a. during the phase of full moon, what phase would you see for earth? would it be daylight or dark where you live?

The tilt of Earth's axis causes the ecliptic to intersect the celestial equator at two points, creating the seasons.

The ecliptic is the unmistakable method of the Sun on the heavenly circle as seen from Earth. It isn't concurred with the magnificent equator, which is the projection of the World's equator onto the heavenly circle, considering the way that the World's center is moved by around 23.5 degrees relative with the plane of its circle around the Sun. Consequently, over the range of a year, the World's Northern and Southern Parts of the globe then again slant towards and away from the Sun, causing the seasons. The ecliptic meets the eminent equator at two spots, known as the equinoxes, where the length of every day of the week is generally same. The inclination of the World's turn, got together with the World's circle around the Sun, prompts the changing seasons and the moving spot of the ecliptic near with the superb equator.

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During the brief time interval when the elevator is descending with free-fall acceleration, the scale would show your weight to be zero.

Free-fall acceleration is the acceleration that an object experiences due to the force of gravity, assuming no other forces are acting on the object. In the absence of air resistance or any other resistance, all objects near the surface of the Earth, regardless of their mass or composition, will experience the same constant free-fall acceleration due to gravity, which is denoted by the symbol "g" and has a value of approximately 9.8 meters per second squared (m/s²) or 32.2 feet per second squared (ft/s²).

This means that if an object is dropped from rest near the surface of the Earth, it will fall with a constant acceleration of g, and will increase its velocity by 9.8 m/s or 32.2 ft/s every second. Similarly, if an object is thrown upwards, it will experience a deceleration of g due to gravity until it comes to rest at the highest point of its trajectory, after which it will begin to fall downwards with free-fall acceleration.

If the elevator is in free-fall acceleration, it means that the only force acting on you is the force due to gravity, and there is no normal force acting on you from the scale. In this case, according to Newton's second law of motion, your weight is equal to the force due to gravity acting on your mass.

So, during the brief time interval when the elevator is descending with free-fall acceleration, the scale would show your weight to be zero. This is because your body is in a state of weightlessness, as you and the scale are accelerating downwards at the same rate.

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The weight of the copper sheet is approximately 6.21 newtons.

Newtons are a unit of measurement used to quantify force in the International System of Units (SI). One newton is defined as the amount of force required to accelerate a mass of one kilogram at a rate of one meter per second squared.

In simpler terms, if a force is applied of one newton to an object with a mass of one kilogram, the object will accelerate at a rate of one meter per second squared.

The symbol for newton is N, and it is named after Sir Isaac Newton, the famous physicist and mathematician who formulated the laws of motion. Newtons are commonly used in physics, engineering, and other sciences to describe the amount of force acting on an object.

To find the weight of the copper sheet, one has to know its mass and the acceleration due to gravity, which is approximately 9.81 m/s^2.

The volume of the sheet can be found by calculating the volume of the cylinder with height equal to the thickness of the sheet: V = πr^2h = π(15 cm)^2(0.1 cm) = 70.69 cm^3

Next, calculate the mass of the copper sheet, which can be found by multiplying its volume by its density. The density of copper is approximately 8.96 g/cm^3:

Finally, find the weight of the copper sheet by multiplying its mass by the acceleration due to gravity:

Therefore, the weight of the copper sheet is approximately 6.21 newtons.

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The symmetric peak divides the lights of short wavelength and long wavelength lights, which occurs at the green light boundary.

A symmetric peak refers to a peak that is roughly the same shape on both sides of the highest point. This means that the left and right sides of the peak are mirror images of each other.

Symmetric peaks are often seen in graphs or charts that represent data such as intensity versus wavelength graph as shown in the diagram.

At the the symmetric peak, the wavelength of the particle is 500 mm which corresponds to wavelength of green light.

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The induced EMF is-0.45V and the induced current for the first and third intervals is -0.9A.

the slope of B vs t gives the dB/dt

from the relation emf = NAdB/dt

a) from 0 to 3 s

dB/dt = 0.4-0/(3-0) = 0.133 T/s

emf = 48*0.14*0.133 = 0.894 V

for 3 to 6 sec

dB/dt = 0 (slope is zero)

emf = 0

for 6 to 9 sec

dB/dt = (0.2-0.4)/(9-6) = -0.067 T/s

emf = 48*0.14(-0.067) = -0.45 V

b) if R = 0.5 ohm

current i = 0.894/0.5 = 1.788 A

for 6 to 9 sec

i = -0.45/0.5 = -0.9 A

Induced EMF (Electromotive Force) is the voltage or potential difference that is generated in a conductor when it is exposed to a changing magnetic field. This is due to Faraday’s Law of Electromagnetic Induction, which states that a time-varying magnetic field induces an electric field in a conductor.Induced EMF is the basis for the operation of many electrical devices such as generators and transformers.

Generators convert mechanical energy into electrical energy through the use of induced EMF, while transformers use it to change the voltage and current levels of an AC power system.When a conductor is placed in a magnetic field and the field strength or direction changes, it causes the magnetic flux through the conductor to change.

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Complete Question: -

A magnetic field passes through a stationary wire loop, and its magnitude changes in time according to the graph in the drawing. The direction of the field remains constant, however. There are three equal time intervals indicated in the graph: 0 – 3.0 s, 3.0 – 6.0 s, and 6.0 – 9.0 s. The loop consists of 48 turns of wire and has an area of 0.14 m2. The magnetic field is oriented parallel to the normal to loop. (a) For each interval, determine the induced emf. (b) The wire has a resistance of 0.50 Ω. Determine the induced current for the first and third intervals.

When the spring reaches its equilibrium length, or the point at which all the energy stored in the spring is transferred to kinetic energy, the block moves at its fastest speed. Since the object is at rest when it starts, Ki = 0.

When a spring is compressed or extended to a length that differs by an amount x from its equilibrium length, it produces a force F = -kx that pushes it back towards its equilibrium position. A spring's force works as a restoring force, bringing the spring back to its equilibrium length.

Simply divide the weight you will be placing on your spring by the amount of movement or compression you anticipate from your spring as a result of that load.

Therefore, When the box is dropped from a larger height, the spring will compress further since the box will have more energy. enabling it to compress the spring more forcefully.

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The centripetal force required for a planet to revolve in a circular motion around the sun is provided by the sun's gravitational pull on the planet. The round motion of the planet is caused by the centripetal force, which is always pointed in the direction of the sun's center at every point of its course.

The force of gravity accelerates items as they descend to the ground. Velocity is a measure of the speed and direction of motion, and acceleration is a change in velocity. The longer an object is in free fall, the faster it descends towards the ground due to gravity.

A planet needs to accelerate towards the circle's centre in order to travel in a curved route. Centripetal acceleration, which is provided by the gravitational attraction of the sun and the planet, is what causes this.

Therefore, yes, change in direction is acceleration.

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The direction of the force on the particle due to the magnetic field a charged particle is moving is perpendicular to the plane.

Glamorous fields ply forces on moving charges. This force is one of the most introductory known. The direction of the glamorous force on a moving charge is vertical to the aeroplane formed by v and B and follows right hand rule – 1( RHR- 1). The magnitude of the force is commensurable to q, v, B, and the sine of the angle between v andB.

still, or is zero, the glamorous force will be zero, If the flyspeck haste happens to be aligned resemblant to the glamorous field. This differs from the case of an electric field, where the flyspeck haste has no bearing, on any given moment, on the magnitude or direction of the electric force.

The angle dependence of the glamorous field also causes charged patches to move vertical to the glamorous field lines in a indirect or spiral fashion, while a flyspeck in an electric field will move in a straight line along an electric field line.

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The resultant force acting on the door at an altitude of 10 km is 115.2 kilonewtons (kN).

The pressure inside an aircraft is kept at 80 kilopascals (kPa) and the doors have an area of 2 square meters (m²).

The atmospheric pressure at an altitude of 10 kilometers (km) is much lower. To calculate the difference in pressure, we need to know the atmospheric pressure at that altitude.

At an altitude of 10 km, the atmospheric pressure is around 22.4 kPa, which is much lower than the pressure inside the aircraft.

The difference in pressure can be calculated as 80 kPa - 22.4 kPa = 57.6 kPa.

The force acting on the door can be calculated using the equation:

Force = Pressure x Area

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The kinetic energy of each ejected electron is 3.31 x 10⁻⁴² J/electron, and its velocity is 8.51 x 10³ m/s.

Minimum thermodynamic work needed to remove electron from solid to the point in vacuum immediately outside the solid surface is called work function.

E = hf

hc/λ = hf + Φ

K.E. = hf - Φ

E is energy of a photon, h is Planck's constant, f is frequency of the photon, c is speed of light, λ is wavelength of the photon, Φ is work function, K.E. is kinetic energy of  ejected electron.

E = hf = Φ + hc/λ

hf = Φ + hc/λ

f = (Φ + hc/λ) / h

E = hc/λ = h((Φ + hc/λ) / h) = Φh/h + hc/λh

E = Φ + hc/λ

Given, Φ = 483.4 kJ/mol photons = (483.4 kJ/mol photons) / (6.022 x 10²³ photons/mol) = 8.03 x 10⁻¹⁹ J/photon

c = 3.00 x 10⁸ m/s h = 6.626 x 10⁻³⁴ J·s  λ = 225.0 nm = 225.0 x 10⁻⁹ m

So, E = Φ + hc/λ = (8.03 x 10⁻¹⁹ J/photon) + (6.626 x 10⁻³⁴ J·s x 3.00 x 10⁸ m/s) / (225.0 x 10⁻⁹ m) = 2.79 x 10⁻¹⁸ J/photon

K.E. = hf - Φ = E - Φ

K.E. = (2.79 x 10⁻¹⁸ J/photon) - (8.03 x 10⁻¹⁹ J/photon) = 1.99 x 10⁻¹⁸  J/photon

K.E. = (1.99 x 10⁻¹⁸  J/photon) / (6.022 x 10²³ photons/mol) = 3.31 x 10⁻⁴² J/electron

K.E. = 1/2 mv²

m = 9.109 x 10⁻³¹ kg

K.E. = 3.31 x 10⁻⁴² J/electron

3.31 x 10⁻⁴² J/electron = 1/2 (9.109 x 10⁻³¹ kg) v²

v² = (2 x 3.31 x 10⁻⁴² J/electron) / (9.109 x 10⁻³¹ kg)

v^2 = 7.26 x 10⁷ m²/s²

v = √(7.26 x 10⁷m²/s²) = 8.51 x 10³ m/s

Therefore, the kinetic energy of each ejected electron is 3.31 x 10⁻⁴²J/electron, and its velocity is 8.51 x 10³ m/s.

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Dark nebulae are thought not to contain stellar nurseries because they are primarily composed of gas and dust, which are the building blocks of stars, but they are too cold and dense to collapse and form stars.

A nebula is a distinctively luminous region of the interstellar medium, which may be made up of cosmic dust, neutral, neutrally ionized, or molecular hydrogen.

Because dark nebulae are predominantly made of gas and dust, the raw materials for stars, but are too cold and dense to collapse into stars, it is believed that they do not contain stellar nurseries.

In other words, the gas and dust in a black nebula are not in an ideal environment to start the star-forming process.

The quantity of light that is accessible for star formation may be diminished by the dust particles in dark nebulae that can absorb and scatter light.

Thus, despite the fact that black nebulae may contain a lot of gas and dust, they are not suitable for the formation of new stars, and are unlikely to contain stellar nurseries.

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The type of orbital fracture described in the question is commonly referred to as a "blowout fracture."

This occurs when the eye experiences a blunt force trauma, such as being hit with a ball or fist. The force of the impact causes the contents of the eye socket (orbit) to be displaced posteriorly, potentially causing damage to the muscles and nerves that control eye movement. This can also create a sudden increase in pressure within the orbit that can lead to a fracture of the orbital floor, which is the bony structure at the bottom of the eye socket. The term "blowout" refers to the fact that the force of the impact causes the orbit to "blow out" at its weakest point, typically the orbital floor. The type of orbital fracture described in the question is commonly referred to as a "blowout fracture."  

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Two like masses are attracted to one another by gravitational forces.

Is the force of gravitation between two masses always alluring?

Any two bodies in our world will gravitationally attract one another, according to Newton's law of gravitation. Therefore, the gravitational attraction between two masses is constant.

The gravitational force created by one mass would be better represented by the electromagnetic field of a negative charge. This is thus because both the field representation of a negative charge and the gravitational force between two masses are attractive forces. When placed in an electric field, a positive charge will often move in the direction of the electric field lines, while a negative charge would typically move in the opposite way.

When a positive charge and a negative charge interact, their forces move from the positive to the negative charge in the same manner. The electric field and consequent forces produced by two electrical charges of opposing polarity cause opposite charges to attract one another. Compared to gravitational forces, electrostatic forces are substantially stronger. This is due to the fact that gravity is dependent on mass, and since atoms have such little masses, there is almost no gravitational pull between them. The electrostatic force, however, is greater when there are charges present.

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We observe an absorption line spectrum when white light travels through a cold cloud of gas.

The atmosphere's gas scatters some of the light at particular wavelengths, resulting in darker bands. When common materials were heated, light waves that later came to be known as "spectral lines" were produced and recorded.

Spectrum of Absorption: Part of the starlight that travels through a cloud of gas is absorbed while some of it is transmitted through the gas. T Depending on which elements are involved, different light wavelengths are absorbed.

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The linear velocity at a point on the edge of the object is π/450 meters per second. One revolution per hour is equivalent to 1/3600 revolutions per second (since there are 3600 seconds in an hour).

To convert revolutions per second to radians per second, we need to multiply by 2π since there are 2π radians in one revolution. So, 1/3600 revolutions per second is equal to (1/3600) * 2π radians per second, which simplifies to π/1800 radians per second. To find the linear velocity at a point on the object's edge, we can use the formula: v = ωr; where v is the linear velocity, ω is the angular velocity (in radians per second), and r is the radius of the object.

In this case, the radius is 4m, and we just found that the angular velocity is π/1800 radians per second. So, we can plug these values into the formula to get: v = (π/1800) * 4

Simplifying this expression gives: v = π/450 m/s

So, the linear velocity at a point on the object's edge is π/450 meters per second.

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The height of the building if a ball is thrown upwards at 6m/s from the top of the building is 102.48m.

The height of the building in this question can be calculated using one of the equations of motion as follows:

s = ut + ½at²

Where;

According to this question, a ball is thrown upwards at 6.00 m/s from the top of a building. If the ball hits the ground 4.00 seconds after you throw the ball, the height can be calculated as follows:

s = 6 × 4 + ½ × 9.81 × 4²

s = 24 + 78.48

s = 102.48m

Therefore, 102.48m is the height of the building.

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To appear as though the sun is stationary with respect to the passengers, the plane must travel at a speed of about 1670 km/h along the equator of the planet.

How fast must the plane fly in order to make the sun appear to be stationary in the sky? is the query. This is the same as the plane moving in such a way that it cancels out the Earth's axis rotation, which causes the sun to appear to move across the sky.

At the equator, the Earth's circumference is around 40,000 km, and it rotates once every 24 hours. This indicates that the linear speed of a place on the equator of the Earth is roughly 1670 km per hour. So, in order to make the sun appear, the plane must fly at this speed in the same direction as the Earth's rotation, or to the east.

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The correct answer is option b) high temperatures correspond to faster average molecule speeds.

The term "average molecule speed" describes the typical speed of a gas's molecules. The root-mean-square (rms) velocity formula can be used to determine the average speed of all the molecules in a gas. Individual molecules in a gas move at different speeds as a result of collisions with other molecules.

[tex]\sqrt{3kT/m} = v[/tex]

Where T is the gas's temperature in kelvins, v is the gas molecules' average speed, k is the Boltzmann constant, and m is the mass of a single gas molecule.

The relationship between the gas's molecular mass, pressure, and temperature govern the average molecule speed. The Maxwell-Boltzmann distribution states that as the gas's temperature rises, so does its average molecular speed. Similar to this, while temperature and pressure are constant, gases with lower molecular masses move molecules more quickly on average than gases with greater molecular masses.

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Without additional context, it is difficult to determine the direction of the missing electric field vector on the front face. The direction of the electric field vector depends on the charge distribution and the boundary conditions of the problem

What is Electric Field?

An electric field is a region of space around an electric charge or group of charges where other charges experience a force. The electric field is a vector field, which means that at every point in space, it has both a magnitude and a direction. The strength of the electric field at a point is determined by the magnitude and distribution of the charges that create the field.

An electric field can be visualized by imagining a small positive test charge placed at a point in space, and then observing the direction and magnitude of the force that the test charge experiences due to the presence of other charges in the system. The direction of the electric field at a point is defined as the direction of the force that a positive test charge would experience if placed at that point.

In general, the direction of the electric field vector at a given point is defined as the direction of the force that a positive test charge would experience if placed at that point. If the charge distribution on the front face is such that it would attract a positive test charge, then the electric field vector would point inward toward the face. Conversely, if the charge distribution would repel a positive test charge, then the electric field vector would point outward away from the face.

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When a star is rising straight up in the east, it will be high in the south when it is at its peak point over the horizon.

In both hemispheres, the star ascends in the east and sets in the west. This results from the rotation of the earth. Also, they circle the north celestial pole in a clockwise way whereas the south celestial pole is in a counterclockwise direction.

Nonetheless, the south celestial pole will be visible above the southern horizon at an angle proportional to your latitude. Toward the northern sky, rising stars in the east will go higher and to the left. As you travel farther south, the celestial equator will likewise pass across the northern sky, getting progressively lower.

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The amount of heat required to vaporize a certain amount of water is given by:

Q = ml

where Q is the amount of heat, m is the mass of water, and l is the specific latent heat of vaporization.

In this case, the heat energy supplied to the water is:

Q = Pt

where P is the power supplied and t is the time taken.

Since the water is at its boiling point, its temperature remains constant while it is vaporizing. Therefore, the energy supplied to the water is solely used for vaporization.

Equating the two expressions for Q, we have:

Pt = ml

Solving for t, we get:

t = ml / P

where m = 250 g and l = 2260 J/g.

Substituting the values, we get:

t = (250 g) x (2260 J/g) / (3000 W) = 0.1883 hours

Converting to minutes, we have:

t = 0.1883 hours x (60 minutes/hour) = 11.3 minutes (approx.)

Therefore, it will take approximately 11.3 minutes for 250 g of water to vaporize.

Every new and full moon, when the sun, moon, and earth are in alignment, spring tides occur. When lunar and solar tides align, they reinforce one another and create a larger overall tidal.

The Earth's tides are significantly influenced by the elliptical orbits of the moon around the planet and the planet around the sun. The largest spring tides happen when the moon is close to perigee and the sun is close to perihelion.

Every month, at perigee, when the moon is closest to Earth, tidal-generating forces are stronger than usual, resulting in tide ranges that are higher than typical.

Therefore, When the sun, earth, and moon are at a straight angle and the moon is in its first or third quarter, neap tides happen.

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The type of radioactivity that has a negative charge is beta rays.

Alpha rays consist of particles which have two protons and two neutrons identical to a positively charged helium nucleus. They get attracted towards the negatively charged plate as they possess a charge of +2. They have very high ionization power.

Beta radiation has a negative charge because it contains particles similar to an electron. It contains the same mass as an electron, and the mass is lower than proton and neutron masses. Also, each particle contains a single negative charge, making the radiation negatively charged.

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Approximately 1.12 x 10^18 electrons would have to pass through the given point in a wire in 3.00 seconds to produce a current of 60 mA.

Electrons are subatomic particles that have a negative charge and are fundamental components of atoms. They are located in shells or orbitals around the atomic nucleus and play a crucial role in many physical and chemical processes.

Electrons are the carriers of electric charge in materials and are responsible for the flow of current in electrical conductors. They also play a key role in chemical bonding and reactions, as they are involved in the sharing and transfer of electrons between atoms.

Electrons are extremely small and have a mass of approximately 9.11 x 10^-31 kilograms, which is about 1/1836th the mass of a proton.

To determine the number of electrons that pass through a given point in a wire, we can use the equation:

I = Q/t

where I is the current in amperes, Q is the charge in coulombs, and t is the time in seconds.

We can rearrange this equation to solve for the charge Q:

Q = I*t

Now, use the elementary charge of an electron, which is approximately 1.602 x 10^-19 coulombs, to calculate the number of electrons that pass through the wire in 3.00 seconds:

Q = (60 mA) * (3.00 s) = 0.18 C

Number of electrons = Q / e = 0.18 C / (1.602 x 10^-19 C/e) = 1.12 x 10^18 electrons

Therefore, approximately 1.12 x 10^18 electrons would have to pass through the given point in the wire in 3.00 seconds to produce a current of 60 mA.

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The charge will not change if the capacitor is not connected to the battery. When the plates of a capacitor are shifted further apart, the capacitance Cd1 drops.

The energy stored by capacitor U(=2Cq) grows when the battery is disconnected because the charge on the capacitor stays constant.

The capacitor, which we were informed was entirely depleted, has zero voltage across it when the switch is first closed, making it appear as though there is a short circuit.

The capacitor will eventually operate as an open circuit because the voltage of the capacitor will eventually equal the voltage of the battery.

Therefore, after a capacitor is simply connected across a battery, its voltage will be the same as the battery terminal voltage when the battery is disconnected, and it will have an energy reserve equal to capacitance times voltage divided by two.

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The statement C is True, a projectile is fired at an angle upward from the horizontal such that the initial horizontal and vertical components of its velocity are both non-zero at the highest point in the motion, the horizontal component of the velocity is zero.

A projectile is any object that is thrown or launched into the air and follows a path determined by the forces acting upon it, such as gravity and air resistance. The motion of a projectile is characterized by two components: horizontal motion and vertical motion. The horizontal motion is constant and is not affected by gravity, while the vertical motion is determined by the acceleration due to gravity.

Projectile motion can be analyzed using mathematical equations and is important in fields such as physics, engineering, and sports. For example, in sports such as basketball and football, the trajectory of a ball being thrown or kicked is a projectile. In engineering, projectile motion is used to design rockets and missiles that are launched into space or aimed at specific targets.

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The required charge density on the conducting sphere is calculated to be 136.23 × 10⁻⁹C/m²

The radius of the conducting sphere is given as 6.5 cm = 0.065 m

The voltage of the power supply is 1000 v.

The expression to calculate the surface area of the sphere is known to be,

A = 4 π r²

Putting the values, we have,

A = 4 π (0.065)² = 0.053 m²

The relation to find out charge on the sphere is known to be,

Q = r V/k

where,

r is radius of sphere

k is Coulomb's constant (9 × 10⁹ N m²/C)

V is voltage

Entering the numbers, we have,

Q = r V/k = 0.065(1000)/(9 × 10⁹) = 7.22 × 10⁻⁹ C

Charge density is given by the expression,

ρ = Q/A = 7.22 × 10⁻⁹/0.053 = 136.23 × 10⁻⁹ C/m²

Thus, the charge density is calculated to be 136.23 × 10⁻⁹C/m².

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The resistance of the wire will increase by a factor of 8.

When the length of a wire is doubled, its resistance also doubles because resistance is directly proportional to the length. On the other hand, when the diameter of the wire is halved, the cross-sectional area of the wire reduces by a factor of 4 (πr^2 -> π(r/2)^2). As a result, the resistance decreases by a factor of 1/4.

So, when both changes are made, the resistance of the wire increases by a factor of 8 (2 x 4). This is because the effect of doubling the length is greater than the effect of halving the diameter. Thus, the net effect is an increase in resistance. This relationship between resistance, length, and cross-sectional area is described by the formula for resistance, which is R = ρL/A, where R is the resistance, ρ is the resistivity of the material, L is the length of the wire, and A is its cross-sectional area.

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If today the sun appears to be located in the middle of the constellation Virgo. therefore, tomorrow the sun will be in the constellation Virgo. Hence, option D is correct.

An arrangement of stars is a constellation. Others have observed patterns in the stars that are used to classify the groups. A lion's form, for instance, appears to be traced by the stars of the constellation Leo.

The western zodiac consists of the 12 constellations Aries, Taurus, Gemini, Cancer, Leo, Virgo, Libra, Scorpio, Sagittarius, Capricorn, Aquarius, and Pisces is one constellation tradition.

Thus, if today the sun appears to be located in the middle of the constellation Virgo. Then, tomorrow the sun will be in the constellation Virgo. Hence, option D is correct.

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The sensor should say that the goalkeeper absorbed about 216.998 J of energy when blocking the soccer ball, not accounting for wind and drag.

To calculate the energy absorbed by the goalkeeper, we can use the law of conservation of energy, which states that the initial energy of the ball before the kick is equal to the sum of the kinetic and potential energy after the kick and after the ball is blocked by the goalkeeper. We can assume that the ball is initially at rest before the kick, so the initial energy is zero.

The final kinetic energy of the ball after the kick can be calculated as:

[tex]KE1 = (1/2)mv1^2[/tex]

where m is the mass of the ball (converted to kg) and v1 is the velocity of the ball after the kick. Substituting the given values, we get:

[tex]KE1 = (1/2) (0.454 kg) (31 m/s)^2[/tex] = 218.147 J

The potential energy of the ball at this point is also zero since it is on the ground.

When the goalkeeper blocks the ball, the kinetic energy of the ball is transferred to the goalkeeper, so the energy absorbed by the goalkeeper is equal to the kinetic energy of the ball before it was blocked. The final kinetic energy of the ball can be calculated as:

[tex]KE2 = (1/2)mv2^2[/tex]

where v2 is the velocity of the ball after it is blocked and rolls back toward the player. Substituting the given values, we get:

[tex]KE2 = (1/2) (0.454 kg) (2.25 m/s)^2[/tex] = 1.149 J

The energy absorbed by the goalkeeper is then the difference between the initial kinetic energy of the ball and the final kinetic energy of the ball:

Energy absorbed = KE1 - KE2 = 218.147 J -1.149 J =  216.998 J

Therefore, the sensor should say that the goalkeeper absorbed about 216.998 J of energy when blocking the soccer ball, not accounting for wind and drag.

For more such questions on energy: brainly.com/question/8630757

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