of the third year?
The value 3 years after it was purchased is
Answers
Answer:
$3285.47
Step-by-step explanation:
We know the value decreased by a factor of 2500/28000 after 5 years.
This means the value decreased by a factor of (2500/28000)⅕ per year.
Therefore, after 3 years, the value is
[tex]28000(2500/28000)^{3/5} \approx 3285.47[/tex]
Which measurement is closet to the lateral surface area in square centimeters of the cylinder?
H = 7.6
B = 5.8
Answers
A. 164.9 cm (2)
B. 277.0 cm (2)
C. 138.5 cm (2)
D. 191.3 cm (2)
Answers
The value closest to the lateral area of the cylinder is 138. 5cm^2. Option C
How to determine the valueThe formula for determining the lateral area of a cylinder is expressed as;
Lateral area = 2 πrh
Where;
r is the radiush is the height of the cylinderNote that radius is half the diameter;
radius, r = 5. 8/ 2 = 2. 9 cm
Substitute into the formula
Lateral area = 2 ( 3. 142 × 2. 9 × 7. 6)
Lateral area = 2 ( 69. 249)
Lateral area = 138. 49 cm^2
Thus, the value closest to the lateral area of the cylinder is 138. 5cm^2. Option C
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