∠A and \angle B∠B are vertical angles. If m\angle A=(2x+19)^{\circ}∠A=(2x+19) ∘ and m\angle B=(3x-18)^{\circ}∠B=(3x−18) ∘ , then find the measure of \angle A∠A.

The value of expression |-4 + 3| · 8 is 8.

What is Modulus function?

A modulus function is a function which gives the absolute value of numbers or variable.

The expression is given as;

| -4 + 3 | * 8

Now, Solve the expression as;

⇒ | -4 + 3 | * 8

⇒ | - 1 | * 8

⇒ 1 * 8

⇒ 8

Since, Modulus of a negative number gives the positive of that number.

Hence, The value of expression |-4 + 3| · 8 is 8.

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Answer:

If there are dotted lines available then use dotted lines for the range where its only greater than or less than, when there is no equals to sign then you use dotted lines

Step-by-step explanation:

Answer:

1204.7 in

Explanation:

The perimeter of the triangle in discuss expressed in terms of the length of the base as required in the task content is; Perimeter= 5x.

According to the task content, it follows that the perimeter of the triangle in terms of the length of the base is to be determined.

Let x = length of the base

Therefore, length of each leg = 2x.

Therefore, since the perimeter of the triangle is the sum of all sides; it follows that we have;

Perimeter = x + 2x +2x

Perimeter = 5x.

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a) If the [tex]n[/tex]-th term is [tex]x_n = cn+d[/tex], then

[tex]x_1 = c + d = 16[/tex]

[tex]x_2 = 2c + d = 19[/tex]

Eliminating [tex]d[/tex],

[tex](2c+d) - (c+d) = 19-16 \implies c = 3[/tex]

Solving for [tex]d[/tex],

[tex]3 + d = 16 \implies d = 13[/tex]

Then

[tex]\boxed{x_n = 3n + 13}[/tex]

b) When [tex]n=11[/tex], we get

[tex]x_{11} = 3\cdot11 + 13 = \boxed{46}[/tex]

======================================================

Work Shown:

20% of $9.50 = 0.20*9.50 = 1.90

You earn an extra $1.90 on top of the $9.50 already there. So the new wage is 9.50 + 1.90 = 11.40 dollars per hour

-----------

Shortcut:

1.20*9.50 = 11.40

Think of 1.20 as 100% + 20% = 1 + 0.20 = 1.20, and this represents an increase of 20%

Answer: 1/7 or 0.142857

Step-by-step explanation:

Answer:

1/7 :)

Step-by-step explanation:

Check the picture below.

[tex]\textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2 + b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{7}\\ b=\stackrel{opposite}{\sqrt{95}}\\ \end{cases} \\\\\\ c=\sqrt{7^2~~ + ~~(\sqrt{95})^2}\implies c=\sqrt{49+95}\implies c=\sqrt{144}\implies c=12 \\\\[-0.35em] ~\dotfill\\\\ sin(C )=\cfrac{\stackrel{opposite}{\sqrt{95}}}{\underset{hypotenuse}{12}}\implies sin(C)\approx \text{\LARGE 0.81}[/tex]

Answer:

27

Step-by-step explanation:

4.5*3*2 = 27

hi,

You just have to multiply the three measures.  

So :  

2*3*4.5 =  27 cm³

Easy, is it not ?  

The price of the perpetuity is $2200

The present value of a perpetuity is determined by simply dividing the amount of the regular cash flows by the discount rate. A growing perpetuity includes a growth rate that increases the cash flows received each period going forward.

Given:

coupon=$55

yield to maturity=2.5%

As, we know price of the perpetuity is determined by dividing the coupon by the yield to maturity.

So,

price=coupon/yield to maturity

price=$55/2.5%

price=$2200

Hence, the price of the perpetuity is $2200

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False, If we know the distance of an object from earth, we can determine the size of the object by measuring its parallax.

What is parallax explain?

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Based on the number of cookies that Fatima was able to package in a certain amount of time, the relationship between the cookies and the time it takes to package them is a single cookie is packaged in 12 seconds.

To find the amount of time it takes to package the cookies, the formula is:

= Number of minutes /  Number of cookies

= 4 / 20

= 1/5

= 0.20 minutes  

When converted to minutes, this is:

= 0.20 x 60 seconds per minute

= 12 seconds

In conclusion, it takes 12 seconds to package a cookie on average.

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The average fraction of students in the two classes who went on the field trip is 11/16

The given parameters are:

Class 1 = 3/4

Class 2 = 5/8

The average is calculated as

Average = 1/2 * (Class 1 + Class 2)

So, we have

Average = 1/2 * (3/4 + 5/8)

Evaluate

Average = 11/16

Hence, the average fraction of students in the two classes who went on the field trip is 11/16

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The difference quotient of the function that has been presented to us will turn out to be 5.

In this step, we wish to determine the difference quotient for the function that was supplied.

To begin, keep in mind that the difference quotient may be calculated by:

Lim h->0 [tex]\frac{f(x+h)-f(x)}{h}[/tex]

Now, for the purpose of the function, we need this:

Then we will have:

[tex]$$\begin{aligned}&\lim _{h \rightarrow 0} \frac{j(x+h)-j(x)}{h} \\&\lim _{h \rightarrow 0} \frac{5 *(x+h)-3-5 * x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 x+5 h-3-5 x+3}{h} \\&\lim _{h \rightarrow 0} \frac{5 h}{h}=5\end{aligned}$$[/tex]

j(x) = 5x - 3

Then the following will be true:

Therefore, 5 is the value of the difference quotient for j(x) is %

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Answer: 0

Step-by-step explanation:

Answer:

The answer is A

Step-by-step explanation:

Answer:

not sure what you were asking, but its 15 cups of purple paint

The expression to show the stock's value is -$138 x 13

Given that the price of a stock is steadily decreasing.

Decreasing values are usually represented along with a negative sign.

The decreased price = $138

This means the decrease is of -$138.

Number of months = 13 years

That is $138 is decreased over 13 years.

Then The expression to show the stock's value is -$138 x 13

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Given [tex]2d+32[/tex]

[tex]d=8[/tex]

Put the value of d in the given equation

[tex]2d+32[/tex]

[tex]2(8)+32[/tex]

[tex]16+32[/tex][tex]= 48[/tex]

What we do in  Evaluation in math?

The verb "evaluate" is used in mathematics to mean to discover or determine the worth of something. Finding the precise value of an algebraic expression or numerical computation is relevant here as well as financial mathematics.

In mathematics, the terms "evaluate" and "solve" are often used interchangeably. Consider the following basic multiplication problem: "Evaluate the cost of six tomatoes when the tomatoes are purchased at $2 each." The student would multiply 6 by 2 to get the result of $12. The term evaluate might also come before a list of inquiries, as a list of straightforward algebraic equations.

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Answer:

9

Step-by-step explanation:

→ Substitute in the values

2³ +√64 ÷ 8

→ Simplify

8 + 8 ÷ 8

→ Calculate

8 + 1 = 9

Answer:

9

Step-by-step explanation:

2 to the power of 3 is 8

8 + 64 = 72

72 ÷ 8 = 9

Answer:

[tex]m^8-4[/tex]

Step-by-step explanation:

[tex]Rule: a^b\cdot \:a^c=a^{b+c}\\=m^7m=m^{7+1}\\=m^{7+1}-4\\=m^8-4[/tex]

First you want to make the fractions have equal denominators. So you want to convert 1/2 to 2/4. Now you can add 1 1/4 to 2 2/4. After adding that subtract it from 6 1/4. Whatever your answer is will be how much more she needs.

Beginning with the graph of f(x) = x2, The transformations that are needed to form  [tex]g(x)=\frac{1}{2}(x+4)^2-3[/tex] is

The graph of g(x) is wider than f(x) and is shifted to the left 3 units and down 3 units

This is further explained below.

Generally, A point, a line, or a geometric figure may undergo one of these four distinct transformations in order for the point's, line's, or figure's shape and/or location to be altered.

The shape of the item as it was before the transformation is referred to as the Pre-Image, while the shape and location of the object after the change make up the Image.

In conclusion, The necessary transformations may be found by beginning with the graph of the function f(x) = x2.

[tex]g(x)=\frac{1}{2}(x+4)^2-3[/tex]

The graph of g(x) is bigger than the graph of f(x), and it is displaced 3 units to the left and 3 units down from its original position.

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Answer:

The graph of g(x) is wider than f(x) and is shifted to the left 4 units and down 3 units.

Step-by-step explanation:

I got it right.

There are 3 computer games she can brought at $75.

Unitary method

Unitary method is defined as the process of finding the value of a unit and then the value of a required number of units.

Given,

Arianna buys computer games from an online store.

Each game she orders costs $22 and shipping for her total is $9.

Arianna can spend no more than $75.

Here we need to find how many computer games did Arianna Brought.

Let x be the number of computer games she brought.

We know that,

Cost for one game = $22

Shipping cost = $9.

She spent = $75.

So, it can be written as,

=> 22x + 9 = 75

=> 22x = 75 - 9

=> 22x = 66

=> x = 66/22

=> x = 3.

So, she can brought 3 computer games at $75.

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Answer:

See the picture below.

Step-by-step explanation:

Answer:

[tex]\sqrt{-63}=3i\sqrt{7}[/tex]

[tex]\sqrt{-156}=2i\sqrt{39}[/tex]

[tex]6\sqrt{-12}=12i\sqrt{3}[/tex]

[tex]-5\sqrt{-75}=-25i\sqrt{3}[/tex]

Step-by-step explanation:

An imaginary number is a non-zero real number multiplied by the imaginary unit [tex]i[/tex].

[tex]\boxed{\begin{minipage}{4 cm}\begin{center}\underline{Imaginary Number Rule}\end{center}\\\begin{center}$\sqrt{-1}=i$\end{center}\end{minipage}}[/tex]

[tex]\boxed{\begin{minipage}{4 cm}\begin{center}\underline{Radical Rule}\end{center}\\\begin{center}$\sqrt{a \cdot b}=\sqrt{a} \sqrt{b}$\end{center}\end{minipage}}[/tex]

[tex]\begin{aligned}\sqrt{-63} & = \sqrt{9 \cdot -1 \cdot 7}\\& = \sqrt{9}\sqrt{-1}\sqrt{7}\\& = 3i\sqrt{7}\end{aligned}[/tex]

[tex]\begin{aligned}\sqrt{-156} & = \sqrt{4 \cdot -1 \cdot -39}\\& = \sqrt{4} \sqrt{-1} \sqrt{39}\\& = 2i\sqrt{39}\end{aligned}[/tex]

[tex]\begin{aligned}6 \sqrt{-12} & = 6 \sqrt{4 \cdot -1 \cdot -3} \\& = 6 \sqrt{4} \sqrt{-1} \sqrt{3} \\& = 6 \cdot 2 i \sqrt{3} \\& = 12i \sqrt{3}\end{aligned}[/tex]

[tex]\begin{aligned}-5 \sqrt{-75} & = -5 \sqrt{25 \cdot -1 \cdot -3} \\& = -5 \sqrt{25} \sqrt{ -1 } \sqrt{3} \\& = -5 \cdot 5i \sqrt{3} \\& = -25i \sqrt{3}\end{aligned}[/tex]

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Answer: Marie ran 4.5 miles on Monday.

Step-by-step explanation: 5.7

                                            +1.2

                                             6.9      

The expression for the area within the circle but outside the triangle as a function of the length 3x of the side of the triangle is [tex]\frac{88r^2}{7}-\frac{9\sqrt{3} }{2}x^2[/tex].

It is given that:-

Radius of circle = 2r

Length of side of equilateral triangle = 3x

We have to find the expression for the area within the circle but outside the triangle as a function of the length 3x of the side of the triangle.

We know that,

Area of circle = [tex]\pi R^2[/tex]

Where R is the radius of the circle.

We have R = 2r

Area of an equilateral triangle = [tex]\frac{\sqrt{3} }{2}a^2[/tex]

Where, a is the length of side of equilateral triangle.

a = 3x

Hence,

Expression = [tex]\pi R^2-\frac{\sqrt{3} }{2}a^2[/tex]

Expression = [tex]\frac{22}{7}*(2r)^2-\frac{\sqrt{3} }{2}*(3x)^2 = \frac{88r^2}{7}-\frac{9\sqrt{3} }{2}x^2[/tex].

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since you said please: 127*