Determine the MASS of the object in kg. (use g=10 m/s/s

Answer:

The acceleration is g.

Taking the upward direction as positive

V = Vy y - 1/2 g t^2

Taking the downward direction as positive

V = -V y + 1/2 g t^2

One can choose either direction as positive, but the acceleration is

the same as g (it is g) while the projectile is in the air.

When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). Thus, the correct option is D.

Projectile motion is the motion of an object which is thrown or projected high into the air. After the initial force applied on the object that launches the object, the object only experiences the gravitational force. The object is called a projectile and the path of the object is called trajectory.

When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). When the object achieves highest point, then the vertical acceleration of a projectile is zero meter per second square when it is at the peak of its trajectory motion.

Therefore, the correct option is D.

Learn more about Projectile motion here:

https://brainly.com/question/11049671

#SPJ2

Answer:

the first answer is correct

Answer:

there are two hydrogen atoms in all reactants

Answer:

for the secound one i think it would be 45.87 let me know if this is wrong I love to get my feed back

Explanation:

Answers:

A dog breed can be made smaller by breeding together only the smallest dogs.

Identical twins are more likely to be about the same height than non-identical twins,

Explanation:

The Correct choice is :

Answer:

8. Friction

9. Net force

Explanation:

Hope this helps you. Have a nice day. :)

Diagram:-

[tex]\setlength{\unitlength}{2mm}\begin{picture}(0,0)\thicklines\put(3,6){\circle{3}}\put(2.9,4.5){\vector(0,-3){2cm}}\put(-3.9,-10){\line(3,0){3cm}}\multiput(-3.5,-10)(0.8,0){18}{\line(1,-2){2mm}}\put(-3.7,0){$\sf\footnotesize 9.8 ms^{-2}$}\put(6,0){\vector(0,3){1.2cm}}\put(5.5,6){\line(3,0){2mm}}\put(5,-1.2){\sf\footnotesize height}\put(6,-2){\vector(0,-3){1.2cm}}\put(5.5,-8){\line(1,0){2mm}}\end{picture}[/tex]

Here

[tex]\\ \sf\longmapsto Weight=mg[/tex]

[tex]\\ \sf\longmapsto Weight=6.4(9.8)[/tex]

[tex]\\ \sf\longmapsto weight=62.72N[/tex]

Answer: Thermal Energy

Explanation: I know this answer is correct because I had to look in my notebook for the definition

In my own words: Thermal Energy is the energy coming from heat which means it is generated by the movement of tiny particles with different objects.

Hope this helps! :)

Answer:

10 watts

Explanation:

first calculate work.

Work =force×distance cos thita

10Kg×0.50M cos 0= 5joules

Therefore, Power=Work÷ Time

Therefore, 5joules÷0.50s=10 watts.

Answer:

5 Muscular and strength

Answer:

52355236552255558654

[tex].. { {.y = 392.6. = }^{ + 36yjsss} }^{?} jmijjdrk{am \: {}{}s[/tex]

Answer:

Mars has a thin atmosphere

Explanation:

Okay, so this is going to sound crazy but bare with me. Mar's atmosphere is thin. There is little to no gravitational pull for the atmosphere to stay. Also, no, humans will not be able to live on Mars because the atmosphere, quite literally, contains 1% oxygen. Hopefully this helps! Earth's is thick because of the gravitational pull and gases in Earth's surface.

Answer:

Here is your answer,thanks for using brainly!

Explanation:

B:Molecule

Molecules usually consist of 2 atoms linked together,however some molecules  consist of thousands of atoms!

Here is a list of smalles to largest with the answers provided

Molecules

Atoms

Elements

Mixtures

Hope this helped

Plz mark brainliest

Dont forget to smash that heart at the bottom <3

Have a great day!

Answer:

3.7 m

Explanation:

ASSUMING this means extra distance beyond where the cannonball would land WITHOUT the wind assistance but in general ignoring air resistance. Hmmmmmm...tricky

The ball drops from vertical rest to ASSUMED horizontal ground 15 m below in a time of

t = √ (2h/g) = √(2(15)/9.8) = 1.75 s

Without the tail wind, the ball travels horizontally

d = vt = 68(1.75) = 119 m

The tailwind exerts a constant acceleration on the ball of

a = F/m = 12/5.0 = 2.4 m/s²

The average horizontal velocity during the flight is

v(avg) = (68 + (68 + 2.4(1.75)) / 2 = 70.1 m/s

so the distance with tailwind is

d = v(avg)t = 70.1(1.75) = 122.675 m

The extra distance is 122.675 - 119 = 3.675 = 3.7 m

Answer:

C

Explanation:

C

Answer:

it looks correct to me but im not 11% sure

Explanation:

Answer:

im in hardvard dont cheat get amzing grades if you want to go here

Explanation:

1. 5 WBC's per cubic millimeter.

3. 50 to 80 mg/100 mL

4. 15 to 60 milligrams per deciliter (mg/dL) or 0.15 to 0.6 milligrams per milliliter (mg/mL)

If a test were to be performed here are normal results:

Normal values typically range as follows:

Pressure: 70 to 180 mm H2O

Appearance: clear, colorless

CSF total protein: 15 to 60 mg/100 mL

Gamma globulin: 3% to 12% of the total protein

CSF glucose: 50 to 80 mg/100 mL (or greater than two thirds of blood sugar level)

CSF cell count: 0 to 5 white blood cells (all mononuclear), and no red blood cells

Chloride: 110 to 125 mEq/L

(Source: https://medlineplus.gov/ency/article/003428.htm)

Explanation:

Laws of Newton are

Answer:

Explanation:

tanθ = opp/adj

adj = opp/tanθ

adj = (60 - 40)/tan55 = 14 m

Answer:

[tex]{ \rm{F _{ball \: on \: bat} = - F _{bat \: on \: ball} }}[/tex]

Explanation:

• This is due to the third newtons law of motion which states that "Every action has an equal and opposite reaction".

a) Las balas de cañon disparadas desde el puerto deben tener una ángulo de 27.39° para que puedan impactar al barco, con una velocidad inicial de 82 m/s.

b) El tiempo de vuelo de las balas de cañon para alcanzar al barco que está a 560 m de distancia es de 7.69 s.

c) Sabiendo que el ángulo calculado en el inciso a) es para una distancia de 560 m, el barco debe estar a una distancia mayor para que las balas no lo alcancen.

a)

Podemos usar las ecuaciones de tiro parabólico para encontrar el ángulo que permita derribar al barco invasor.

[tex]x=\frac{v_{i}^{2}sin(2\alpha)}{g}[/tex] (1)

Donde:

Lo que debemos hacer es depejar α de la ecuación 1

[tex]sin(2\alpha)=\frac{xg}{v_{i}^{2}}[/tex]

[tex]sin(2\alpha)=\frac{560*9.81}{82^{2}}[/tex]

[tex]sin(2\alpha)=0.82[/tex]

[tex]\alpha=\frac{sin^{-1}(0.82)}{2}[/tex]

[tex]\alpha=27.39^{\circ}[/tex]

Por lo tanto, el ángulo para que el cañón impacte en el barco es de 27.39 °.

b)

Sabemos que la componente de la velocidad en el eje x es constante, así que podemo usar la siguiente ecuación.

[tex]v_{x}=\frac{x}{t}[/tex]

La componente x de la velocidad es V(x) = V(i)cos(α) y sabiendo la distancia total de 560 m, el tiempo será:

[tex]v_{i}cos(\alpha)=\frac{x}{t}[/tex]

[tex]t=\frac{x}{v_{i}cos(\alpha)}[/tex]

[tex]t=\frac{560}{82cos(27.39)}[/tex]

[tex]t=7.69\: s[/tex]

El tiempo total de vuelo de las balas de cañon es de 7.69 s.

c)

Sabemos que el ángulo calculado en el inciso a) es de 27.39 °, y ese valor fue calcualdo para una distancia de 560 m, por lo tanto el barco debe estar a una distancia mayor que esa para que las balas no lo alcancen.

Puedes encontrar más información sobre tiro parabólico aquí:

https://brainly.lat/tarea/3605927

Espero te haya sido de ayuda!

The distance traveled by the rocket after the given time period is 480 m.

The given parameters;

The distance traveled by the rocket after the given time period is calculated from the second kinematic equation of as shown below;

s = ut + ¹/₂at²

s = (10 x 12) + (0.5 x 5 x 12²)

s = 120 + 360

s = 480 m

Thus, the distance traveled by the rocket after the given time period is 480 m.

Learn more here:https://brainly.com/question/23243663

Answer:

Change volume / volume = .5 / 30 = .01666

coefficient of volume expansion = 3 * 24E-6 = 72E-6

Change in temp = .0167 / 24E-6 = 232 deg C

Final temp = 232 + 30 = 262 deg C

Change in volume / volume = 3 * coeff linear expansion * change in deg C

Explanation:

A. is chemically identical to heroin.