The relative frequency are
i) Pilot error = 15.9 percent
ii) Human Error =3.8 percent
iii) Weather = 19.3 percent
iv) Mechanical problem = 42 percent
v) Sabotage = 19.2 percent
The formula for the relative frequency is = f/n
Where, f = the number of times the data occurred in an observation
n = total number of observations.
If we have to convert it into percentage form we will multiply it by 100
Thus we have been given that
Crashes due to pilot error = 260
Crashes due to other human error = 62
Crashes due to weather = 315
Crashes due to mechanical problem = 682
Crashes due to sabotage = 313
Total number of errors occurred = 260+62+315+682+313
= 1632
Hence, the relative frequency are
i) Pilot error = 260/1632 * 100 = 15.9 percent
ii) Human Error = 62/1632 * 100 =3.8 percent
iii) Weather = 315/1632 * 100 = 19.3 percent
iv) Mechanical problem = 686/1632 * 100 = 42 percent
v) Sabotage = 313/1632 * 100 = 19.2 percent
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Let , which represents the set of points on and inside an in the xy-plane. find two specific examples two vectors, and a vector and a scalar to show that h is not a subspace of .
The two vectors and a vector and a scalar which shows that H is not a subspace of [tex]R^2[/tex] are [tex]\bold{\left[\begin{array}{c}\frac{1}{5} \\\frac{1}{4} \end{array}\right]}[/tex] , [tex]\bold{\left[\begin{array}{c}\frac{1}{6} \\\frac{1}{7} \end{array}\right]}[/tex] and [tex]\left[\begin{array}{c}\frac{1}{6} \\\frac{1}{3} \end{array}\right][/tex] and 6.
Given the set, [tex]H=\{\left[\begin{array}{c}x\\y\end{array}\right] :8x^2+5y^2\leq 1\}[/tex] which represents the set of points on and inside an ellipse in the xy-plane.
We have to show that H is not a subspace.
We can show that this set is not closed under vector addition of two vectors by finding those vectors.
[tex]\left[\begin{array}{c}\frac{1}{5} \\\frac{1}{4} \end{array}\right][/tex] and [tex]\left[\begin{array}{c}\frac{1}{6} \\\frac{1}{7} \end{array}\right][/tex] are two vectors in H, since it satisfies the given condition, [tex]8x^2+5y^2\leq 1[/tex].
i.e., [tex]8\times(\frac{1}{5})^2 + 5\times (\frac{1}{4})^2 = 0.6325\leq 1[/tex] and [tex]8\times(\frac{1}{6})^2 + 5\times (\frac{1}{7})^2 = 0.3242\leq 1[/tex]
[tex]\left[\begin{array}{c}\frac{1}{5} \\\frac{1}{4} \end{array}\right][/tex] + [tex]\left[\begin{array}{c}\frac{1}{6} \\\frac{1}{7} \end{array}\right][/tex] = [tex]\left[\begin{array}{c}\frac{11}{30} \\\frac{11}{28} \end{array}\right][/tex]
But [tex]8\times(\frac{11}{30})^2 + 5\times (\frac{11}{28})^2 =1.847 \geq 1[/tex]
So the vector [tex]\left[\begin{array}{c}\frac{11}{30} \\\frac{11}{28} \end{array}\right][/tex] does not belongs to H.
So It is not closed under addition.
Now we will prove that H is not closed under scalar multiplication of a vector and a scalar either.
[tex]\left[\begin{array}{c}\frac{1}{6} \\\frac{1}{3} \end{array}\right][/tex] is a vector in H. But [tex]6\left[\begin{array}{c}\frac{1}{6} \\\frac{1}{3} \end{array}\right][/tex] does not belongs to H, where 6 is a scalar.
This is because [tex]6\left[\begin{array}{c}\frac{1}{6} \\\frac{1}{3} \end{array}\right][/tex] = [tex]\left[\begin{array}{c}1 \\2 \end{array}\right][/tex] and [tex]8\times1^2 + 5\times 2^2 =28 \geq 1[/tex].
So the two vectors are [tex]\bold{\left[\begin{array}{c}\frac{1}{5} \\\frac{1}{4} \end{array}\right]}[/tex] and [tex]\bold{\left[\begin{array}{c}\frac{1}{6} \\\frac{1}{7} \end{array}\right]}[/tex] and one vector and a scalar are [tex]\left[\begin{array}{c}\frac{1}{6} \\\frac{1}{3} \end{array}\right][/tex] and 6.
The question is incomplete. Find the complete question below:
Let [tex]H=\{\left[\begin{array}{c}x\\y\end{array}\right] :8x^2+5y^2\leq 1\}[/tex], which represents the set of points on and inside an in the xy-plane. Find two specific examples two vectors, and a vector and a scalar to show that H is not a subspace of [tex]R^2[/tex].
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PLS HELP
This is the one thing I need to do for my assignment and I don't know it
Answer:
Step-by-step explanation:
the square root of 74 is 8.60
Even if you round it should be 8.7 but 8.5 is only one digit down from 8.60 if that makes sense so 8.6 is only one digit from 8.5 with is a comparable value
Gabriel finds some dimes and quarters in his change purse. How many coins does he have if he has 11 dimes and 8 quarters? How many coins does he have if he has dd dimes and qq quarters?
Answer:
8 quarters equal 2 dollars 11 dimes is a dollar and 10 cents so 3 dollars and 10 cents
Step-by-step explanation:
Can someone find the measure of angle b
Please, help me. I have no idea.
Solve the compound inequality 6b < 36 or 2b + 12 > 6
A. b < 6 or b > 6
B. b < 6 or b > 3
C. b > 6 or b < −3
D. b < 6 or b > −3
Answer:
D.)
Step-by-step explanation:
After executing the following statement, the value of x is ________. double x = 5 4 * 3 / 2 ;
The value of x is 81 . double x = 5 4 * 3 / 2 .
What is a linear equation?
An algebraic equation of the form y=mx+b is referred to as a linear equation. m is the slope, and b is the y-intercept, and all that is involved is a constant and a first-order (linear) term. The variables in the preceding equation are y and x, and it is occasionally referred to as a "linear equation of two variables."x = 54 * 3/2
x = 27 * 3
x = 81
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Mr McGee found that 6 students in his class have a sports practice today based on this result how many of the 300 students in the school have practice today
Answer: Number of students out of 300 who will attend sports class are 200.
Step-by-step explanation:
Let x be no. of students in 300 students who have sports practice;
Mr McGee found that 6 students out of 9 in his class have a sports practice today.
so according to ratio and proportions we have:
6/9=x/300
by cross multiplying 300 on left hand side we have ;
x=200 students
So
number of students out of 300 who will attend sports class are 200.
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Answer:
Step-by-step explanation: Based on the given condition, formulate :
multiply total students with 6
6×300 =1800
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Labels for gender where 1=female and 2=male is an example of using ______ scale.
Labels for gender where 1=female and 2=male is an example of using a nominal variable scale.
What is a nominal variable?A categorical variable (also known as a nominal variable) has two or more categories but no inherent ordering of the categories. Because the categories (woman, man, transgender, non-binary, etc.) cannot be ordered from high to low, gender is an example of a nominal variable. Medal winners are an example of an ordinal variable because the categories (gold, silver, bronze) can be ordered from most valuable to least valuable. A categorical variable is a variable in statistics that can take on one of a restricted, and usually fixed, a number of possible values, assigning each individual or other unit of inspection to a specific group or nominal category based on some qualitative property. For example, a nominal variable scale is used to label gender, with 1 representing female and 2 representing male.Therefore, labels for gender where 1=female and 2=male is an example of using a nominal variable scale.
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the desert temperature, h, oscillates daily between 40°f at 5am and 80°f at 5pm. write a possible formula for h, measured in hours from 5am, using the form h
The form of a periodic function is H(t) = 20cos(π/12(t+12))+ 60.
What do periodic functions mean?
A function that periodically returns to the same value. Despite the similarity in sound between periodic motion and oscillatory motion, not all periodic motions are oscillatory motion.
Since the values of H oscillates between two values, then the choices of the function are either sine or cosine. However, since the variable measures the time from 4 AM, and 4 AM represents the trough of the oscillation, then cosine is the more appropriate choice. Recall the form of a periodic function
y =A cos(B(x +C))+D
It is given that the peak of desert temperature is at 80F, and the lowest is 40F. Note that the distance between the two temperatures is
80F − 40F =40F
Since the amplitude is the distance from the middle line to either peak or trough, then it is half the distance from the trough to the peak. Hence
A = 40/2= 20
Notice that one full oscillation occurs after one day or 24 hours. Hence the period is
B =2π/24 = π/12
The graph of the cosine function begins at the peak, whereas the function needs to begin at the trough, since the variable t represents the number of hours after 4 AM. Thus, the graph must be shifted horizontally to the left one half-cycle, which is
C = 12
Since the original cosine function has the centerline at x= 0 the centerline of the function must be shifted by the number of units corresponding to the midway point of the peak and the trough. Hence
D= 80 + 40/2 = 120/2 = 60
ubstituting
A =20, B = π/12. C= 12 , and D= 60 into
The form of a periodic function
H(t) = 20cos(π/12(t+12))+ 60
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p+17=9 i need help ASAP
Answer:
P = -8
Step-by-step explanation:
(-2,-4) and (3,-9)?
What we answering with these 2 points ?
Where's the question?
There is a safety fence around a circular pool with a gate. The gate is 150 cm wide.
20 m
gate
150 cm
What is the length of the fence not including the gate?
m
explain why 8 < x < 2 has no solution? need the answer quick
Answer:
8 < x < 2 has no solution because there is no number greater than 8 (8 < x), yet less than 2 (x < 2). It's impossible, so there is no solution.
If the inequality was something like 8 < x < 10, then it will work because 8 can be less than x and x can be less than 10.
Hope this helps and have a great rest of your day! :)
Here is a scale drawing of a window frame that uses a scale of 1 cm to 6 inches.
Compare the scale drawing of a window frame that uses a scale of 1 cm to 12 inches.
the second drawing if the window frame will be 1 / 2 the size of the first drawing of the window frame.
We have that:
Scale of the first drawing is 1 cm to 6 inches.
It can be written in ratio as:
1 : 6
Now the scale of the other drawing of a window is
1 cm to 12 inches.
which can also be written in ratio as:
1 : 12
By comparing both the ratios, we can see that the first drawing is twice in size as the second drawing as it only includes 6 inches in 1 cm.
That mens the second drawing if the window frame will be 1 / 2 the size of the first drawing of the window frame.
Therefore, we get that, the second drawing if the window frame will be 1 / 2 the size of the first drawing of the window frame.
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Find the value of x²+8x+12 when x = -9
Answer:
165
Step-by-step explanation:
x² + 8x + 12 =
= (9)² + 8(9) + 12
= 81 + 72 + 12
= 153 + 12
= 165
Answer:
-165
Step-by-step explanation:
(-9)2+8×-9+12
-81-72+12
-81-84
-165 answer.
Frankie plays 2/7 of a song on his guitar in 3/4 of a minute How long will it take him to play the entire song?
Answer:
1.25
Step-by-step explanation:
A teacher claims that the relationship between
number of hours studied for a test and test score can be
described by g(x) = 45 + 9x, where x represents the
number of hours studied. Graph this function
The graph representing the given function g(x) = 45 + 9x is as drawn in the attachment.
How to draw a Linear Equation Graph?
We are given the equation of line as;
g(x) = 45 + 9x
Where;
x represents the number of hours studied.
g(x) represents the test score
Thus, to plot this graph, we need to input some x values and find their corresponding g(x) values
At x = -10;
g(x) = 45 + 9(-10)
g(x) = -45
At x = -1;
g(x) = 45 + 9(-1)
g(x) = 35
At x = 0;
g(x) = 45 + 9(0)
g(x) = 45
At x = 1;
g(x) = 45 + 9(1)
g(x) = 54
At x = 2;
g(x) = 45 + 9(2)
g(x) = 63
At x = 3;
g(x) = 45 + 9(3)
g(x) = 72
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Travis wrote five checks to the employees of his business, each for $225. if the original balance in his checking account was $890, what is his new balance?
Travis's checking account new balance, after wrote five checks to the employees of his business is - $235
To solve this problem, we have to state the equation using the information of the problem
Information about the problem:
Original balance= $890Check amount of each employer= $225No. of checks= 5Final balance = ?Calculating the checks total amount Travis wrote to the employees of his business:
Total amount for his employers = Check amount of each employer * No. of checks
Total amount for his employers = $225 * 5
Total amount for his employers = $1125
Calculating the final balance, we have:
Final balance = Original balance - Total amount for his employers
Final balance = $890 - $1125
Final balance = - $235
What are algebraic operations?They are the set of numbers and symbols that are related by the different mathematical operation signs such as addition, subtraction, multiplication, division among others.
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round 184329 to the nearest 100
Answer:
184300
Step-by-step explanation:
When rounding to the nearest anything, you look at the place 1 unit smaller. Here, we'd look at the tens place.
184329
Anything 5 or greater increases the value of the place 1 unit bigger. Here, we have a 2 in the tens place. That doesn't increase the 3 in the hundreds place, so we round down to 184300.
q+p-3; use p = 2, and q = -1
Answer:
-2
Step-by-step explanation:
q + p - 3
-1 + 2 - 3 = -2
Lenny starts a lemonade stand for the summer. He thinks that he should be able to operate his business for 10 weeks. the table shows the expenses and revenue after 1 week. Based on this, how much konry will Lenny make during the 1o weeks
I am not understanding
What value of n makes a true statement? 4^nx4² = 16,384
Determine whether each of the following functions is a solution of laplace's equation uxx uyy = 0.
Both functions are the solution to the given Laplace solution.
Given Laplace's equation: [tex]u_{x x}+u_{y y}=0[/tex]
We must determine whether a given function is the solution to a given Laplace equation.If a function is a solution to a given Laplace's equation, it satisfies the solution.(1) [tex]u=e^{-x} \cos y-e^{-y} \cos x[/tex]
Differentiate with respect to x as follows:
[tex]u_x=-e^{-x} \cos y+e^{-y} \sin x\\u_{x x}=e^{-x} \cos y+e^{-y} \cos x[/tex]
Differentiate with respect to y as follows:
[tex]u_{x x}=e^{-x} \cos y+e^{-y} \cos x\\u_{y y}=-e^{-x} \cos y-e^{-y} \cos x[/tex]
Supplement the values in the given Laplace equation.
[tex]e^{-x} \cos y+e^{-y} \cos x-e^{-x} \cos y-e^{-y} \cos x=0[/tex]
The given function in this case is the solution to the given Laplace equation.
(2) [tex]u=\sin x \cosh y+\cos x \sinh y[/tex]
Differentiate with respect to x as follows:
[tex]u_x=\cos x \cosh y-\sin x \sinh y\\u_{x x}=-\sin x \cosh y-\cos x \sinh y[/tex]
Differentiate with respect to y as follows:
[tex]u_y=\sin x \sinh y+\cos x \cosh y\\u_{y y}=\sin x \cosh y+\cos x \sinh y[/tex]
Substitute the values to obtain:
[tex]-\sin x \cosh y-\cos x \sinh y+\sin x \cosh y+\cos x \sinh y=0[/tex]
The given function in this case is the solution to the given Laplace equation.
Therefore, both functions are the solution to the given Laplace solution.
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The correct question is given below:
Determine whether each of the following functions is a solution of Laplace's equation uxx + uyy = 0. (Select all that apply.) u = e^(−x) cos(y) − e^(−y) cos(x) u = sin(x) cosh(y) + cos(x) sinh(y)
Each side of a square is lengthened by 2 inches. The area of
this new, larger square is 36 square inches. Find the length of
a side of the original square.
Please help using systems of equations!!
Answer:
4 inches.
Step-by-step explanation:
Since the shape is a square, each side length will be the same. This mean that you must find the square root of 36 to find the length of each side of the new square.
√36=6
Each side of the new square is 6. It says it was lengthened by 2 inches. Subtract 2 from 6.
6-2=4
Each side of the original square is 4 inches.
Hope this helps!
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Orville is thinking of a number. The product of the number and 39 is 156. Find Orville's number. 46
Answer:
I believe the multiplied number would be 4.
39 × 4 = 156
The number is = 4
Step-by-step explanation:
I'm not sure what is 46 at the end of the question.
what fractions are equivalent to 4.05 with a bar notation over the 0 and 5
Answer:
Part 1) The fractions in the list are not equal to the decimal number indicated
Part 2) The fractions 401/99 and 802/198 are equal to the decimal number indicated.
Part 1)
we have the decimal number
4.05 -----> is a terminating decimal ( t's a decimal with a finite number of digits)
Convert to fraction number
Multiply and divide by 100
Simplify
Divide by 5 both numerator and denominator
therefore
The fractions in the list are not equal to the decimal number indicated.
Part 2) we have
4.050505... ------> is a repeating decimal (is a decimal that has a digit, or a block of digits, that repeat without ever ending)
Let
x=4.050505...
we have that
Multiply by 2 both numerator and denominator
therefore
The fractions 401/99 and 802/198 are equal to the decimal number indicated.
Step-by-step explanation:
Victor wants to learn to snowboard. He went to Snowy Ridge Mountain and rented a snowboard for $35, then took 5 hours of group snowboarding lessons. Victor paid $175 in all.
Which equation can you use to find how much Snowy Ridge charges, x, for each hour of group snowboarding lessons?
Answer: They charge $28 per lesson the Equation is 35 + 5x = $175
Step-by-step explanation: He rented the snowboard for $35 and then took 5 hours of snowboarding lessons. Then the whole thing cost $175.
the world record for the most number of speed skips is 60 seconds is 332 skips if the record holder skipped at a constant ratio of seconds to skips how many makes in 15 seconds
The record holder skips 83 times in 15 seconds
We refer to a ratio as constant if the number we multiply by remains constant throughout the series.
By comparing two amounts of the same units, the ratio can be used to calculate how much of one item is included in the other. There are two different categories for ratios. The first is a part-to-part ratio, whereas the second is a part-to-whole ratio.
The World record for the most number of skips is 332 in 69 seconds.
Let's assume the record holder skipped at a constant ratio.
The proportion, if s is the number of skips:
skips / seconds = s / 15 = 332/60
s / 15 = 332 / 60
s = 332( 15/60 )
s = 332/4
s = 83
She skipped 83 times in the space of 15 seconds.
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