Answer:
No
Step-by-step explanation:
The x-value of 2 maps onto two values of y, 3 and 4, meaning the relation is not a function.
What is -12 + 12 x 10?
a cheetah has the ability to accelerate quickly in 3 seconds suppose a cheetah could travel 1.5 hours at top speed covering 11 1.9 miles. how far can a cheetah travel in 1 hr?
The cheetah will travel a distance of 74.6 miles in one hour.
How do you define the relation of speed, time and distance?Any moving object travels a certain distance over time. We can calculate the speed using these two parameters.
We all know that speed equals distance divided by time. The fundamental unit of speed would be meters per second or 'm'/'s'.However, speed can also be expressed in different units, including such meters per minute as well as kilometers per hour. Speed is usually expressed in kilometers per hour. It is critical to remember that all unit symbols are recorded in the singular.The rate of displacement is actually referred to as speed. These three entities are linked by a formula:
Speed = Distance/Time
The time taken by the cheetah to cover the distance of 111.9 miles is 1.5 hour.
Put the values;
Speed = 111.9/1.5
Speed = 74.6 miles/ hour
Therefore, the distance covered by the Cheetah in 1 hour is 74.6 miles.
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Use braces to write the members of the set, or state that the set has no members.
The whole numbers greater than 5 and less than 9
A.
{6, 7, 8}
B.
{5, 6, 7, 8}
C.
{6, 7, 8, 9}
D.
{5, 6, 7, 8, 9}
Answer:
A
Step-by-step explanation:
What is the quotient of 20/8 divided by 5/12?
85/12
12
16
25/9
Answer:
6 (None of the above)
Step-by-step explanation:
Let's solve the problem,
→ 20/8 ÷ 5/12
→ 20/8 × 12/5
→ 240/40 = 6
Hence, the answer is 6.
pls help i have no clue what this is
Answer:
³√729 = 9
Step-by-step explanation:
The given information is,
→ ³√729
Prime factorization of 729 is,
→ 3 × 3 × 3 × 3 × 3 × 3
We know that,
→ ³√27 = 3
Let's solve the problem,
→ ³√729
→ ³√{(3 × 3 × 3) × (3 × 3 × 3)}
→ ³√(27 × 27)
→ 3 × 3 = 9
Hence, the answer is 9.
The Saavedras purchased a home for $220,000 by making a 15% down payment
and borrowing the rest at 4.2% interest compounded monthly for 20 years. This
made their monthly payment $1152.99. The table below represents the first row
of an amortization table for the first period of the loan.
PLEASE. HURRY
Using proportions, the financial measures for the home purchase are given as follows:
Beginning Balance: $220,000.Interest owed: $228,076.4.Payment toward principal: $33,000.Ending balance: $448,076.4.What is a proportion and what is an example of application?A proportion is a fraction of a total amount, and equations can be built to find the desired measures in the problem using the unit rates, which along with operations such as multiplication or division are used to find the equivalent measures.
For this problem, the beginning balance is the purchase value of the home, hence:
Beginning Balance: $220,000.
15% of that goes towards the down payment, hence:
0.15 x 220,000 = $33,000.
Payment toward principal: $33,000.
The number of monthly payments is given by:
20 x 12 = 360 monthly payments.
Considering the monthly payment, the ending balance is given as follows:
33,000 + 360 x 1,152.99 = $448,076.4.
Hence the interest owed is:
448,076.4 - 220,000 = $228,076.4.
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For the point P(13,
14) and Q(18, 9), find the distance
d(P,Q) and the coordinates of the midpoint M of the
segment PQ
given points P( 13 ,14) and Q( 18,9 )
we have to calculate distance
[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}d = distance(x_1, y_1) = coordinates of the first point(x_2, y_2) = coordinates of the second point[/tex]
d= [tex]\sqrt{( 18-13)^2+(9-14)^2}[/tex]
d=5[tex]\sqrt{2}[/tex]
now calculating midpoints
s= 13+18 /2 =31/2
t= 14+9 / 2= 23/2
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Please help me yall!! This is due tomorrow… I would really appreciate it if y’all could give me some feedback!! Please and thank you!!
Answer:
[tex]\sf (A' \cap B) \cup (A' \cap C') =\{1,6,7\}[/tex]
Step-by-step explanation:
[tex]\begin{array}{|c|c|l|} \cline{1-3} \sf Symbol & \sf N\:\!ame & \sf Meaning \\\cline{1-3} \{ \: \} & \sf Set & \sf A\:collection\:of\:elements\\\cline{1-3} \cup & \sf Union & \sf A \cup B=elements\:in\:A\:or\:B\:(or\:both)}\\\cline{1-3} \cap & \sf Intersection & \sf A \cap B=elements\: in \:both\: A \:and \:B} \\\cline{1-3} \sf ' \:or\: ^c & \sf Complement & \sf A'=elements\: not\: in\: A \\\cline{1-3} \sf - & \sf Difference & \sf A-B=elements \:in \:A \:but\: not\: in \:B}\\\cline{1-3} \end{array}[/tex]
Given sets:
Universal = {1, 2, 3, 4, 5, 6, 7, 8}A = {2, 4, 5, 8}B = {1, 4, 6}C = {1, 2, 3, 4, 5}Therefore, the complement sets are:
[tex]\begin{aligned}\sf A' & = \text{U}-\sf A\\& = \{1,2,3,4,5,6,7,8 \}- \{2,4,5,8 \}\\& = \{1,3,6,7 \}\end{aligned}[/tex]
[tex]\begin{aligned}\sf B' & = \text{U}-\sf B\\& = \{1,2,3,4,5,6,7,8 \}- \{1,4,6 \}\\& = \{2,3,5,7,8 \}\end{aligned}[/tex]
[tex]\begin{aligned}\sf C' & = \text{U}-\sf C\\& = \{1,2,3,4,5,6,7,8 \}- \{1,2,3,4,5 \}\\& = \{6,7,8 \}\end{aligned}[/tex]
Solution
[tex]\begin{aligned}\sf (A' \cap B) \cup (A' \cap C') & = \sf \left(\{1,3,6,7 \} \cap \{1,4,6\} \right) \cup \left(\{1,3,6,7 \} \cap \{6, 7, 8 \} \right)\\\\& = \sf \{1,6\} \cup \{6,7 \} \\\\& = \sf \{1,6,7\} \end{aligned}[/tex]
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high divers use the height of the diving platform to calculate the speed at which they enter the water. The formula 5s- 3h = 12 models the diver's speed's (in miles per hour) and the height h (in feet) of the platform.
Answer:idek
Step-by-step explanation:
i need help on this! its due today
Answer:
a) It's growing by 1 Hexagon in each term
b) (Self Explanatory, but if you still font know, just add 1 hexagon on the bottom tail)
c) 1-4
2-5
3-6
4-7
5-8
d) 1 hexagon is added each time
e) Common Difference = a1 - a
= 5 - 4
= 1
f) Consider the equation n + 3
where n is the number of terms.
In this case, n = 12
= 12 + 3
= 15 Hexagons
g) f(n) = 4 + 1(n-1)
f(1) = 4 + 1 ( 1 - 1)
f(1) = 4 + 1 (0)
f(1) = 4 + 0
f(1) = 4
h) (Forgive me, I actually don't know the answer for this one :'( )
Use braces to write the members of the set, or state that the set has no members.
The integers from 6 to 10 (inclusive)
A.
{7, 8, 9}
B.
{6, 7, 8, 9}
{6, 7, 8, 9}
{6, 7, 8, 9}
{6, 7, 8, 9}
C.
{7, 8, 9, 10}
D.
{6, 7, 8, 9, 10}
The integers from 6 to 10 (inclusive).will be D. {6, 7, 8, 9, 10}.
How to compute the value?It should be noted that the integers given are from 6 to 10 (inclusive).
In this case, this simply means the numbers from 6 to 10.
Therefore, the appropriate number will be: D.
{6, 7, 8, 9, 10}
In conclusion, the correct option is D.
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R,S,Q and P are midpoints of OC, Cb, BA and OA OR=a CS=b and OP=c show that RS is parallel to PQ PLS HELP
how does this trick work? why does it always give the correct date of birthday?
The expression can be simplified to:
x + y/100
Where x is the month and y the day. This is why it always works.
Why does the trick always work?Let's define the two variables x and y as the month of your birth and the day of your birth respectively.
Now let's write the expression by following the steps, you should get:
((((7*x - 1)*13 + y + 3)*11 - x - y)/10 + 11)/100
Now let's simplify the expression we will get:
((((7*x - 1)*13 + y + 3)*11 - x - y)/10 + 11)/100
(((91x - 13 + y + 3)*11 - x - y)/10 + 11)/100
(((91x - 10 + y)*11 - x - y)/10 + 11)/100
((1001x - 110 + 11y - x - y)/10 + 11)/100
(( 1000x - 110 + 10y)/10 + 11)/100
You already can see what will happen here:
(( 1000x - 110 + 10y)/10 + 11)/100
(100x - 11 + y + 11)/100
(100x + y)/100 = x + y/100
So the expression will do the exact same thing for every values of x and y that you decide to use, it does not depend on your exact date of birthday.
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Rewrite 9/4 as a mixed number
Alguien me podria ayudar a resolver o explicar como cintestar ests problemas, fue el primer dia de uni y no lo explico bien el maestro porque segun es nuevo.
Could someone help me solve these problems or explain me how to solve them, it was the first day of university and the teacher didn't explain quiet well because supposedly he is new
Las soluciones para los dos primeros ejercicios son:
10² + 6³ - [4*(5 - 2)]² = 172-3² + (-2)⁴ + - 4³ + (-2)⁴ = -41¿Como resolver operaciones combinadas?Vamos a ver la primer operacion, está es:
10² + 6³ - [4*(5 - 2)]²
Primero se resuelve lo que esta adentro del parentesis, en este caso:
5 - 2 = 3
Reemplazamos eso:
10² + 6³ - [4*(3)]²
Luego se resuelve lo que está dentro de los corchets:
4*3 = 12
Reempazamos eso para obtener:
10² + 6³ - [12]²
Ahora podemos resolver los exponentes, recordar que el exponente nos dice cuantas veces debemos multiplicar un número por si mismo, entonces:
10² = 10*10 = 100
6³ = 6*6*6 = 216
[12]² = 12*12 = 144
Reemplazando eso obtenemos:
100 + 216 - 144 = 316 - 144 = 172
Veamos tambien el siguiente problema:
-3² + (-2)⁴ + - 4³ + (-2)⁴
Apliquemos los exponentes, primero tenemos:
-3²
Notar que el exponente se le aplica solamente al 3, no al signo, entonces:
-3² = -(3)² = -3*3 = -9
En cambio, en:
(-2)⁴
El exponente si se le aplica al signo, entonces:
(-2)⁴ = (-2)*(-2)*(-2)*(-2) = 4*4 = 16
Los otros dos terminos dan:
- 4³ = -4*4*4 = -64
(-2)⁴ = 16
Reemplazando eso en la expresión:
-3² + (-2)⁴ + - 4³ + (-2)⁴ = -9 + 16 - 64 + 16 = -41
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Under his cell phone plan, Gavin pays a flat cost of $62.50 per month and $5 per gigabyte. He wants to keep his bill at $86.50 per month. How many gigabytes of data can he use while staying within his budget?
Answer: 4.8 this is on a school site so i know this because i used the other persons answer and it marked me wrong.
2 5/8 divided by 2 1/4
hi
2* 5/8 = 10/8 = 5*2 /4*2 = 5/4
and 2*1/4 = 1/2
so : 2*5/8 / 2/4 = 5/4 / 1/2 = 5/4 * 2/1 = 5*2 / 2*2*1 = 5/2
Answer:
[tex]=1\frac{1}{6}[/tex] or 7/6
Step-by-step explanation:
[tex]=\frac{21}{8}\div \frac{9}{4}[/tex] <- Convert to improper fraction
[tex]=\frac{21}{8}\times \frac{4}{9}[/tex] <- Fraction Rule
[tex]=\frac{84}{72}[/tex]
[tex]=\frac{7}{6}[/tex]
[tex]=1\frac{1}{6}[/tex]
Emma is baking cookies for her sisters birthday. She is using a bowl in the shape of a hemisphere with a diameter of 11.5 inches. If the bowl is completely full of dough and each cookie is 8.295 cubic inches of dough, how many cookies can she make
Considering the volume of the hemisphere, it is found that she can make 48 cookies.
What is the volume of an hemisphere?The volume of an hemisphere of radius r is given as follows:
[tex]V = \frac{2\pi r^3}{3}[/tex]
The radius is half the diameter, hence, for this problem:
r = 11.5/2 = 5.75.
Hence the volume of the bowl in cubic inches is given as follows:
V = 2π(5.75)³/3 = 398.16 cubic inches.
Consider the volume of a single cookie, the number of cookies that she can make is given by:
398.16/8.295 = 48 cookies.
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Can anyone please help me with #3 ASAP I’ll mark you brainly
Which of the graphs of the inequality y+1<2(x-2)?
Answer:
x> 1/2 y+5/2
i hope this helps you <33
69+69+69-6+9-69+69+420
Answer:780
Step-by-step explanation:
Answer
The answer would be 630
Step-by-step explanation:
69+69 = 138
138+69 =207
207 - 6 = 201
201 + 9 = 210
210 -69 = 141
141 + 69 =210
21 + 420 = 630
PLEASE HELP NOWW PLEASE
Answer: NOW
Step-by-step explanation:
Does 10x = 2.5x have one solution, no solutions, or infinite solutions, and why?
The values are different on both sides, this shows that the equation has no solution.
Equation and expressionLinear equations are equation that has a linear degree of 1. Given the expression below;
10x = 2.5x
You can see that the variable of "x" are on on both sides, hence we can cancel them out to have:
10x/x = 2.5x/x
10 = 2.5
From the result, you can see that the values are different on both sides, this shows that the equation has no solution.
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The linear equation has only one solution, which is x = 0.
How many solutions has the linear equation?
Here we have the linear equation:
10x = 2.5*x
Let's solve this to see how many solutions we have, if we subtract 2.5x in both sides we get:
10x - 2.5x = 0
7.5x = 0
The only solution of this linear equation is x = 0.
7.5*0 = 0
Then we can conclude that the equation has only one solution, which is x = 0.
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Jaylan makes limeade using 3/4 cup of water for every 1/5 cup of lime juice. Rene's limeade recipe is different. He uses 2/3 cup of water for every 1/6 cup of lime juice.
whose limeade has a weaker flavor
Rene's limeade has a weaker flavor as calculated by division of fractions.
One of the four fundamental arithmetic operations, or how numbers are combined to create new numbers, is division.
The other operations are multiplication, addition, and subtraction.On a fundamental level, counting the instances in which one number is included within another is one interpretation of the division of two natural numbers. It's not necessary for this number to be an integer.When no more full chunks of the size of the second number can be allocated during the computation of the quotient, the division with remainder or Euclidean division of two natural numbers yields an integer quotient,Which is the number of times the second number is entirely contained in the first number, and a remainder, which is the portion of the first number that remains.Concentration of Jaylan's limeade [tex]=\frac{3}{4} \div\frac{1}{5} = \frac{15}{4} =3.75[/tex]
Therefore as calculated by division of fractions, concentration of Jaylan's limeade is 3.75 cups of water for 1 cup of lime juice.
Concentration of Rene's Limeade[tex]=\frac{2}{3} \div\frac{1}{6} = \frac{12}{3} =4[/tex]
Therefore as calculated by division of fractions, concentration of Rene's limeade is 4 cups of water for 1 cup of lime juice.
Hence Rene's limeade has a weaker flavor as calculated by division of fractions.
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-4(2x+5)-3x=35 please help ASAP. solve for x
Answer:
-5
Step-by-step explanation:
The 1st, 2nd and 3rd terms of a geometric progression are the 1st, 9th and 21st terms of an arithmetic progression respectively. Given that the 1st term of both progressions is 8 and the common ratio of the geometric progression, r not equation of 1 .Find .
a.The value of r
b.the 4th term of each progression
a. The value of r = 3, -1/2.
b. The 4th term of each progression;
for r = 3; AP = 14, GP = 216.for r = -1/2; AP = 7/2, GP = 1/2.What is defined by AP and GP?An Arithmetic Progression (AP) is a collection of terms with the same differences between them. In a Geometric Progression (GP), each successive term is created by multiplying the common ratio by previously acted.As, per the given question;
Let the first three terms of GP be a, ar, and ar².
The 1st, 2nd and 3rd terms of a GP equals 1st, 9th and 21st terms of an AP respectively.
First term are equal; a = a2nd term GP = 9th term of AP; ar = a + 8d. 3rd term GP = 21st term of AP; ar² = a + 20d.where, 'r' is the common ratio in GP and 'd' is the common difference in AP.
Part 1: Multiply equation 1 by 5 and 2 by 2 and subtract 1 from 2.
2ar² - 5ar - 3a = 0
Put a = 8 and solving.
16r² - 40r - 24 = 0.
Factorising the above equation;
(r - 3)(2r + 1) = 0
Thus, r = 3 and r = -1/2
Part 2:
Case 1: For r = 3; a =8;
ar = a + 8d
d = 2.
Thus, 4th term = a + 3d
= 8 + 3×2
4th term = 14.
For GP;
4th term = ar³
= 8(3)³
4th term = 216.
Case 2: For r = -1/2; a =8;
ar = a + 8d
d = -3/2
Thus, 4th term = a + 3d
= 8 + 3×(-3/2)
4th term = 7/2
For GP;
4th term = ar³
= 8(-1/2)³
4th term = -1.
Therefore, the values for the r and 4th term is estimated.
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At the local farmer’s market, peaches are on sale for $2.56 per pound, watermelons are on sale for $3.25 per pound and mangos are on sale for $2.75 per pound. Trevor wants to buy 1 pound of peaches, his watermelon weighs 3 pounds, and he wants to buy 4 pounds of mangos. How much will Trevor spend rounded to the nearest dollar?
Trevor spent $23.31
How to calculate the amount spent ?Peaches are sold at $2.56 per pound
Watermelons are sold at $3.25 per pound
Mangos are sold at $2.75 per pound
Trevor bought 1 pound of peaches
3 pounds of watermelon= 3 × 3.25
= 9.75
4 pounds of mangos= 4 × 2.75
= 11
The total amount spent is
= 11 + 9.75 + 2.56
= 23.31
Hence Trevor spent $23.31
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4(x+5)-2x/3 when x=6
2. Find the 200th term of
the sequence:
3. 7. 11, 15, 19....
Answer:
our initial is 3
a1=3
difference or d = 4
The general formula is an = a1+(n-1)*d
an= 3+(200-1)*4
an=3+199*4
an=3+396
an = 399
therefore the 200th item is 399
Step-by-step explanation:
a =3 d=4 n=200
apply the general formula for the nth term
? : 24 = 21:14 I need help I need to finish this math packet by today
