find the area of the shaded region.
round to the nearest tenth.

2/3 would use a model or place-value concepts.

What is probability?

The possible rolls are 1,2,3,4,5,6  total of 6

2 or less than 5 rolls are 1,2,3,4  total of 4

P (2 or less than 5) = total number of choices of 2 or less than 5 / total

                               =4/6

                                   =2/3

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The step in which Gwen made an error for the area of the shaded region in the circle is given by:

A. Step 5.

The circumference of a circle of radius r is given by:

C = 2π r.

For this problem, the circumference is of 6π units, hence the radius is given as follows:

6π = 2π r.

r = 6/2.

r = 3 units.

The area of a circle of radius r is given by pi multiplied by the radius squared, as follows:

A = πr².

The entire area of the circle englobes 360º, but we want only the area at an angle of 72º, hence it is given by:

A = (72/360) πr².

Which is where Gwen made an error, at Step 5, hence option A is correct.

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Answer:

the equation is y=1/2+0.5

Answer:

923.08

Step-by-step explanation:

48000/52 weeks

Answer:

923.08

Step-by-step explanation:

There are 52.1429 weeks in a year, so divide.

Answer:

63 crayons are broken

Step-by-step explanation:

84 ÷ 4 = 21

21 x 3 = 63

can be checked by 84 - 63 = 21

We would use r = p/b formula to find 50 is what percent of 20.

The correct answer is an option (b)

For given question,

we need to find the formula which we use to find 50 is what percent of 20

We make the assumption that 20 is 100% since it is our output value.

Let the value we seek be m.

So, 100 % = 20 ...............(1)

m % = 50           ..............(2)

By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS

(left hand side) of both equations have the same unit (%); we have

[tex]\frac{100\%}{m\%}=\frac{2}{5}[/tex]

So, m = 250%

This means, 50 is 250% of 20

The formula PERCENTAGE  p = rb – The result obtained when a number is multiplied by a percent.

The formula BASE ( b = p/r) – The whole in a problem. The amount you are taking a percent of.

The formula RATE (r = p/b) – The ratio of amount to the base. It is written as a percent.

Therefore, we would use r = p/b formula to find 50 is what percent of 20.

The correct answer is an option (b)

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Answer:

Could I see the available choices?

Step-by-step explanation:

Answer:

didnt have the choices but any that would have it as the same problem different order

Step-by-step explanation:

17+14+13=13+14+17=14+13+17=14+17+13=17+13+14=13+17+14

The linear equation to calculate the height is H(t)=33t.

Given that the elevator descends at the speed of 33 feet/second.

If a person gets on the elevator at the observer deck and after 10 seconds he finds himself at 1490 feet above the ground then height descended  in 10 seconds= 33×10

                                         = 330 feet

The height of the observer deck from the ground = 1490+330

                                                                             = 1820 feet

The required equation to calculate the height of above the ground H(t)=33t.

We can calculate  the height of the elevator at any instant using the above expression.

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Answer:

the answer is

Step-by-step explanation:

Q/R= G/F

= QF=GR

divide both sides by Q

Q and Q are off so

therefore F= GR/Q

The original amount borrowed was $517.

Simple Interest is the method to calculate the interest charged for a given number of years and given rate , in simple interest the principle remains same for each year.

Simple interest =[tex]\frac{P*R*T}{100}[/tex]

where P= principle, R=rate in % , T= time

We know that Amount= Principle+ Simple Interest........(1)

According to the question

Amount=$610.06

Rate=18%

time = 1yr

Substituting the value in equation (1) we get

[tex]610.06=P+\frac{P*18*1}{100}[/tex]

[tex]610.06=\frac{100P+18P}{100}[/tex]

[tex]610.06=\frac{118P}{100}[/tex]

[tex]61006=118P[/tex]

[tex]P=\frac{61006}{118}[/tex]

[tex]P=517[/tex]

Therefore  , The original amount borrowed was $517.

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The equation system to represent these two plans is:

c=100+10d, c=40d where c is the total cost and d represents the data used.

We have to understand the plans provided by AT&K and Verikon separately to find the equation system. We know that the total cost incurred is c and the amount of data used is d. It is given that AT&K charges a monthly flat rate of $100 and additional $10 for every gigabyte of data used. We can say that for a month the total cost incurred from AT&K is $100 plus $10xd, the amount of data used.

c=100+10d

For verikon it is given that it does not have any flat monthly rate and it charges $40 for each gigabyte of data used.We can easily say that the total cost in this case is $40 multiplied to amount of data used.

c=40d

Thus the system of equation for the two different plans is

c=100+10d and c=40d

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Answer:

m = e/c

Step-by-step explanation:

Answer:

1.1n represents the cost of the pencils

1.7m is the cost of the pads of paper

The expression represents that she bought a package of pencils and a pad of paper

Step-by-step explanation:

We need to know how to solve the equations by substituting values for this problem. (a)The number of rabbits on the farm at the end of June is 164 and (b) after a long time the number of rabbits on the farm will become zero.

In the given question we know that the number of rabbits on a farm at the end of month n is [tex]P_{n}[/tex] and that the number of rabbits at the end of the next month is [tex]P_{n+1} =1.2P_{n} -50[/tex]. We know that the number of rabbits at the end of March is 200, so we can have [tex]P_{1}[/tex]=200, we need to find the number of rabbits at the end of June, which will be [tex]P_{4}[/tex], we can form an equation from here

[tex]P_{4} =1.2P_{3} -50[/tex]

Since we don't know what [tex]P_{3}[/tex] is we can replace it by [tex]P_{2}[/tex] and then replace that by [tex]P_{1}[/tex].

[tex]P_{4} =1.2P_{3} -50\\P_{4} =1.2(1.2P_{2} -50)-50\\P_{4} =1.2(1.2(1.2P_{1} -50)-50)-50 = 1.2(1.44P_{1} -60-50)-50=1.728P_{1} -72-60-50=1.728P_{1} -182[/tex]

We know that [tex]P_{1} =200[/tex]

So, [tex]P_{4}[/tex]=1.728x200-182=345.6-182≈164

Therefore the number of rabbits at the end of June is 164 and after a long time the number of rabbits on the farm might become zero since the number of rabbits is decreasing with every month.

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Yes the organizer will fit. See the explanation of the word problem below.

Because 3/4  = 6/8,

69 6/8 is larger than 69 1/8 by 5/8".

That is 6 eighths minus 1 eighth is 5 eighths).

Hence, we may disregard the 69 inches because there is no difference in total inches.

The only distinction is in fractions of an inch.

Hence the organizer will be able to fit inside the closet.

A word problem in mathematics is a math question expressed in one or more sentences that demands students to apply their arithmetic skills to a'real-life' setting.

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Answer:

Step-by-step explanation:

Answer:

(6, 7) and (-2, -1)

Step-by-step explanation:

if y=x+1 intersects with y=x^2-3x-11

then we need to find x and y such that both of those equations are true.

If y = x + 1 is true and y=x^2-3x-11, then

y - y = x^2-3x-11 - x - 1 is also true

0 = x^2 - 4x - 12

use your preferred method to solve the quadratic equation

0 = (x - 6)(x + 2)

x = 6 or x = -2

now for each x we take y from either equation, but y = x + 1 is simpler.

for x = 6 the coordinates are (6, 7) and for x = -2 the coordinates are (-2, -1)

Answer:

Step-by-step explanation:

Answer:D

Step-by-step explanation:

The distance of point from the axis of rotation of the second hand is 8.2 cm.

Here,

A point located on the second hand of a large clock has a radial acceleration of 0.09 cm/s2.

We have to find the distance of point from the axis of rotation of the second hand.

What is Rotation?

The circular motion of an object around the circle is called Rotation.

Now,

Let us consider the equation for the centripetal acceleration given by;

[tex]a_{c} = \frac{v^{2} }{r}[/tex]

where, v is the velocity and r is the radius.

Now, the velocity can be expressed as;

[tex]v = wr = \frac{2\pi r}{T}[/tex]

where, ω is the angular velocity and T is the period.

Solving for the radius using these equations given as;

[tex]a_{c} = \frac{v^{2} }{r}\\\\v^{2} = a_{c} r\\\\(\frac{2\pi r}{T} )^2 = a_{c} r\\\\\frac{4\pi ^{2}r^{2} }{T^{2} } = a_{c} r\\\\r = \frac{T^{2} a_{c} }{4\pi ^{2} } \\\\r = \frac{(60s)^2(0.09 cm/s^2)}{4\pi ^{2} } \\\\r = 8.2 cm[/tex]

Hence, The distance of point from the axis of rotation of the second hand is 8.2 cm.

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Answer:

Using the horizontal line test, the one to one functions are those which do not intersect with the line more than one time

In the given graphs, the fourth graph represents the one - one fucntion.

Use the concept of graph of fucntion defined as:

Drawing the curve that represents a function on a coordinate plane is known as graphing a function. Every point on the curve will satisfy the function equation if the curve (or graph) reflects the function.

The graph of a one-to-one function is a representation that shows each input value (x) uniquely paired with a corresponding output value (y), with no repetition or overlap in the mapping.
It passes both the vertical line test and horizontal line test, ensuring each input has a distinct output and vice versa.

In the fourth graph:

Apply the vertical line test and we get,

Each input has a distinct output.

Hence,

The fourth graph represents the one-one fucntion.

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Step-by-step explanation:

[tex] \frac{3x - 5}{4} \leq1[/tex]

[tex]3x - 5 \leq1 .4[/tex]

[tex]3x - 5 \leq4[/tex]

[tex]3x \leq4 + 5[/tex]

[tex]3x \leq9[/tex]

[tex]x \leq \frac{9}{3} [/tex]

[tex]x \leq3[/tex]

x = {3,2,1,0,...}

The time they would both meet at the starting point is 140 minutes (third option).

The time they would both meet at the starting point will be a common multiple of the time it takes each of them to complete a lap.

A multiple of a number is the product of an integer and that number. A common multiple is a multiple that is common to two or more numbers.

Multiple of 20 = 20, 40, 60, 80, 100, 120, 140

Multiple of 35 = 35, 70, 105, 140, 175

Lowest common multiple of 20 and 35 = 140

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The correct option is the first one, (1.176*10¹) is 14.7 times larger than (8*10⁻¹)

Here we want to see how many times larger is (1.176*10¹) larger than (8*10⁻¹), we can see that both numbers are in scientific notation.

To check that, we just need to take the quotient between the two numbers, we will get:

(1.176*10¹)/(8*10⁻¹) = (1.176/8)*(10¹/10⁻¹)

(1.176/8)*(10¹/10⁻¹) =  (1.176/8)*(10¹⁻⁽⁻¹⁾) =  (1.176/8)*10² = 0.147*10²

Now, returning to standard notation, we can rewrite:

0.147*10² = 14.7

The correct option is the first one, (1.176*10¹) is 14.7 times larger than (8*10⁻¹)

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Answer:

tear 35 is ans

pla mark me brainliest ans

Answer:

Hello,

Answer 80

Step-by-step explanation:

[tex]\left\{\begin{array}{cccc}t+e+a&=&30&(1)\\n+t+e+a&=&50&(2)\\t+a+n&=&40&(3)\\t+e+n&=&35&(4)\\t+e+a+r&=&55&(5)\end{array} \right.\\\\\\\left\{\begin{array}{cccc}n&=&20&(2)-(1)=(6)\\t+a&=&20&(7)\\t+e&=&15&(8)\\r&=&25&(5)-(1)=(9)\\t+e+a&=&30&(1)\end{array} \right.\\\\\\\left\{\begin{array}{cccc}n&=&20&(6)\\t&=&5&(7)+(8)-(1)=(10)\\a&=&15&(7)\ and \ (10)\\e&=&10&(8)\ and \ (10)\\r&=&25&(9)\\\end{array} \right.\\[/tex]

[tex]\\\\\boxed{ENTREE=3*e+n+t+r=3*10+20+5+25=80}\\[/tex]

Answer:

6

Step-by-step explanation:

10⁰=1

9⁰=1

7⁰=1

5⁰=1

3⁰=1

1¹⁰⁰=1

so,

10⁰+9⁰+7⁰+5⁰+3⁰+1¹⁰⁰=1+1+1+1+1+1=6

Answer:

6

Step-by-step explanation:

We are working with exponents

Any number to the power of 0 is 1

a^0 = 1

1 to a power is 1

10⁰+9⁰+7⁰+5⁰+3⁰+1¹⁰⁰​

1 + 1 + 1 + 1 + 1 + 1

6

Answer:

1; 1

2:3

3:9

4:27

5:81

6:243

7:729

8:2,187

9:6,561

10:19,683

11:59,049

12:177,147

The 715 cm² area of the disc and the ±5 cm² error tolerance, gives;

a) x = √(715/π) cm

b) The range for the radius is; [√(710/π) cm, √(720/π) cm]

c)

f(x) = π•x²

L = 715 cm²

E = 5 cm

d = √(5/π) cm

Area of the circular metal disk = 715 cm²

a) Required; The disk radius

Let A represent the area of the disk and let x represent the radius, we have;

A = π•x²

Therefore;

x = √(A/π)

Which gives;

x = √(715/π) cm

b) Allowed area error tolerance = ± 5 cm²

The allowed range of values for the area is therefore;

Which gives;

√(710/π) ≤ x ≤ √(720/π)

c) From the [tex] \epsilon / \delta [/tex] definition of limits, we have;

[tex] \lim\limits_{x → √(715/π)} f(x) = 715 [/tex]

Which gives;

f(x) = A = π•x²

L = 715

|f(x) - L| < E = 5 cm

|x - √(715/π)| < d = √(5/π)

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a. Interest of the first year = $26.93

b. Balance after the first year = $1256.93

c. Interest for the second year = $27.52

d. Balance after the second year = $1284.45

Although a part of your question is missing, you might refer to this full question: Gerry deposited $1230 in an account that pays 2.19% simple interest for one year.

a. How much interest will he earn in one year?

b. What will be his balance after one year?

c. Gerry withdraws all of the principal and interest after the first year and deposits into another one-year account at the same rate. What will be his interest for the second year?

d. What will his balance be after two years?

Principal = $1230

Rate = 2.19%

Formula to be used:

Simple interest = (P*R*T)/100

where P = principal

R = rate

T = time in years

Calculating interest for the first year:

S.I = (1230*2.19*1)/100

S.I = 26.93

So, he will earn $26.93 as interest in the first year

And balance after the first year will be $1256.93

Solving for the second year:

P = 1256.93

S.I = (1256.93*2.19*1)/100

= 27.52

So, interest for the second year will be $27.52

And balance after the second year will be $1284.45

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