The friction drag acting on the surface of the plate is approximately 0.074 N.
The friction drag acting on the surface of the plate can be calculated using the following formula:
[tex]$F_D = \frac{1}{2} \rho V^2C_D A$[/tex]
where \rho is the density of water,
V is the velocity of the plate relative to the water,
C_D is the drag coefficient, and
A is the surface area of the plate.
To determine the drag coefficient C_D.
We need to know the Reynolds number of the flow.
For a flat plate, the drag coefficient can be estimated using the following formula for laminar flow:
[tex]$C_D = \frac{1.328}{\sqrt{Re_x}}$[/tex]
where Re_x is the Reynolds number based on the distance from the leading edge of the plate to the point of interest (in this case, the trailing edge).
For turbulent flow, we can use the following formula for the drag coefficient:
[tex]$C_D = \frac{0.074}{Rex^{1/5}}[/tex]
The critical Reynolds number for a flat plate is around 5,000, above which the flow is typically turbulent.
In this case, the Reynolds number of 950,000 indicates that the flow is definitely turbulent.
To calculate the drag coefficient, we need to use the turbulent flow formula:
[tex]$C_D = \frac{0.074}{Rex^{1/5}}[/tex]
[tex]= \frac{0.074}{(380 \times 6.3 / \nu)^{1/5}}[/tex]
where nu is the kinematic viscosity of water at the given temperature.
Assuming a temperature of 25°C, the kinematic viscosity of water is approximate nu = 8.85* [tex]10^{-7}[/tex] [tex]m^2\\[/tex]/s.
Plugging in the values, we get:
[tex]C_D = \frac{0.074}{(380 \times 6.3 / 8.85 \times )^{1/5}}[/tex] approx 0.0093
Finally, we can calculate the friction drag:
[tex]F_D = \frac{1}{2} \rho V^2 C_D A\\ = \frac{1}{2} \times 1000 \times 6.3^2 \times 0.0093 \times 0.0038\\ \approx. 0.074N[/tex]
Therefore, the friction drag acting on the surface of the plate is approximately 0.074 N.
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the formant frequencies of speech are also influenced by the density of the propagating medium. the human vocal tract is approximately 17 cm long. what is the first and second formants of this voice? the velocity of sound in air is vair
Studies of the frequency spectra of skilled speakers and classical singers, particularly male vocalists, reveal a distinct formant at about 3000 Hz (between 2800 and 3400 Hz) that is absent from speech or the spectra of untrained speakers or singers.
What frequencies of speech are influenced by the density?For men, the fundamental frequency of the complex speech tone, commonly referred to as the pitch or f0, falls between 100 and 120 Hz, though changes outside this range might happen. A little over an octave higher is the f0 for females.
If this is regarded as a closed cylinder, it would result in a fundamental frequency of approximately 500 Hz. In line with the measured frequencies, this would expect formant frequencies of 500, 1500, and 2500.
We have Vair = 331 m/s
L= 17 cm = 0.17 m
V = 965 m/s
a. first formant frequencies of the voice in the air is
[tex]F_air \frac{V_air}{4L} = \frac{331 \frac{m}{s}}{4\times 0.17m} = 486.76s^-1[/tex]
for second format
[tex]F_2air = (2n-1) F_1air[/tex]
[tex]= (4-1)\times 486.76= 1460.29 Hz[/tex]
b. by using the relation
[tex]F_1he= (\frac{v_he}{v_air})\times F_1air[/tex]
[tex]F_1he= (\frac{965}{331})\times 486.76[/tex]
[tex]F_1he = 1419.1 Hz[/tex]
[tex]F_2he = (\frac{965}{331})\times 1460.29 HZ[/tex]
[tex]F_2he = 4257.3[/tex]
Therefore, first formant frequencies is 1460.29Hz and second formant frequencies is 4257.3
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under favorable circumstances including reaction time
A car with adequate brakes traveling at 50 mph can be stopped within: 229 feet under ideal conditions, including response time.
How much time does it take to respond?Reaction time is a term used to describe how rapidly an organism responds to a stimuli (RT). The length of time (RT) that passes between the stimulus's presentation and the emergence of the subject's appropriate voluntary response is calculated.
Is IQ a factor in reaction time?Reaction time is a more straightforward measure of the brain's information-processing capacity than intelligence, and it has a mildly positive relationship with IQ. It also has little to do with other, potentially confusing aspects like knowledge, education, or history.
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a potter's wheel moves uniformly from rest to an angular speed of 0.19 rev/s in 34.0 s. (a) find its angular acceleration in radians per second per second.
The angular acceleration of the potter's wheel that moves uniformly is [tex]0.0352 radians/s^2[/tex]
Angular acceleration is a measure of how quickly an object's angular velocity changes with respect to time. In this case, the potter's wheel undergoes a uniform acceleration, which means that its angular acceleration remains constant over time.
We can use the following equation to find the angular acceleration of the potter's wheel:
angular acceleration = (final angular speed - initial angular speed) / time
Here, the initial angular speed is zero because the wheel starts from rest. The final angular speed is 0.19 rev/s. The time taken to reach this speed is 34.0 s. We can convert the final angular speed to radians per second using the conversion factor 1 rev/s = 2π radians/s:
final angular speed = 0.19 rev/s * 2π radians/rev = 1.196 radians/s
Put values:
angular acceleration = (1.196 radians/s - 0 radians/s) / 34.0 s = [tex]0.0352 radians/s^2[/tex]
Therefore, the angular acceleration of the potter's wheel is [tex]0.0352 radians/s^2[/tex]
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a curve in a road has a bank angle calculated and posted for 80 km>h. however, the road is covered with ice, so you cautiously plan to drive slower than this limit. what might happen to your car? why?
The automobile may slide or skid sideways off the road if the road is covered with ice and the vehicle is being driven at a slower rate of speed than the indicated bank angle.
A vehicle is kept driving in a circular path without sliding by the centripetal force created by the bank angle of a road bend.
This force is produced by the tire-perpendicular normal force of the road, which acts on the tire.
The bank angle is intended to boost the normal force to counteract the centrifugal force that seeks to pull the automobile away from the curve as speed rises.
On an ice road, however, there is a considerable reduction in the coefficient of friction between the tires and the surface, which also affects the normal force.
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describe the significance of laser irradiance and exposure in vp processes. how do these phenomena affect the solidification, scan pattern, and quality of a vp build? what is the difference between irradiance and exposure?
Laser irradiation of a solution is an effective way to generate crystal nucleinuclei.
Vat polymerisation employs a vat of liquid photopolymer resin in which the model is built layer by layer. Where necessary, an ultraviolet (UV) light is used to cure or harden the resin, while a platform moves the object being made downwards after each new layer is cured.
Because the process employs liquid to form objects, there is no structural support from the material during the build phase, as opposed to powder-based methods, which provide support from the unbound material. In this case, additional support structures are frequently required. Resins are cured using photopolymerisation (Gibson et al., 2010) or UV light, in which the light is directed across the surface of the resin using motorised mirrors (Grenda, 2009). The resin cures or hardens where it comes into contact with light.
The layer thickness lowers the build platform from the top of the resin vat downwards.
The resin is cured layer by layer with a UV light. The platform continues to descend, and new layers are added on top of the previous ones.
Some machines use a blade that moves between layers to provide a smooth resin base on which to build the next layer.
After completion, the resin is drained from the vat and the object is removed.
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Listen
Which concept is present in all three of Newton's laws of motion?
O displacement
O acceleration
O force
mass
Answer: I think D. Mass!
Explanation: I hope this helps and I hope everyone has a good day/Friday&weekend^^
if the mass of the compact car is 1200 kg, what force is needed to make it accelerate to 20 m/s2? show your calculations.
when loading a trailer, what percent of the weight should be in the front?
The percentage of weight that should be in front of the trailer is 60%
According to the GMC Trailering Guide, to get the right trailer tongue weight, you should concentrate about 60% of the load evenly on the front half of the trailer. 60% of the trailer load should be in front of the axle and 40% behind it. This ensures the correct weight of the tongs and prevents the trailer from rocking. Weight distribution should be as efficient as possible by placing 60% of the weight in the front of the trailer and 40% in the rear. There are some additional safety precautions to consider.
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A ball is thrown straight up into the air with initial velocity 62.8 m/s. How fast is the ball moving when it first reaches 56.4 meters?
The final velocity of the ball is equal to 53.06 m/s.
Gravity's acceleration is always constant and downward, but the direction and magnitude of velocity vary. The ball has zero velocity at its highest point in its trajectory, and the magnitude of velocity increases again as the ball falls back towards the earth.
In free fall, an object experiences an acceleration of -9.8 m/s/s. (A downward acceleration is indicated by the - sign.) Whether explicitly stated or not, the acceleration in the kinematic equations for any freely falling object is -9.8 m/s/s.
By using the equation:-
[tex]mgh_{A} + \frac{1}{2} mv^{2} _{A} = mgh_{B} + K.E.[/tex]
We are given:-
[tex]V_{A} =(62.8)m/s[/tex]
g= 9.8 or 10 [tex]m/s^{2}[/tex]
[tex]h_{B} = 56.4[/tex]m.
Putting the values in the equation, we get:-
[tex]\frac{1}{2} mV^{2} _{A} = mg*56.4+\frac{1}{2} mV^{2} _{B} \\=2*(\frac{1}{2} *(62.8)^{2} )= 10*56.4+ \frac{1}{2} V^{2} _{B} \\= (3943.84= 1128+ V^{2} _{B} )\\V_{B} = \sqrt{2815.84} = 53.06 m/s.[/tex]
Hence, the final velocity of the ball is equal to 53.06m/s.
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consider two people, one on the earth's surface at the equator and the other at the north pole. which has the larger centripetal acceleration? explain.
Both at the north pole and one at the equator on the surface of the globe. The centripetal acceleration is greater for the person on the equator.
The centripetal acceleration is the acceleration that is directed towards the center of a circular path. On the surface of the Earth, the rotation of the planet around its axis creates a circular path for any object on its surface. This means that any object on the Earth's surface is subject to a centripetal acceleration due to the Earth's rotation.
The magnitude of the centripetal acceleration:-
a = v²/r
here, v tangential velocity of the object
r radius of circular path.
The tangential velocity is velocity of the object in the direction tangent to the circular path.
The tangential velocity of an object on the surface of the Earth is given by:-
v = ω r
here, ω is angular velocity of the Earth's rotation,
r is radius of the Earth.
The angular velocity is rate at which the Earth rotates around its axis.
Since, the radius of the Earth is largest at the equator, an object at the equator has a larger radius than an object at the North Pole. This means that the tangential velocity of an object on the equator is larger than the tangential velocity of an object at the North Pole. Therefore, the centripetal acceleration of an object on the equator is larger than the centripetal acceleration of an object at the North Pole.
In summary, an object on the Earth's surface experiences a centripetal acceleration due to the Earth's rotation, and the magnitude of this acceleration is determined by the tangential velocity and the radius of the circular path. Since the radius is larger at the equator than at the North Pole, an object on the equator has a larger centripetal acceleration than an object at the North Pole.
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A ball is thrown downward with an initial velocity of 14 m/s. Using the approximate value of g = 10 m/s2, what is the ball's velocity 3.0 seconds after it is released?; A ball is thrown downward with an initial velocity of 14 m/s. Using the approximate value of g = 10 m/s2, what is the ball's velocity 3.0 seconds after it is released?
The final velocity is 43.4 m/s. As we can see in the calculation.
What is the first equation of motion?Acceleration is a measure of how quickly an object changes its velocity. It is defined as the rate of change of velocity with respect to time. Mathematically, acceleration is represented by the symbol "a" and can be calculated using the following formula:
a = v - u / t
We have that;
v = u + gt
v = final velocity
u = initial velocity
g = acceleration due to gravity
t = time
v = 14 + 9.8 * 3
v = 43.4 m/s
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Suppose that a teacher driving a 1972 LeMans zooms out of a darkened tunnel at 31.3 m/s. He is momentarily blinded by the sunshine. When he recovers, he sees that he is fast overtaking a camper ahead in his lane moving at the slower speed of 13.5 m/s. He hits the brakes as fast as he can (his reaction time is 0.39 s). If he can decelerate at 3.0 m/s2, what is the minimum distance between the driver and the camper when he first sees it so that they do not collide?
The minimum distance between the driver and the camper when he first sees it so that they do not collide is 16.86 m.
What is distance?Distance is the physical length between two points. It is a measure of the space between two objects or a point and a line. Distance can be measured in various ways, such as in meters, kilometers, feet, inches, miles, and even light-years. Distance can also refer to the amount of time or effort required to reach a destination.
The minimum distance between the driver and the camper when he first sees it so that they do not collide is calculated using the following formula:
d = vₒt + (1/2)at²
Where d is the distance, vₒ is the initial velocity, t is the reaction time, and a is the deceleration.
Plugging in the given values, we get:
d = 31.3 m/s × 0.39 s + (1/2) × 3.0 m/s² × (0.39 s)²
d = 16.86 m
Therefore, the minimum distance between the driver and the camper when he first sees it so that they do not collide is 16.86 m.
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how does the speed of sound in sea water compare to the speed of sound in air? a the speed of sound is faster in sea water because the molecules in sea water are closer to each other and more dense. b the speed of sound is slower in sea water because the molecules in sea water are closer to each other and more dense. c the speed of sound is faster in sea water because the molecules in sea water are closer to each other and less dense. d the speed of sound is slower in sea water because the molecules in sea water are closer to each other and less dense.
Seawater has sound travelling at a substantially higher speed than air. The speed of sound in air is roughly 343 metres per second at a temperature of 25 °C.
How quickly does sound travel across sea water?The sound speed in the oceans fluctuates between 1,450 and 1,570 metres per second (or 4,760 and 5,150 feet per second). With every 1 °C increase in temperature and every 1 psu increase in salinity, it grows by around 4.5 metres (about 15 feet) and 1.3 metres (about 4 feet) every second, respectively.
Why does sound travel faster in water than in air?In water, sounds move more quickly than in the air. Because the particles are considerably closer together, They may quickly transfer vibrational energy from one particle to the next because of the water. Sound generally travels through water four times more quickly than through air.
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Does the north pole of a magnet point to the north magnetic pole of the earth? Explain.
The geographic north pole is not shown by a magnetic compass. The earth's magnetic poles, which are distinct from the planet's geographic poles, are shown by a magnetic compass.
What is the magnetic pole of the earth?A magnet will always point northward or southward. A magnet's north pole will always point in the direction of the Earth's geographic north (which is also its magnetic south pole).
Since opposite poles pull together, the earth's magnetic north pole is actually located on the Southern Hemisphere, making it operate like a physical magnet.
The direction of magnetic field lines is set up so that they come out of the north pole of the magnet and go in through the south pole.
Therefore, the magnetic pole that is closest to the geographic north pole of the earth is the south magnetic pole. The law of attraction applies to magnets.
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The amount of incoming solar radiation available at various places on the earth depends mainly onlongitude.the angle at which the sun's rays strike the earth and the number of daylight hours.the earth's rotation.the absorbance of the earth surface material.
"The amount of incoming solar radiation available at various places on the earth depends mainly on the angle at which the sun's rays strike the earth and the number of daylight hours." Correct option is B.
The amount of incoming solar radiation that is accessible varies on the latitude, day of the year, time of day, and amount of cloud cover. The amount of solar energy received at a particular latitude would not change throughout the year if the earth were not tilted from the perpendicular.
The incoming solar energy received on a daily basis depends primarily on the angle of the Sun above the horizon, the length of time the surface is exposed to the Sun, and atmospheric conditions.
Following the latitude of the Earth we observe that the sun’s rays are more intense at the equator and they become less intense as we approach the poles. At the same time this intensity fluctuates during the seasons due to the Earth's tilted axis (23.5 degree angle), this makes that the hemisphere that is closer to the sun receives more sunlight than the opposing hemisphere.
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Answer: THE ANSWER IS B
over the course of a single night, does the position of mars in its home constellation change dramatically? group of answer choices yes no
Over the course of a single night, the position of mars in its home constellation do not change dramatically. Correct answer us no.
The position of Mars in its home constellation changes over the course of a single night, but not dramatically. Mars, like all celestial objects, appears to move across the night sky due to the rotation of the Earth.
However, the magnitude of this change in position over the course of a single night is not usually considered to be "dramatic" in astronomical terms. The apparent motion of Mars across the night sky is relatively slow, and its position relative to the surrounding stars may only change by a few degrees over the course of several hours.
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can someone please help me answer this
Answer:
Rₓ = -10 N
Explanation:
The x-component of a vector R can be found using the following formula:
[tex]\boxed{{R_x = Rcos \ \theta}}[/tex],
where Rₓ is the x-component of R and Θ is the angle between the vector and the positive x-axis.
The 60° angle in the diagram is formed between the vector R and the negative x-axis. The angle we need, Θ, is its supplementary angle. Therefore,
Θ = 180° - 60°
= 120°
Now that we have the value of Θ, we can find its x-component using the formula above:
[tex]{{R_x = Rcos \ \theta}}[/tex]
⇒ [tex]R_x = 20 \times cos(120^{\circ})[/tex]
⇒ [tex]R_x = \bf -10[/tex]
Therefore, the x-component of R is -10 N.
. two blocks are connected by a massless rope as shown below. the mass of the block on the table is 4.0 kg and the hanging mass is 1.0 kg. the table and the pulley are frictionless. (a) find the acceleration of the system. (b) find the tension in the rope. (c) find the speed with which the hanging mass hits the floor if it starts from rest and is initially located 1.0 m from the floor.
A- The acceleration of the system is 1.96 [tex]m/s^{2}[/tex], B- the tension in the rope is 7.84N, C- the velocity at which the hanging mass strikes the ground if it begins at rest and is positioned 1.0 meters off the ground is 1.98 m/s.
A- both the masses will have same magnitude of acceleration a ,
m2g-T = m2a
T=m1a
from both the equations a = m2g/(m1 + m2) = 1.96[tex]m/s^{2}[/tex]. Therefore, The acceleration of the system is 1.96 [tex]m/s^{2}[/tex]
B- T = m1a = 7.84 N is the tension in the rope
C- [tex]V_{f^{2} }[/tex] = [tex]V_{i^{2} }[/tex] + 2as
= 0 + 2am
= 1.98 m/s
Hence , the velocity at which the hanging mass strikes the ground if it begins at rest and is positioned 1.0 meters off the ground is 1.98 m/s.
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The complete question is :
As seen in the illustration below, a massless rope links two blocks. The hanging mass is 1.0 kg, whereas the block on the table weighs 4.0 kg. No friction exists between the table and the pulley. Find the system's acceleration in (a). (b) Determine the rope's tension. (c) determine the speed at which the hanging mass will strike the ground if it begins at rest and is 1.0 m from the ground.
A negatively charged rod is brought near a metal can that rests on a wood table. You touch the opposite side of the can momentarily with your finger. The can is then
Group of answer choices
negatively charged
positively charged
uncharged
charged the same as it was before
The can is then positively charged after you touch it with your finger, option B.
What is induction?Induction is a process by which a change in a magnetic field induces a current flow in a conductor, such as a wire. In physics, electromagnetic induction refers to the production of an electromotive force (EMF) across a conductor that is exposed to a changing magnetic field.
When the negatively charged rod is brought near the can, electrons are attracted to the positively charged can. When you touch the can, electrons flow from your body to the can, leaving it positively charged.
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How are atoms in a molecule held together?
through shared electrons
through shared neutrons
through shared protons
through shared energy
a satellite is orbiting the earth in a cicular orbit at a height above the earth's surface equal to the earth's radius. what is the accleration of the sattilite.
Acceleration of a satellite refers to the rate of change of its velocity as it moves in its orbit. The acceleration of a satellite is caused by the gravitational force between the satellite and the planet it is orbiting.
What is acceleration of the satellite?When a satellite is in circular orbit, it experiences centripetal acceleration, which is provided by the gravitational attraction between the satellite and the Earth.
The acceleration of the satellite can be calculated using the following formula:
a = v^2/r
where a is the acceleration, v is the velocity of the satellite, and r is the radius of the circular orbit.
In this case, the height of the satellite above the Earth's surface is equal to the Earth's radius, so the radius of the circular orbit is:
r = height above the surface + Earth's radius
= 2 * Earth's radius
The velocity of the satellite can be calculated using the formula for the circular motion:
v = (G*M/r)^0.5
where G is the gravitational constant, M is the mass of the Earth, and r is the radius of the circular orbit.
Substituting the values, we get:
v = (GM/(2Earth's radius))^0.5
Now, we can calculate the acceleration:
a = v^2/r
= ((GM/(2Earth's radius))^0.5)^2/(2Earth's radius)
= GM/(4*Earth's radius)
Therefore, the acceleration of the satellite is directly proportional to the mass of the Earth and inversely proportional to four times the Earth's radius. The value of the acceleration is approximately 1.23 m/s^2.
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why is the moment of inertia of a hoop that has a mass m and a radius r greater than the moment of inertia of a disk that has the same mass and radius?
Moment of inertia of hoop is greater than disk of same mass and radius because hoop mass is at greater distance from the axis of rotation.
Moment of inertia measures an object's resistance to rotational motion around given axis. Depends on mass distribution geometry of object. Hoop's Moment of inertia is greater than disk with same mass and radius as hoop's mass is at greater distance from axis of rotation.
A hoop is a thin circular ring, and all its mass is located on its outer edge. Therefore, the mass is concentrated at a maximum distance from the axis of rotation, resulting in a larger moment of inertia. In contrast, a disk has a more uniform mass distribution, with the mass distributed closer to the axis of rotation than in the case of the hoop. As a result, a disk has a smaller moment of inertia than a hoop with the same mass and radius.
To illustrate this concept, consider two objects with the same mass and radius: a solid disk and a hoop with no thickness. The moment of inertia of the hoop is twice that of the disk, even though they have the same mass and radius. This is because all the mass of the hoop is located at a larger radius than the mass in the disk, leading to a larger moment of inertia.
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An aluminum wing on a passenger jet is
25 m
long when its temperature is
19°C. At what temperature would the wing be 3 cm (0. 03 m) shorter?
The temperature at which the wing is 3 cm shorter than its initial length is 19°C - 54°C = -35°C.
Is 37 degrees Fahrenheit hot or cold?A normal temperature is between 36 and 37 degrees Celsius, though this varies depending on your age, what you've been doing, the time of day, and the method used to take the reading. Colds, the flu, and COVID-19 are examples of viral respiratory illnesses that can raise a person's temperature.
The thermal expansion coefficient of aluminum is approximately 22.2 × 10⁻⁶ per degree Celsius (or 22.2 × 10⁻⁶/°C).
The change in length of the wing, ΔL, is given by:
ΔL = α L ΔT
We know that the original length of the wing is 25 m, and the change in length is 3 cm, which is 0.03 m.
So, we have:
0.03 m = (22.2 × 10⁻⁶/°C) × (25 m) × ΔT
Solving for ΔT, we get:
ΔT = 0.03 m / ((22.2 × 10⁻⁶/°C) × (25 m))
ΔT ≈ 54°C
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a 900 kg car driving 20 m/s collides with a 1,100 kg truck going 15 m/s. The vehicle bounce off each other and the car moves back 18 m/s. Whats the velocity of the truck after the collision?
Answer: The velocity of the truck after the collision is 18.2 m/s.
Explanation:
Step 1: Determine the total momentum of the two vehicles before the collision.
Momentum is equal to mass multiplied by velocity (p = mv). The momentum of the car before the collision was 900 kg x 20 m/s = 18,000 kg m/s. The momentum of the truck before the collision was 1,100 kg x 15 m/s = 16,500 kg m/s. The total momentum of the two vehicles before the collision was 34,500 kg m/s.
Step 2: Determine the total momentum of the two vehicles after the collision.
After the collision, the car moves back 18 m/s so the momentum of the car is now 900 kg x (-18 m/s) = -16,200 kg m/s. The momentum of the truck after the collision is not given, so we will use the letter "v" to represent this. The total momentum of the two vehicles after the collision is then -16,200 kg m/s + (1,100 kg x v).
Step 3: Use the law of conservation of momentum to solve for the velocity of the truck.
The law of conservation of momentum states that the total momentum of two objects before a collision is equal to the total momentum of two objects after the collision. This means that 34,500 kg m/s = -16,200 kg m/s + (1,100 kg x v), or 34,500 kg m/s = -16,200 kg m/s + 1,100v. Since we know all of the values on the right side of the equation, we can solve for v by rearranging the equation. We get v = (34,500 kg m/s + 16,200 kg m/s) / 1,100 kg = 18.2 m/s.
Therefore, the Step 1: Determine the total momentum of the two vehicles before the collision.
Momentum is equal to mass multiplied by velocity (p = mv). The momentum of the car before the collision was 900 kg x 20 m/s = 18,000 kg m/s. The momentum of the truck before the collision was 1,100 kg x 15 m/s = 16,500 kg m/s. The total momentum of the two vehicles before the collision was 34,500 kg m/s.
Step 2: Determine the total momentum of the two vehicles after the collision.
After the collision, the car moves back 18 m/s so the momentum of the car is now 900 kg x (-18 m/s) = -16,200 kg m/s. The momentum of the truck after the collision is not given, so we will use the letter "v" to represent this. The total momentum of the two vehicles after the collision is then -16,200 kg m/s + (1,100 kg x v).
Step 3: Use the law of conservation of momentum to solve for the velocity of the truck.
The law of conservation of momentum states that the total momentum of two objects before a collision is equal to the total momentum of two objects after the collision. This means that 34,500 kg m/s = -16,200 kg m/s + (1,100 kg x v), or 34,500 kg m/s = -16,200 kg m/s + 1,100v. Since we know all of the values on the right side of the equation, we can solve for v by rearranging the equation. We get v = (34,500 kg m/s + 16,200 kg m/s) / 1,100 kg = 18.2 m/s.
Therefore, the velocity of the truck after the collision is 18.2 m/s.
The dependence of the rate constant on temperature is expressed by which equation The Arrhenius equation. The de Broglie equation. The van't Hoff equation. Temperature has no effect on the rate constant.
The dependence of the rate constant on temperature is expressed by the Arrhenius equation.
What is Arrhenius equation?The Arrhenius equation is an equation that is used to describe the relationship between the reaction rate of a chemical reaction and the temperature at which the reaction takes place. The equation states that the reaction rate is equal to the frequency factor (A) multiplied by the product of the Boltzmann constant (k) and the temperature (T) raised to the power of the activation energy (E): rate = A * kT^E.
Therefore, The dependence of the rate constant on temperature is expressed by the Arrhenius equation.
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Copernicus said that the rotation of the Earth on its axis caused the
A. phases of the Moon.
B. retrograde motion of the planets.
C. eclipses of the Moon
D. motion of the Sun along the ecliptic.
E. daily motions in the heavens.
According to this theory, the Sun lies at the center of the solar system and the Earth's rotation around its own axis is what causes the days and nights to alternate. Thus, option C is correct.
What is the rotation of the Earth on its axis cause?Day and darkness are created by the Earth's axis rotating. Only half of the Earth faces the sun at any given time due to rotation. Daylight is present on the side facing the sun, while darkness is present on the side facing the sun (night).
To share his theory of the cosmos with his pals, Copernicus wrote a book by hand. In it, he put out the theory that the sun rather than Earth was the centre of the universe.
Therefore, Copernicus said that the rotation of the Earth on its axis caused the eclipses of the Moon.
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While running at a constant velocity, how should you throw a ball with respect to you so that you can catch it yourself? Neglect air resistance.
While running at a constant velocity, how should you throw a ball with respect to you so that you can catch it yourself? Neglect air resistance.
A. Straight up
B. Slightly backward
C. It is impossible.
D. Slightly forward
If you are running at a constant velocity, you should throw the ball slightly forward with respect to you so that you can catch it yourself. Therefore, option D is correct.
What is constant velocity?An object is said to be moving at constant velocity when it is moving straight and fast. As a result, the item is not accelerating, which is defined as a change in velocity over time in either direction or speed. In other words, there is no net force acting on an item that is travelling at a constant speed.
If there are no forces acting on an object or if those forces are balanced, the object can have a constant velocity. A car is going with constant velocity, for instance, if it is moving at a constant speed in a straight path on a flat road with no external forces acting on it. Likewise, if a thing is going straight line at a constant speed through a vacuum, with no external forces acting upon it, then it is also moving with constant velocity.
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a conducting sphere contains positive charge distributed uniformly over its surface. which statements about the potential due to this sphere are true? all potentials are measured relative to infinity. (there may be more than one correct choice.) choose all that apply. a conducting sphere contains positive charge distributed uniformly over its surface. which statements about the potential due to this sphere are true? all potentials are measured relative to infinity. (there may be more than one correct choice.)choose all that apply. the potential is lowest, but not zero, at the center of the sphere. the potential at the center of the sphere is zero. the potential at the center of the sphere is the same as the potential at the surface. the potential at the center is the same as the potential at infinity. the potential at the surface is higher than the potential at the center.
The statements "the potential at the center of the sphere is zero", "the potential at the surface of the sphere is the same as the potential at infinity", and "the potential is lowest at the center of the sphere" are all true.
The correct statements about the potential due to this conducting sphere are:The potential at the center of the sphere is zero, The potential at the surface of the sphere is the same as the potential at infinity,The potential is lowest at the center of the sphere.
When a charged particle moves in an electric field, the field exerts a force that can do work on the particle. The work can be expressed in terms of electric potential energy. Electric potential energy depends only on the position of the charged particle in the electric field.
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. Static electricity is both an enemy and a friend.
Static electricity can be both an enemy and a friend depending on the situation.
How does Static energy work?Static electricity is a well-known electric phenomenon that involves the transfer of charged particles from one body to another. As a friend, static electricity is used in various technologies such as electrostatic spraying, electrostatic printing, and electrostatic precipitators.
However, as an enemy, static electricity can cause sparks that can ignite flammable materials, cause electronic devices to malfunction, and shock people. Static electricity can also cause clothing to cling together or hair to stand on end, which can be annoying but is generally harmless.
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if a voltage of 13 v moves 1.25 c of charge between two points? round the final answer to one decimal place.
If a voltage of 12 V moves 1.25C of charge between two points then charge must be moved with 15 J in joules of energy.
Here, we need to determine how much energy 12 V expends to transport a charge of 1.25 C between two places.
Voltage, which is defined as the effort or energy necessary to transfer a unit charge between two places, is known to drive electrons in a circuit. It can be calculated mathematically by dividing work/energy by charge.
Thus, we have the equation shown below:
[tex]V= \frac{E}{Q}[/tex]
If we rearrange the formula above, we obtain:
[tex]E=(V).(Q) (1)[/tex]
Here,
V→ Voltage
E→ Energy
Q→ Charge
Once the values are entered into equation number 1, we will obtain:
[tex]E = ( 12 V).( 1.25 C ) = 15 J[/tex]
As a result, we discovered that the amount of energy required to move the charge is 15 J in joules.
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Correct question:
How much energy is expended, in joules, if a voltage of12 V moves 1.25C of charge between two points?
