A 20-year U.S. Treasury bond has a 3.50 percent interest rate, while a same maturity corporate bond has a 5.25 percent interest rate. Real interest rates and inflation rate expectations would be the same for the two bonds. If a default risk premium of 1.50 percentage points is estimated for the corporate bond, determine the liquidity premium for the corporate bond.

Answer: None of the above

Step-by-step explanation:

Answer:

the answer is 42

Step-by-step explanation:

you add 217+153+88=458

500-458=42

Answer:

a) $168,760

b) $119,275

Step-by-step explanation:

For this, I believe you do $288,035 - $49,485. This equals $238,550.

Then divide this by 2 to get the salary for state B, which is $119,275 .

$168,760 remains, so it's the salary for state A.

Answer:

Governor of state A = 168,760

Governor of state B = 119,275

Step-by-step explanation:

A = 49485 + B         Eq. 1

A + B = 288035       Eq. 2

A = Earns  of governor of state A

B = Earns of governor of state B

Replacing Eq. 1 in Eq. 2:

(49485+B) + B =288035

2B + 49485 = 288035

2B = 288035  - 49485

2B = 238550

B = 238550/2

B = 119275

From eq. 1

A = 49485 + 119275

A = 168760

Check:

from eq. 2:

A + B = 288035

168760 + 119275 = 288035

Answer:

x=11

Step-by-step explanation:

9x=7x+22

9x-7x=22

2x=22

2x/2=22/2

x=11

Answer: 4/3 or 2/1.5

Step-by-step explanation:

       The constant of proportionality is also known as the slope. This can be found with change in y over change x.

       Since we have a graph with distinct points, we can use rise over run. For this graph, we will count 3 units up from (0, 0) and 4 units right to (4, 3). This becomes 4/3 or 2/1.5. This is the constant of proportionality.

Start by dividing both sides by G, giving us

[tex]\frac{F}{G}=\frac{m_{1} m_{2} }{d^{2} } }[/tex]. Multiply both sides by d^2. [tex]\frac{F}{G}(d^{2})=m_{1} m_{2}[/tex].

Finally, divide both sides by m2.

[tex](\frac{F}{G}\div{m_{2}}) (\frac{d^{2} }{m_{2} } )=m_{1}[/tex]

Hope this helps! This was a tough problem for me too.

Answer:

I think they're 800miles from starting point

Step-by-step explanation:

Volume of water in the tank after one minute is 10,991 gallons

Volume of water in the tank after two minutes is 10,962 gallons

Volume of water in the tank after one minute is 10,730 gallons

The given parameters are;

The volume of water the large industrial tank holds, V = 11,020 gallons

The rate of flow out of the tank through the drain on the bottom; Q = 29 gallons per minute

The initial level of water in the tank if the tank is initially filled is; 11,020 gallons

We want to find out the amount of water in gallons left in the tank after one minute.

The volume, V_out, of water that flows out of the tank after a given time, t, is given as follows;

V_out = Q × t

When t = 1 minute, we have;

V_out = 29 * 1

V_out = 29 gallons

The volume of water left in the tank, V_in tank , is given as follows;

V_in tank = V - V_out

Thus, volume left after one minute is;

V_in tank = 11020 - 29

V_in tank = 10991 Gallons

Similarly, after 2 minutes;

When t = 2 minute, we have;

V_out = 29 * 2

V_out = 58 gallons

The volume of water left in the tank, V_in tank , is given as follows;

V_in tank = V - V_out

Thus, volume left after two minutes is;

V_in tank = 11020 - 58

V_in tank = 10672 Gallons

Similarly, after 10 minutes;

When t = 10 minute, we have;

V_out = 29 * 1 0

V_out = 290 gallons

The volume of water left in the tank, V_in tank , is given as follows;

V_in tank = V - V_out

Thus, volume left after ten minutes is;

V_in tank = 11020 - 290

V_in tank = 10933 Gallons

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Answer:

9

Step-by-step explanation:

x/9 = 1

Multiply both sides by 9

x = 9

Also, any number over itself is equal to 1.

Answer:

y= -3x-4.

Step-by-step explanation:

1) the slope-interception form is:

y=slope*x+i, where i - interception;

2) using the given two points it is possible to calculate the slope:

[tex]slope=\frac{5+1}{-3+1}=-3;[/tex]

then the required equation has the form:

y=-3x+i;

3) in order to calculate the 'i', it is enough to substitute the coordinates of the one point into this form of the required equation:

-1=-3*(-1)+i; ⇒ i=-4.

4) finally, the required equation is:

y=-3x-4.

P.S. the suggested way is not the shortest one.

The linear equation would be y = 18 - 4x which represents the distance Jordan still has to walk after x hours.

The y-intercept represents the total distance Jordan has to walk.

Distance is defined as the product of speed and time.

We have to determine the distance.

So distance = speed× time

Given that his speed is 4 mph and x hours of walking, then:

So distance = 4 × x

Let it Start of the trail: 0 miles

And the end of the trail: 18 miles​

The trail length is 18 miles, so if he walked 1 mile, 18 - 1 = 17 miles are left, in general:

⇒ y = 17 - 4(x)

Here y would be the distance Jordan still has to walk.

The y-intercept would be if substitute x = 0, then:

⇒ y = 17- 4(0)

⇒ y = 17

This represents the total distance Jordan has to walk

Hence, the linear equation would be y = 18 - 4x which represents the distance Jordan still has to walk after x hours.

The y-intercept represents the total distance Jordan has to walk.

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The answer to given question is given below in detailed manner.

Business Commencement Date means the first date on which the Company or any Affiliate, licensee or sublicensee of the Company makes a commercial sale of any Product within the Field of Activity in the Territory that would generate a payment to the Partnership or the Class A Limited Partners.

Hence here commencement date is not applicable;

for starting capital required=10000+5000

Now adding commencement of business with cash 10000 and goods 5000​ as date commencement is not applied here so we get =15000

The capital account is a liability for business this amount is needed to return to investor one day.

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Answer: The answer to given question is given below:

Step-by-step explanation:

Business Commencement Date means the first date on which the Company or any Affiliate, licensee or sublicensee of the Company makes a commercial sale of any Product within the Field of Activity in the Territory that would generate a payment to the Partnership or the Class A Limited Partners.

hence here

commencement date is not applicable;

for starting capital required=10000+5000

=15000

The capital account is a liability for business

this amount is needed to return to investor one day.

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The length of the rectangle is 12 meters and its width is 4 meters.

A rectangle is a four sided figure, whose opposite sides are equal and the angle formed by any two adjacent sides is 90 degrees.

Here, we are given that the perimeter of the rectangle is 32 meters.

Let the length of the rectangle be L and breadth or width be B

We known that perimeter of a rectangle = 2(L + B)

Now, it is given that the length is 4 m more than two times the width

⇒ L = 4 + 2B

Thus, the area of the perimeter will be-

Perimeter = 2(4 + 2B + B)

⇒ 32 = 2(4 + 2B + B)

32/2 = 4 + 2B + B

16 = 4 + 3B

16 - 4 = 3B

12 = 3B

or 3B = 12

B = 12/3

B = 4

Thus, the width of the rectangle is 4 meters.

Therefore, L = 4 + 2(4)

L = 4 + 8

L = 12

Thus, the length of the rectangle is 12 meters.

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Answer:

11 and 22

Step-by-step explanation:

We can say that BC=2AC.

Since AB=33, AC=11 and BC=22.

Answer:the heart and planet are the only ones

Step-by-step explanation:

the clover looks like maybe but the stem is curved. the planet the line goes verticle through the rings

Answer:

★ How to do :-

Here, we are given with a fraction in which we are asked to find the second number in which we get it's product when multiplied as one. We aren't given with the appropriate first number but it's written in thr form of multiplication. If we multiply those numbers, we'll get the value of the first number. After finding the first number, we shift thr obtained value from LHS to RHS. We should always remember that while shifting the numbers, the sign of the appropriate number changes. So, let's solve!!

\:

➤ Solution :-

{\tt \leadsto 3 \: \bigg( \dfrac{7}{9} \bigg) \times x = 1}⇝3(97)×x=1

First, multiply the numbers on LHS.

{\tt \leadsto \bigg( \dfrac{3}{1} \times \dfrac{7}{9} \bigg) \times x = 1}⇝(13×97)×x=1

First solve the bracket on LHS.

{\tt \leadsto \dfrac{21}{9} \times x = 1}⇝921×x=1

Shift the first fraction from LHS to RHS, changing it's sign.

{\tt \leadsto x = 1 \div \dfrac{21}{9}}⇝x=1÷921

Take the reciprocal of second fraction and multiply both the fractions.

{\tt \leadsto x = \dfrac{1}{1} \times \dfrac{9}{21}}⇝x=11×219

Multiply the fractions now.

{\tt \leadsto x = \dfrac{9}{21}}⇝x=219

\:

{\red{\underline{\boxed{\bf So, \: the \: other \: number \: is \: \dfrac{9}{21}}}}}So,theothernumberis219

\:

Verification :-

{\tt \leadsto 3 \: \bigg( \dfrac{7}{9} \bigg) \times x = 1}⇝3(97)×x=1

Substitute the value of x.

{\tt \leadsto 3 \: \bigg( \dfrac{7}{9} \bigg) \times \dfrac{9}{21} = 1}⇝3(97)×219=1

Multiply the numbers on LHS in the bracket.

{\tt \leadsto \bigg( \dfrac{7 \times 3}{9 \times 1} \bigg) \times \dfrac{9}{21} = 1}⇝(9×17×3)×219=1

Multiply the numerators and denominators.

{\tt \leadsto \dfrac{21}{9} \times \dfrac{9}{21} = 1}⇝921×219=1

Multiply the numbers on LHS.

{\tt \leadsto \dfrac{21 \times 9}{9 \times 21} = 1}⇝9×2121×9=1

Multiply the numerators and denominators.

{\tt \leadsto \dfrac{189}{189} = 1}⇝189189=1

Write the fraction in lowest form on LHS.

{\tt \leadsto 1 = 1}⇝1=1

So,

{\sf \leadsto LHS = RHS}⇝LHS=RHS

\:

Hence verified !!

Answer:

Step-by-step explanation:

Given function:

[tex]y=\sqrt{x-2}[/tex]

The domain is the set of all possible input values (x-values).

As the square root of a negative number cannot be taken, the domain of the given function is restricted.

[tex]x-2\geq 0 \implies x\geq 2[/tex]

Therefore, the domain of the given function is [2, ∞).

The range is the set of all possible output values (y-values).

As the square root of a negative number cannot be taken, the range of the given function is restricted.  

Therefore, the range of the given function is [0, ∞).

A function f(x) is continuous when, for every value [tex]c[/tex] in its domain:

[tex]\text{$f(c)$ is de\:\!fined \quad and \quad $\displaystyle \lim_{x \to c} f(x) = f(c)$}[/tex]

Therefore, the function is continuous on its domain [2, ∞).

Stationary points occur when the gradient of a graph is zero.

Therefore, to find the x-coordinate(s) of the stationary points of a function, differentiate the function, set it to zero and solve for x.

[tex]\begin{aligned}y & = \sqrt{x-2}\\& = (x-2)^{\frac{1}{2}\\\implies \dfrac{\text{d}y}{\text{d}x} & = \dfrac{1}{2}(x-2)^{-\frac{1}{2}}\\ & = \dfrac{1}{2\sqrt{x-2}}\\\\\dfrac{\text{d}y}{\text{d}x} & = 0\\\implies \dfrac{1}{2\sqrt{x-2}} &= 0\\\dfrac{1}{2} &\neq 0\end{aligned}[/tex]

Therefore, there are no stationary points.

As the domain is restricted and f(x) ≥ 0, the minimum point of the function is at point (2, 0).

[tex]\textsf{A function is \textbf{increasing} when the \underline{gradient is positive}} \implies \dfrac{\text{d}y}{\text{d}x} > 0[/tex]

[tex]\textsf{A function is \textbf{decreasing} when the \underline{gradient is negative}} \implies \dfrac{\text{d}y}{\text{d}x} < 0[/tex]

Increasing

[tex]\begin{aligned}\dfrac{\text{d}y}{\text{d}x} & > 0 \\ \implies \dfrac{1}{2\sqrt{x-2}} & > 0 \\ \dfrac{1}{\sqrt{x-2}} & > 0\\ \textsf{If $\frac{1}{a} > 0$ then $a > 0$}: \\ \implies \sqrt{x-2} & > 0\\ x-2 & > 0\\ x & > 2\end{aligned}[/tex]

Decreasing

[tex]\begin{aligned}\dfrac{\text{d}y}{\text{d}x} & < 0 \\ \implies \dfrac{1}{2\sqrt{x-2}} & < 0 \\ \dfrac{1}{\sqrt{x-2}} & < 0\\ \textsf{If $\frac{1}{a} < 0$ then $a < 0$}: \\ \implies \sqrt{x-2} & < 0\\ \textsf{As $\sqrt{x}\geq 0$, no solution.}\end{aligned}[/tex]

Therefore:

[tex]\textsf{A function is \underline{even} when $f(x) = f(-x)$ for all $x$.}[/tex]

[tex]\textsf{A function is \underline{odd} when $-f(x) = f(-x)$ for all $x$.}[/tex]

As there is no symmetry about the y-axis (even symmetry) and no origin symmetry (odd symmetry), the symmetry of the function is neither.

Answer:

Domain: [2, ∞)

Range: [0, ∞)

Continuity: Function is continuous on its domain [2, ∞).

Minimum point at (2, 0).

Increasing function: (2, ∞)

Symmetry: Neither as there is no symmetry about the y-axis and no origin symmetry.

Answer:

Step-by-step explanation:

Answer:

44

Step-by-step explanation:

because if u pit it together 44 is what u get

Answer:

It's the nitrogen concentration, since it's the one being decided.

Answer:

(-1, -4)

Step-by-step explanation:

y = -x is the 45° diagonal through the origin from top left to bottom right.

a reflection across that line brings anything that is in quadrant 1 (x and y are positive) to quadrant 3 (x and y are negative) like this point. and vice versa.

points in quadrant 2 stay in quadrant 2, points in quadrant 4 stay in quadrant 4.

but in every case x and y are exchanged and both signs are flipped like (-1, 2) turns into (-2, 1).

or for our point : (4, 1) turns into (-1, -4)

Answer: Your computer will be worth $1,171.12

Step-by-step explanation:

[tex]a_n = 1500(0.94)^4\\a_n=\boxed{1171.12}[/tex]

Subtracting the initial amount of water from the amount used, the remaining amount of water is given by:

1.) 3.075 gallons.

To find the remaining amount of water in the barrel, we have to subtract the initial amount by the amount used.

We have that:

Hence the remaining amount is:

15 - 11.925 = 3.075 gallons.

Which means that option 1 is correct.

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Answer: 3.075 gallons

Step-by-step explanation:

Answer:

if 3 equal 8 , then 600 will be 1600.

Answer:

Add all like terms

12s = 0

s = 0

Step-by-step explanation:

8s + 6 + 4s = 6

12s + 6 = 6

       -6   -6

12s = 0

÷12   ÷12

s = 0

I hope this helps!

The set notation of the numbers is {x | x < 50 ∪ x > 50}

The set is given as

The set of all real numbers less than 50 or greater than 50

Let the number be represented by x

So, we have

x less than 50 or x greater than 50

When represented as an inequality, we have

x < 50 or x > 50

Using set notation, we have

{x | x < 50 ∪ x > 50}

Hence, the set notation of the numbers is {x | x < 50 ∪ x > 50}

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[tex] \Large {\mathbb {SOLUTION: }}[/tex]

[tex] \: \: \text{L = 3w - 1}[/tex]

[tex] \: \: \text{P=46}[/tex]

[tex] \: \: \text{2(3w-1) + 2w = 46}[/tex]

[tex] \: \: \text{6w - 2 + 2w = 46}[/tex]

[tex] \: \: \text{8w = 48}[/tex]

[tex] \: \: \text {W = 6 }[/tex]

[tex] \: \: \text{L = 17}[/tex]

[tex] \: \: \text{Applying the inequalities:}[/tex]

[tex] \: \: \text{L>=17 and w=6}[/tex]

[tex] \: \: \text{The perimeter is at least 46.}[/tex]

Answer:

[tex]8^{20}[/tex]

Step-by-step explanation:

using the rule of exponents

[tex](a^m)^{n}[/tex] = [tex]a^{mn}[/tex] , then

[tex](8^5)^{4}[/tex] = [tex]8^{5(4)}[/tex] = [tex]8^{20}[/tex]

Answer:

Evaluate the numerical expression. 1/4 - (- 5/8)

Step-by-stepexplanation:

Answer: pretty sure 4

Step-by-step explanation:

took test

yeaswass

The sentence "5 is subtracted from the square of a number" represented as an algebraic expression is x² -5.

Algebraic expressions: what are they?

Given,

Let the number be x and 3 is subtracted from a number.

Represent it in expression.

Step 2

3 is subtracted from a number means 3 is subtracted from x.

Here we have to subtract 3 from x. It can be represented as = x - 3

Let the number be x.

In this exercise, you're required to write an algebraic expression to represent the word problem (sentence). Also, the number would be denoted by the letter x and no need for further simplification of the algebraic expression.

Translating the word problem (sentence) into an algebraic expression, we have;

Square of a number (x) = x²

Subtracting 5 from the the square of x, we have  x² -5 .

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