Book A with a mass of 1.00 kg is placed on a horizontal table. Book B with a mass of 0.500 kg is placed on top of book A. What is the magnitude of the normal force exerted on book A by the table?

Answer:63745.6573

Explanation:

Answer:  

4.27s

Explanation:

If "t" represents the time traveled from the time rock 2 is dropped until the collision, then the time traveled for rock 1 = t + 1. And, since rock #1 is dropped making its initial velocity = 0, then:

The distance rock 1 travels is  

x = (0)(t + 1) + 1/2(-9.8)(t + 1)2 = -4.9(t2 + 2t + 1) = -4.9t2 - 9.8t - 4.9

The distance rock 2 travels  

x = -11.3t + 1/2(-9.8)t2 = -11.3t - 4.9t2

For the distances must be equal when the rocks collide:  

-4.9t2 - 9.8t - 4.9 = -11.3t - 4.9t2  

-9.8t - 4.9 = -11.3t  

-4.9 = -1.5t  

t = 3.267 s

Now, the distance they traveled can be found by plugging the 3.267 s back into either equation:

x = -11.3(3.267) - 4.9(3.267)2 = -89.2 m or 89.2 m below where they began

The time the first rock was in the air is t + 1 = 3.267 + 1 = 4.267 s = 4.27 s

Let

First rocks time be x

Second rocks time be x+1

initial velocity=u=11.3m/s

Distance of both rocks be s1 and s2

[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]

Now

[tex]\\ \sf\longmapsto s1=11.3x+5x^2[/tex]

[tex]\\ \sf\longmapsto s2=11.3(x+1)+5(x+1)^2[/tex]

As both collide then

[tex]\\ \sf\longmapsto s1=s2[/tex]

[tex]\\ \sf\longmapsto 11.3x+5x^2=11.3x+11.3+5(x+1)^2[/tex]

[tex]\\ \sf\longmapsto 5x^2=11.3+5x^2+10x+1[/tex]

[tex]\\ \sf\longmapsto 10x+12.3=0[/tex]

[tex]\\ \sf\longmapsto x=1.23s[/tex]

Displacement

[tex]\\ \sf\longmapsto 11.3(1.23)=13.8m[/tex]

Done

The actual speed or velocity of the man relative to the earth is 15.52km/hr.

The direction of the man's velocity relation to earth is 75° South of West.

Given the data in the question;

To get the velocity of the man relative to the earth. From Pythagorean theorem

We can simply say

[tex]v_E = \sqrt{(v_{mrs})^2 + (v_s)^2}[/tex]

We substitute in our given values

[tex]v_E = \sqrt{(4km/hr)^2 + (15km/hr)^2}\\\\v_E = \sqrt{(16km^2/hr^2) + (225km^2/hr^2})\\\\v_E = \sqrt{241km^2/hr^2}\\\\v_E = 15.52 km/hr[/tex]

Therefore, the actual speed or velocity of the man relative to the earth is 15.52km/hr

To get the direction of the man's speed. From the three main trigonometric ratios: SOH CAH TOA

[tex]tan\theta = \frac{opposite}{adjacent}[/tex]

[tex]tan\theta = \frac{v_s}{v_{mrs}}[/tex]

We substitute in our values;

[tex]tan\theta = \frac{15km/hr}{4km/hr}\\\\tan\theta = 3.75\\\\\theta = tan^{-1}( 3.75)\\\\\theta = 75^o[/tex]

Therefore, the direction of the man's velocity relation to earth is 75° South of West

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Answer:

133 kg

Explanation:

the statement was the last time I get home and get some sleep and then we can

Answer:

need my points back

Explanation:

Answer:

A coral reef is an underwater ecosystem characterized by reef-building corals. Reefs are formed of colonies of coral polyps held together by calcium carbonate. ... Unlike sea anemones, corals secrete hard carbonate exoskeletons that support and protect the coral.

Coastal oceans are commonly defined as the areas from the shoreline to the outer edge of the continental margin. They connect the continents to the open ocean and serve as a link for transporting organic and inorganic, natural and anthropogenic material from land to sea.

Coastal oceans in tropical areas have similar characteristics to their temperate counterparts. ... Coral reefs are biologically diverse and rich habitats that occur in relatively nutrient-poor environments along coastlines. Areas that have too many nutrients often harbor too much algal growth to sustain coral growth.,

Explanation:

Explanation:

Sorry but the question is incomplete

4.9 m/s to the right

Explanation:

We are going to use the conservation law of linear momentum to find her velocity. Initially, they are motionless so their initial total momentum is zero. Let's assume that anything moving to the left has a negative velocity and anything moving to the right has a positive velocity. We can write the conservation law of momentum as

[tex]0 = M_mv_m + M_wv_w[/tex]

where

[tex]M_m[/tex] = mass of the man = 55 kg

[tex]v_m[/tex] = velocity of the man = -4.3 m/s

[tex]M_m[/tex] = mass of the woman = 48 kg

[tex]v_w[/tex] = velocity of the woman

[tex]\Rightarrow 0 = (55\:\text{kg})(-4.3\:\text{m/s}) + (48\:\text{kg})v_w[/tex]

Solving for [tex]v_w,[/tex]

[tex]v_w = \left(\dfrac{55\:\text{kg}}{48\:\text{kg}}\right)(4.3\:\text{m/s}) = 4.9\:\text{m/s}[/tex]

going to the right.

Answer:

I think the second one! So sorry if it's wrong!

Explanation:

Because if it's sitting motionless, then nothing is happening to it.

A book sits motionless on a table so the forces acting on the book are balanced by each other.

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

A book sits motionless on a table that means forces acting on the book are balanced by each other. As book have mass so gravitational force acting in downward but opposite to that normal force because of friction is acting that stops book to be in motion.

A book sits motionless on a table so the forces acting on the book are balanced by each other.

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The kinematics allows finding the answers for the positions of the body as a function of time and making its graph are:

Given parameters

To find

Kinematics studies the motion of bodies, gives relationships between the position, velocity and acceleration of bodies, let's use the relationship

          x = v₀ t + ½ a t²

Where x is the position, v or the initial velocity, at the acceleration and t is the time.

Let's substitute

           x = 5 t + ½ 2.5 t²

           x = 5 t + 1.25 t²

Let's calculate the position and write it in the table

t = 0 s       x = 0 m

t = 1 s        x = 5 1 + 1.25 1² = 6.25 m

t = 2 s       x = 5 2 + 1.25 2² = 15 m

t = 3s        x = 5 3 + 1.25 3² = 26.25 m

t = 4 s       x = 5 4 + 1.25 4² = 40 m

t = 5 s       x = 5 5 + 1.25 5² = 56.25 m

In the following table the time and positions of the body are given, these given are used for the attached graph

time (s)      position (m)

   0                  0

    1                  6.25

   2                 15

   3                 26.25

   4                 40

   5                 56.25

In conclusion, using kinematics we can find the answers for the positions of the body as a function of time and make its graph are:

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Following are the solution to the given points:

Given:

[tex]\to mass(m)= 65\ kg\\\\\to h=10.0 \ m\\\\\to g=9.8 \ \frac{m}{s^2}[/tex]

To find:

gravitational potential energy(GPE)=?

kinetic energy(KE)=?

concept=?

v=?

Solution:

For point a:

[tex]\to GPE= mgh[/tex]

             [tex]= 65 \times 10 \times 9.8\\\\ = 6370 \ J\\\\[/tex]

For point b:  

[tex]\to KE=\frac{1}{2} m v^2\\\\[/tex]

           [tex]=\frac{1}{2} \times 65 \times 14^2 \\\\=\frac{1}{2} \times 65 \times 14 \times 14 \\\\= 65 \times 14 \times 7 \\\\=6370\ J\\[/tex]

For point c:

As we've seen, there really is no force acting, and the mechanic KE: GPE is used. Because legitimate is conserved. Home energy loss means GPE must be equal to KE gain.

For point d:

A diver has risen 5 feet above the surface. As a result, according to the energy conservation law:

[tex]\to U_i + K_i= U_f + K_f\\\\ \to mg \times h + 0 = mg \times \frac{h}{2} + \frac{1}{2} m v^2\\\\ \to 9.8 \times 10 = 9.8 \times 5 + \frac{v^2}{2}\\\\\to 9.8 \times 10 - 9.8 \times 5 = \frac{v^2}{2}\\\\\to \frac{v^2}{2} =9.8( 10 - 5) \\\\\to v^2 =9.8( 10 - 5) \times 2 \\\\\to v^2 =9.8\times 5 \times 2 \\\\\to v^2 =98 \\\\\to v =98\ \frac{m}{s^2} \\\\[/tex]

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Answer:

c.

5 m/s2

Explanation:

Δv = at

a = Δv/t

a = (0 - 25)/5

a = 5 m/s²

Answer:

0.75 grams

Explanation:

Today we have 6 grams

In 30 years, 3 grams remain

In 60 years 1.5 grams remain

in 90 years 0.75 grams remain

mathematically It would look like this

m = 6(0.5⁽ⁿ/³⁰⁾) where n is number of years

Answer:

Basketball

Explanation:

Im asuming basketball because a basketball has the least movement out of the rest of the answers.

Answer:

2.0 m/s

Explanation:

Remember that F = maF=maF, equals, m, a, where FFF is the net force, mmm is the mass of the object, and aaa is its acceleration. To solve this problem, we will need to first find the net force acting on the piano and then use F = maF=maF, equals, m, a to find the piano’s acceleration.

Hint #22 / 4

The net force is the sum of all of the forces on the piano. In this circumstance, Elvis's and Noah's forces are in the same direction, and the friction force is in the opposite direction. So, our net force equation would be:

​

=400 N+150 N−100 N

=450 N

Now, we can use F = maF=maF, equals, m, a and solve for the acceleration:

225 kg

450 N

=2.0

The acceleration of the piano is 2.0 m/s

The acceleration of the piano is 2m/s².

We know the formula for force is

F =ma

where f is force, m is mass and a is acceleration.

We need to calculate the total force used in moving the piano

F= Total force- Frictional force

F= 400N+150N-100N= 450N.

We have F=450N and m= 225kg

F=ma

450N= 225ˣ a

a= 450/225

a= 2m/s²

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Answer:

Explanation:

Without the FBD or a good description of the set up, I'd have to say we cannot tell.

If the set up is of the simplest form with a mass on a horizontal surface being acted on by a horizontal force, then that force must be 80 + 25 = 105 N.

As force is a vector, there are an infinite number of other possibilities for force magnitude depending on which direction the force is acting. The mass is also an unknown variable that would affect the applied force magnitude if the direction is not horizontal.

50 mL of water have to poured to the glass bottle of 100 g to increase the stretching of the spring from 1.8 cm to 2.7 cm.

A spring can hang when it loads a weight. The stretching of spring is the change in length of the spring end from its initial length.  Spring balance works with the principle of Hooks law.

The stretching is made by the elasticity of the spring which make it in a wave like motion.

Given that the glass bottle with 100 g weight when loaded on the spring scale, it will stretch down to 1.8 cm. Then the weight required to make a stretch of 2.7 cm is calculated as follows:

weight required  = (100 g × 1.8 cm) /2.7 cm

                            = 150 g.

A total of 150 g is needed to stretch into 2.7 cm. Thus we have to add 50 g of water to the glass weighing 100 g . 50 g is equivalent to 50 ml, since density of water is 1 g/L.

Hence, 50 ml of water should be poured to the glass.

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Answer:

The square of orbital period is proportional to the cube of the semi-major axis.

Explanation:

I just took the quick check

Answer:

120 V.

Explanation:

voltage V=IxR

= 4x30

= 120 V.

Answer:

1) which planet's orbit was Kepler first studying when he began to developed his laws of orbital motion? Answer: Mars

2) which is the best description of Earth's orbit? Answer: almost circular

3) which orbital shape did most scientists in the early 1600s think the planets of our solar system have? Answer: circular

4) which of these describes Kepler's third law of orbital motion? Answer T^2 OX a^3

5) which statement describes Kepler's third law of orbital motion? Answer The square of orbital period is proportional to the cube of the semi-major axis.

Explanation:

I just took the connexus quick check and got a 100%

T2 ∝ a3 is the relation that describes Kepler’s third law of orbital motion, therefore the correct answer is option C.

There are three laws of Kepler as follows,

The orbit of the planet is elliptical and the sun is present at one of the two foci of the elliptical route followed by the rotating planet.

A line segment linking a planet and the Sun covers equal regions throughout equal intervals of the time period.

The semi-major axis length of an elliptical planet's orbit is equal to the square of the planet's orbital period.

T2 ∝ a3 is the relation that describes Kepler’s third law of orbital motion,

Thus, the correct answer is option C.

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Answer:

C. 10

Explanation:

On the graph you can see that at the 10 second mark it is at the 10 meters mark as well.

Explanation:

given :

m = 20 g

sh = 0.39 J/g°C

∆T = 40-20 = 20°C

Find the Energy!

solution :

E =m. sh. ∆T

= 20 × 0.39 × 20

= 156 J

So, energy required is

Energy = mass*sh*∆T

Energy = 20g*0.39j/g°c*20°

Energy = 156joule✅

~Physics#1

Answer:

[tex]\sf\longmapsto \: 2.0m/s[/tex]

Explanation:

Initial momentum = 0

[tex]\sf\longmapsto \: 77 \: velocity + 62 \times 2.5 = 0[/tex]

[tex]\sf\longmapsto \: 77 \: velocity = - 155[/tex]

[tex]\sf\longmapsto \: velocity = \frac{ - 155}{77} [/tex]

[tex]\sf\longmapsto \: \: velocity = - 2.012[/tex]

[tex]\sf\longmapsto \: 2.0 \: m/ s[/tex]

Answer:

In a third class lever, the effort is located between the load and the fulcrum. If the fulcrum is closer to the load, then less effort is needed to move the load. If the fulcrum is closer to the effort, then the load will move a greater distance. ... These levers are useful for making precise movements.

Explanation:

The sun is what makes the water cycle work. The sun provides what almost everything on Earth needs to go—energy, or heat. Heat causes liquid and frozen water to evaporate into water vapor gas, which rises high in the sky to form clouds... clouds that move over the globe and drop rain and snow.

Answer:

"The sun is what makes the water cycle work. ... Heat causes liquid and frozen water to evaporate into water vapor gas, which rises high in the sky to form clouds... clouds that move over the globe and drop rain and snow. This process is a large part of the water cycle."

Explanation:

Answer:

the correct answer is cells can generate from nonliving matter

Answer:

Power = Work / Time

available power = .154 * 85.7 = 13.2 hp

1 hp = 746 watts (joule/sec)

13.2 hp = 13.2 * 746 = 9850 J/sec

Work = P * t = 9850 J/sec * 14.3 s = 141,000 joules

This is the work performed on the airplane and the car

Work = F * s   (force * distance)

F = 141000 J / 26 m = 5420 Newtons    opposes the motion

Answer:

Distance =60m, Time = 6s, Speed = ?

Speed = distance/time

= 60/6

=10m/s

Explanation:

Hope that this is helpful.

Have a nice day.

Answer:

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Explanation:

ndnskskdjdkskdkxjdis bdjdkdnd

Answer:

Games such as Patintero, Tumbang Preso, Piko, Sipa, Turumpo, and many others, are still played daily in neighborhoods.

Explanation:

Hope this helps... Maybe

Answer:

Explanation:

a_c = ω²R

14 rev/min (2π rad/rev)(1 min/60 s) = 1.466 rad/s

a_c = 1.466²(0.27/2)

a_c = 0.29 m/s²

Le hamster est lent