An astronomer observes two ordinary stars. the first one turns out to be twice as hot as the second. this means that the first one radiates:________

The horizontal force p must a worker, new tension is P= 122.62 N

The tension in the rope is

[tex]T_{1}=W_{create} g[/tex]

T1=50×9.81

T1=490.5 N

And the rope is in vertical position

When a worker exert a horizontal force P on the rope, new tension is

[tex]T_{2} =\sqrt{T1^{2} +P^{2} }[/tex]

[tex]T_{2} =\sqrt{490.5}^{2}+P^{2}[/tex]

Since T1 is vertical component to the tension T2

[tex]T_{1} =T_{2} cos \alpha[/tex]

[tex]490.5^{2} /cos^{2} 14.036=490.5^{2} +P^{2}[/tex]

[tex]P^{2} =490.5^{2} /cos^{2} 14.036 - 490.5^{2}[/tex]

P= 122.62 N

As long as no horizontal applied forces are present, the horizontal response force is zero. A single-support cantilever beam has a response force and reaction moment. The total applied forces on the beam are equal to the reaction force.

When the compression pressures are removed, the distortion may either be permanent or reversible. In the latter scenario, the deformation creates reaction forces that compete with the compression forces and may ultimately bring them into balance.

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A kangaroo will stay 0.699s in the air when he jumps.

A projectile is an object that is launched vertically into the air and moves while being pulled by gravity. A projectile is an object that is launched into the air horizontally and moves regardless of gravity.

G = -9.81 m/s2 is the acceleration of gravity close to the earth. Simply multiply the acceleration of gravity by the period since the object was released to determine the object's speed (or velocity). In other words, velocity is equal to -9.81 m/s2 * time, or V = gt.

From the conversion of energy  =[tex]h=\frac{g t^2}{2}[/tex]

                                                 t = √(2h/g)

                                                   =  √((2 x 2.40) / 9.8)

                                                  =0.699 s

A kangaroo will stay 0.699s in the air when he jumps.

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C3H7Br would neutralize 78.2 ml of 2.549 m hydrobromic acid.

Hydrobromic acid, a powerful acid that is created by dissolving hydrogen bromides in water, is the end product.

Hydrobromic acid is a diatomic compound with the molecular symbol HBr. Hydrogen bromide is a colorless, suffocating gas that is extremely soluble and dissociated in water.

It quickly reeks when moist air is present. When encountered, hydrogen bromide gas, a very corrosive chemical, can cause severe burns.

Hydrobromic Acid’s Chemical Makeup – HBr

Sulfur dioxide, bromine, and water are produced when hydrobromic acid and sulfuric acid are combined. Below is the chemical equation.

Br2 + SO2 + 2H2O = 2HBr + H2SO4

2-Bromopropane is created when hydrobromic acid and propene undergo an addition process. Below is the chemical equation.

C3H6 + HBr = C3H7Br

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Answer: Oxygen, silicon, iron and aluminum

Explanation: Oxygen, which composes about 49.5% of the total mass of the Earth’s crust, waters and atmosphere, according to the textbook “Modern Chemistry.” Silicon is second at 28%. Aluminum is a distant third, at only 8%. Compounds of silicon and oxygen make up 87% of the materials in the Earth’s crust.

The algebraic expression for the electric field for a point

We know that,

Φ = Q / ε[tex]_{0}[/tex]

Φ = EA

Q = σ A

where,

Φ = Electric flux

Q = Total charge

ε[tex]_{0}[/tex] = Electric constant

σ = Surface charge density

A = Area

Area of cylinder = 2 π R l

where,

R = Radius of cylinder

l = Length of cylinder

To calculate electric field at a point outside the cylinder, a gaussian surface is considered outside the cylinder with a radius r ( > R ) and length l. The flux on Gaussian cylinder is equal to the charge on surface of the cylinder.

Q = σ 2 π R l

The electric flux on the surface of cylinder is

Φ = σ 2 π R l / ε[tex]_{0}[/tex]

The electric flux on the Gaussian cylinder is

Φ = E 2 π r l

On equating both,

σ 2 π R l / ε[tex]_{0}[/tex] = E 2 π r l

E = σ R / ε[tex]_{0}[/tex] r

This is the equation for electric field at a point outside the cylinder.

To calculate electric field at a point inside the cylinder, a gaussian surface is considered inside the cylinder with a radius r ( < R ) and length l.

E 2 π r l = 0 ( Since there is no flux created inside a closed cylinder )

E = 0

This is the equation for electric field at a point inside the cylinder.

Gauss law states that the total flux outside a closed surface is directly proportional to net charge enclosed by the surface.

Therefore, the algebraic expression for the electric field for a point

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The photon energy excite the hydrogen atom when its electron is in the ground state −13.6eV.

The second energy level is -3.4 eV.

Therefore, if we calculate the energy levels E₁ & E₂

E₂ − E₁ = -3.4 eV − -13.6 eV = 10.2 eV

Hence, the above expression shows, to excite the electron from the ground state to the first excited state. Similarly

The energy of the electron in ground state is −13.6eV.and the energy required to move electrons from ground state to third excited state is 12.75eV.

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Spacecraft will take around 49 minute and 92 second to coast from perigee to the apogee.

We use Kepler's third law for which the time period is defined as

[tex]T = 2 \pi \sqrt[]{\frac{a^{3} }{GM} }[/tex]

The Prague's altitude is the shortest distance between the earth's surface and satellite.

The average distance of the perigee and  apogee of satellite can be defined as

a = R + [tex]\frac{r_{1} +r_{2} }{2}[/tex]

R is the radius of earth (6374.1km)

r1 is the lower orbit. (500km)

r2 is the higher orbit.(900km)

Using the values in above equation we get:

6374.1+ (500+ 900)/2

a = 7078.1 km

Time taken to fly from perigee to apogee equals to the half of the orbital speed so

t = T/2

[tex]t = \pi \sqrt[]{\frac{a^{3} }{GM} }[/tex]

by using the values we get-

=  √[(7078.1)³/6.67 ×10⁻¹¹ × 6×10²⁴]

= 295573.94 * 10⁻²

= 2995.73s

t = 49 mint 92 sec

It will take around 49 minute and 92 second to coast from perigee to the apogee.

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The left hand plays a steady one-two beat in duple meter, while the right hand emphasizes notes that fall in between these beats. The name for this technique is syncopation.

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The acceleration of the particle will be 0.

We have position function of a particle is a linear function of time.

We have to determine its acceleration.

The rate of change of velocity with respect to time is called Acceleration.

According to the question -

Assume that the linear function of position of a particle is as follows -

x = mt + c

Where x is displacement of particle and t is time.

Now, Differentiating with respect time, we get velocity -

[tex]$\frac{dx}{dt} = \frac{d}{dt}\;(mt+c) = m[/tex]

Differentiating again with respect time, we get acceleration -

[tex]$\frac{d^{2} x}{dt^{2} } = \frac{d}{dt}\;m = 0[/tex]

Hence, the acceleration of the particle will be 0.

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To find the electron and hole concentrations and fermi levels in silicon at 300 k for boron, fermi level is 9.3 x [tex]10^4 cm^-3[/tex].

Ionization energy for boron in Si, 0.045 eV

Fermi level in silicon,

300 K at [tex]10^{15} cm^{-3}[/tex] (Boron atoms)

All boron impurities are ionized, 300K

Electron, hole concentrations and Fermi levels is found out,

The value of Na = [tex]10^{15} cm^{-3}[/tex]

np = [tex]\frac{ni^2}{nA}[/tex]

np = [tex]\frac{(9.65 x 10^9)^2}{10^15}[/tex]

np= 9.3 x [tex]10^4 cm^-3[/tex]

Fermi level is calculated,

Ef - Ev = kT ln(NV/ND)

value of kT = 0.0259 eV (300° K)

So, substitution the values

Ef - Ev = kT ln(NV/ND)

Ef - Ev = 0.0259ln (2.66 x [tex]10^{19} / 10^{15}[/tex] )

Ef - Ev = 0.0259ln (26600)

Ef - Ev = 0.0259 x 10.18

Ef - Ev = 0.263 eV

What is ionization energy?

Ionization energy, also known as ionization energy (IE) or ionization energy (British English spelling), is the minimal amount of energy needed to free the most loosely bonded electron from an isolated gaseous atom, positive ion, or molecule in physics and chemistry.

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The correct answer is 5.6 Newton is the force on the egg .

Using newtons 2 law of motion

force  = mass  * accelaration

now accelaration =10 m / s^2

mass = 0.56 kg

force  = 0.56 * 10

force  = 5.6 newton

Newton's second law of motion governs the behavior of objects when all available forces are not balanced. The second law states that an object's acceleration is determined by two variables: the net force acting on the object and the object's mass. The acceleration of an object is proportional to the net force acting on it and inversely proportional to its mass. The acceleration of an object increases as the force acting on it increases. The acceleration of an object decreases as the mass of the object increases.

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Here the total time of flight is used to determine how long it will take the ball. it takes 5s to the ball to hit the ground.

u = 25 m/s

h= 1.90 m

so tine of ascent = v= u + at

so u = gt so we have t =u/g

putting up the values we have,

t = 2.5 s

so total time of flight = 5s = time taken by the ball to hit the ground.

An object is said to be in free fall if there are no external forces acting on it other than gravity, which has the determined constant value of g = -9.8 m/s2. The object’s height, or h, is equal to ½ gravity times the square of the falling time. Horizontal projectile motion equations

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Its nucleus has eleven protons.

The nucleus of it has 12 neutrons.

The nucleus is surrounded by 10 electrons.

Net charge, proton (+1), and electron charges are used to calculate the number of electrons (-1).

Calculated from the atomic number of 11 and the mass number of 23, are 12 neutrons.

What are mass number and atomic number?

The total number of protons or electrons in an element is known as its atomic number. Therefore, using the atomic number to distinguish one element from another is helpful. The total number of protons and neutrons in an element is known as the mass number.

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Question:

An atom of sodium-23 (Na-23) has a net charge of +1. Identify the number of protons, neutrons, and electrons in the atom. Then, explain how you determined the number of each type of particle. Use the periodic table to help you.

The cart's speed is 0.5 m/s and the puck's speed is 0.45 m/s is 0.05 and .95m/s

Given:

A=The cart's speed is 0.5 m/s

B=The puck's speed is 0.45 m/s

Relative velocity formula =

[tex]V_{AB}=V_{A}-V_{B}[/tex]

[tex]V_{AB}=.5-.45=.05\\[/tex]

[tex]V_{BA}=V_{B}-V_{A}[/tex]

=.5+.45=0.95

The velocity of an object in respect to another object is defined as relative velocity. It is a measure of how rapidly two items move in relation to each other. In physics, relative velocity is significant because it explains how objects move and interact with one another. Many different sorts of interactions can have their relative velocity quantified. The velocity of an object in respect to another object is defined as relative velocity. It is a measure of how rapidly two items move in relation to each other. In physics, relative velocity is significant because it explains how objects move and interact with one another.

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The visible light spectrum is bounded by these two types of radiation: ultraviolet and near infrared.

In physics, electromagnetic radiations are kind of waves that carry electromagnetic field and travel through space.

These waves transport electromagnetic energy while traveling through space.

Different types of electromagnetic waves are radio waves, infrared light, microwaves, gamma rays, UV radiations, and x-rays. While visible light is made up of only infrared and UV.

All these waves have different wavelengths, frequency and energy and make definite part of the electromagnetic spectrum.

These waves have dual nature and also exhibit dual particle nature and travel with light speed.

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The ball goes at the highest setting of 2.25cm, which compresses the spring by 3 cm.

Spring is an elastic object that holds mechanical energy. Typically, springs are fabricated from spring steel. Springtime has many different patterns. A conventional spring without stiffness variability features exerts an opposing force that is roughly proportional to its change in length when it is compressed or stretched from its resting state. The word is frequently used to describe coil springs in daily speech (this approximation breaks down for larger deflections). The rate also referred to as the spring constant, is the proportion of a spring's change in force to change in deflection. In other words, it is the force against the deflection curve's gradient.

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Answer:

c

Explanation:

The texture of the string. I took this test a week ago I got a 90% it is c!

The airplane lands with a velocity of 150 m/s and its rate of deceleration is constant at -3 m/s^2,

[tex]u = 150 m/s[/tex]

[tex]a = -3 m/s^{2}[/tex]

[tex]v = 0[/tex]

According to the Equation of motion , [tex]v^{2} = u^{2} + 2as[/tex]

s = 3750 m

Equations of motion are the mathematical formula that describes the position, velocity, or acceleration of a body relative to a given frame of reference.

The airplane will have to travel 3750 m until it stops if its rate of deceleration is constant at -3 m/s^2.

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If a hypothetical planet is twice as far from the sun as the earth, it should have a time period of 1032 days.

In the early 17th century, Johannes Kepler observed planetary motions and researched them to give three laws known as Kepler’s Laws.

These laws are:

(1) Law of orbits

(2) Law of Areas

(3) Law of Periods

According to the third law, the square of the time period of revolution of a planet around the sun is proportional to the cube of the distance between the sun and the planet, represented by the following  formula

T^2 = r^3

Let T1 be the time period of the revolution of Earth and T2 be the time period of the revolution of the hypothetical planet.

Let r1 be the distance between Earth and the sun and r2 be the distance between the hypothetical planet and the sun.

From the above equation

T1^2 = r1^3

T2^2 = r2^3

Dividing the above equations,

(T1/T2)^2 = (r1/r2)^3

We are given that,

r2 = 2 x r1

And T1 = 365 days

So,

(365/T2)^2 = (r1/2r1)^3

Solving the above equation,

T2 comes out to be 1032 days.

Hence, if a hypothetical planet is twice as far from the sun as the earth, it should have a time period of 1032 days.

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4.89g of solid magnesium nitrate (148.3 g/mol) should be added to 500 ml of 0.118 m of sodium nitrate in order to produce an aqueous 0.25 m solution of nitrate ions.

From the given info, we know that there is already the presence of nitrate already mixed in the solution. then we have to find out how more is required to be added to it.

first, we find moles of NaNO3

0.500L x 0.118 M = 0.059 moles NaNO3

this means there are 0.059 moles of[tex]NO^{-} _{3}[/tex]

Here volume is not changing, so amount of moles needed to make this concentration = 0.25M x 0.5L = 0.125 moles

0.125 - 0.059 moles = 0.066 moles of [tex]NO^{-} _{3}[/tex] required to be added in the solution.

for every 1 mole of Mg[tex](NO^{-} _{3} )_ {2}[/tex], there are 2 moles of [tex]NO^{-} _{3}[/tex].

so, we will only need half of the total moles of magnesium nitrate.

converting moles to grams,

0.033 moles Mg[tex](NO^{-} _{3} )_ {2}[/tex] x 148.3 g/mol = 4.89g Mg[tex](NO^{-} _{3} )_ {2}[/tex]

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Answer:

Telescope, Probware, etc,..

Answer: probeware

Explanation:

the answer is probeware

if you mean by the options,

A. a ruler

B. a thermometer

C. a beaker

D. probeware

Olympus mons can be found on Mars planet.

In the Tharsis Montes region, close to the Martian equator, Olympus Mons is one of a dozen large volcanoes, many of which are ten to one hundred times taller than their terrestrial counterparts. The massive Martian mountain towers high above the surrounding plains of the red planet and may be waiting for the next eruption. The highest of them all runs about 374 miles (624 km), or about as far as the state of Arizona, and rises 16 miles (25 km) over the plains below. Olympus Mons rises three times higher than Mount Everest, which has a peak elevation of 5.5 miles above sea level and is the tallest mountain on Earth.

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The minimum speed the ball must be served so as to clear the net is 25.69 m / s

We know that,

Speed = Distance / Time

In order to calculate the time, we can use one of the equations of motion,

y = [tex]y_{0}[/tex] + [tex]v_{0}[/tex]t + 1/2 a[tex]t^{2}[/tex]

where,

y = Initial height

[tex]y_{0}[/tex] = Final height

[tex]v_{0}[/tex] = Initial velocity

a = Acceleration due to gravity

t = Time

Given that,

y = 2.7 m

[tex]y_{0}[/tex] = 1.08 m

[tex]v_{0}[/tex] = 0

a = -9.81 m / [tex]s^{2}[/tex] (Due to gravity)

Distance = 14.9 m

y = [tex]y_{0}[/tex] + [tex]v_{0}[/tex]t + 1/2 a[tex]t^{2}[/tex]

2.7 = 1.08 + 0 + 1/2  * ( -9.81 ) * [tex]t^{2}[/tex]

[tex]t^{2}[/tex] = 1.62 / ( - 4.9 ) = 0.33

t = 0.58 s

Speed = 14.9 / 0.58

Speed = 25.69 m / s

Velocity (speed) is the rate of change of distance with respect to time. It is denoted as V.

Therefore, the minimum speed the ball must be served so as to clear the net is 25.69 m / s

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Phase contrast microscope shows cells against a bright background and the intracellular structures of unstained cells based on their varying densities.

A technique called phase-contrast microscopy is used to contrast a translucent object without staining it. Phase-contrast microscopy has a number of benefits, including the ability to employ high-resolution objectives, but doing so necessitates a specialised condenser and more expensive objectives.

With the help of the optical contrast technique known as phase contrast, biological specimens' cells can show their unstained architecture. With brightfield illumination, cell structures that appear transparent can be seen in high contrast and in great detail with phase contrast.

Phase-contrast photographs often have a grey backdrop with varying amounts of light and dark elements. Halo-light ring creation, a drawback of phase-contrast microscopy, is one.

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An earth satellite has a speed of 7.5 km/s and a flight path angle of 10 degrees when its radius is 8000 km.

-21.7km square /s square is the angular momentum (in km 2/s).

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The following question can be solved using formulas of Motion on one dimension as there is no updrift or downdrift

We will use the formula

[tex]v^{2}-u^2=2aS[/tex]

where v is the final velocity

u is the initial velocity

a is the acceleration of the boat

s is the distance in meters

u=0 as the initially the boat is at rest

S=12meter

acceleration is 5 m/s^2

[tex]v^{2}=[/tex]2 x 5 x 12

v^2=120

therefore final velocity is [tex]\sqrt{120}[/tex]=10.95m/s

Now using the formula v=u+at

v=[tex]\sqrt{120}[/tex]

[tex]\sqrt{120}[/tex]=0+5 x t

t= [tex]\sqrt{ 120[/tex]/5

t = 2.20 seconds

t is the time taken

Hence the boat takes 2.20seconds

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The height need to change by 4 to double the final velocity.

The final velocity of an object during a free fall is related to maximum height of fall as given the equation below.

v = √2gh

v² = 2gh

v²/h = 2g

v₁²/h₁ = v₂²/h₂

when v₂ = 2v₁, change in height is calculated as;

h₂ = h₁v₂²/v₁²

h₂ = (h₁ (2v₁)²) / (v₁)²

h₂ = 4h₁v₁² / v₁²

h₂ = 4h₁

Thus, the height need to change by 4 to double the final velocity.

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Answer:

See below

Explanation:

It will be 1 PM distance (27km)  + 2 1/2 hrs of 98 km/hr

   =     27   +      2 1/2 * 98 = 272 km west of school