101
3. Mike solved the following linear system and got
a solution of (-5, 3).
Linear System:
-x+y=8
2x - y = 3
Mike's Work:

like to see step by step work

Answer:

Explanation:

To find the class width, we need to divide the range of the data (which is the difference between the maximum and minimum values) by the number of classes.

The range of the data is 91 - 8 = 83

The class width is 83 / 7 = 11.857142857142857 (rounded to one decimal place, it becomes 11.9)

To find the lower class limits, we start from the minimum value and add the class width repeatedly until we reach the upper limit.

Lower class limits:

Class 1: 8 (minimum value)

Class 2: 8 + 11.9 = 19.9

Class 3: 19.9 + 11.9 = 31.8

Class 4: 31.8 + 11.9 = 43.7

Class 5: 43.7 + 11.9 = 55.6

Class 6: 55.6 + 11.9 = 67.5

Class 7: 67.5 + 11.9 = 79.4

To find the upper class limits, we add the class width to each lower class limit.

Upper class limits:

Class 1: 8 + 11.9 = 19.9

Class 2: 19.9 + 11.9 = 31.8

Class 3: 31.8 + 11.9 = 43.7

Class 4: 43.7 + 11.9 = 55.6

Class 5: 55.6 + 11.9 = 67.5

Class 6: 67.5 + 11.9 = 79.4

Class 7: 79.4 + 11.9 = 91.3 (maximum value)

So, the class width is 11.9, the lower class limits are 8, 19.9, 31.8, 43.7, 55.6, 67.5, 79.4, and the upper class limits are 19.9, 31.8, 43.7, 55.6, 67.5, 79.4, 91.3.

We must divide the data's range—that is, the difference between the maximum and minimum values—by the number of classes in order to determine the class width. The data's range is 91 - 8 = 83.

Thus, Class width is the distance between any class's (category's) upper and bottom bounds. It may also refer to one of the following more precisely, depending on the author.

The difference between the lower limits of two successive classes, or the difference between the upper limits of two successive (neighboring) classes.

An important element of a frequency distribution table is class breadth. A teacher documenting the percentage of pupils that received A's (90+), B's (80-89), C's (70-79), etc. on a test is a nice example of a frequency distribution table.

Thus, We must divide the data's range—that is, the difference between the maximum and minimum values—by the number of classes in order to determine the class width. The data's range is 91 - 8 = 83.

Learn more about Class width, refer to the link:

https://brainly.com/question/30459609

#SPJ6

Answer:

Explanation:

Answer:

i got u i have your email

Step-by-step explanation:

Answer:

Explanation:

Here are the results for the data:

Mean: The mean, or average, of the data can be calculated by summing up all the values and dividing by the number of values:

(11+16+10+30+24+5+6+12+11+45+9+8+3+4+35+31)/16 = 201/16 = 12.5625

So, the mean number of days spent by COVID-19 patients in the ICU is 12.5625 days.

Range: The range of the data is the difference between the maximum and minimum values:

45 - 3 = 42

So, the range of the data is 42 days.

Interquartile Range: The interquartile range (IQR) is a measure of the dispersion of the data that is less sensitive to outliers than the range. To calculate the IQR, we first need to find the median (Q2), first quartile (Q1), and third quartile (Q3) of the data:

Q1 = (6+8)/2 = 7

Q2 = (11+12)/2 = 11.5

Q3 = (24+30)/2 = 27

The IQR is the difference between Q3 and Q1:

IQR = Q3 - Q1 = 27 - 7 = 20

Variance and Standard Deviation: Variance is a measure of the dispersion of the data that is used to calculate the standard deviation. The formula for variance is:

Variance = sum of squared deviations from the mean / number of values

First, we need to calculate the deviations from the mean:

11 - 12.5625 = -1.5625

16 - 12.5625 = 3.4375

10 - 12.5625 = -2.5625

...

The sum of the squared deviations from the mean is:

Variance = 596.9375/16 = 37.93359375

The standard deviation is the square root of the variance:

Standard deviation = √Variance = √37.93359375 = 6.15

Coefficient of Variation: The coefficient of variation (CV) is a measure of the relative variability of the data, expressed as a percentage of the mean. The formula for the CV is:

CV = (Standard deviation / mean) * 100

CV = (6.15 / 12.5625) * 100 = 49.03%

Comment on Results:

The mean number of days spent by COVID-19 patients in the ICU at the University of Ghana Medical Centre is 12.5625 days. The range of the data is 42 days, while the interquartile range is 20 days. The variance is 37.93 and the standard deviation is 6.15. The coefficient of variation is 49.03%, which indicates a relatively high degree of variability in the data. These results show that the number of days spent by COVID-19 patients in the ICU at the University of Ghana Medical Centre can vary widely, with some patients spending as few as 3 days and others spending as many as 45 days in the ICU.

The X-1 aircraft's mission is based on To put a man on the moon, travel at the speed of light, and launch an aeroplane into space

The latest box office sensation Hidden Figures (2017) sheds light on the previously mostly untold tale of the women who worked as computers on NASA's Project Mercury in the 1960s. The main three actors in the film are Taraji P. Henson, Janelle Monáe, and Octavia Spencer.

When the women's car breaks down on the way to Langley Research Center and a police comes up asking for identification, Katherine hands him her card and murmurs seriously, "NASA, sir," in one of Hidden Figures' greatest scenes.

To know more about computers visit:-

https://brainly.com/question/30146762

#SPJ1

Answer:

9

Explanation:

To find the positive solution to the equation x^2 + 10 = 91, we'll start by isolating x^2 on one side of the equation. To do this, we'll subtract 10 from both sides:

x^2 + 10 - 10 = 91 - 10

x^2 = 81

Next, we'll take the square root of both sides of the equation to solve for x:

√(x^2) = √(81)

x = ±9

Since we are looking for the positive solution, x = 9.