A dog is running at an initial speed of 10 m/s. He covers 50 m in 4 seconds. What is the acceleration of the dog?

a.
1.25 m/s2

b.
1.04 m/s2

c.
5 m/s2

d.
3.2 m/s2

Answers

Answer 1
D i hope this helps
:))

Related Questions

Helppppppppppppppp please and explain!

Answers

An EM with a short energy has more energy than a longer wavelength. the higher the frequency, the shorter the wavelength and the higher the energy of the wave. yw

Let us remember your previous lesson on Physical Press Components! Directions: Analyze the folawna fitness components. Put a check in the box to which Physical Fitness belongs to Components Slab-Related Health Related 1. Power 2. Agility 3. Balance 5. Muscular Strength​

Answers

Answer:

5 Muscular and strength

How many hydrogen atoms are there in all the reactants?

Answers

Answer:

there are two hydrogen atoms in all reactants

Kelvin is a unit of temperature, whereas ampere is a unit of current.
True or False

Answers

Answer:

Kelvin is a unit of temperature, whereas ampere is a unit of current.

True or False

Explanation:

true

Help me with this please

Answers

Answer:

for the secound one i think it would be 45.87 let me know if this is wrong I love to get my feed back

Explanation:

Please help, I need this in by today

Answers

Answer:
1.) Force of friction on the cart pointing towards the left
2.) The force of tension of the rope on the cart pointing towards the right
3.) Normal force of the surface on the cart pointing up
4.) Gravitational force of the Earth on the cart pointing downwards
5.) If the cart is not moving, then the friction force acting on the cart must be equal than the tensile force that acts on the cart.
This can be explained using Newton’s First Law: An object at rest will remain at rest, and an object an motion will remain in motion unless acted upon by another force.
(However you’re really only looking at the first part)

Explanation:
Hmm, it is a little difficult to see since the top of the picture is cut off.
There are a few things I will assume:
1.) There is a cart attached to a rope/string, with no other object present other than the weight on the right
2.) You are working with friction

WHY IS NO ONE HELPING I'M BOUTTA GET REPORTED FR!!!!!!!!!!!!!!
what would happen to the weather if half of the human race just died off? would it get colder? why?

Answers

yes it would get colder because people help people learn through experiences with no one to help teach the world would be a cold lifeless place.

PLz help Asap 10 POINT
I MIGHT GIVE BRAINLIST IF RIGHT AND IF I CAN.

Answers

Answer:

Mars has a thin atmosphere

Explanation:

Okay, so this is going to sound crazy but bare with me. Mar's atmosphere is thin. There is little to no gravitational pull for the atmosphere to stay. Also, no, humans will not be able to live on Mars because the atmosphere, quite literally, contains 1% oxygen. Hopefully this helps! Earth's is thick because of the gravitational pull and gases in Earth's surface.

Help on these two thanks

Answers

Answer:

8. Friction

9. Net force

Explanation:

Hope this helps you. Have a nice day. :)

Help ,I wanna know if this is correct or not

Answers

Answer:

it looks correct to me but im not 11% sure

Explanation:


Which of the following could be evidence that an organism's growth is influenced by the organismis genes?
(Hint identical twins have identical genes. Non-identical twins have about half the same genes.)
Adog breed can be made smaller by breeding together only the smallest dogs.
Identical twins are more likely to be about the same height than non-identical twins,
Chdren are likely to have friends who are about the same height
Identical twins often have slightly different weights at birth

Answers

Answers:

A dog breed can be made smaller by breeding together only the smallest dogs.

Identical twins are more likely to be about the same height than non-identical twins,

Explanation:

what’s 12cm in kilometers

Answers

0.00001 is the correct answer you have an amazing day

Two buildings near each other stand 40m and 60 m tall as measured from the ground to the rooftop. You are standing on the rooftop of the shorter building and observe that the rooftop of the taller building is 55o above the horizontal, as shown in the diagram below. Determine the horizontal distance (in meters) between the two buildings.

Answers

Answer:

Explanation:

tanθ = opp/adj

adj = opp/tanθ

adj = (60 - 40)/tan55 = 14 m

1)How fast is a ball moving when falling from rest and hits the ground 1.70
seconds later?

Answers

The final velocity of the ball is16.66 m/s.

Given the following data:

Initial velocity, U = 0 m/s (since the ball is falling from rest). Time, t = 1.70 seconds.

We know that acceleration due to gravity (a) for a ball in free fall is equal to 9.8 meter per seconds square.

To find how fast (velocity) the ball is moving, we would use the first equation of motion:

Mathematically, the first equation of motion is calculated by using the formula;

[tex]V = U + at[/tex]

Where:

V is the final velocity. U is the initial velocity.a is the acceleration. t is the time measured in seconds.

Substituting the given parameters into the formula, we have;

[tex]V = 0 + 9.8(1.7)[/tex]

[tex]V = 9.8[/tex] × [tex]1.70[/tex]

Final velocity, V = 16.66 m/s.

Therefore, the final velocity of the ball is16.66 m/s.

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PLS HELP ME WITH THIS

Answers

Answer:

C

Explanation:

C

HELP ASAP

Newtons three laws of motion: describe the ______ between an object and the forces acting upon it, and it's motion in_______ to those forces

Answers

Relations with respect to

Explanation:

Laws of Newton are

An object remains at its position of rest or motion until or unless any external force applied.Force=Mass×Acceleration.The initial momentum and final momentum remains same.

Question 6 (3 points)
A high school has a football field that is exactly east-west from end zone to end zone. Football fields are 53.333 yards wide. Starting at the
southwest corner of the field, you walk to the north end of the western 30 yard line. What is the vector (magnitude and angle) of your
displacement? Round to the nearest yard and nearest degree. Make sure you label the angle with the direction (N, S, NE, NW, etc.)
Magnitude:
yards
Angle:
Blank 1:
Blank 2:
Blank 3:

Answers

Answer:

52355236552255558654

[tex].. { {.y = 392.6. = }^{ + 36yjsss} }^{?} jmijjdrk{am \: {}{}s[/tex]

at 30°c an almunium spher is 30cm³ long
the cofficen linear expansion is 24×10`⁶ if the final volume is 30.5cm³
what's the final temperatur of the almunium sphere​

Answers

Answer:

Change volume / volume = .5 / 30 = .01666

coefficient of volume expansion = 3 * 24E-6 = 72E-6

Change in temp = .0167 / 24E-6 = 232 deg C

Final temp = 232 + 30 = 262 deg C

Change in volume / volume = 3 * coeff linear expansion * change in deg C

Question 1
A) Which sentence about galaxies provides evidence of universe expansion that supports the Big Bang Theory?(1 point)

Galaxies are moving away from each other.


Galaxies are in constant motion.


Galaxies are moving at different speeds and in different directions.


Galaxies are moving more slowly than they have in the past.


Question 2
A) Which provides evidence of universe expansion that supports the Big Bang Theory? Select the three correct answers.(2 points)

The temperature of the universe is increasing.


An enormous amount of weak background radiation has been detected in the universe.


The temperature of Cosmic Microwave Background radiation varies widely from one part of the universe to another.


Galaxies are moving away from each other.


The temperature of the universe is decreasing.


The universe is undergoing a cycle of contraction and expansion.


Question 3
A) Which is evidence of universe expansion that supports the Big Bang Theory?(1 point)

The temperature of the universe has cooled and warmed repeatedly over time.


The temperature of the universe has warmed over time.


The temperature of the universe is the same as it was at the time of the Big Bang.


The temperature of the universe has cooled over time.

Answers

The characteristics of the Big Bang allow you to find the correct answers for the different questions are:

1.  The galaxies are moving away from each other.

2.  There is a large amount of weak background radiation in the universe

The galaxies are moving away from each other The temperature of the universe is decreasing

3. The temperature of the universe has cooled over time

The Big Bang model says that initially the universe was born from a great initial explosion about 14 10⁹ years ago, with this idea several facts arise:

The galaxies after their formation must be in a constant expansion There must be an energy in the entire universe remaining from the big explosion As the energy is constant, the energy per unit volume must decrease, consequently the temperature of the universe must be decreasing.

Let's apply these ideas to the different questions, to find the correct answers.

1) What phrase about galaxies provides evidence of the expansion of the universe proposed by the Big Bang

the correct answer is:

The galaxies are moving away from each other.

As there is no friction, the initial forces create a speed in the galaxies, therefore they must move away from each other at this speed

2) What phrases give evidence of the expansion of the universe

the correct answer is:

There is a large amount of weak background radiation in the universe The galaxies are moving away from each other The temperature of the universe is decreasing

3) What evidence of expansion

  The temperature of the universe has cooled over time

In conclusion with the characteristics of the Big Bang we can find the correct answers for the different questions are:

    1.  The galaxies are moving away from each other.

    2.  There is a large amount of weak background radiation in the universe

The galaxies are moving away from each other The temperature of the universe is decreasing

   3. The temperature of the universe has cooled over time

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write two examples of chemical properties and explain what they are

Answers

Chemical Properties are properties of a substance that are seen during a chemical reaction. In other words, chemical properties cannot be found by looking/touching the substance. Those are its physical properties.

Examples

Flammability
toxicity
solubility
Acidity
Electronegativity

When a projectile reaches the highest point the vertical component of the acceleration is:
(A) Less than g (B) Greater than g (C) Positive g (D) Negative g

Answers

Answer:

The acceleration is g.

Taking the upward direction as positive

V = Vy y - 1/2 g t^2

Taking the downward direction as positive

V = -V y + 1/2 g t^2

One can choose either direction as positive, but the acceleration is

the same as g (it is g) while the projectile is in the air.

When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). Thus, the correct option is D.

What is Projectile motion?

Projectile motion is the motion of an object which is thrown or projected high into the air. After the initial force applied on the object that launches the object, the object only experiences the gravitational force. The object is called a projectile and the path of the object is called trajectory.

When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). When the object achieves highest point, then the vertical acceleration of a projectile is zero meter per second square when it is at the peak of its trajectory motion.

Therefore, the correct option is D.

Learn more about Projectile motion here:

https://brainly.com/question/11049671

#SPJ2

En el diseño de una sesión de aprendizaje, la profesora Patricia, tiene como propósito de aprendizaje: Aplica sus habilidades motrices generales en la práctica de juegos diversos. ¿Cuál es el nivel de aprendizaje en que se encuentran sus estudiantes en relación con el propósito de aprendizaje?

Answers

Answer:

im in hardvard dont cheat get amzing grades if you want to go here

Explanation:

Draw a free body diagram of an 6.4 kg ball falling towards earth. Calculate the weight of the ball.​

Answers

Diagram:-

[tex]\setlength{\unitlength}{2mm}\begin{picture}(0,0)\thicklines\put(3,6){\circle{3}}\put(2.9,4.5){\vector(0,-3){2cm}}\put(-3.9,-10){\line(3,0){3cm}}\multiput(-3.5,-10)(0.8,0){18}{\line(1,-2){2mm}}\put(-3.7,0){$\sf\footnotesize 9.8 ms^{-2}$}\put(6,0){\vector(0,3){1.2cm}}\put(5.5,6){\line(3,0){2mm}}\put(5,-1.2){\sf\footnotesize height}\put(6,-2){\vector(0,-3){1.2cm}}\put(5.5,-8){\line(1,0){2mm}}\end{picture}[/tex]

Here

m=6.4kg

[tex]\\ \sf\longmapsto Weight=mg[/tex]

[tex]\\ \sf\longmapsto Weight=6.4(9.8)[/tex]

[tex]\\ \sf\longmapsto weight=62.72N[/tex]

someone pls helpp meeee

Answers

Answer:

the first answer is correct

What is the Normal CSF for:

Leukocytes (per mm³)

% Neutrohils

Glucose (mg/dL)

Protein (mg/dL)

Please provide source if possible.

Answers

1. 5 WBC's per cubic millimeter.

3. 50 to 80 mg/100 mL

4. 15 to 60 milligrams per deciliter (mg/dL) or 0.15 to 0.6 milligrams per milliliter (mg/mL)

If a test were to be performed here are normal results:

Normal values typically range as follows:

Pressure: 70 to 180 mm H2O

Appearance: clear, colorless

CSF total protein: 15 to 60 mg/100 mL

Gamma globulin: 3% to 12% of the total protein

CSF glucose: 50 to 80 mg/100 mL (or greater than two thirds of blood sugar level)

CSF cell count: 0 to 5 white blood cells (all mononuclear), and no red blood cells

Chloride: 110 to 125 mEq/L

(Source: https://medlineplus.gov/ency/article/003428.htm)

The neurotransmitter acetylcholine:
A. is chemically identical to heroin.
B. is found in all sensory neurons.
C. can cause hallucinations when present in abnormally excessive amounts.
D. is involved in muscle contractions and memory.

Answers

Explanation:

A. is chemically identical to heroin.

Someone pls help I don’t understand this

Answers

Answer:

[tex]{ \rm{F _{ball \: on \: bat} = - F _{bat \: on \: ball} }}[/tex]

Explanation:

• This is due to the third newtons law of motion which states that "Every action has an equal and opposite reaction".

3)(20pts) Un barco invasor se encuentra a 560m de un puerto de defensa, el puerto tiene cañones que
disparan con una velocidad de 82m/s. a) ¿Qué ángulo debe de tener el barco para poder golpear el
barco invasor? b) ¿Cuál es el tiempo de vuelo de las balas disparadas por el cañón utilizando el ángulo
de la respuesta "a"? c) ¿Qué tan lejos debe alejarse el barco invasor de la costa para lograr estar fuera
del alcance de los cañones?

Answers

a) Las balas de cañon disparadas desde el puerto deben tener una ángulo de 27.39° para que puedan impactar al barco, con una velocidad inicial de 82 m/s.

b) El tiempo de vuelo de las balas de cañon para alcanzar al barco que está a 560 m de distancia es de 7.69 s.

c) Sabiendo que el ángulo calculado en el inciso a) es para una distancia de 560 m, el barco debe estar a una distancia mayor para que las balas no lo alcancen.

a)

Podemos usar las ecuaciones de tiro parabólico para encontrar el ángulo que permita derribar al barco invasor.

[tex]x=\frac{v_{i}^{2}sin(2\alpha)}{g}[/tex] (1)

Donde:

v(i) es la velocidad inicial del cañon (82 m/s)α es el ángulo de tirog es la gravedad (9.81 m/s²)x es el desplazamiento total (560 m)

Lo que debemos hacer es depejar α de la ecuación 1

[tex]sin(2\alpha)=\frac{xg}{v_{i}^{2}}[/tex]

[tex]sin(2\alpha)=\frac{560*9.81}{82^{2}}[/tex]

[tex]sin(2\alpha)=0.82[/tex]

[tex]\alpha=\frac{sin^{-1}(0.82)}{2}[/tex]

[tex]\alpha=27.39^{\circ}[/tex]

Por lo tanto, el ángulo para que el cañón impacte en el barco es de 27.39 °.

b)

Sabemos que la componente de la velocidad en el eje x es constante, así que podemo usar la siguiente ecuación.

[tex]v_{x}=\frac{x}{t}[/tex]

La componente x de la velocidad es V(x) = V(i)cos(α) y sabiendo la distancia total de 560 m, el tiempo será:

[tex]v_{i}cos(\alpha)=\frac{x}{t}[/tex]

[tex]t=\frac{x}{v_{i}cos(\alpha)}[/tex]

[tex]t=\frac{560}{82cos(27.39)}[/tex]

[tex]t=7.69\: s[/tex]

El tiempo total de vuelo de las balas de cañon es de 7.69 s.

c)

Sabemos que el ángulo calculado en el inciso a) es de 27.39 °, y ese valor fue calcualdo para una distancia de 560 m, por lo tanto el barco debe estar a una distancia mayor que esa para que las balas no lo alcancen.

Puedes encontrar más información sobre tiro parabólico aquí:

https://brainly.lat/tarea/3605927

Espero te haya sido de ayuda!

Compared to a 1-kg block of solid iron, a 2-kg block of solid iron has the same:
A. Density
B. Mass
C. Volume
D. Inertia

Answers

The Correct choice is :

Density

A rocket traveling through space with a constant velocity of 10 m/s fires up a booster. The booster accelerates the rocket at a rate of 5 m/s. What distance in meters has the rocket traveled within 12 seconds after the booster is turned on?​

Answers

The distance traveled by the rocket after the given time period is 480 m.

The given parameters;

velocity of the rocket, v = 10 m/sacceleration of the rocket, a = 5 m/s²time of motion of the rocket, t = 12 s

The distance traveled by the rocket after the given time period is calculated from the second kinematic equation of as shown below;

s = ut + ¹/₂at²

s = (10 x 12) + (0.5 x 5 x 12²)

s = 120 + 360

s = 480 m

Thus, the distance traveled by the rocket after the given time period is 480 m.

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