A farmer can plow a given field in 11 hours. If his son helps him, they can plow the vehicle together in 7 hours. How many hours would it take his son to plow the field alone? Express your answer as a fraction reduced to lowest terms, if needed

Answers

Answer 1

The total number of hours taken by farmer's son to plow the farm is 19 hours.

What is the concept of time and work?

Time refers to the duration of any task or activity that occurs or continues.

Work is a process or set of tasks designed to achieve a specific result.

We can define work happening as follows: - If a person A completes a task in X days, the amount of work finished in 1 day is 1/x.Likewise, if a person B finished work in Y days, his work completed in 1 day will become 1/Y.We can conclude from the preceding two points that A and B can complete (1/(X+Y) amount of work in one day. As a result, A and B could really complete the task in X Y/(X+Y) days.

For, the given question;

Let F be the number of hours taken by farmer to finish the work.

Let S be the number of hours taken by farmer' son to finish the work.

The amount of work finished in 1 hour by farmer is 1/F = 1/11.

The amount of work finished in 1 hour by farmer's son is 1/S.

The amount of work finished by both in 1 hours is;

1/F + 1/S = 1/7

1/S = 1/7 - 1/F

1/S = 1/7 - 1/11

Simplifying the given term;

1/S = 4/77

or, S = 77/4 = 19.25 hours.

S = 19 hours (fraction reduced to lowest terms)

Thus, the time taken by the farmer's son to complete the plow of field is 19 hours.

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Related Questions

Please help!! It’s due today!!

Answers

Answer:

A to B: 4

B to A: 1/4

​​If it is given that m ∠ J K L = m ∠ X Y Z and m ∠ X Y Z = m ∠ Q R S , then concluding that m ∠ J K L = m ∠ Q R S is an example of:

Answers

Concluding that m∠ J K L = m ∠ Q R S is an example of: substitution property of equality

What is Substitution Property of Equality?

The substitution property of equality states that 'If a variable x is equal to another variable y, then x can be substituted in place of y in any equation/expression and y can be substituted in place of x in any equation/expression.

Now, we are told that m ∠ J K L = m ∠ X Y Z and m ∠ X Y Z = m ∠ Q R S.

Thus, concluding that m ∠ J K L = m ∠ Q R S is an example of: substitution property of equality

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Estimate the quotient of
68)6080
Express any remainder beginning with an R.

Answers

The answer in decimals is 89.4117647059

Your final estimated answer is 89 R 28
(aka 89, 28 Remainder)
89 R 28 is the answer to your question


6 less the quantity 9 times a number

Answers

hi

with " x' a number then  :  

6 -9X

Helppp!

h(x)=x^2-6

Evaluate h(-3)

Answers

Answer:

3

Step-by-step explanation:

input -3 into h(x)=x^2-6

h(-3)=-3^2-6=9-6=3

What is the slope of a line parallel to the line whose equation is 2x - 5y = 30. Fully simplify your answer.

Answers

Answer: [tex]\boxed{y=\frac{2}{5} x-7}\ as\ an\ example[/tex]

Step-by-step explanation:

Find the slope-intercept form:

[tex]2x-5y=30\\\\-5y=-2x+30\\\\y=\frac{-2x+30}{-5} \\\\y=\frac{2}{5} x-6[/tex]

Therefore the slope is 2/5

An example of a line parallel to this line is

[tex]y=\frac{2}{5} x-7[/tex]

Under her cell phone plan, Morgan pays a flat cost of $54 per month and $5 per gigabyte, or part of a gigabyte. (For example, if she used 2.3 gigabytes, she would have to pay for 3 whole gigabytes.) She wants to keep her bill under $70 per month. What is the maximum whole number of gigabytes of data she can use while staying within her budget?

Answers

Answer: She can use 4 gigabyte while remaining in her budget.

Step-by-step explanation:

You would first subtract 54  from 70 which leaves you with 16,

Then you would divide 16 by 4 to find how many gigabytes she could use which gives you 4

So she can use 4 gigabyte while remaining in her budget.

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Answer: Answer is 3

Step-by-step explanation:

let the maximum number of gigabytes of data is x

total budget is  $70

then, flat cost is $54 and $5per gigabyte

we get:

54 +5 × x= 70

5x =70 - 54

x = [tex]\frac{16}{5}[/tex]  = 3.2 ≈ 3

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What is the number of combinations on a lock. (for a 40-number lock, no successive repeating numbers)

(permutations or combinations).

Answers

64,000 different combinations
The lock in the challenge requires that you choose from 40 different numbers, three different times. Therefore, there are 40 × 40 × 40, or 64,000 different combinations.
The lock in the challenge requires that you choose from 40 different numbers, three different times. So then there would be 40 × 40 x 40, or 64,000 different combinations.

If f(x) = 2ax + b/x-1, lim x→0 f(x) = -3, lim x→∞ f(x)=4, prove that: f(2)= 11. ​

Answers

If

[tex]f(x) = \dfrac{2ax+b}{x-1}[/tex]

Note that

[tex]f(2) = \dfrac{4a+b}{2-1} = 4a+b[/tex]

From the given information we have

[tex]\displaystyle \lim_{x\to0} f(x) = \lim_{x\to0} \frac{2ax+b}{x-1} = \frac{0+b}{0-1} = -b = -3 \\\\ ~~~~ \implies b=3[/tex]

and

[tex]\displaystyle \lim_{x\to\infty} f(x) = \lim_{x\to\infty} \frac{2ax+b}{x-1} = \lim_{x\to\infty} \frac{2a+\frac bx}{1-\frac1x} = \frac{2a+0}{1-0} = 2a = 4 \\\\ ~~~~ \implies a=2[/tex]

It follows that

[tex]f(2) = 4\cdot2+3 = 11[/tex]

as required.

(3, 4, 5, ...} is finite or infinite

Answers

The given set is (3, 4, 5, ...} is infinite set.

A set with an infinite number of elements is one that cannot be numbered. A set that has no last element is said to be endless. A set that can be put into a one-to-one correspondence with a suitable subset of itself is said to be infinite. No issue with the in-class assignment.

The stars in the clear night sky, water droplets, and the billions of cells in the human body are just a few examples of endless sets of objects that surround us. A set of natural numbers, however, serves as the best illustration of an infinite set in mathematics. There is no limit to the amount of natural numbers.

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What is 5+3 72 times

Answers

Answer: 576

Step-by-step explanation:

5+3 = 8

8*72=576

Answer:576

Step-by-step explanation: just add and multiply

2(x-1)+5(x-9) Show your work please!

Answers

Step-by-step explanation:

2(x-1) + 5(x-9)

2x - 2 + 5x - 45

2x + 5x - 2 - 45

7x - 47

Answer:

2x -2 + 5x -45       7x -47

Step-by-step explanation:

2*x = 2x

2*-1 = -2

5*x =5x

5*-9 = -45

need help on 11-17 pls. Thank u

Answers

11) 58 degrees for both angles
12) 72 and 108 degrees (left to right)
14) b=-3/2
I don’t have the rest I’m sorry

The perimeter of the pentagon below is 63 units. Find the length of side AB.
Write your answer without variables.

Answers

Answer:

15

Step-by-step explanation:

The sides add to 63, so:

[tex]11+3x+11+x+2+2x+3=63 \\ \\ 6x+27=63 \\ \\ 6x=36 \\ \\ x=6 \\ \\ \implies AB=2(6)+3=15[/tex]

Which is true?
5/4 > 5/6
3/3 > 4/3
3/3 < 3/6

Answers

Answer:

5/4 > 5/6

Step-by-step explanation:

Find the smallest value of k if 360k is a perfect square

Answers

Answer:

k = 1

Step-by-step explanation:

since 360 = 60² , a perfect square , then

360 × 1 ← is a perfect square

that is 360k with k = 1 is a perfect square

Convert the following temperatures from Fahrenheit to Celsius or vice versa.
C= F-32/1.8
F = 1.8C+32
a. 50°F
b. 75°C
c. -40°C

Answers

Answer:

10°C

Step-by-step explanation:

c = [tex]\frac{F - 32}{1.8}[/tex]  Plug in 50 for F and solve for C

c = [tex]\frac{50-32}{1.8}[/tex]

C = [tex]\frac{18}{1.8}[/tex] Divide

c = 10

Sterling already owes his parents $40. He asks to borrow money from them to purchase candy bars for his friends that cost $1.50 each. The rule in Sterling's house is that he can owe his parents no more than $50. How many candy bars can he purchase and still stay within the maximum borrowing amount?

Answers

Answer: 6

Step-by-step explanation: 6 because then he would owe his parents 49 dollars

Round 1803.2684 to the nearest thousandth

Answers

Answer:

1,803.268

Step-by-step explanation:

so thousandths place is three number after the decimal just see the fourth number after the decimal and if it 5 or greater round the (in this case) 8 but since the fourth number was 4 it stays the same but only three numbers

1803.268
The third number after the decimal is the thousandth place meaning you need to round the 8. Since the last number is under 5 you round down

-4 + (-19) = ? I need a answer

Answers

Answer: - 23

Step-by-step explanation:

Hope this helps!

The point N lies on the segment MP.
Find the coordinates of N so that the ratio of MN to NP is 6 to 1.
M(-13, 20)
N (?, ?)
P(1-1)

Answers

If the point N lying on the Line segment MP, divides MP such that the ratio of MN to NP is 6 to 1, and the coordinates of M(-13, 20) and P(1-1), then the coordinates of "N" is

As per the question statement, N lying on the Line segment MP, divides MP such that the ratio of MN to NP is 6 to 1.

We are required to find out the coordinates of "N".

To solve this question, we need to know the formula to calculate the coordinates of a point (Say "c") that divides a line segment AB in the ratio of (m:n).

The formula goes as:

Abscissa of c [tex](x_{3})=\frac{mx_{2}-nx_{1} }{m-n}[/tex]

and, Ordinate of c [tex](y_{3})=\frac{my_{2}-ny_{1} }{m-n}[/tex]

where, [tex](x_{1}, y_{1})[/tex] are the coordinates of point A, while

[tex](x_{2}, y_{2})[/tex] are the coordinates of point B.

Using our given data in the above formulae, we get

Abscissa of N =  [tex]\frac{(6*1)-[1*(-13)]}{6-1} =\frac{6-(-13)}{5}=\frac{6+13}{5}=\frac{19}{5}[/tex]

And, Ordinate of N = [tex]\frac{[6*(-1)-(1*20)}{6-1} =\frac{(-6)-20}{5}=\frac{-(20+6)}{5}=\frac{-26}{5}[/tex].

Hence, our concerned point N = [tex](\frac{19}{5}, \frac{-26}{5})\\[/tex].

Line Segment: In Euclidean geometry, a line segment is a part of a straight line that is bounded by two distinct end points, and contains every point on the line that is between its endpoints and it's length is given by the Euclidean distance between its endpoints.

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Which measurement is closet to the lateral surface area in square centimeters of the cylinder?

H = 7.6

B = 5.8

Answers

A. 164.9 cm (2)

B. 277.0 cm (2)

C. 138.5 cm (2)

D. 191.3 cm (2)

Answers

The value closest to the lateral area of the cylinder is 138. 5cm^2. Option C

How to determine the value

The formula for determining the lateral area of a cylinder is expressed as;

Lateral area = 2 πrh

Where;

r is the radiush is the height of the cylinder

Note that radius is half the diameter;

radius, r = 5. 8/ 2 = 2. 9 cm

Substitute into the formula

Lateral area = 2 ( 3. 142 × 2. 9 × 7. 6)

Lateral area = 2 ( 69. 249)

Lateral area = 138. 49 cm^2

Thus, the value closest to the lateral area of the cylinder is 138. 5cm^2. Option C

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26.
12/2(x+6)=2x-9
21

Answers

[tex]\frac{12}{2} (x+6)=2x-9[/tex]

[tex]6x+36=2x-9[/tex]

[tex]6x - 2x = -9 + 36[/tex]

[tex]4x = -45[/tex]

[tex]x = -\frac{45}{4}[/tex]

Hope that I helped you!


An 8-ounce cup of juice costs $1.20. A 12-ounce cup of the same juice costs
$1.44. Can the relationship between cost and ounces of juice be described
by a constant rate? Explain.

Answers

Answer: It can.

Step-by-step explanation:

If an 8 oz. cup of juice cost $1.20 and a 12 oz. cup of juice cost $1.44, there is a $0.24 difference between the money and cups of juice in ounces. If there were to be a constant rate of change, a 16 oz. cup of juice MUST cost $1.68

No, the relationship between cost and ounces of juice cannot be described by a constant rate.

What is Algebra?

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

We are given that;

Cost of 8 ounce juice= $1.20

Cost of 12 ounce juice= $1.44

Now,

If the relationship between cost and ounces of juice was described by a constant rate, then the cost per ounce would be the same for both the 8-ounce cup and the 12-ounce cup. However, we can see that the cost per ounce is different for each cup:

For the 8-ounce cup: cost per ounce = $1.20 / 8 ounces = $0.15 per ounce

For the 12-ounce cup: cost per ounce = $1.44 / 12 ounces = $0.12 per ounce

Therefore, by algebra the cost per ounce is different for each cup, the relationship between cost and ounces of juice cannot be described by a constant rate.

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The reading on a mercury manometer at 25 C ( open to the atmosphere at one end ) is 56.38 cm the local acceleration of gravity is 9.832m.s^-2 atmospheric pressure is 101.78kpa what is the absolute pressure in kpa being measured? The density of mercury at 25 C is 13.534 g.cm^-3

Answers

If the reading on a mercury manometer at 25 C is 56.38 cm the local acceleration of gravity is 9.832m.s^-2 atmospheric pressure is 101.78kpa The absolute pressure in kpa being measured is: 176.803kPa.

Absolute pressure

Using this formula

Pabs=Pg+Patm

Where:

Pabs= Absolute pressure.

Patm=Atmospheric pressure

ρm=Density of mercury

g=Acceleration of gravity

h=Reading on a mercury manometer

Let plug in  the formula

Pabs=101.78×10³Pa+( 13.534×10³kg/m×9.832 m/s²×0.5638 m.

Pabs=101.78×10³Pa+75.023×10³kg/m.s²

Pabs=101.78×10³Pa+75.023×10³Pa

Pabs=176.803×10³Pa

Pabs=176.803kPa

Therefore If the reading on a mercury manometer at 25 C is 56.38 cm the local acceleration of gravity is 9.832m.s^-2 atmospheric pressure is 101.78kpa The absolute pressure in kpa being measured is: 176.803kPa.

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Determine if the following relations represent a function
1. {(-1, -2), (0, -2), (1, -2), (2, -2)}
2. {(1, 0), (1,1), (1, 2), (1, -2)}

Answers

1) Yes, because each value of x maps onto only one value of y.

2) No, because the x-value of 1 maps onto 4 different y values.

Answer:

yes, a function.no, not a function.

Step-by-step explanation:

You want to know if the given sets of ordered pairs represent a function.

Function

A function is a relation that maps an input value to a single output value. On a graph, this means no two points are vertically aligned. For a table or set of ordered pairs, it means no input (x) value is repeated.

1.

The input (x) values are {-1, 0, 1, 2} with no repeats. This relation is a function.

2.

The input values are {1, 1, 1, 1} with repeats. This relation is not a function.

Alonso's family rented a car when they flew to
Orlando for a 4-day vacation. They paid $39
per day and $0.09 for each mile driven. How
much did it cost to rent the car for 4 days and
drive 350 miles, not including tax?

Answers

Answer:

$187.5

Step-by-step explanation:

39 (4) + 0.09 (350)

156 + 31.5

$187.5

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Answer:

$187.5

Step-by-step explanation:

You need to multiply the daily cost by the days. In this case, 39*4 = 156. Then, we can get the cost for the miles driven, being 0.09*350 = 31.5.

We can now add the two numbers together:

156 + 31.5 = $187.5

A bowl weighs 11/40 pound express this weight as a decimal

Answers

Answer:

0.275 lb

Step-by-step explanation:

Use a calculator to divide 11 by 40.

11/40 = 0.275

Answer:

0.275 pounds

Step-by-step explanation:

divide 11 (numerator) by 40 (denominator).

what is the slope of a line parallel line whose equation is 5x-2y=2

Answers

The slope of the given line and a line parallel to it is
5
2
.
Explanation:
Given:
5
x

2
y
=
11
is the standard form of a linear equation.
A line parallel to this line has the same slope. To determine the slope, solve for
y
to change the equation to slope-intercept form:
y
=
m
x
+
b
,
where:
m
is the slope and
b
is the y-intercept.
5
x

2
y
=
11
Subtract
5
x
from both sides.

2
y
=

5
x
+
11
Divide both sides by

2
.
y
=

5

2
x
+
11

2
Simplify.
y
=
5
2
x

11
2
The slope of the given line and a line parallel to it is
5
2
.

[tex] \boxed{\begin{gathered} \rm Let \: \psi_1 : [0, \infty ) \to \mathbb{R} , \psi_2 : [0, \infty ) \to \mathbb{R},f :[0, \infty )\to \mathbb{R} \: and \: g :[0, \infty) \to \mathbb{R} \: be \\ \rm functions \: such \: that \: f(0) = g(0) = 0, \\\\ \rm \psi_{1}(x) = {e}^{ - x} + x, \: \: x \geq0, \\ \rm \psi_{2}(x) = {x}^{2} - 2x - 2 {e}^{ - x} + 2, \: \: x > 0, \\ \rm f(x) = \int_{ - x}^{x} ( |t| - {t}^{2} ) {e}^{ - {t}^{2} } \: dt, \: \: x > 0 \\\\ \rm g(x) = \int_0^{ {x}^{2} } \sqrt{t} \: {e}^{ - t} \: dt, \: \: x > 0 \end{gathered}}[/tex]

Which of the following is True?
[tex] \rm (A) \: \rm \: f ( \sqrt{ \ln 3 } )+ g( \sqrt{ \ln3} ) = \dfrac{1}{3} [/tex]
(B) For every x>1, there exists an α ∈ (1,x) such that ψ₁(x)=1+ax

(C) For every x>0, there exists a β ∈ (0,x) such that ψ₂(x)=2x(ψ₁(β)-1)

(D) f is an increasing function on the interval [tex] \bigg [0 , \dfrac{3}{2} \bigg][/tex] ​

Answers

(A) is false. By symmetry,

[tex]\displaystyle f(x) = \int_{-x}^x (|t|_t^2) e^{-t^2} \, dt = 2 \int_0^x (t-t^2) e^{-t^2} \, dt[/tex]

where [tex]|t|=t[/tex] since [tex]x>0[/tex]. Substitute [tex]s=t^2[/tex] to get the equivalent integral,

[tex]\displaystyle f(x) = \int_0^{x^2} (1 - \sqrt s) e^{-s} \, ds[/tex]

Then

[tex]\displaystyle f(x) + g(x) = \int_0^{x^2} e^{-s} \, ds[/tex]

[tex]\displaystyle f(\sqrt{\ln(3)}) + g(\sqrt{\ln(3)}) = \int_0^{\ln(3)} e^{-s} \, ds = \frac23 \neq \frac13[/tex]

(B) is false. Note that [tex]1+\alpha x[/tex] is linear so its derivative is the constant [tex]\alpha[/tex] at every point. We then have

[tex]{\psi_1}'(\alpha) = -e^{-\alpha}+1 = \alpha \implies 1-\alpha = e^{-\alpha}[/tex]

But this has no solutions, since the left side is negative for [tex]\alpha>1[/tex] and the right side is positive for all [tex]\alpha[/tex].

(C) is true. By the same reasoning as in (B), the line [tex]2x(\psi_1(\beta)-1)[/tex] has constant derivative, [tex]2\psi_1(\beta)-2 = 2e^{-\beta+2\beta-2[/tex]. Then

[tex]{\psi_2}'(\beta) = 2\beta-2+2e^{-\beta} = 2e^{-\beta}+2\beta-2[/tex]

holds for all values of [tex]\beta[/tex].

(D) is false. We use the first derivative test. By the fundamental theorem of calculus,

[tex]\displaystyle f(x) = 2 \int_0^x (t-t^2)e^{-t^2}\,dt \implies f'(x) = 2(x-x^2)e^{-x^2}[/tex]

Solve for the critical points.

[tex]f'(x) = 0 \implies x-x^2 = 0 \implies x = 0 \text{ or } x = 1[/tex]

[tex]e^{-x^2}>0[/tex] for all [tex]x[/tex], so the sign of [tex]f'[/tex] depends on the sign of [tex]x-x^2[/tex]. It's easy to see [tex]f'>0[/tex] for [tex]x\in(0,1)[/tex] and [tex]f'<0[/tex] for [tex]x\in\left(0,\frac32\right)[/tex]

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