The period of motion when the mass-spring system is displaced from equilibrium by 15.0 cm is 6.0 seconds.
What is the mass-spring system?The period of a mass-spring system is given by:
[tex]T = 2pisqrt(m/k)[/tex]
where m is the mass and k is the spring constant.
The period of motion is not affected by the amplitude (displacement from equilibrium) of the oscillation for small amplitudes. However, for large amplitudes, the period does depend on the amplitude.
To find the period when the system is displaced from equilibrium by 15.0 cm, we need to find the new value of k, which depends on the displacement.
When the system is displaced by 5.0 cm, we have:
[tex]5.0 cm = A = x_max[/tex]
where A is the amplitude and [tex]x_max[/tex] is the maximum displacement from equilibrium.
When the system is displaced by 15.0 cm, we have:
[tex]15.0 cm = A = x_max[/tex]
The new spring constant k' can be found by:
[tex]k' = m*(2*pi/T')^2[/tex]
where T' is the period of motion when the system is displaced by 15.0 cm.
The energy of the system is conserved, so the potential energy at the maximum displacement is equal to the kinetic energy at the equilibrium position.
At the maximum displacement, all of the potential energy is converted into kinetic energy, so:
[tex]1/2 k' A^2 = 1/2 k x_max^2[/tex]
Solving for k' and substituting into the expression for the period, we get:
[tex]T' = 2pisqrt(m/k') = 2pisqrt(m/(k*(A/x_max)^2))[/tex]
Substituting the given values, we get:
[tex]T' = 2pisqrt(m/k*(15.0 cm/5.0 cm)^2) = 6.0 s[/tex]
Therefore, the period of motion when the mass-spring system is displaced from equilibrium by 15.0 cm is 6.0 seconds.
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The Arrhenius Equation The Arrhenius equation shows the relationship between the rate constant k and the temperature T in kelvins and is typically written as k = Ae^-Ea/RT where R is the gas constant (8.314 J/mol. K), A is a constant called the frequency factor, and Ea is the activation energy for the reaction. However, a more practical form of this equation is which is mathmatically equivalent to where k1 and k2 are the rate constants for a single reaction at two different absolute temperatures (T1 and T2). The activation energy of a certain reaction is 38.2 kJ/mol . At 20 degree C , the rate constant is 0.0140s^-1. At what temperature in degrees Celsius would this reaction go twice as fast? Express your answer with the appropriate units. Part B Given that the initial rate constant is 0.0140s^-1 at an initial temperature of 20 degree C , what would the rate constant be at a temperature of 180 degree C for the same reaction described in Part A?
The Arrhenius equation is a mathematical formula that describes the relationship between the rate of a chemical reaction and the temperature at which it occurs.
What would the rate constant be at a temperature of 180 degree C for the same reaction described in Part A?Part A:
We can use the modified Arrhenius equation to solve for the temperature at which the reaction goes twice as fast as at 20°C. Let's call this temperature T2:
k2 = k1 * e^(-Ea/R * (1/T2 - 1/T1))
We know k1 = 0.0140 s^-1, T1 = 20°C + 273.15 = 293.15 K, and Ea = 38.2 kJ/mol. We want to solve for T2.
First, let's rearrange the equation to isolate e^(-Ea/R * (1/T2 - 1/T1)):
e^(-Ea/R * (1/T2 - 1/T1)) = k2/k1
Now we can take the natural logarithm of both sides:
-ln(k2/k1) = Ea/R * (1/T2 - 1/T1)
Let's plug in the values we know:
-ln(2/1) = (38.2 kJ/mol) / (8.314 J/mol.K) * (1/T2 - 1/293.15 K)
Simplifying this equation gives:
1/T2 = 1/293.15 K - ln(2) * (8.314 J/mol.K) / (38.2 kJ/mol)
Solving for T2:
T2 = 1 / (1/293.15 K - ln(2) * (8.314 J/mol.K) / (38.2 kJ/mol)) - 273.15 K
T2 ≈ 356.9 K ≈ 83.8°C
Therefore, the temperature at which the reaction goes twice as fast as at 20°C is approximately 83.8°C.
Part B:
We can again use the modified Arrhenius equation to solve for the rate constant at 180°C. Let's call this rate constant k3:
k3 = k1 * e^(-Ea/R * (1/T3 - 1/T1))
We know k1 = 0.0140 s^-1, T1 = 20°C + 273.15 = 293.15 K, and Ea = 38.2 kJ/mol. We want to solve for k3 when T3 = 180°C + 273.15 = 453.15 K.
Plugging in the values we know:
k3 = 0.0140 s^-1 * e^(-38.2 kJ/mol / (8.314 J/mol.K) * (1/453.15 K - 1/293.15 K))
k3 ≈ 11.22 s^-1
Therefore, at a temperature of 180°C, the rate constant for the reaction would be approximately 11.22 s^-1.
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What does it mean that an electron behaves in ways that are at least partially indeterminate?
An electron behaves in ways that are at least partially indeterminate it means electron does not follow the same trajectory.
An electron is a quantum entity and a very tiny atom. The bonding of individual atoms depends heavily on electrons. The charge on the electron is adverse.
Species holding negative charge are popular by the name of" electrons" and electromagnetic field is employed to capture electrons by laboratory instruments. Several chemistry generalities are described using electrons and colorful subatomic patches.
This statement means that electrons have indeterminate geste which states that under identical conditions an electron doesn't follow the same line. Also, the electrons don't land in the same spot each time. thus, an electron behaves in ways that are at least incompletely indeterminate.
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As a warehouse worker pushes a crate across a concrete floor, the force he applies is not perfectly horizontal, as shown in the image below. If the coefficient of kinetic friction between the crate and concrete floor is 0.5, what is the net force on the crate?
A. 87 N
B. 110 N
C. 77 N
D. 135 N
will the efficiency increase decrease or remain the same if you make the inclined plane steeper
Answer:
The efficiency of a simple machine such as an inclined plane will decrease if the plane is made steeper. This is because a steeper plane requires more force to lift the same load, leading to a greater loss of energy due to friction and other sources of inefficiency. A gentler slope allows the force applied to the load to be spread out over a greater distance, reducing the force required to lift the load and therefore increasing the overall efficiency of the machine.
Explanation:
ALLEN
A 250 gram cart starts from rest and rolls down an inclined plane from a height of 0.94 m. Determine its speed
at a height of 0.17 m above the bottom of the incline.
The speed of the cart at a height of 0.17 m above the bottom of the incline would be 3.90 m/s.
Speed of an object on an inclined planeLet's call the speed of the cart at a height of 0.17 m above the bottom of the incline "v". We can calculate v using the following equation:
v^2 = 2 * g * (h1 - h2)
where
g = 9.8 m/s^2 (acceleration due to gravity)
h1 = 0.94 m (initial height)
h2 = 0.17 m (final height)
Plugging in the values, we get:
v^2 = 2 * 9.8 * (0.94 - 0.17)
v^2 = 2 * 9.8 * 0.77
v^2 = 15.156
v = sqrt(15.156)
v = 3.90 m/s
So the speed of the cart at a height of 0.17 m above the bottom of the incline would be approximately 3.90 m/s.
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If this collision occurs during a time of 0.012 seconds, what is the average force exerted on the ball
(a) The change in momentum is -12.04 kg-m/s
(b) The force exerted by the bat is 1003.33 N
How to calculate?The given values are :
The mass of a ball, m = 0.14 kg
Initial speed of the ball, u = 40 m/s
Final speed of the ball, v = -46 m/s
(a) The change in momentum of the ball during the collision with the bat is given by :
Change in P = m(v-u )
Change in P = 0.14(-46-40)
Change in P = - 12.04 kg-m/s
(b) Time for collision, t = 0.012 s
the force can be calculated as follows :
force = Change in P/ t
force = 1003.33 N
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Complete question:
An official major league baseball has a mass of 0.14 kg. A pitcher throws a 40 m/s fastball which is hit by the batter straight back up the middle at a speed of 46 m/s.
a) What is the change in momentum of the ball during the collision with the bat?
b) If this collision occurs during a time of 0.012 seconds, what is the average force exerted by the bat on the ball?
What 2 factors affect the gravitational potential energy of an object?
Gravitational potential energy of an object is affected by mass, gravity, and height. Energy is directly proportional to all three variables.
An thing inherently possesses a certain quantity of energy. The amount of energy an item possesses when a force coming from a distance, like as gravity, is acting on it and an object is not supporting it is known as the Gravitational Potential Energy. This energy can be utilised later to move an item since it can be stored and utilised at a later time.
We can claim that the following things affect the gravitational potential energy: weight of the thing. Size of the thing.
The energy that a large object has in relation to another large object due to gravity is known as gravitational potential energy.
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the tortoise and the hare are running a 1 km race. after running comfortably for 7 s, the hare is so far ahead that he decides to take a nap under a tree, 100 m away from the finish line. if the tortoise is moving constantly at a speed of 0.27 m/s, and the maximum speed of the hare is 15 m/s, how long can the hare afford to nap if he does not want to lose the race?
The hare can afford to nap for a maximum time of 6.67 seconds without losing the race if his speed is 15 m/s.
After running for 7 seconds, the hare has covered a distance of:
[tex]d_h = v_h * t = 15 m/s * 7 s = 105 m[/tex]
The hare is now 895 m away from the starting line and 100 m away from the finish line. The tortoise is 895 m away from the starting line and moving towards the finish line at a speed of 0.27 m/s.
The hare needs to cover a distance of 100 m to reach the finish line, while the tortoise needs to cover a distance of 895 m. If the hare takes a nap for a certain amount of time, the tortoise will continue to move towards the finish line and may eventually cross the finish line before the hare wakes up.
We can calculate the time it would take the tortoise to reach the finish line by dividing the distance by its speed:
[tex]t_t = d_t / v_t = 895 m / 0.27 m/s = 3314 s[/tex]
The hare needs to wake up and cover the remaining distance to the finish line before the tortoise does. The distance the hare needs to cover is:
[tex]d_h = 100 m[/tex]
The maximum speed of the hare is 15 m/s, which means the time it would take the hare to cover the distance is:
[tex]t_h = d_h / v_h = 100 m / 15 m/s = 6.67 s[/tex]
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an electron is accelerated from rest by a potential difference of 450 v. it then enters a uniform magnetic field of magnitude 170 mt with its velocity perpendicular to the field. calculate the speed of the electron.
The frequency of its circular motion is[tex]2.67 *10^8 Hz[/tex]. This frequency represents the number of complete circles that the electron makes in one second. It is also known as the cyclotron frequency.
To calculate the speed of the electron, we need to use the equations for the motion of a charged particle in a magnetic field.
First, we can calculate the acceleration of the electron due to the potential difference. We know that the potential difference is 450 V, which is also equal to the electron's kinetic energy. Therefore, we can use the equation for kinetic energy:
[tex]KE =\frac{ 1}{2} mv^2[/tex]
where KE is the kinetic energy, m is the mass of the electron, and v is its velocity. We can rearrange this equation to solve for v:
[tex]v = \sqrt(\frac{2KE}{m})[/tex]
We know that KE = eV, where e is the charge of the electron and V is the potential difference, so we can substitute:
[tex]v = \sqrt(\frac{2eV}{m})[/tex]
where e is the elementary charge [tex](-1.602 * 10^{-19 }C)[/tex] and m is the mass of the electron[tex](9.109 *10^{-31} kg)[/tex]. Plugging in the values, we get:
[tex]v = \sqrt\frac{(2*(-1.602 *10^{-19} C)*(450 V)}{(9.109 * 10^{-31} kg)}) \\ = 6.02 x 10^6 m/s[/tex]
This is the initial speed of the electron as it enters the magnetic field.
Next, we need to consider the motion of the electron in the magnetic field. Since the electron's velocity is perpendicular to the magnetic field, it will experience a force that is perpendicular to both its velocity and the magnetic field. This force can be calculated using the equation:
F = qvB
where F is the magnetic force, q is the charge of the electron, v is its velocity, and B is the magnetic field strength.
The magnetic force will cause the electron to move in a circular path with a radius given by the equation:
[tex]r =\frac{ mv }{ (qB)}[/tex]
where r is the radius of the circular path.
Since we know the velocity of the electron and the magnetic field strength, we can calculate the radius of the circular path:
[tex]r = \frac{mv }{ (qB)}[/tex]
[tex]=\frac{ (9.109 * 10^{-31} kg) * (6.02 * 10^{6 }m/s) }{ (1.602 *10^{-19 }C * 0.170 T) }\\\\= 1.18 * 10^{-2} m[/tex]
Finally, we can use the speed of the electron and the radius of its circular path to calculate the frequency of its circular motion:
[tex]f =\frac{v}{ (2\pi r) }\\ = \frac{(6.02 * 10^{6 }m/s) }{ (2\pi * 1.18 * 10^{-2 }m)} \\= 2.67 * 10^{8 }Hz[/tex]
This frequency represents the number of complete circles that the electron makes in one second. It is also known as the cyclotron frequency, and is a useful parameter in many applications involving charged particles in magnetic fields.
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two similar wooden blocks are tied one behind the other and pulled across a level surface. friction is not negligible. the force required to pull them at constant speed is f. if one block is stacked upon the other, how would the new force required to pull them at constant speed compare to f?
If the force required to pull the two separate blocks at constant speed is F, then the force required to pull the two stacked blocks at a constant speed will be 2F.
When two blocks are tied together and pulled across a level surface with friction, the force required to pull them at constant speed is determined by the frictional force between the blocks and the surface. Let's call this force F.
When one block is stacked on top of the other, the total mass of the two blocks is now doubled, but the contact area between the blocks and the surface remains the same. As a result, the frictional force between the blocks and the surface will also double, since it is proportional to the normal force (the force perpendicular to the surface), which is equal to the weight of the blocks. Therefore, the force required to pull the two stacked blocks at a constant speed will be twice the original force F required to pull the two separate blocks.
In other words, if the force required to pull the two separate blocks at constant speed is F, then the force required to pull the two stacked blocks at a constant speed will be 2F.
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what is the speed of the ball as it swings through this point? express your answer with the appropriate units.
The speed of the ball as it swings through this point is a) 23.8 m/s
b) 0
The most crucial scientific notion is measurement. A variety of measurable quantities are quantified using base or physical fundamental units.. One such quantifiable metric is speed, which calculates the ratio between the distance an item travels and the time needed to cover that distance. Let's explore speed in-depth in this session. Given that it just has a direction and no magnitude, speed is a scalar quantity.
a) The ball deviates from a straight line course due to the strain in the rope, which counteracts the effects of gravity. Last year's acceleration is
a =[tex]\frac{ T -mg}{m}[/tex] = 2g = [tex]\frac{v^2}{r}[/tex]. . . . m is mass
v = [tex]\sqrt(2gr)[/tex]= [tex]\sqrt{(2\times9.8 \times29 )} = \sqrt{(568.4 m^2/s^2)}[/tex]
v ≈ 23.8 m/s a rough estimate of the ball's speed at the low point
b) The acceleration needed to cause the ball to veer from its horizontal course is determined using the same procedure.
a = a =[tex]\frac{ T -mg}{m}[/tex] = [tex]\frac{ mg -mg}{m}[/tex]= 0
and the velocity is v = [tex]\sqrt{(ar)[/tex] = 0 . . . . . speed of the ball where the rope is vertical
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the tortoise and the hare are running a 1 km race. after running comfortably for 7 s, the hare is so far ahead that he decides to take a nap under a tree, 100 m away from the finish line. if the tortoise is moving constantly at a speed of 0.27 m/s, and the maximum speed of the hare is 15 m/s, how long can the hare afford to nap if he does not want to lose the race?(a) 6.67 s(b) 370 s(c) 3630 s(d) 3690 s
The correct option is D. 3690s They can hare afford to nap if he does not want to lose the race.
D= 1000m
[tex]V_T[/tex]= 0.27 m/s
[tex]T_t=\frac{1000}{0.27} = 3703.7sec[/tex]
[tex]T_h = \frac{100}{15}[/tex][tex]= 6.7sec[/tex]
[tex]T_t = 7+ t_n +t_h[/tex]
[tex]3703.7 = 7+t_n +6.7\\t_n = 3703.7- 13.7\\t_n = 3690sec[/tex]
The pace is measured as the ratio of distance to the time wherein the distance is turned into a blanket. the pace is a scalar quantity because it has the most effective course and no importance. For the size of the pace in vehicles, speedometers are used. pace also can be calculated with the assistance of a graph. the space-time graph allows know-how of the rate of an object.
In regular use and in kinematics, the rate of an object is the value of the change of its position over the years or the importance of the alternate of its function per unit of time; its miles as a result a scalar amount. the spot pace is the limit of the common pace because the period of the time c program language period approaches 0. pace isn't always similar to velocity.
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An airplane flies 170 km in 15 minutes.
What is its average speed
Answer:
11.33 km/min
Explanation:
170km ÷ 15min = 11.33km/min
the moon is decreasing in light between a full moon and a last quarter moon called___
The moon is decreasing in light between a full moon and a last quarter moon called waning.
Describe about moon?
Moon is the satellite of Earth and the only natural satellite of Earth. It is the fifth-largest natural satellite in the Solar System. It orbits around Earth in an elliptical path and takes 27.3 days to complete one revolution. It is made up of different types of rocks and dust and has no atmosphere. Its surface is covered with impact craters, mountains, valleys, and lava-filled plains. It also has frozen water at the poles. The moonlight is reflected sunlight and the light of the moon changes its shape throughout the month due to its changing position with respect to the Earth and the Sun. It is the Earth's only natural satellite and the most visible object in the night sky.
Therefore, The moon is decreasing in light between a full moon and a last quarter moon called waning.
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a large truck tire is inflated to a gauge pressure of 78 psi. the total area of one sidewall of the tire is 1,270 in2. what is the net outward force (in lb) on the sidewall because of the air pressure? (enter the magnitude.)
The current official highest registered air temperature on Earth is 56.7 °C (134.1 °F), recorded on 10 July 1913 at Furnace Creek Ranch, in Death Valley in the United States.
Yes, that is correct. The World Meteorological Organization (WMO) has recognized a temperature of 56.7 °C (134.1 °F) recorded on July 10, 1913, at Furnace Creek Ranch in Death Valley, California, USA, as the highest temperature ever reliably recorded on Earth. This record was set during a period of intense heat in the region and remains the subject of some debate and scrutiny by scientists due to the quality of the recording equipment used at the time.
What is the World Meteorological Organization (WMO)?In order to foster worldwide collaboration in meteorology, the study of the Earth's atmosphere and its phenomena, and allied geophysical disciplines, the United Nations has established the World Meteorological Organization (WMO). It was founded in 1950, and Geneva, Switzerland, serves as its corporate headquarters.
The WMO's goals are to encourage the growth and use of meteorology for the benefit of humanity and to make it easier for its member nations to exchange meteorological and related information. National meteorological and hydrological services are given direction and support by it, which enables them to build better weather forecasting and warning systems as well as methods for dealing with the effects of weather-related disasters and climate change.
The World Meteorological Organization (WMO) is in charge of a number of significant global projects and programs, such as the World Weather Watch, which gathers and disseminates meteorological information and forecasts globally, and the Global Atmosphere Watch, which tracks changes in the composition of the Earth's atmosphere and their effects on climate and the environment.
For the measurement of weather and climate variables, the WMO also upholds a number of international standards and norms. It also plays a significant role in advancing scientific research and capacity building in developing nations.
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Yes, that is correct. The World Meteorological Organization (WMO) has recognized a temperature of 56.7 °C (134.1 °F) recorded on July 10, 1913, at Furnace Creek Ranch in Death Valley, California, USA, as the highest temperature ever reliably recorded on Earth.
What is the World Meteorological Organization (WMO)?In order to foster worldwide collaboration in meteorology, the study of the Earth's atmosphere and its phenomena, and allied geophysical disciplines, the United Nations has established the World Meteorological Organization (WMO). It was founded in 1950, and Geneva, Switzerland, serves as its corporate headquarters.
The WMO's goals are to encourage the growth and use of meteorology for the benefit of humanity and to make it easier for its member nations to exchange meteorological and related information. National meteorological and hydrological services are given direction and support by it, which enables them to build better weather forecasting and warning systems as well as methods for dealing with the effects of weather-related disasters and climate change.
The World Meteorological Organization (WMO) is in charge of a number of significant global projects and programs, such as the World Weather Watch, which gathers and disseminates meteorological information and forecasts globally, and the Global Atmosphere Watch, which tracks changes in the composition of the Earth's atmosphere and their effects on climate and the environment.
For the measurement of weather and climate variables, the WMO also upholds a number of international standards and norms. It also plays a significant role in advancing scientific research and capacity building in developing nations.
This record was set during a period of intense heat in the region and remains the subject of some debate and scrutiny by scientists due to the quality of the recording equipment used at the time.
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this image of a roller coaster is designed to show important informtion about potential and kinetic energy. one of these labeled pieces of information is incorrect. which information is wrong, and why?
The connection of kinetic energy and potential is demonstrated by this animated roller coaster created by WGBH. When the coaster cars travel around the track's loop and ascend and descend the hills.
Describe kinetic.
Those who are learning English Kinetic is defined as being related to or pertaining to the motion of physical objects, including the forces that cause those motions. Kinetic energy: of or pertaining to the energy and energy involved in the motion of physical objects.
What is the kinetic energy relationship?
She was the initial person to publish the kinetic energy relationship. This implies that an object traveling at twice the speed will strike twice as forcefully. The energy an object has as a result of motion is known as kinetic energy in physics. It is described as the effort required to move a mass-determined body from rest to the indicated velocity.
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what is the electric field strength inside the hole at radial distance r
The electric field is given by the formula e for the sphere + e for the cylinder, which is equal to negative row r over 3 б+ ρr over 2 б + ρr / s.
We prefer to find the strength of our electric field at r because distances are less than a. If an is less than a, we can think of our length cylinder as being coaxial with a galcene cylinder of radius r. Now, let's say that our cylinders resemble this. The charge contained within the cylinder is then equal to either row times v or row pi r, squared times l. Gauss law can then be used to calculate our electric field.
Since e da da is equal to q, enclosed divided by epsilon naught, e times integral of da is equal to q, enclosed divided by epsilon naught, so e times 2 π r l = rho π r, squared l divided by Epsilon naught, so e is equal to row r divided by 2 б. Since the average cylinder is positively charged, this Let's now think about a galcene sphere with radius r. This calcium sphere has a charge that is negative row times 4/3πr³.
Let's now determine the electric field at a place that is e times away from the centre. Negative row 4/3πr³/б (epsilon) = 4πr². As a result, some of these components of our electric field—which is negative, pi negative row, and r divided by 3 epsilon—are also present inside the hole. So, we do. The electric field is given by the formula e for the sphere + e for the cylinder, which is equal to negative row r over 3 epsilon plus row r over 2 epsilon plus row r divided by s.
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Please answer this quick!
The forces among the positive protons in the nucleus of an atom are all repulsive, so we would expect the nucleus to fly apart. The
reason all the nuclei in your body are not spontaneously exploding at this moment is that there is an attractive force in action. This
force acts between neutrons and protons and does not influence chemical reactions. Which force is responsible for this
phenomenon?
A. gravitational force
B. weak nuclear force
C. electrostatic force
D. strong nuclear force
Strong nuclear force acts between neutrons and protons and does not influence chemical reactions, so nuclei in your body are not spontaneously exploding, hence option D is correct.
What is nuclear force?The nuclear force is a kind of force that acts between the protons and neutrons of atoms. Neutrons and protons, both nucleons, are influenced by the nuclear force almost equally.
It is the force that binds neutrons and protons together and does not allow them to fly apart. This force can act between neutrons and protons, protons and protons, and neutrons and neutrons.
Therefore, strong nuclear force is responsible for this phenomenon.
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the maximum audible range is about 15 to 20,000 hz. determine the range of wavelengths for sound over this range of frequency. assume room temperature.
The range of the wavelengths for the sound over the audible range of frequencies in room temperature is from 24 meters to 18×10⁻³ meters.
The relation between velocity , wavelength and frequency of a sound is given by the following equation :
⇒ V = λ x ν where, V stands for the velocity of the sound, λ stands for the wavelength, and ν stands for frequency of the sound. To find wavelength, we have to put ν on the left side of the equation which gives us :
λ = V/ν
Velocity of the sound at room temperature ≈ 360m/s
For 15 hertz, Wavelength = V/ν
= 360/15
=24 meters
For 20,000 hertz, Wavelength = V/ν
= 360/20000
=18×10⁻³ meters
Therefore, the audible range of wavelengths is from 24 meters to 18×10⁻³ meters.
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what units are used to measure mass in gravity calculations?a. N/kgb. mgc. gd. kge. Mg
The sign "kg" stands for kilogramme (kg), which is the unit of mass used in gravity calculations.
What units are used in gravity calculations to measure mass?The kilogramme is the standard mass unit that is used almost globally and is the SI unit of mass. The kilogramme weighs 9.8 Newtons under normal conditions on the surface of the Earth, and the Newton is the corresponding SI unit of force and weight.
Does mass have a newton unit?The unit of measurement for mass, or mass in kilogramme, is matter. A bird's bulk remains constant. No matter where you weigh something—on Earth, the Moon, or Mars—it always weighs 15 grammes. Weight is a measurement of the gravitational pull of an object and is determined by newtons.
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ms. knuth places a stick in a pond. when she looked down at the stick, it appeared to be broken or bent at the point where the stick entered the water. this was caused by: a diffraction of light waves around the stick. b reflection of light waves passing from air into water. c a refraction of light from the water. d refraction of light waves passing from air into water.
Option B is correct Light waves travelling through air are reflected in water.
Light, as we know, requires a medium for propagation. Every medium has its unique refractive index, which is often measured with relation to air. For the purpose of simplicity, the refractive index of air is assumed to be one.
When we view anything, the light from that item passes via the medium of air to our retina. During its propagation, light has a fixed wavelength and speed.
When an item is positioned between two mediums, light travels through both before reaching our eyes.
The two media in this case are air and water. Water has a greater refractive index than air, resulting in refraction. The speed of light reduces when the medium changes. The refraction is what causes Due to the difference in light speed, the stick in the water seems twisted or broken.
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two identical boats with identical engines (so they push with the same force) race across a lake. one boat carries four large men, and the other carries two small women. which boat wins the race?
If all other conditions (such as wind speed and water current) are equal and there are two identical boats with identical engines that push with the same force, the boat carrying the two little women is likely to win the race.
Assuming the two boats have identical mass and shape, the boat carrying the four large men will be slower than the boat carrying the two small women. This is because the boat carrying the men has more total weight, and thus has a greater force of gravity acting upon it. The greater force of gravity increases the frictional forces between the boat and the water, which in turn decreases the speed of the boat. According to Newton's second law of motion, the acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass. Since the two boats are being pushed with the same force, the boat with less mass (i.e., the boat carrying the two small women) will experience greater acceleration than the boat with more mass (i.e., the boat carrying the four large men). Therefore, the boat carrying the two small women is likely to win the race, assuming all other factors (such as wind speed and water current) are equal.
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Calculate the freezing point of a solution containing 10.6 g FeCl3 in 159 g water
Calculate the boiling point of a solution above.
The freezing point of the solution will decreases by the addition of the salt. The freezing point of the solution is - 0.76 °C and boiling point increases to 100.21 °C.
What is depression in freezing point ?The addition of a nonvolatile salt into a solvent will decrease the freezing point of the solution. Similarly the salt addition will increases the boiling point of the solution. Both are colligative properties and depends on the molality as written below:
ΔTf = Kf m
ΔTb = Kb m
Where, kb for water is 0.52 °C kg/mol and Kf is 1.86 °C kg/mol.
Molar mass of FeCl₃ = 162.3 g/mol
no.of moles in 10.6 g = 10.6 /162. 3 = 0.065 moles.
mass of water = 159 g = 0.159 kg.
molality of the solution = 0.065 mol/0.159 kg = 0.4088.
now, ΔT = 0.186 °C kg/mol × 0.4088 = 0.76
T = 0 - 0.76 = -0.76°C (freezing point of water = 0°C ).
Similarly ΔTb = 0.52 °C kg/mol × 0.4088 = 0.212
Tb = 100 + 0.212 = 100.21 °C (boiling point of water =100°C ).
Therefore, the freezing point of the solution is- 0.76 °C and boiling point of the solution is 100.21 °C.
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A student measures the mass of a solution before and after a chemical reaction takes place. In both cases the students measures the mass to be 50.25 g on an electronic balance with an uncertainty of 0.05 g. The student realizes that the ranges of uncertainty for each measurement overlap exactly. Which claim can the student make?
A. The mass definitely stayed the same because the measurement of 50.25 g was obtained each time.
B. The mass definitely stayed the same because the ranges of uncertainty overlap exactly.
C. We can’t know for sure whether or not the mass changed, but it seems reasonable to claim that the mass did not change, given that the ranges of uncertainty overlap.
The correct claim the student can make is: B. The mass definitely stayed the same because the ranges of uncertainty overlap exactly.
What is mass?A measurement of the quantity of matter in an item or system, mass is a basic physical characteristic of matter. Due to its scalar nature, it has simply magnitude and no direction. One of the most fundamental ideas in physics is mass, which is also connected to other key ideas like weight, force, and energy.
The kilogram is the SI unit of mass (kg). There are several ways to measure mass, but the most popular one is with a balance or a scale. A balance assesses an object's mass in relation to a recognized standard. Contrarily, a scale employs a force to overcome an object's gravitational pull before measuring the result.
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why is the following situation impossible? a technician is testing a circuit that contains a resistance . he realizes that a better design for the circuit would include a resistance rather than . he has three additional resistors, each with resistance . by combining these additional resistors in a certain combination that is then placed in series with the original resistor, he achieves the desired resistance.
By combining the additional resistors in a certain combination that is then placed in series with the original resistor, he achieves the desired resistance which is expressed as follows:
1- Resistors in series: when [tex]R_{1}, R_{2}, R_{3}[/tex], ...... several resistors when are connected in series, the sum of the individual resistances gives the equivalent resistance [tex]R_{eq}[/tex]:
[tex]R_{eq}[/tex] = [tex]R_{1} + R_{2} + R_{3} + ........[/tex]
2- Resistors in Parallel: when [tex]R_{1}, R_{2}, R_{3}[/tex], ...... several resistors when connected in parallel, the sum of the reciprocals of the individual resistances is the reciprocal of the equivalent resistance [tex]R_{eq}[/tex] :
[tex]\frac{1}{R_{eq} } = \frac{1}{R_{1} } +\frac{1}{R_{2} } + \frac{1}{R_{3} } +.... (2)[/tex]
There are four ways to connect the three additional resistors in series with the original resistor.
The first way is if all the resistors are in series. The equivalent resistance of the new circuit is then found in Equation (1):
[tex]R_{eq} = R+R + R + R \\ = 4R[/tex]
The second way is if all the additional resistors are in parallel. The three resistors in the blue rectangle are in parallel and their equivalent resistance is from Equation(2):
[tex]\frac{1}{R_{eq} } = \frac{1}{R} + \frac{1}{R} + \frac{1}{R} \\ R_{eq} = \frac{R}{3}[/tex]
The R/3 and R resistors are in series and their equivalent resistance is ind from Equation (1):
[tex]R_{eq} = \frac{R}{3} + R\\ = \frac{4}{3} R[/tex]
The third way is if two resistors from the additional resistors are in parallel and the third one is in series with the combination. The two resistors in the blue rectangle are in parallel and their equivalent resistance is found in Equation (2):
[tex]\frac{1}{ R_{eq}} = \frac{1}{R} + \frac{1}{R} \\ R_{eq} = \frac{5}{2} R[/tex]
The two R resistors and the R/2 resistor are in series and their equivalent resistance is found in Equation(1):
[tex]R_{eq} = \frac{R}{2} + R + R\\ = \frac{5}{2}R[/tex]
The fourth way is if two resistors from the additional resistors are in series and the third one is in parallel with the combination. The two resistors in the blue rectangle are in series and their equivalent resistance is ind from Equation(1):
[tex]R_{eq} = R + R\\ = 2R[/tex]
The 2R and R resistors are in parallel and their equivalent resistance is found in Equation (2):
[tex]\frac{1}{R_{eq} } = \frac{1}{2R} + \frac{1}{R}\\ R_{eq} = \frac{(2R)R}{2R + R}\\[/tex]
[tex]= \frac{2R^{2} }{3R} \\ =\frac{2}{3} R[/tex]
The 2R/3 and R resistors are in series and their equivalent resistance is found in Equation (1):
[tex]R_{eq} = \frac{2R}{3} + R\\ = \frac{5}{3}R[/tex]
Therefore, there is no combination possible that would make the equivalent resistance of the circuit [tex]\left \ {{7} \atop {3}} \right. R[/tex] and the expressed situation is impossible.
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100 + 50 + BRAINLIST PLEASE HELP!!!
1. What are the forces acting on the block when it is hanging freely from the spring scale? What is the net force on the block? What are the magnitudes of each of the forces acting on the block? Explain.
2. What are the forces that act on the block when it is placed on the ramp and is held in place by the spring scale? What is the net force acting on the block? Explain. (Assume that the ramps are frictionless surfaces. )
3. What is the magnitude of normal force acting on the block when it is resting on the flat surface? How does the normal force change as the angle of the ramp increases? Explain. (Assume that the ramps are frictionless surfaces. )
1. The forces acting on the block while it is hanging freely are gravitational force and tension force.
2. The forces acting on the block while placed on the ramp with the spring scale are:
The force of gravity acting downwardThe normal force acting upward from the rampThe tension force acting upward from the spring scale3. The magnitude of the normal force acting on the block when it is resting on a flat surface is equal to the force of gravity acting on the block, or m * g.
Forces acting on the Block1. The forces acting on the block when it is hanging freely from the spring scale are:
The force of gravity (also known as weight) acting downwardThe tension force acting upward from the spring scaleThe net force on the block is zero, as the block is in static equilibrium, meaning that the sum of all forces acting on the block is equal to zero.
The magnitude of the force of gravity acting on the block can be calculated using the formula:
F_gravity = m * g
where m is the mass of the block and g is the acceleration due to gravity (approximately 9.8 m/s^2).
The magnitude of the tension force acting on the block is equal to the reading on the spring scale, as the scale measures the tension in the string to which the block is attached.
2. The forces acting on the block when it is placed on the ramp and held in place by the spring scale are:
The force of gravity acting downwardThe normal force acting upward from the rampThe tension force acting upward from the spring scaleThe net force acting on the block is equal to the force of gravity minus the normal force, as the ramp is a frictionless surface and there is no friction acting on the block. This net force will cause the block to accelerate down the ramp.
The magnitude of the normal force acting on the block can be calculated using the formula:
F_normal = m * g * cos(θ)
where θ is the angle of the ramp with respect to the horizontal.
3. The magnitude of the normal force acting on the block when it is resting on a flat surface is equal to the force of gravity acting on the block, or m * g.
As the angle of the ramp increases, the normal force acting on the block decreases. This is because the component of the force of gravity acting perpendicular to the ramp (the component responsible for the normal force) decreases as the angle of the ramp increases. The decrease in the normal force leads to an increase in the net force acting on the block, causing it to accelerate down the ramp.
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Which phase change represents a decrease in entropy?answer choicesa. solid to liquidb. gas to liquidc. liquid to gasd. solid to gas
Gas to liquid is the phase change represents a decrease in entropy.
option B
The measurement of randomness or disorder in a system is known as entropy.
As for the order of entropy, The increase in disorder causes the entropy to rise when we transition from the solid state to the liquid state to the gaseous state. Entropy will decrease when we transition from a gaseous state to a liquid state and then a solid state because chaos is becoming less disorganized. Entropy rises for options 1, 3, and 4. whereas the entropy falls in option 2. Entropy is the measurement of the amount of thermal energy per unit of temperature in a system that cannot be used for productive labor. Entropy is also a measure of molecular disorder since work is produced by ordered molecular motion.
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If a wave has a speed of 47 m/s and a wavelength of 25 m, what is the frequency of the wave? Give your answer to 2 decimal places.
Answer:
The formula is:
v = f λ
Where,
v is the velocity or speed of the wave (in m/s)
f is the frequency of the wave (in Hz)
λ is the wavelength of the wave (in m)
We can rearrange this formula to solve for the frequency:
f = v / λ
We are given the speed and the wavelength of the wave, so we can plug them into the formula:
f = 47 m/s / 25 m
f = 1.88 Hz
To give the answer to 2 decimal places, we round it to:
f = 1.88 Hz
Therefore, the frequency of the wave is 1.88 Hz.
Explanation:
Answer:
1.88 Hz.
Explanation:
The frequency (f) of a wave is related to its speed (v) and wavelength (λ) by the equation f = v/λ.
So to find the frequency of a wave with a speed of 47 m/s and a wavelength of 25 m, we just need to substitute these values into the equation:
f = 47 m/s / 25 m
f = 1.88 Hz
Rounding to 2 decimal places, the frequency of the wave is 1.88 Hz.
a hanging spring is stretched by 0.2 m when a mass of 0.5 kg is attached to it. the mass is then pulled down a further 0.1 m and released from rest. what is the angular frequency of the resulting oscillations? show your work.
The angular frequency of the oscillations is 3.126 rad/s.
What is the angular frequency?To find the angular frequency of the oscillations, we need to use the formula:
ω = √(k/m)
where ω is the angular frequency, k is the spring constant, and m is the mass attached to the spring.
First, let's find the spring constant k. According to Hooke's law, the force F applied to a spring is proportional to its displacement x from its equilibrium position, and the constant of proportionality is the spring constant k:
F = -kx
where the negative sign indicates that the force is in the opposite direction to the displacement. We can rearrange this equation to solve for k:
k = -F/x
where F is the weight of the mass attached to the spring, which is given by:
F = mg
where m is the mass of the object and g is the acceleration due to gravity. Therefore, we have:
k = -(mg)/x
Substituting the given values, we get:
[tex]k = -(0.5 kg)(9.81 m/s^2)/(0.2 m)[/tex]
= -24.525 N/m
Next, we need to find the new equilibrium position of the mass after it is pulled down by an additional 0.1 m. Since the spring is initially stretched by 0.2 m, the total displacement from the rest position is 0.2 m + 0.1 m = 0.3 m. Therefore, the new equilibrium position is 0.3 m below the original rest position.
Now, we can find the angular frequency of the oscillations using the formula:
ω = √(k/m)
where m is the mass of the object. Since the mass is the same as before, we have:
ω = √(k/m)
= √(-24.525 N/m / 0.5 kg)
= 3.126 rad/s
Therefore, the angular frequency of the oscillations is 3.126 rad/s.
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