Complete the table. File is attached

The value closest to the lateral area of the cylinder is 138. 5cm^2. Option C

The formula for determining the lateral area of a cylinder is expressed as;

Lateral area = 2 πrh

Where;

Note that radius is half the diameter;

radius, r = 5. 8/ 2 = 2. 9 cm

Substitute into the formula

Lateral area = 2 ( 3. 142 × 2. 9 × 7. 6)

Lateral area = 2 ( 69. 249)

Lateral area = 138. 49 cm^2

Thus, the value closest to the lateral area of the cylinder is 138. 5cm^2. Option C

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The value of x is 4 , 12 , - 1 resp. in eq 1 , 2 and 3 .

Finding values of unknown variable x .

Following are linear equations in one variable .

On solving them we get ,

1 )          2 ( 3 x - 5 ) = - 4 x + 30

             6 x - 10 = - 4 x + 30

              10 x =40

                 x = 4

2 )          5 x - 6 - 3 x = 18

              2 x = 18 + 6

              2 x = 24

               x = 12

3 )         - 11 - 5 x = 6 ( 5 x + 4 )

               - 11 - 5 x = 30 x + 24

                 - 35 x = 35

                x = - 1

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Answer:

1st one is the right option

Answer:

[tex]x=\frac{3\left(1+\sqrt{3}\right)}{2},\:x=\frac{3\left(1-\sqrt{3}\right)}{2}[/tex]

Step-by-step explanation:

[tex]x_{1,\:2}=\frac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:2\left(-9\right)}}{2\cdot \:2} < - InsertQuadraticFormula[/tex]
[tex]x_{1,\:2}=\frac{-\left(-6\right)\pm \:6\sqrt{3}}{2\cdot \:2}[/tex]
[tex]x_1=\frac{-\left(-6\right)+6\sqrt{3}}{2\cdot \:2},\:x_2=\frac{-\left(-6\right)-6\sqrt{3}}{2\cdot \:2} < - Separate THE Solutions[/tex]
[tex]x=\frac{3\left(1+\sqrt{3}\right)}{2},\:x=\frac{3\left(1-\sqrt{3}\right)}{2}[/tex]

Answer:

21

Step-by-step explanation:

Just substitute -3 in for a and 2 in for b

[tex]a^2 + 6b\\-3^2 + 6(2)\\9 + 6(2)\\9 + 12\\21[/tex]

When you square a negative number, the answer is positive. Good luck, and have a great day!

Also, Jesus loves you!!!!

According to this the temperature in February = 4.5°F.

The absolute value (or modulus) of a real number x is its non-negative value regardless of its sign. For example, 5 has an absolute value of 5, and 5 has an absolute value of 5. A number's absolute value can be conceived of as its proximity from zero along the real number line.

The temperature on the same day in February has the same absolute vale as the temperature in the January, but is not the same temperature according to this the temperature in February = 4.5°F.

The absolute value is the same but not the same temperature:

|-4.5| = 4.5

So,

Its 4.5°F

According to this the temperature in February = 4.5°F.

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[tex]\sqrt{10^2 - 3^2}=\boxed{\sqrt{91} \text{ ft}}[/tex]

An equation that relates the number of bags, x, to the cost, y is y = 5x.

An equation is a mathematical statement that claims that the two sides are equal.

An equation involves two or more variables that require some mathematical operations to obtain their equivalent value.

Therefore, an equation contains numbers, variables, and operators, which show a value after the mathematical operations.

Let the number of bags for the class = x (number of students)

Let the unit cost of a bag = $5

Let y = the total cost

Equation, y = 5x

Thus, an equation that relates the number of bags, x, to the cost, y is y = 5x.

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Answer:

$3285.47

Step-by-step explanation:

We know the value decreased by a factor of 2500/28000 after 5 years.

This means the value decreased by a factor of (2500/28000)⅕ per year.

Therefore, after 3 years, the value is

[tex]28000(2500/28000)^{3/5} \approx 3285.47[/tex]

Answer: 576

Step-by-step explanation:

5+3 = 8

8*72=576

Answer:576

Step-by-step explanation: just add and multiply

The number of nails in each box is: 1300, 1400, 600, 1200, and 500

Given 5000 nails in five boxes.

Let X denote the universal set.

Then n(X) = 5000.

Let A denote the first box,

B denote the second box,

C denote the third box,

D denote the fourth box, and

E denotes the fifth box.

The first and second boxes have 2700 nails altogether.

⇒n(A ∪ B) = 2700

The second and third boxes have 2000 nails altogether.

⇒n(B ∪ C) = 2000

The third and fourth boxes have 1800 nails altogether.

⇒n(C ∪ D) = 1800

The fourth and fifth boxes have 1700 nails altogether.

⇒n(D ∪ E) = 1700

We need to find out how many nails are there in each box.

That is to find out: n(A), n(B), n(C), n(D), and n(E).

Note that all these five sets are disjoint. This means that the intersection is empty.

n(A ∪ B ∪ C ∪ D) = n(A ∪ B) + n(C ∪ D) = 2700 + 1800 = 4500

n(E) = n(X) - n(A ∪ B ∪ C ∪ D) = 5000 - 4500 = 500

n(D) = n(D ∪ E) - n(E) = 1700 - 500 = 1200

n(C) = n(C ∪ D) - n(D) = 1800 - 1200 = 600

n(B) = n(B U C) - n(C) = 2000 - 600 = 1400

n(A) = n(A U B) - n(B) = 2700 - 1400 = 1300

Therefore, the number of nails in each box is 1300, 1400, 600, 1200, and 500.

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Answer:

x = 23 degrees

Because if you look at diagram x is vertical to angle FBC, and angle FEC and angle EBA are alternate interior angles so they are equal to each other, and AC is a straight line which means it equals to 180 degrees.

[tex]4x+65+x = 180[/tex]

x = 23 degrees

Answer: its c

Step-by-step explanation:

The difference between the payroll of football and baseball is 2.7752 × 10¹¹. Hence, option C is correct.

Equations are logical assertions in mathematics that have two algebraic expressions on either side of an equals (=) sign. The expression on the left and the expression on the right is shown to be equal in reference to one another. LHS = RHS (left hand side = right hand side) appears in all mathematical equations. You can solve equations to determine the value of an unknown variable that represents an unknown quantity.

The payroll of the baseball team is 2.48 × 10⁹ and,

The payroll of the football team is 2.8 × 10¹¹.

So, the football team's payroll is more than the baseball team's payroll by,

(2.8 × 10¹¹) - (2.48 × 10⁹)

= 2.7752 × 10¹¹.

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Add -9 to both sides.

Solve Absolute Value.

No solutions. (Absolute value cannot be less than 0.)

Answer:

[tex]V=lwh\\\frac{V}{lw} = \frac{lwh}{lw} \\\frac{V}{lw} = h[/tex]

We get that the equation of the line PQ will be 2 x - 7 y + 17 = 0.

A) We know that the equation of the line is:

y - y₁ = m (x - x₁)

where m = y₂ - y₁ / x₂ - x₁

Now, we have:

P = ( x₁, y₁) = (2, 3)

Q = (x₂, y₂) = (9, 5)

We get m by substituting the values as:

m = 5 - 3 / 9 - 2 = 2 / 7

The equation then will be:

y - y₁ = 2 / 7 (x - x₁)

Substituting the values, we get that:

y - 3 = 2/7 ( x - 2)

7 y - 21 = 2 x - 4

2 x - 7 y - 4 + 21 = 0

2 x - 7 y + 17 = 0

B) When PQ will intersect x-axis, then the point will be = ( x, 0)

2 x - 7 y + 17 = 0

2 x - 7 (0) + 17 = 0

2 x = -17

x = - 17 / 2

Point = (-17 / 2 , 0)

Therefore, we get that the equation of the line PQ will be 2 x - 7 y + 17 = 0.

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The sum of the ball's kinetic energy and potential energy remains the same. as the ball rolls from point A to E.( if there is no friction between the ball and the ground).

based on the law of mechanical energy's conservation, the sum of both kinetic and potential energies i.e. the total amount of mechanical energy remain conserved even in the absence of dissipative forces ( friction or air resistance) in a bound system.

the kinetic energy is when ball goes downward but potential energy decreases and reverse happens when ball goes up. but in these case, the sum energy would be constant one.

The ball would not change the energy.

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Answer:

x = 3.25

Step-by-step explanation:

Use the Rule of 3 to solve this

Work in picture

AAnswer:

AB (-1, 4) = 34^ and B = (3,-1) 249*32 = 20

Step-by-step explanation:

Answer:

[tex]AB=\sqrt{53}\:\sf units[/tex]

[tex]EF=\sqrt{349}\:\sf units[/tex]

Step-by-step explanation:

Distance between two points

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]\textsf{where }(x_1,y_1) \textsf{ and }(x_2,y_2)\:\textsf{are the two points}.[/tex]

Given:

Substitute the given points into the distance formula and solve for AB:

[tex]\begin{aligned}\implies AB & =\sqrt{(x_B-x_A)^2+(y_B-y_A)^2}\\& =\sqrt{(3-(-4))^2+(-1-1)^2}\\& =\sqrt{(7)^2+(-2)^2}\\& =\sqrt{49+4}\\& = \sqrt{53}\end{aligned}[/tex]

Given:

Substitute the given points into the distance formula and solve for EF:

[tex]\begin{aligned}\implies EF & =\sqrt{(x_F-x_E)^2+(y_F-y_E)^2}\\& =\sqrt{(11-(-7))^2+(3-(-2))^2}\\& =\sqrt{18^2+5^2}\\& =\sqrt{324+25}\\& =\sqrt{349}\end{aligned}[/tex]

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answer and steps to get it in the picture

Answer:y=mx+b

Step-by-step explanation:

Answer:

Let x be the amount invested in funds that earned 8%.

Then the amount invested in stock that suffered 3% loss is 18,000 - x.

The profit from investment in funds is 8%x

The loss from investment in stock is 3%(18,000 - x).

The net profit is 8%x - 3%(18,000 - x).

As the net profit given in the problem is $780, we have:

8%x - 3%(18,000 - x) = 780

Step-by-step explanation:

In linear equation , 2n/7 is Expression for the quotient .

What in mathematics is a linear equation?

Let the number = n

A quotient is the result of a division.

the quotient of twice a number = 2n

= 2n/7

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If a high school student decides to apply four of six famous colleges, then the four colleges can be selected in as many as 15 different combinations.

As per question statement, a high school student decides to apply four of six famous colleges.

We are required to calculate the number of combinations in which the four colleges can be selected.

To solve this question, we need to know the formula of Combination which goes as [tex](nCr)=\frac{n!}{r!(n-r)!}[/tex]

, i.e., we are to select a set or "r" from a set of "n".

Here, we have to select a combination of 4 from a set of 6.

Therefore applying (nCr) formula with (n = 6) and (r = 4), we get,

[tex](6C4)=\frac{6!}{4!(6-4)!} =\frac{6!}{4!2!}=\frac{4!*5*6}{4!*2}=\frac{5*6}{2}=(5*3)=15[/tex].

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Answer:

12.50m/s

in 2 seconds: 25

im not really good at math but i tried

Answer:

y=1 x=1

×[[×[+[[+[+[+[+[+[+[+[+[+[[

Answer:

10°C

Step-by-step explanation:

c = [tex]\frac{F - 32}{1.8}[/tex]  Plug in 50 for F and solve for C

c = [tex]\frac{50-32}{1.8}[/tex]

C = [tex]\frac{18}{1.8}[/tex] Divide

c = 10

Answer:

C.) Equally as distant.