Answer:
3.7 m
Explanation:
ASSUMING this means extra distance beyond where the cannonball would land WITHOUT the wind assistance but in general ignoring air resistance. Hmmmmmm...tricky
The ball drops from vertical rest to ASSUMED horizontal ground 15 m below in a time of
t = √ (2h/g) = √(2(15)/9.8) = 1.75 s
Without the tail wind, the ball travels horizontally
d = vt = 68(1.75) = 119 m
The tailwind exerts a constant acceleration on the ball of
a = F/m = 12/5.0 = 2.4 m/s²
The average horizontal velocity during the flight is
v(avg) = (68 + (68 + 2.4(1.75)) / 2 = 70.1 m/s
so the distance with tailwind is
d = v(avg)t = 70.1(1.75) = 122.675 m
The extra distance is 122.675 - 119 = 3.675 = 3.7 m
Someone pls help I don’t understand this
Answer:
[tex]{ \rm{F _{ball \: on \: bat} = - F _{bat \: on \: ball} }}[/tex]
Explanation:
• This is due to the third newtons law of motion which states that "Every action has an equal and opposite reaction".
Help ,I wanna know if this is correct or not
Answer:
it looks correct to me but im not 11% sure
Explanation:
PLz help Asap 10 POINT
I MIGHT GIVE BRAINLIST IF RIGHT AND IF I CAN.
Answer:
Mars has a thin atmosphere
Explanation:
Okay, so this is going to sound crazy but bare with me. Mar's atmosphere is thin. There is little to no gravitational pull for the atmosphere to stay. Also, no, humans will not be able to live on Mars because the atmosphere, quite literally, contains 1% oxygen. Hopefully this helps! Earth's is thick because of the gravitational pull and gases in Earth's surface.
8. What is generated by the movement of tiny particles within an object? *
(2 Points)
endothermic
exothermic
heat
thermal
Answer: Thermal Energy
Explanation: I know this answer is correct because I had to look in my notebook for the definition
In my own words: Thermal Energy is the energy coming from heat which means it is generated by the movement of tiny particles with different objects.
Hope this helps! :)
Question 6 (3 points)
A high school has a football field that is exactly east-west from end zone to end zone. Football fields are 53.333 yards wide. Starting at the
southwest corner of the field, you walk to the north end of the western 30 yard line. What is the vector (magnitude and angle) of your
displacement? Round to the nearest yard and nearest degree. Make sure you label the angle with the direction (N, S, NE, NW, etc.)
Magnitude:
yards
Angle:
Blank 1:
Blank 2:
Blank 3:
Answer:
52355236552255558654
[tex].. { {.y = 392.6. = }^{ + 36yjsss} }^{?} jmijjdrk{am \: {}{}s[/tex]
Help on these two thanks
Answer:
8. Friction
9. Net force
Explanation:
Hope this helps you. Have a nice day. :)
Kelvin is a unit of temperature, whereas ampere is a unit of current.
True or False
Answer:
Kelvin is a unit of temperature, whereas ampere is a unit of current.
True or False
Explanation:
true
PLS HELP ME WITH THIS
Answer:
C
Explanation:
C
Peering through a telescope could be considered Step 1 of the scientific method.
True
False
When a projectile reaches the highest point the vertical component of the acceleration is:
(A) Less than g (B) Greater than g (C) Positive g (D) Negative g
Answer:
The acceleration is g.
Taking the upward direction as positive
V = Vy y - 1/2 g t^2
Taking the downward direction as positive
V = -V y + 1/2 g t^2
One can choose either direction as positive, but the acceleration is
the same as g (it is g) while the projectile is in the air.
When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). Thus, the correct option is D.
What is Projectile motion?Projectile motion is the motion of an object which is thrown or projected high into the air. After the initial force applied on the object that launches the object, the object only experiences the gravitational force. The object is called a projectile and the path of the object is called trajectory.
When a projectile reaches the highest point the vertical component of the acceleration is negative g (acceleration due to gravity). When the object achieves highest point, then the vertical acceleration of a projectile is zero meter per second square when it is at the peak of its trajectory motion.
Therefore, the correct option is D.
Learn more about Projectile motion here:
https://brainly.com/question/11049671
#SPJ2
what’s 12cm in kilometers
3)(20pts) Un barco invasor se encuentra a 560m de un puerto de defensa, el puerto tiene cañones que
disparan con una velocidad de 82m/s. a) ¿Qué ángulo debe de tener el barco para poder golpear el
barco invasor? b) ¿Cuál es el tiempo de vuelo de las balas disparadas por el cañón utilizando el ángulo
de la respuesta "a"? c) ¿Qué tan lejos debe alejarse el barco invasor de la costa para lograr estar fuera
del alcance de los cañones?
a) Las balas de cañon disparadas desde el puerto deben tener una ángulo de 27.39° para que puedan impactar al barco, con una velocidad inicial de 82 m/s.
b) El tiempo de vuelo de las balas de cañon para alcanzar al barco que está a 560 m de distancia es de 7.69 s.
c) Sabiendo que el ángulo calculado en el inciso a) es para una distancia de 560 m, el barco debe estar a una distancia mayor para que las balas no lo alcancen.
a)
Podemos usar las ecuaciones de tiro parabólico para encontrar el ángulo que permita derribar al barco invasor.
[tex]x=\frac{v_{i}^{2}sin(2\alpha)}{g}[/tex] (1)
Donde:
v(i) es la velocidad inicial del cañon (82 m/s)α es el ángulo de tirog es la gravedad (9.81 m/s²)x es el desplazamiento total (560 m)Lo que debemos hacer es depejar α de la ecuación 1
[tex]sin(2\alpha)=\frac{xg}{v_{i}^{2}}[/tex]
[tex]sin(2\alpha)=\frac{560*9.81}{82^{2}}[/tex]
[tex]sin(2\alpha)=0.82[/tex]
[tex]\alpha=\frac{sin^{-1}(0.82)}{2}[/tex]
[tex]\alpha=27.39^{\circ}[/tex]
Por lo tanto, el ángulo para que el cañón impacte en el barco es de 27.39 °.
b)
Sabemos que la componente de la velocidad en el eje x es constante, así que podemo usar la siguiente ecuación.
[tex]v_{x}=\frac{x}{t}[/tex]
La componente x de la velocidad es V(x) = V(i)cos(α) y sabiendo la distancia total de 560 m, el tiempo será:
[tex]v_{i}cos(\alpha)=\frac{x}{t}[/tex]
[tex]t=\frac{x}{v_{i}cos(\alpha)}[/tex]
[tex]t=\frac{560}{82cos(27.39)}[/tex]
[tex]t=7.69\: s[/tex]
El tiempo total de vuelo de las balas de cañon es de 7.69 s.
c)
Sabemos que el ángulo calculado en el inciso a) es de 27.39 °, y ese valor fue calcualdo para una distancia de 560 m, por lo tanto el barco debe estar a una distancia mayor que esa para que las balas no lo alcancen.
Puedes encontrar más información sobre tiro parabólico aquí:
https://brainly.lat/tarea/3605927
Espero te haya sido de ayuda!
Compared to a 1-kg block of solid iron, a 2-kg block of solid iron has the same:
A. Density
B. Mass
C. Volume
D. Inertia
The Correct choice is :
DensityPlease help, I need this in by today
Two buildings near each other stand 40m and 60 m tall as measured from the ground to the rooftop. You are standing on the rooftop of the shorter building and observe that the rooftop of the taller building is 55o above the horizontal, as shown in the diagram below. Determine the horizontal distance (in meters) between the two buildings.
Answer:
Explanation:
tanθ = opp/adj
adj = opp/tanθ
adj = (60 - 40)/tan55 = 14 m
write two examples of chemical properties and explain what they are
What is the Normal CSF for:
Leukocytes (per mm³)
% Neutrohils
Glucose (mg/dL)
Protein (mg/dL)
Please provide source if possible.
1. 5 WBC's per cubic millimeter.
3. 50 to 80 mg/100 mL
4. 15 to 60 milligrams per deciliter (mg/dL) or 0.15 to 0.6 milligrams per milliliter (mg/mL)
If a test were to be performed here are normal results:
Normal values typically range as follows:
Pressure: 70 to 180 mm H2O
Appearance: clear, colorless
CSF total protein: 15 to 60 mg/100 mL
Gamma globulin: 3% to 12% of the total protein
CSF glucose: 50 to 80 mg/100 mL (or greater than two thirds of blood sugar level)
CSF cell count: 0 to 5 white blood cells (all mononuclear), and no red blood cells
Chloride: 110 to 125 mEq/L
(Source: https://medlineplus.gov/ency/article/003428.htm)
at 30°c an almunium spher is 30cm³ long
the cofficen linear expansion is 24×10`⁶ if the final volume is 30.5cm³
what's the final temperatur of the almunium sphere
Answer:
Change volume / volume = .5 / 30 = .01666
coefficient of volume expansion = 3 * 24E-6 = 72E-6
Change in temp = .0167 / 24E-6 = 232 deg C
Final temp = 232 + 30 = 262 deg C
Change in volume / volume = 3 * coeff linear expansion * change in deg C
Let us remember your previous lesson on Physical Press Components! Directions: Analyze the folawna fitness components. Put a check in the box to which Physical Fitness belongs to Components Slab-Related Health Related 1. Power 2. Agility 3. Balance 5. Muscular Strength
Answer:
5 Muscular and strength
WHY IS NO ONE HELPING I'M BOUTTA GET REPORTED FR!!!!!!!!!!!!!!
what would happen to the weather if half of the human race just died off? would it get colder? why?
The neurotransmitter acetylcholine:
A. is chemically identical to heroin.
B. is found in all sensory neurons.
C. can cause hallucinations when present in abnormally excessive amounts.
D. is involved in muscle contractions and memory.
Explanation:
A. is chemically identical to heroin.
En el diseño de una sesión de aprendizaje, la profesora Patricia, tiene como propósito de aprendizaje: Aplica sus habilidades motrices generales en la práctica de juegos diversos. ¿Cuál es el nivel de aprendizaje en que se encuentran sus estudiantes en relación con el propósito de aprendizaje?
Answer:
im in hardvard dont cheat get amzing grades if you want to go here
Explanation:
HELP ASAP
Newtons three laws of motion: describe the ______ between an object and the forces acting upon it, and it's motion in_______ to those forces
Explanation:
Laws of Newton are
An object remains at its position of rest or motion until or unless any external force applied.Force=Mass×Acceleration.The initial momentum and final momentum remains same.How many hydrogen atoms are there in all the reactants?
Answer:
there are two hydrogen atoms in all reactants
someone pls helpp meeee
Answer:
the first answer is correct
Helppppppppppppppp please and explain!
A rocket traveling through space with a constant velocity of 10 m/s fires up a booster. The booster accelerates the rocket at a rate of 5 m/s. What distance in meters has the rocket traveled within 12 seconds after the booster is turned on?
The distance traveled by the rocket after the given time period is 480 m.
The given parameters;
velocity of the rocket, v = 10 m/sacceleration of the rocket, a = 5 m/s²time of motion of the rocket, t = 12 sThe distance traveled by the rocket after the given time period is calculated from the second kinematic equation of as shown below;
s = ut + ¹/₂at²
s = (10 x 12) + (0.5 x 5 x 12²)
s = 120 + 360
s = 480 m
Thus, the distance traveled by the rocket after the given time period is 480 m.
Learn more here:https://brainly.com/question/23243663
Help me with this please
Answer:
for the secound one i think it would be 45.87 let me know if this is wrong I love to get my feed back
Explanation:
Which of the following could be evidence that an organism's growth is influenced by the organismis genes?
(Hint identical twins have identical genes. Non-identical twins have about half the same genes.)
Adog breed can be made smaller by breeding together only the smallest dogs.
Identical twins are more likely to be about the same height than non-identical twins,
Chdren are likely to have friends who are about the same height
Identical twins often have slightly different weights at birth
Answers:
A dog breed can be made smaller by breeding together only the smallest dogs.
Identical twins are more likely to be about the same height than non-identical twins,
Explanation:
Draw a free body diagram of an 6.4 kg ball falling towards earth. Calculate the weight of the ball.
Diagram:-
[tex]\setlength{\unitlength}{2mm}\begin{picture}(0,0)\thicklines\put(3,6){\circle{3}}\put(2.9,4.5){\vector(0,-3){2cm}}\put(-3.9,-10){\line(3,0){3cm}}\multiput(-3.5,-10)(0.8,0){18}{\line(1,-2){2mm}}\put(-3.7,0){$\sf\footnotesize 9.8 ms^{-2}$}\put(6,0){\vector(0,3){1.2cm}}\put(5.5,6){\line(3,0){2mm}}\put(5,-1.2){\sf\footnotesize height}\put(6,-2){\vector(0,-3){1.2cm}}\put(5.5,-8){\line(1,0){2mm}}\end{picture}[/tex]
Here
m=6.4kg[tex]\\ \sf\longmapsto Weight=mg[/tex]
[tex]\\ \sf\longmapsto Weight=6.4(9.8)[/tex]
[tex]\\ \sf\longmapsto weight=62.72N[/tex]
