A machine has an efficiency of 15% . If the energy inputs is 300 joules, how much useful energy is generated

Answers

Answer 1

Answer:

you made with your performance, and then consider whether you would do anything differently if yo

Explanation:

Answer 2

The useful energy generated by the machine having an efficiency of 15% and an energy input of 300 J is 45 J

From the question given above, the following data were obtained:

Efficiency = 15% = 0.15

Work input = 300 J

Work output =?

The useful energy generated (i.e work output) by the machine can be obtained as follow:

[tex]Efficiency = \frac{workout}{workin} * 100\\\\0.15 = \frac{Workout}{300}[/tex]

Cross multiply

Work output = 0.15 × 300

Work output = 45 J

Therefore, the useful energy generated by the machine is 45 J

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Related Questions

8. What is generated by the movement of tiny particles within an object? *
(2 Points)
endothermic
exothermic
heat
thermal

Answers

Answer: Thermal Energy

Explanation: I know this answer is correct because I had to look in my notebook for the definition

In my own words: Thermal Energy is the energy coming from heat which means it is generated by the movement of tiny particles with different objects.

Hope this helps! :)

Question 6 (3 points)
A high school has a football field that is exactly east-west from end zone to end zone. Football fields are 53.333 yards wide. Starting at the
southwest corner of the field, you walk to the north end of the western 30 yard line. What is the vector (magnitude and angle) of your
displacement? Round to the nearest yard and nearest degree. Make sure you label the angle with the direction (N, S, NE, NW, etc.)
Magnitude:
yards
Angle:
Blank 1:
Blank 2:
Blank 3:

Answers

Answer:

52355236552255558654

[tex].. { {.y = 392.6. = }^{ + 36yjsss} }^{?} jmijjdrk{am \: {}{}s[/tex]

What is the smallest part of a compound called?
element
O
molecule
O
atom
O
mixture
o

Answers

Answer:

Here is your answer,thanks for using brainly!

Explanation:

B:Molecule

Molecules usually consist of 2 atoms linked together,however some molecules  consist of thousands of atoms!

Here is a list of smalles to largest with the answers provided

Molecules

Atoms

Elements

Mixtures

Hope this helped

Plz mark brainliest

Dont forget to smash that heart at the bottom <3

Have a great day!

at 30°c an almunium spher is 30cm³ long
the cofficen linear expansion is 24×10`⁶ if the final volume is 30.5cm³
what's the final temperatur of the almunium sphere​

Answers

Answer:

Change volume / volume = .5 / 30 = .01666

coefficient of volume expansion = 3 * 24E-6 = 72E-6

Change in temp = .0167 / 24E-6 = 232 deg C

Final temp = 232 + 30 = 262 deg C

Change in volume / volume = 3 * coeff linear expansion * change in deg C

Please help as soon as possible! I will give Brainliest! I just need to know the answers to this diagram.

Answers

Hope it will help you

The neurotransmitter acetylcholine:
A. is chemically identical to heroin.
B. is found in all sensory neurons.
C. can cause hallucinations when present in abnormally excessive amounts.
D. is involved in muscle contractions and memory.

Answers

Explanation:

A. is chemically identical to heroin.

Help on these two thanks

Answers

Answer:

8. Friction

9. Net force

Explanation:

Hope this helps you. Have a nice day. :)

Two buildings near each other stand 40m and 60 m tall as measured from the ground to the rooftop. You are standing on the rooftop of the shorter building and observe that the rooftop of the taller building is 55o above the horizontal, as shown in the diagram below. Determine the horizontal distance (in meters) between the two buildings.

Answers

Answer:

Explanation:

tanθ = opp/adj

adj = opp/tanθ

adj = (60 - 40)/tan55 = 14 m

PLz help Asap 10 POINT
I MIGHT GIVE BRAINLIST IF RIGHT AND IF I CAN.

Answers

Answer:

Mars has a thin atmosphere

Explanation:

Okay, so this is going to sound crazy but bare with me. Mar's atmosphere is thin. There is little to no gravitational pull for the atmosphere to stay. Also, no, humans will not be able to live on Mars because the atmosphere, quite literally, contains 1% oxygen. Hopefully this helps! Earth's is thick because of the gravitational pull and gases in Earth's surface.

Compared to a 1-kg block of solid iron, a 2-kg block of solid iron has the same:
A. Density
B. Mass
C. Volume
D. Inertia

Answers

The Correct choice is :

Density

what’s 12cm in kilometers

Answers

0.00001 is the correct answer you have an amazing day

Help ,I wanna know if this is correct or not

Answers

Answer:

it looks correct to me but im not 11% sure

Explanation:

En el diseño de una sesión de aprendizaje, la profesora Patricia, tiene como propósito de aprendizaje: Aplica sus habilidades motrices generales en la práctica de juegos diversos. ¿Cuál es el nivel de aprendizaje en que se encuentran sus estudiantes en relación con el propósito de aprendizaje?

Answers

Answer:

im in hardvard dont cheat get amzing grades if you want to go here

Explanation:

When a projectile reaches the highest point the vertical component of the acceleration is:
(A) Less than g (B) Greater than g (C) Positive g (D) Negative g

Answers

Answer:

The acceleration is g.

Taking the upward direction as positive

V = Vy y - 1/2 g t^2

Taking the downward direction as positive

V = -V y + 1/2 g t^2

One can choose either direction as positive, but the acceleration is

the same as g (it is g) while the projectile is in the air.

When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). Thus, the correct option is D.

What is Projectile motion?

Projectile motion is the motion of an object which is thrown or projected high into the air. After the initial force applied on the object that launches the object, the object only experiences the gravitational force. The object is called a projectile and the path of the object is called trajectory.

When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). When the object achieves highest point, then the vertical acceleration of a projectile is zero meter per second square when it is at the peak of its trajectory motion.

Therefore, the correct option is D.

Learn more about Projectile motion here:

https://brainly.com/question/11049671

#SPJ2

HELP ASAP

Newtons three laws of motion: describe the ______ between an object and the forces acting upon it, and it's motion in_______ to those forces

Answers

Relations with respect to

Explanation:

Laws of Newton are

An object remains at its position of rest or motion until or unless any external force applied.Force=Mass×Acceleration.The initial momentum and final momentum remains same.

Please answer ASAP with science! Will give ya brainliest :) !!

Answers

Answer:

d

Explanation:

Jake lifted a 10-kg bell by a distance of 0.50 meters in 0.50 seconds. How much power did Jake use?​

Answers

Answer:

10 watts

Explanation:

first calculate work.

Work =force×distance cos thita

10Kg×0.50M cos 0= 5joules

Therefore, Power=Work÷ Time

Therefore, 5joules÷0.50s=10 watts.

3)(20pts) Un barco invasor se encuentra a 560m de un puerto de defensa, el puerto tiene cañones que
disparan con una velocidad de 82m/s. a) ¿Qué ángulo debe de tener el barco para poder golpear el
barco invasor? b) ¿Cuál es el tiempo de vuelo de las balas disparadas por el cañón utilizando el ángulo
de la respuesta "a"? c) ¿Qué tan lejos debe alejarse el barco invasor de la costa para lograr estar fuera
del alcance de los cañones?

Answers

a) Las balas de cañon disparadas desde el puerto deben tener una ángulo de 27.39° para que puedan impactar al barco, con una velocidad inicial de 82 m/s.

b) El tiempo de vuelo de las balas de cañon para alcanzar al barco que está a 560 m de distancia es de 7.69 s.

c) Sabiendo que el ángulo calculado en el inciso a) es para una distancia de 560 m, el barco debe estar a una distancia mayor para que las balas no lo alcancen.

a)

Podemos usar las ecuaciones de tiro parabólico para encontrar el ángulo que permita derribar al barco invasor.

[tex]x=\frac{v_{i}^{2}sin(2\alpha)}{g}[/tex] (1)

Donde:

v(i) es la velocidad inicial del cañon (82 m/s)α es el ángulo de tirog es la gravedad (9.81 m/s²)x es el desplazamiento total (560 m)

Lo que debemos hacer es depejar α de la ecuación 1

[tex]sin(2\alpha)=\frac{xg}{v_{i}^{2}}[/tex]

[tex]sin(2\alpha)=\frac{560*9.81}{82^{2}}[/tex]

[tex]sin(2\alpha)=0.82[/tex]

[tex]\alpha=\frac{sin^{-1}(0.82)}{2}[/tex]

[tex]\alpha=27.39^{\circ}[/tex]

Por lo tanto, el ángulo para que el cañón impacte en el barco es de 27.39 °.

b)

Sabemos que la componente de la velocidad en el eje x es constante, así que podemo usar la siguiente ecuación.

[tex]v_{x}=\frac{x}{t}[/tex]

La componente x de la velocidad es V(x) = V(i)cos(α) y sabiendo la distancia total de 560 m, el tiempo será:

[tex]v_{i}cos(\alpha)=\frac{x}{t}[/tex]

[tex]t=\frac{x}{v_{i}cos(\alpha)}[/tex]

[tex]t=\frac{560}{82cos(27.39)}[/tex]

[tex]t=7.69\: s[/tex]

El tiempo total de vuelo de las balas de cañon es de 7.69 s.

c)

Sabemos que el ángulo calculado en el inciso a) es de 27.39 °, y ese valor fue calcualdo para una distancia de 560 m, por lo tanto el barco debe estar a una distancia mayor que esa para que las balas no lo alcancen.

Puedes encontrar más información sobre tiro parabólico aquí:

https://brainly.lat/tarea/3605927

Espero te haya sido de ayuda!

Draw a free body diagram of an 6.4 kg ball falling towards earth. Calculate the weight of the ball.​

Answers

Diagram:-

[tex]\setlength{\unitlength}{2mm}\begin{picture}(0,0)\thicklines\put(3,6){\circle{3}}\put(2.9,4.5){\vector(0,-3){2cm}}\put(-3.9,-10){\line(3,0){3cm}}\multiput(-3.5,-10)(0.8,0){18}{\line(1,-2){2mm}}\put(-3.7,0){$\sf\footnotesize 9.8 ms^{-2}$}\put(6,0){\vector(0,3){1.2cm}}\put(5.5,6){\line(3,0){2mm}}\put(5,-1.2){\sf\footnotesize height}\put(6,-2){\vector(0,-3){1.2cm}}\put(5.5,-8){\line(1,0){2mm}}\end{picture}[/tex]

Here

m=6.4kg

[tex]\\ \sf\longmapsto Weight=mg[/tex]

[tex]\\ \sf\longmapsto Weight=6.4(9.8)[/tex]

[tex]\\ \sf\longmapsto weight=62.72N[/tex]

How many hydrogen atoms are there in all the reactants?

Answers

Answer:

there are two hydrogen atoms in all reactants

What is the Normal CSF for:

Leukocytes (per mm³)

% Neutrohils

Glucose (mg/dL)

Protein (mg/dL)

Please provide source if possible.

Answers

1. 5 WBC's per cubic millimeter.

3. 50 to 80 mg/100 mL

4. 15 to 60 milligrams per deciliter (mg/dL) or 0.15 to 0.6 milligrams per milliliter (mg/mL)

If a test were to be performed here are normal results:

Normal values typically range as follows:

Pressure: 70 to 180 mm H2O

Appearance: clear, colorless

CSF total protein: 15 to 60 mg/100 mL

Gamma globulin: 3% to 12% of the total protein

CSF glucose: 50 to 80 mg/100 mL (or greater than two thirds of blood sugar level)

CSF cell count: 0 to 5 white blood cells (all mononuclear), and no red blood cells

Chloride: 110 to 125 mEq/L

(Source: https://medlineplus.gov/ency/article/003428.htm)

Help me with this please

Answers

Answer:

for the secound one i think it would be 45.87 let me know if this is wrong I love to get my feed back

Explanation:

Let us remember your previous lesson on Physical Press Components! Directions: Analyze the folawna fitness components. Put a check in the box to which Physical Fitness belongs to Components Slab-Related Health Related 1. Power 2. Agility 3. Balance 5. Muscular Strength​

Answers

Answer:

5 Muscular and strength

Peering through a telescope could be considered Step 1 of the scientific method.
True
False

Answers

True:
Because doing so can be used through scientific method<3

A 5.0 kg cannonball is fired horizontally at 68 m/s from a 15-m-high cliff. A strong tailwind exerts a constant 12 N horizontal force in the direction the cannonball is traveling. What is the extra distance (d)?

Answers

Answer:

3.7 m

Explanation:

ASSUMING this means extra distance beyond where the cannonball would land WITHOUT the wind assistance but in general ignoring air resistance. Hmmmmmm...tricky

The ball drops from vertical rest to ASSUMED horizontal ground 15 m below in a time of

t = √ (2h/g) = √(2(15)/9.8) = 1.75 s

Without the tail wind, the ball travels horizontally

d = vt = 68(1.75) = 119 m

The tailwind exerts a constant acceleration on the ball of

a = F/m = 12/5.0 = 2.4 m/s²

The average horizontal velocity during the flight is

v(avg) = (68 + (68 + 2.4(1.75)) / 2 = 70.1 m/s

so the distance with tailwind is

d = v(avg)t = 70.1(1.75) = 122.675 m

The extra distance is 122.675 - 119 = 3.675 = 3.7 m

write two examples of chemical properties and explain what they are

Answers

Chemical Properties are properties of a substance that are seen during a chemical reaction. In other words, chemical properties cannot be found by looking/touching the substance. Those are its physical properties.

Examples

Flammability
toxicity
solubility
Acidity
Electronegativity

Someone pls help I don’t understand this

Answers

Answer:

[tex]{ \rm{F _{ball \: on \: bat} = - F _{bat \: on \: ball} }}[/tex]

Explanation:

• This is due to the third newtons law of motion which states that "Every action has an equal and opposite reaction".

someone pls helpp meeee

Answers

Answer:

the first answer is correct


Which of the following could be evidence that an organism's growth is influenced by the organismis genes?
(Hint identical twins have identical genes. Non-identical twins have about half the same genes.)
Adog breed can be made smaller by breeding together only the smallest dogs.
Identical twins are more likely to be about the same height than non-identical twins,
Chdren are likely to have friends who are about the same height
Identical twins often have slightly different weights at birth

Answers

Answers:

A dog breed can be made smaller by breeding together only the smallest dogs.

Identical twins are more likely to be about the same height than non-identical twins,

Explanation:

A rocket traveling through space with a constant velocity of 10 m/s fires up a booster. The booster accelerates the rocket at a rate of 5 m/s. What distance in meters has the rocket traveled within 12 seconds after the booster is turned on?​

Answers

The distance traveled by the rocket after the given time period is 480 m.

The given parameters;

velocity of the rocket, v = 10 m/sacceleration of the rocket, a = 5 m/s²time of motion of the rocket, t = 12 s

The distance traveled by the rocket after the given time period is calculated from the second kinematic equation of as shown below;

s = ut + ¹/₂at²

s = (10 x 12) + (0.5 x 5 x 12²)

s = 120 + 360

s = 480 m

Thus, the distance traveled by the rocket after the given time period is 480 m.

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