Can someone please help me?? :(

The automobile covers 224.48 km.

This problem can be solved by using the unitary method.

In this method we calculate the value for a unit quantity and then multiply it with the desired number for which we want to calculate.

Here it is given that a automobile covers 1122.4 km with 80 liters.

For 1 liter of gasoline distance covered = [tex]\frac{1122.4}{80}[/tex]

                                                              = 14.03 km

So, for 16 liters of gasoline distance covered will be = 16× 14.03

                                                                                  = 224.48 km

Therefore the automobile covers 224.48 km for 16 liters of gasoline.

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The solution to the given inequality is x≥50.

The given inequality is 50≤x≥1000.

Inequalities are mathematical expressions in which both sides are not equal. In inequality, unlike in equations, we compare two values. The equal sign in between is replaced by less than (or less than or equal to), greater than (or greater than or equal to), or not equal to sign.

Now,

Move all terms not containing x from the centre section of the inequality.

Inequality Form: x≥50

Interval Notation: [50,∞)

The solution to the inequality is marked on the number line.

Therefore, the solution to the given inequality is x≥50.

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Answer: By having the arrow going to the left of the number line

Step-by-step explanation:

When subtracting, you always go to the left of the number line. Just like how you go to the right when adding. also having the line going from 5 to 1.

The correct graph of the ellipse is identified and attached below.

Given the equation is (x₋3)²/16 ₊ (y₋4)²/9 = 1

step 1: identify the center (h,k) of the ellipse in standard form:

(x₋h)²/a² ₊ (y₋k)²/b² = 1

In the standard form of an ellipse, notice that there is a minus sign in front of the h and k.

In our equation  (x₋3)²/16 ₊ (y₋4)²/9 = 1 , we have:

h = 3 and k = 4

Therefore, center (h,k) = (3,4)

Step 2: Identify the orientation by determining the major axis and minor axis in (x₋h)²/a² ₊ (y₋k)²/b² = 1

if a>b, the major axis is horizontal and the minor axis is vertical, making the ellipse a horizontal ellipse.

if a<b, the minor axis is horizontal and the major axis is vertical, making the ellipse a vertical ellipse.

For  (x₋3)²/16 ₊ (y₋4)²/9 = 1

a² = 16, a = 4 and b² = 9 , b = 3

so, 4>3, the major axis is horizontal and the minor axis is vertical, making the ellipse a horizontal ellipse.

Step 3:

Plot the co-vertices along the minor axis and the vertices along the main axis (endpoints). No matter which way around, draw points a horizontal distance of a to the left and right from the center and points b above and below the center.

Therefore the vertices are marked along the major axis.

vertices are (3,7) and (3,1)

and co vertices are marked along the minor axis

co vertices are (₋1,4 ) and (7,4)

step 4: connect the vertices and co vertices making a smooth horizontal ellipse.

Hence a horizontal ellipse is made.

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She make 5 apple pie and 2 peach pie.

In the given statement is:

Bonnie made 7 pies. there were 6 slices in each apple pie and 7 slices in each peach pie. if Bonnie made 44 slices of pie in total.

To find the how many of each pie did she make

Now, According to the question :

Let start the solution

Total number of slices made by Bonnie is 44

Let Number of apple pies be x

and, number of peach pies is (7 - x) ............(1)

Pieces of an apple pie is 6x

Pieces of peach pie = 7 (7 - x)

Calculation

6x + 7(7 - x) = 44

6x + 49 -7x = 44

-x = 44 - 49

-x = -5

x = 5

Put the value of x in equation (1)

7 - x = 7 - 5 = 2

She make 5 apple pie and 2 peach pie.

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Answer:

6f-15

Step-by-step explanation:

First distribute 3/2.

3/2(4) =6

3/2(-10) =15

So, the answer should be 6f-15.

Let me know if you do not understand or need further explanation :)

This type of sum is Liquidated damages.

Liquidated damages are presented in certain legal contracts as an estimate of otherwise intangible or hard-to-define losses to one of the parties.

As per the given situation we have

parties to a sales contract have stipulated that a specific sum be paid by any party

Liquidated damages occur in such a situation.

The amount of damages that the parties estimate and agree upon at the time of the contract for a breach of the agreement by either party is referred to as liquidated damages.

Regardless of the actual cost of any potential damages due to the breach of the contract, this amount becomes due immediately.

According to Section 74 of the Indian Contract Act, 1972, if parties agree a sum to be paid as damages or a penalty to be imposed for a breach, the harmed party is only entitled to that sum or penalty and no other higher or lesser sum.

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Answer:

12.5988 feet.

Step-by-step explanation:

Length of shadow = 15 feet.

Height of flagpole = A.

We know the angle of elevation is 40∘. Using this angle and the tangent ratio, we can find A.

Hope this helps! :)

The area occupied by the photograph in terms of x described by the quadratic equation A = x² - 20 · x + 100.

Both the backing card and the photograph are represented by two concentric squares, the area of the square is equal to the square of the side length. The expression for the area occupied by the photograph is described by the following polynomial:

A = l²

A = (x - 10) · (x - 10)

A = (x - 10)²

A = x² - 20 · x + 100

The area occupied by the photograph in terms of x described by the quadratic equation A = x² - 20 · x + 100.

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Approximately 6.8 hours Alyssa spends on the train per day.

Given that, Alyssa spent 365 hours commuting on the train over the course of 54 days.

We need to find the number of did Alyssa spend on the train per day.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

Let the number of hours Alyssa spends on the train per day be x.

Now, x=365/54

=6.759≈6.8 hours

Therefore, approximately 6.8 hours Alyssa spends on the train per day.

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Step-by-step explanation:

2a: Domain [3,7] Range: [1,5]

2b: domain: (-infinity, 1] Range: All real numbers

2c: domain [-3, 6] range [-4,2]

2d: (-infinity,-2] U (2, infinity] range: [0, infinity)

2e domain is [0, infinity) range is all real numbers

The required image of kite QRST after a reflection over the line y= -x has shown in the attached graph.

point Q (3,10)

point R (-1,9)

point S (3,7)

point T (7,9)

A graph can be defined as a pictorial representation or a diagram that represents data or values.

Reflection over the y = −x is defined as reflecting a point across they = −x,  the x-coordinate and y-coordinate change places, and t the line y = x is the coordinates (y, x). the line y = -x is the coordinates (-y, -x).

Here point Q (−7,5) reflected across the line y = -x will become (3,10).

Similarly

point R (-1,9)

point S (3,7)

point T (7,9)

Therefore, the required image of kite QRST after a reflection over the line y= -x has shown in the attached graph.

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The slope of the line for the pair of points (4,5) and (5,1) is  m= -4.

As given in the question,

Let the pair of points of the line are

(x₁ ,y₁) = (4, 5)

(x₂ , y₂) = (5,1)

Slope of the line  passing through the pair of points (x₁ ,y₁) = (4, 5) and

(x₂ , y₂) = (5,1) is given by

   m = (y₂ -y₁) / (x₂ - x₁)

⇒ m = (1-5) / (5 -4)

⇒ m = -4

Therefore, the slope of the line for the pair of points (4,5) and (5,1) is

m= -4.

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The given data be 6.1, 6.8, 8.7, 9.0, 10.2, 10.3, 10.6, 10.8, 10.9, 11.0, 11.1, 11.5, 11.7, 12.2, 13.4 then the sample range is 7.3.

A well-liked and straightforward method for comparing the variability of various data distributions is the sample range. The formula for the sample range is the greatest value minus the smallest value. It is based on two values in a data set: the maximum and minimum.

The probability distribution of a statistic that is acquired by repeated sampling of a particular population is called the sampling distribution. It outlines a variety of potential possibilities for a statistic, such as the mean or mode of a population's mean or mode of some variable.

Arrange all values in your information set from low to high.

Subtract the lowest value from the highest value.

Let the given data be 6.1, 6.8, 8.7, 9.0, 10.2, 10.3, 10.6, 10.8, 10.9, 11.0, 11.1, 11.5, 11.7, 12.2, 13.4

13.4 - 6.1 = 7.3

Therefore, the sample range is 7.3

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3000 ÷ 40 =

75 ⇐ Quotient

――――

40)3000 ⇐ Dividend

280

---

200

200

3000 divided by 40 is equal to quotient of 75 with no remainder.

To perform long division for 3000 divided by 40, Set up the long division format.

Determine how many times 40 can go into the leftmost digit of 3000 (which is 3).

The answer is 75. Write 75 on top of the division bar.

Now, subtract 3000 - 3000 to get the remainder.

The remainder is 0.

Hence,  3000 divided by 40 is equal to 75.

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Answer:

Step-by-step explanation:

Answer:

The surface area is the sum of all the faces (or surfaces) of a 3D shape. Composite figures are 2 figures put together. (There is an example of a composite figure below) You find an area of both shapes and then add them together, to find the area of the full figure.

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

When you simplify, the answer is 1.

Answer:

1

Step-by-step explanation:

Answer:

x = 14    y = 59

Step-by-step explanation:

the angle (5x - 11) is equal to the angle (3x + 17) and 3x+ 17 is equal to y

5x - 11 = 3x + 17

5x - 3x = 17 + 11

2x = 28

x = 28/2

x = 14

3x+17 = y

3(14) + 17 = y

y = 59

Step-by-step explanation:

Fact 1: Alternate angles are equal.

Angles, (5x-11)° and (3x+17)° are ALTERNATE angles and so,

(5x-11)° = (3x+17)°

5x - 3x = 17 + 11

2x = 28

x = 28 ÷ 2

x = 14

NB: x does NOT have the degree sign because it's NOT an angle on its own, but rather within the bracket/part of the calculation to get the angle degree.

Fact 2: Opposite angles are equal.

Y° and (3x+17)° are OPPOSITE angles

y = (3x+17)°

y = (3x14) + 17

y= 42 + 17

y = 59°

Hope this helps!

Answer:

1. 15          2. 30

Step-by-step explanation:

1. (2/5)x = 20

20/(2/5) = x

x = 50

50 × (3/10) = 15

2.  (2/3)y = 24

24/(2/3) = y

y = 36

36 × (5/6) = 30

The sample mean of the given data is 24.

To find the mean:

Therefore, the sample mean of the given data is 24.

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Answer:

16cm

Step-by-step explanation:

The area of a 2d figure is w x h. We know the area, a, is 80cm^2, the height, h, is 5, and the width, w, is 2x + 8.

Since we are solving for x, we want to isolate the variable.

5 x 2x + 8 = 80
80/5 = 2x + 8

We can now solve for x.

80/5 = 2x + 8
16 = 2x + 8
16 - 8 = 2x + 8 - 8
8 = 2x
8/2 = 2x/2
4 = x

We aren't done, we still need to solve for w, where we now know x = 4

w = 2x + 8
w = 2(4) + 8
w = 8 + 8
w = 16

Answer:

four times the amount of mike

Step-by-step explanation:

Answer:

1.  -10x+36

2.  24x+121

3.  2x-8xy+32y

4.  50x-10xy+y^2

Step-by-step explanation:

i think dis right

Answer:

see explanation

Step-by-step explanation:

using the following expansions

a² + 2ab + b² = (a + b)²

a² - 2ab + b² = (a - b)²

1

x² - 12x + 36

with a = x and b = 6 , then

x² - 12x + 36 = x² - 2(x)(6) + 6² = (x - 6)²

2

x² + 22x + 121

with a = x and b = 11 , then

x² + 22x + 121 = x² + 2(x)(11) + 11² = (x + 11)²

3

x² - 8xy + 16y²

with a = x and b = 4y , then

x² - 8xy + 16y² = x² - 2(x)(4y) + 16y² = (x - 4y)²

4

25x² - 10xy + y²

with a = 5x and b = y , then

25x² - 10xy + y² = 25x² - 2(5x)(y) + y² = (5x - y)²

Step-by-step explanation:

y=4x+rx+6

y-6=4x+rxy−6=4x+rx Subtract \ 6 \ from \ both \ sidesSubtract 6 from both sides

y-6=x(4+r)y−6=x(4+r) Factor \ out \ the \ common \ term \ xFactor out the common term x

\dfrac{y-6}{4+r} =x

4+r

y−6

=x Divide \ both \ sides \ by \ 4+rDivide both sides by 4+r

Answer:

the answer is clear

Step-by-step explanation:

you have to get the answer by completing the answer

Answer:

[tex]3\sqrt{3}[/tex]

Step-by-step explanation:

The values of the functions are:

a. When x =-4 then f(x) =  -x+4

b. When x = -2 then f(x) =  -x+4

c. When x = -1 then f(x) =  -x+4

d. When x=1/2 then f(x) = 3

e. When x = 2 then f(x) =  2x-5

Given, g(x) = {-x+4 , if x≤-1

                      3 ,   if -1≤x<2

                      2x-5, if x≥2 }

a. when x = -4, f(x) = ?

-4 comes under the condition x≤-1.

therefore, when x=-4 ⇒ f(x) = -x+4

f(-4) = -4+4 = 0

b. when x=-2, f(x)= ?

Again -2 comes under the condition if x≤-1

therefore when x=-2 ⇒ f(x) = -x+4

f(-2) = -2+4 = 2

c. when x=-1, f(x) = ?

-1 comes under the condition if x≤-1

therefore, when x=-1 then f(x) = -x+4

f(-1) = -1+4 = 3

d. when x=1/2 , f(x) = ?

1/2 comes under the condition, if -1≤x<2

therefore, when x=1/2 then f(x) = 3.

e. when x=2, f(x) = ?

2 comes under the condition, if x≥2

therefore, when x=2 then f(x)= 2x-5.

hence we get the required results of the given functions.

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The possible coordinates of point l are (7,3),(7,-13),(-5,3),(-5,-13),(9,1),(9,-11),(-7,1), and (-7,-11).

Given that:-

Coordinates of k = (1,-5)

Distance between point k and point l = 10 units.

We have to find the coordinates of point l.

Let the coordinates of point l be (x,y).

By using distance formula, we can write:-

[tex]\sqrt{(x-1)^2+(y+5)^2} =10[/tex]

Squaring on both sides, we get:-

[tex](x-1)^2+(y+5)^2=100[/tex]

For, integer coordinates, the possibilities are 36+ 64 or 64+36.

Hence, we can write,

[tex](x-1)^2+(y+5)^2 = 36 + 64 \\or\\(x-1)^2+(y+5)^2 = 64 + 36[/tex]

Hence,

[tex](x-1)^2 = 36[/tex]

x - 1 = 6 or x -1 = -6

x = 7 , -5

[tex](y+5)^2 =64[/tex]

y + 5 = 8 or y + 5 = -8

y = 3,-13

or

[tex](x-1)^2=64[/tex]

x - 1 = 8 or x - 1 = -8

x = 9,-7

[tex](y+5)^2[/tex]

y + 5 = 6 or y + 5 = -6

y = 1,-11

Hence, the possible values of coordinates of point l are (7,3),(7,-13),(-5,3),(-5,-13),(9,1),(9,-11),(-7,1), and (-7,-11).

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The solution are-

(a) lim h (x) = -2

   x → -2⁻

(b) lim h (x) = -2

   x → -2⁺

(c) lim h (x) = -2

   x → -2

A limit describes the value which a function approaches as its inputs get increasingly closer to a certain number.

The concept of a limit is at the heart of all calculus.

(a) lim h (x) = -2

   x → -2⁻

Put x = 2 at the place of x in h(x).

This limit is called the left hand limit of the function as there is negative sign over 2.

(b) lim h (x) = -2

   x → -2⁺

Put x = 2 at the place of x in h(x).

This limit is called the right hand limit of the function as there is positive sign over 2.

(c) lim h (x) = -2

  x → -2

Put x = 2 at the place of x in h(x).

This limit exists just at x = 2.

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